Transformation and Solution of Equations
[40/88%]The roots of the equation are real under the condition . When are the roots of the equation real?
Solve the equation by the substitution with a suitable choice of .
Reduce the following equation to one with integer coefficients and leading coefficient equal to unity, applying a substitution of the form : .
Reduce the following equation to one with integer coefficients and leading coefficient equal to unity, applying a substitution of the form : .
In the equation , one of the roots equals the square of another. Solve the equation.
Solve the equation .
Solve the equation .
Under what condition do two of the roots of the equation differ only in sign?
Prove the theorem: the palindromic equation
is, by the substitution , reduced to solving an equation of degree and a quadratic equation.
A polynomial with real coefficients
cannot, on the interval , remain in absolute value less than throughout.
An equation with real coefficients
has at least one root in the interval , if .
An equation with real coefficients
has a root in the interval , where . (Chebyshev.)
Transform the following equation by the indicated substitution (Tschirnhaus transformation): ; .
Transform the following equation by the indicated substitution (Tschirnhaus transformation): ; .
Transform the following equation by the indicated substitution (Tschirnhaus transformation): ; .
Transform the following equation by the indicated substitution (Tschirnhaus transformation): ; .
Find the equation for whose roots are expressed in terms of the roots of the given equation in the indicated way: ; , , .
Find the equation for whose roots are expressed in terms of the roots of the given equation in the indicated way: ; , and so on.
Find the equation for whose roots are expressed in terms of the roots of the given equation in the indicated way: ; .
Find the equation for whose roots are expressed in terms of the roots of the given equation in the indicated way: ; .
Find the equation for whose roots are expressed in terms of the roots of the given equation in the indicated way: ; .
Solve the equation .
Solve the equation .
Solve the equation .
Solve the equation .
Solve the equation .
Solve the equation .
Solve the equation .
Solve the equation by Cardano's formula and Ferrari's method.
A general cubic equation is reduced, by the linear substitution , to the equation . The latter is solved by the substitution , which introduces two new unknowns: setting , , we obtain Cardano's formula:
For the cube roots one should take only those values whose product equals (Hudde's method).
A general quartic equation is reduced, by the substitution , to the equation ; Ferrari's method solves such an equation by introducing an auxiliary parameter - a root of the cubic resolvent - and reducing the original equation to two quadratics:
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).
Solve the equation by Cardano's formula and Ferrari's method (see problem 2730).