Partial Isometries
[11/100%]If is a normal operator and if is a continuous function on , then .
Prove without using the spectral theorem that, for Hermitian operators, if and only if .
If is a normal operator on a separable Hilbert space, and if is diagonal for some positive integer , does it follow that is diagonal?
An operator is diagonal (see Problem 61) if there exists an orthonormal basis of the space consisting entirely of eigenvectors of that operator.
If is a continuous function on the complex plane, is the mapping , defined for all normal operators, continuous?
A bounded linear transformation is a partial isometry if and only if is a projection.
An isometry is a linear transformation (from a Hilbert space into itself, or from one Hilbert space into another) such that for all . A necessary and sufficient condition that a linear transformation be an isometry is that . Caution: the conditions and are not equivalent. The latter condition is satisfied in case is an isometry; in that case is called a co-isometry.
A partial isometry is a linear transformation that is isometric on the orthogonal complement of its kernel. It is easy to verify that a partial isometry is bounded, in fact if is not , then .
The orthogonal complement of the kernel of a partial isometry is frequently called its initial space. The initial space of a partial isometry turns out to be equal to the set of all those vectors for which . The range of a partial isometry is equal to the image of the initial space and is necessarily closed. For partial isometries, the range is sometimes called the final space.
Discover the implication relations between the statements "" and " reduces " when is a maximal partial isometry.
For partial isometries and , write in case agrees with on the initial space of ; this implies that the initial space of is included in the initial space of . A partial isometry is called maximal if it is not dominated, in this order, by any partial isometry other than itself. A partial isometry is maximal if and only if either it or its adjoint is an isometry.
The set of all non-zero partial isometries is closed but not connected (with respect to the norm topology of operators).
If and are partial isometries such that , then , , and .
If is a partial isometry, write , , and . These three cardinal numbers are called the rank, the co-rank, and the nullity of , respectively.
Each pair of partial isometries (on the same Hilbert space) with the same rank, co-rank, and nullity, can be joined by a continuous curve of partial isometries with the same rank, co-rank, and nullity.
If is a partial isometry, write , , and for its rank, co-rank, and nullity, respectively.
If and are unitarily equivalent contractions, then and are unitarily equivalent, and conversely.
An operator is a contraction if ; for a contraction , the operator is positive, so there exists a unique positive operator whose square is . The operator matrix
is a partial isometry.
What conditions must a set of complex numbers satisfy in order that it be the spectrum of some non-unitary partial isometry?