Section 16

Additional exercises

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Problem 16.1

Find the greatest possible value of a third-order determinant composed:

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(a)

of the numbers 0 and 1;

(b)

of the numbers 1 and -1.

Problem 16.2

Prove that if, in a determinant of order nn, the entries at the intersection of some kk rows and ll columns are all zero, and k+l>nk+l>n, then the determinant equals zero.

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Problem 16.3

Let DD be a determinant of order n>1n>1, and let D1D_{1} and D2D_{2} be the determinants obtained from DD by replacing each entry aija_{i j} by its cofactor AijA_{i j} for D1D_{1}, and by its minor MijM_{i j} for D2D_{2}. Prove that D1=D2D_{1}=D_{2}.

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Problem 16.4

The adjugate (or adjoint) matrix A^\widehat{A} of a square matrix AA of order nn is the matrix whose (i,j)(i,j) entry is the cofactor AjiA_{j i}. Prove that:

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(a)

∣A^∣=∣A∣n−1\left|\widehat{A}\right|=\left|A\right|^{n-1};

(b)

A^^=∣A∣n−2A\hat{\hat{A}}=\left|A\right|^{n-2} A for n>2n>2, and A^^=A\hat{\hat{A}}=A for n=2n=2.

Problem 16.5

Let A=(aij),B=(bij)A=\left(a_{i j}\right), B=\left(b_{i j}\right) be matrices of size m×nm \times n, and let Ai1,…,imA_{i_{1}, \ldots , i_{m}} and Bi1,…,imB_{i_{1}, \ldots , i_{m}} be the minors of order mm of the matrices AA and BB, respectively, formed from the columns numbered i1,…,imi_{1}, \ldots , i_{m},

cij=∑k=1naikbjk,C=(cij),i=1,…,m;j=1,…,m c_{i j}=\sum _{k=1}^{n} a_{i k} b_{j k}, \quad C=\left(c_{i j}\right), \quad i=1, \ldots , m ; \quad j=1, \ldots , m

Prove that

det⁡C=∑1⩽i1<i2<…<im⩽nAi1,…,imBi1,…,im \operatorname {det} C=\sum _{1 \leqslant i_{1}<i_{2}<\ldots <i_{m} \leqslant n} A_{i_{1}, \ldots , i_{m}} B_{i_{1}, \ldots , i_{m}}

if m⩽nm \leqslant n, and det⁡C=0\operatorname {det} C=0 if m>nm>n.

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Problem 16.6

Let AA and BB be matrices of sizes p×np \times n and n×kn \times k, respectively, A(i1…imj1…jm),B(i1…imj1…jm)A\left(\begin{array}{lll}i_{1} & \ldots & i_{m} \\ j_{1} & \ldots & j_{m}\end{array}\right), \quad B\left(\begin{array}{lll}i_{1} & \ldots & i_{m} \\ j_{1} & \ldots & j_{m}\end{array}\right) the minors of the matrices AA and BB lying at the intersections of the rows numbered i1,…,imi_{1}, \ldots , i_{m} and the columns numbered j1,…,jmj_{1}, \ldots , j_{m}, and let C=ABC=A B. Prove that

C(i1…imj1…jm)={∑1⩽k1<k2<…<km⩽nA(i1…imk1…km)B(k1…kmj1…jm), if m⩽n,0, if m>n. C\left(\begin{array}{lll}i_{1} & \ldots & i_{m} \\ j_{1} & \ldots & j_{m}\end{array}\right) = \begin{cases} \displaystyle \sum _{1 \leqslant k_{1}<k_{2}<\ldots <k_{m} \leqslant n} A\left(\begin{array}{lll}i_{1} & \ldots & i_{m} \\ k_{1} & \ldots & k_{m}\end{array}\right) B\left(\begin{array}{lll}k_{1} & \ldots & k_{m} \\ j_{1} & \ldots & j_{m}\end{array}\right), & \text{ if } m \leqslant n, \\ 0, & \text{ if } m>n. \end{cases}
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Problem 16.7

Prove that the sum of the principal minors of order kk of the matrix A⋅tAA \cdot { }^{t} A equals the sum of the squares of all minors of order kk of the matrix AA.

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Problem 16.8

Let

D=[a11…a1n…………an1…ann] D=\left[\begin{smallmatrix} a_{11} & \ldots & a_{1 n} \\ \ldots \ldots & \ldots & \ldots \\ a_{n 1} & \ldots & a_{n n} \end{smallmatrix}\right]

Prove that

[a11…a1nx1……………an1…annxnx1…xnz]=Dz−∑i,j=1nAijxixj \left[\begin{smallmatrix} a_{11} & \ldots & a_{1 n} & x_{1} \\ \ldots \ldots & \ldots & \ldots & \ldots \\ a_{n 1} & \ldots & a_{n n} & x_{n} \\ x_{1} & \ldots & x_{n} & z \end{smallmatrix}\right]=D z-\sum _{i, j=1}^{n} A_{i j} x_{i} x_{j}
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Problem 16.9

Prove that the sum of the cofactors of the entries of a row of a determinant does not change if the same number is added to all entries of the matrix.

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Problem 16.10

Prove that if all entries of some row (column) of a determinant equal 1, then the sum of the cofactors of all entries of the determinant equals the determinant itself.

∗∗∗ * \quad * \quad *
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Problem 16.11

Let

A=[a11…a1n……………an1…ann],B=[b11…b1k…………bk1…bkk], A=\left[\begin{smallmatrix} a_{11} & \ldots & a_{1 n} \\ \ldots \ldots \ldots & \ldots & \ldots \\ a_{n 1} & \ldots & a_{n n} \end{smallmatrix}\right], \quad B=\left[\begin{smallmatrix} b_{11} & \ldots & b_{1 k} \\ \ldots \ldots & \ldots & \ldots \\ b_{k 1} & \ldots & b_{k k} \end{smallmatrix}\right], D=∣ a11b11…a1nb11a11b12…a1nb12…a11b1k…a1nb1k…………………………an1b11…annb11an1b12…annb12…an1b1k…annb1k…………………………. D=\left\lvert \, \begin{array}{llllllllll} a_{11} b_{11} & \ldots & a_{1 n} b_{11} & a_{11} b_{12} & \ldots & a_{1 n} b_{12} & \ldots & a_{11} b_{1 k} & \ldots & a_{1 n} b_{1 k} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ a_{n 1} b_{11} & \ldots & a_{n n} b_{11} & a_{n 1} b_{12} & \ldots & a_{n n} b_{12} & \ldots & a_{n 1} b_{1 k} & \ldots & a_{n n} b_{1 k} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \end{array}.\right.

where DD (a determinant of order nkn k) is the Kronecker product of the determinants AA and BB. Prove that D=AkBnD=A^{k} B^{n}.

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Problem 16.12

A continuant is the determinant

(a1a2…an)=[a1100…00−1a210…000−1a31…00…………………0000…−1an]. \left(a_{1} a_{2} \ldots a_{n}\right)=\left[\begin{smallmatrix} a_{1} & 1 & 0 & 0 & \ldots & 0 & 0 \\ -1 & a_{2} & 1 & 0 & \ldots & 0 & 0 \\ 0 & -1 & a_{3} & 1 & \ldots & 0 & 0 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & 0 & 0 & \ldots & -1 & a_{n} \end{smallmatrix}\right].
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(a)

Express (a1a2…an)(a_{1} a_{2} \ldots a_{n}) as a polynomial in a1,…,ana_{1}, \ldots , a_{n}.

(b)

Write the expansion of the continuant along the first kk rows.

(c)

Establish the following connection of the continuant with continued fractions:

(a1a2…an)(a2a3…an)=a1+1a2+1a3+…+1⋱1an−1+1an \frac{\left(a_{1} a_{2} \ldots a_{n}\right)}{\left(a_{2} a_{3} \ldots a_{n}\right)}=a_{1}+\frac{1}{a_{2}+\frac{1}{a_{3}+\ldots +\frac{1}{\ddots } \frac{1}{a_{n-1}+\frac{1}{a_{n}}}}}
Problem 16.13

Prove that if A,B,C,DA, B, C, D are square matrices of order nn and C⋅tD=D⋅tCC \cdot { }^{t} D=D \cdot { }^{t} C, then

[ABCD]=∣A⋅tD−B⋅tC∣ \left[\begin{smallmatrix} A & B \\ C & D \end{smallmatrix}\right]=\left|A \cdot { }^{t} D-B \cdot { }^{t} C\right|
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Problem 16.14

Prove that if A,B,C,DA, B, C, D are square matrices of order nn, where CC or DD is a nonsingular matrix, and CD=DCC D=D C, then

[ABCD]=∣AD−BC∣ \left[\begin{smallmatrix} A & B \\ C & D \end{smallmatrix}\right]=\left|A D-B C\right|
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Problem 16.15

Compute the determinant ∣cEAAcE∣\left|\begin{array}{cc}c E & A \\ A & c E\end{array}\right|, where

A=[a100…01a10…001a1…0………………0000…a] A=\left[\begin{smallmatrix} a & 1 & 0 & 0 & \ldots & 0 \\ 1 & a & 1 & 0 & \ldots & 0 \\ 0 & 1 & a & 1 & \ldots & 0 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & 0 & 0 & \ldots & a \end{smallmatrix}\right]
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Problem 16.16

Prove that the determinant obtained by deleting the kk-th column of the matrix

(aij)=((j−1i−1)),i=1,…,n+1;j=1,…,n+2 \left(a_{i j}\right)=\left(\binom {j-1}{i-1}\right), \quad i=1, \ldots , n+1 ; \quad j=1, \ldots , n+2

equals (n+1k−1)\binom {n+1}{k-1}.

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Problem 16.17

Prove that

[12!13!14!⋯1(2k+2)!112!13!⋯1(2k+1)!0112!⋯1(2k)!⋯⋯⋯⋯⋯000⋯12!]=0,k∈N. \left[\begin{smallmatrix} \frac{1}{2!} & \frac{1}{3!} & \frac{1}{4!} & \cdots & \frac{1}{(2 k+2)!} \\ 1 & \frac{1}{2!} & \frac{1}{3!} & \cdots & \frac{1}{(2 k+1)!} \\ 0 & 1 & \frac{1}{2!} & \cdots & \frac{1}{(2 k)!} \\ \cdots & \cdots & \cdots & \cdots & \cdots \\ 0 & 0 & 0 & \cdots & \frac{1}{2!} \end{smallmatrix}\right]=0, \quad k \in \mathbb {N}.
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Problem 16.18

Multiplying the matrices

[x1x2x3x4x2−x1−x4x3x3x4−x1−x2x4−x3x2−x1],[y1y2y3y4y2−y1−y4y3y3y4−y1−y2y4−y3y2−y1], \left[\begin{smallmatrix} x_{1} & x_{2} & x_{3} & x_{4} \\ x_{2} & -x_{1} & -x_{4} & x_{3} \\ x_{3} & x_{4} & -x_{1} & -x_{2} \\ x_{4} & -x_{3} & x_{2} & -x_{1} \end{smallmatrix}\right], \quad \left[\begin{smallmatrix} y_{1} & y_{2} & y_{3} & y_{4} \\ y_{2} & -y_{1} & -y_{4} & y_{3} \\ y_{3} & y_{4} & -y_{1} & -y_{2} \\ y_{4} & -y_{3} & y_{2} & -y_{1} \end{smallmatrix}\right],

prove that

(x12+x22+x32+x42)(y12+y22+y32+y42)==(x1y1+x2y2+x3y3+x4y4)2+(x1y2−x2y1−x3y4+x4y3)2++(x1y3+x2y4−x3y1−x4y2)2+(x1y4−x2y3+x3y2−x4y1)2 \begin{aligned} & \left(x_{1}^{2}+x_{2}^{2}+x_{3}^{2}+x_{4}^{2}\right)\left(y_{1}^{2}+y_{2}^{2}+y_{3}^{2}+y_{4}^{2}\right)= \\ & \quad =\left(x_{1} y_{1}+x_{2} y_{2}+x_{3} y_{3}+x_{4} y_{4}\right)^{2}+\left(x_{1} y_{2}-x_{2} y_{1}-x_{3} y_{4}+x_{4} y_{3}\right)^{2}+ \\ & \quad +\left(x_{1} y_{3}+x_{2} y_{4}-x_{3} y_{1}-x_{4} y_{2}\right)^{2}+\left(x_{1} y_{4}-x_{2} y_{3}+x_{3} y_{2}-x_{4} y_{1}\right)^{2} \end{aligned}
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Problem 16.19

Compute the determinant of the matrix (aij)(a_{i j}) of order nn, where:

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(a)

aija_{i j} equals 1 if ii divides jj, and equals 0 otherwise;

(b)

aija_{i j} equals the number of common divisors of ii and jj.

Problem 16.20

Prove that the determinant of the matrix (dij)(d_{i j}) of order nn, where dijd_{i j} is the greatest common divisor of ii and jj, equals φ(1)φ(2)…φ(n)\varphi (1) \varphi (2) \ldots \varphi (n).

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Problem 16.21

Let x1…xn,y1…ynx_{1} \ldots x_{n}, y_{1} \ldots y_{n} be numbers such that xiyj≠1x_{i} y_{j} \neq 1 for all i,j=1,…,n,Δ(x1,…,xn),Δ(y1,…,yn)i, j=1, \ldots , n, \quad \Delta \left(x_{1}, \ldots , x_{n}\right), \Delta \left(y_{1}, \ldots , y_{n}\right) are Vandermonde determinants. Prove that

Δ(x1,…,xn)Δ(y1,…,yn)=det⁡(11−xiyj)i,j=1,…,n∏i,j=1n(1−xiyj) \Delta \left(x_{1}, \ldots , x_{n}\right) \Delta \left(y_{1}, \ldots , y_{n}\right)=\operatorname {det}\left(\frac{1}{1-x_{i} y_{j}}\right)_{i, j=1, \ldots , n} \prod _{i, j=1}^{n}\left(1-x_{i} y_{j}\right)
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