Group actions on sets
[9/56%]Let and be homomorphisms of a group into and , respectively. Then the actions on and on that they define are called equivalent if there exists a bijective map , making the diagram
commutative for all . Thus, . Prove that every transitive action of a group is equivalent to the action of on the left cosets with respect to some subgroup .
Relying on Theorem 2, prove that all groups of order ( a prime number) are abelian.
Show that the center of the group , given at the end of Example 1, has the form
Find the conjugacy classes of the group .
Let be a natural number. Write it as a sum with . Denote by the number of all such partitions with , so that , etc. The decomposition of every permutation into a product of independent cycles (see [ВА I, Ch. 1, § 8]) uniquely determines a partition of the number . Show that the conjugacy classes of the group are in bijective correspondence with the partitions of the number .
Let a permutation be written as a product of cycles of length cycles of length 2, cycles of length 3, and so on, so that Show that the cardinality of the conjugacy class in containing the permutation is given by the formula
Let a group act on a set . Let us call a subset invariant with respect to (or -invariant) if for all and . For example, invariant sets under the action of on are concentric rings.
Fig. 1
Show that every invariant subset of is a union of orbits, and that the -orbit of any element is precisely the smallest invariant subset containing .
Show that for a group with a subgroup , the action , defined by the shift , gives a partition of into right cosets of with respect to .
By modifying the proof of Theorem 1, obtain the relation
where is the number of orbits of a permutation group acting on a set .
Alongside the centralizer in a group , one also considers the skew centralizer
which occurs in the theory of dynamical systems. In general, is not a group.
Prove that:
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is a group and ;
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the set is always a group.