Chapter 8

Inverse Matrices

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Problem 8.1

Let AA represent an m×nm \times n matrix. Show that

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(a)

if AA has a right inverse, then n≥mn \geq m and

(b)

if AA has a left inverse, then m≥nm \geq n.

Problem 8.2

An n×nn \times n matrix AA is said to be involutory if A2=IA^2 = I, that is, if AA is invertible and is its own inverse.

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(a)

Show that an n×nn \times n matrix AA is involutory if and only if (I−A)(I+A)=0(I-A)(I+A) = 0.

(b)

Show that a 2×22 \times 2 matrix A=(abcd)A = \left(\begin{smallmatrix} a & b \\ c & d \end{smallmatrix}\right) is involutory if and only if (1) a2+bc=1a^2+bc = 1 and d=−ad = -a or (2) b=c=0b = c = 0 and d=a=±1d = a = \pm 1.

Problem 8.3

Let AA represent an n×nn \times n nonnull symmetric matrix, and let BB represent an n×rn \times r matrix of full column rank rr and TT an r×nr \times n matrix of full row rank rr such that A=BTA = BT. Show that the r×rr \times r matrix TBTB is nonsingular.

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Remark.
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Observe that A′A=A2=BTBTA'A = A^2 = BTBT.

Problem 8.4

Let AA represent an n×nn \times n matrix, and partition AA as A=(A1,A2)A = (A_1, A_2).

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(a)

Show that if AA is invertible and A−1A^{-1} is partitioned as A−1=(B1B2)A^{-1} = \left(\begin{smallmatrix} B_1 \\ B_2 \end{smallmatrix}\right) (where B1B_1 has the same number of rows as A1A_1 has columns), then

B1A1=I,B1A2=0,B2A1=0,B2A2=I,A1B1=I−A2B2,A2B2=I−A1B1. \begin{align} & B_1 A_1 = I, \quad B_1 A_2 = 0, \quad B_2 A_1 = 0, \quad B_2 A_2 = I, \tag {E.1} \\ & A_1 B_1 = I - A_2 B_2, \quad A_2 B_2 = I - A_1 B_1. \tag {E.2} \end{align}
(b)

Show that if AA is orthogonal, then

A1′A1=I,A1′A2=0,A2′A1=0,A2′A2=I,A1A1′=I−A2A2′,A2A2′=I−A1A1′. \begin{align} & A_1' A_1 = I, \quad A_1' A_2 = 0, \quad A_2' A_1 = 0, \quad A_2' A_2 = I, \tag {E.3} \\ & A_1 A_1' = I - A_2 A_2', \quad A_2 A_2' = I - A_1 A_1'. \tag {E.4} \end{align}
Problem 8.5

Let AA represent an m×nm \times n nonnull matrix of rank rr. Show that there exists an m×mm \times m orthogonal matrix whose first rr columns span C(A)\mathcal{C}(A).

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Problem 8.6

Let TT represent an n×nn \times n triangular matrix. Show that rank(T)\mathrm{rank}(T) is greater than or equal to the number of nonzero diagonal elements in TT.

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Problem 8.7

Let

A=(A11A12⋯A1r0A22⋯A2r⋮⋱⋮00⋯Arr),B=(B110⋯0B21B220⋮⋮⋱Br1Br2⋯Brr) A = \left(\begin{smallmatrix} A_{11} & A_{12} & \cdots & A_{1r} \\ 0 & A_{22} & \cdots & A_{2r} \\ \vdots & & \ddots & \vdots \\ 0 & 0 & \cdots & A_{rr} \end{smallmatrix}\right), \qquad B = \left(\begin{smallmatrix} B_{11} & 0 & \cdots & 0 \\ B_{21} & B_{22} & & 0 \\ \vdots & \vdots & \ddots & \\ B_{r1} & B_{r2} & \cdots & B_{rr} \end{smallmatrix}\right)

represent respectively an n×nn \times n upper block-triangular matrix whose ijijth block AijA_{ij} is of dimensions ni×njn_i \times n_j (j≥i=1,…,rj \geq i = 1, \ldots , r) and an n×nn \times n lower block-triangular matrix whose ijijth block BijB_{ij} is of dimensions ni×njn_i \times n_j (j≤i=1,…,rj \leq i = 1, \ldots , r).

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(a)

Assume that AA and BB are invertible, and ``recall'' that

A−1=(F11F12⋯F1r0F22⋯F2r⋮⋱⋮00⋯Frr),B−1=(G110⋯0G21G220⋮⋮⋱Gr1Gr2⋯Grr), A^{-1} = \left(\begin{smallmatrix} F_{11} & F_{12} & \cdots & F_{1r} \\ 0 & F_{22} & \cdots & F_{2r} \\ \vdots & & \ddots & \vdots \\ 0 & 0 & \cdots & F_{rr} \end{smallmatrix}\right), \qquad B^{-1} = \left(\begin{smallmatrix} G_{11} & 0 & \cdots & 0 \\ G_{21} & G_{22} & & 0 \\ \vdots & \vdots & \ddots & \\ G_{r1} & G_{r2} & \cdots & G_{rr} \end{smallmatrix}\right),

where

Fii=Aii−1,Fij=−Aii−1∑k=i+1jAikFkj(j>i=1,…,r),Gii=Bii−1,Gij=−Bii−1∑k=ji−1BikGkj(j<i=1,…,r). \begin{align} F_{ii} & = A_{ii}^{-1}, \quad F_{ij} = -A_{ii}^{-1} \sum _{k=i+1}^{j} A_{ik} F_{kj} \quad (j > i = 1, \ldots , r), \tag {*} \\ G_{ii} & = B_{ii}^{-1}, \quad G_{ij} = -B_{ii}^{-1} \sum _{k=j}^{i-1} B_{ik} G_{kj} \quad (j < i = 1, \ldots , r). \tag {**} \end{align}

Show that the submatrices FijF_{ij} (j≥i=1,…,rj \geq i = 1, \ldots , r) and GijG_{ij} (j≤i=1,…,rj \leq i = 1, \ldots , r) are also expressible as

Fjj=Ajj−1,Fij=−(∑k=ij−1FikAkj)Ajj−1(i<j=1,…,r),Gjj=Bjj−1,Gij=−(∑k=j+1iGikBkj)Bjj−1(i>j=1,…,r). \begin{align} F_{jj} & = A_{jj}^{-1}, \quad F_{ij} = -\left( \sum _{k=i}^{j-1} F_{ik} A_{kj} \right) A_{jj}^{-1} \quad (i < j = 1, \ldots , r), \tag {E.5} \\ G_{jj} & = B_{jj}^{-1}, \quad G_{ij} = -\left( \sum _{k=j+1}^{i} G_{ik} B_{kj} \right) B_{jj}^{-1} \quad (i > j = 1, \ldots , r). \tag {E.6} \end{align}

Do so by applying results (**) and (*) to A′A' and B′B', respectively.

(b)

Formulas () form the basis for an algorithm for computing A−1A^{-1} in rr steps: the first step is to compute the matrix Frr=Arr−1F_{rr} = A_{rr}^{-1}; the (r−i+1)(r-i+1)th step is to compute the matrices Fii,Fi,i+1,…,FirF_{ii}, F_{i,i+1}, \ldots , F_{ir} from formulas () (i=r−1,r−2,…,1i = r-1, r-2, \ldots , 1). Similarly, formulas () form the basis for an algorithm for computing B−1B^{-1} in rr steps: the first step is to compute the matrix G11=B11−1G_{11} = B_{11}^{-1}; the iith step is to compute the matrices Gi1,Gi2,…,GiiG_{i1}, G_{i2}, \ldots , G_{ii} from formulas () (i=2,…,ri = 2, \ldots , r). Describe how formulas (E.5) and (E.6) in Part (a) can be used to devise rr-step algorithms for computing A−1A^{-1} and B−1B^{-1}, and indicate how these algorithms differ from those based on formulas (*) and (**).