Section 2.3

The Line in Space

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Problem 459

Find the planes projecting the line

{x−y+2z+3=0,2x−y−z+1=0 \begin{cases} x-y+2z+3 = 0, \\ 2x-y-z+1 = 0 \end{cases}

onto the coordinate planes.

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Problem 460

Find the angles of the line

{3x−y+2z=0,6x−3y+2z=2 \begin{cases} 3x-y+2z = 0, \\ 6x-3y+2z = 2 \end{cases}

with the coordinate axes.

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Problem 461

Find the angle between the lines

{x+2y+z−1=0,x−2y+z+1=0 \begin{cases} x+2y+z-1 = 0, \\ x-2y+z+1 = 0 \end{cases}

and

{x−y−z−1=0,x−y+2z+1=0. \begin{cases} x-y-z-1 = 0, \\ x-y+2z+1 = 0. \end{cases}
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Problem 462

Find the angle between the lines

{x+y=0,x−y=2 \begin{cases} x+y = 0, \\ x-y = 2 \end{cases}

and

{y+z=0,y−z+2=0. \begin{cases} y+z = 0, \\ y-z+2 = 0. \end{cases}
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Problem 463

The plane x+y+z=ax+y+z = a is intersected by the planes x=yx = y and 3x=y3x = y. Determine the angle between these lines of intersection.

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Problem 464

The line

{x+y−z=0,y=xtg⁡α \begin{cases} x+y-z = 0, \\ y = x \tg \alpha \end{cases}

is projected:

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(a)

onto the plane xOzxOz;

(b)

onto the plane yOzyOz.

Determine the angle between these projections.

Problem 465

Find the angle between the line

{x+y+3z=0,x−y−z=0 \begin{cases} x+y+3z = 0, \\ x-y-z = 0 \end{cases}

and the plane x−y−z+1=0x-y-z+1 = 0.

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Problem 466

Draw a line through the points (1,2,1)(1,2,1) and (2,1,3)(2,1,3).

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Problem 467

Draw a line through the points (1,2,1)(1,2,1) and (1,2,3)(1,2,3).

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Problem 468

Through the points A(2,−1,3)A(2,-1,3) and B(0,2,−1)B(0,2,-1) a line is drawn. Find the point of intersection of the line ABAB with the plane 3x−y+z=03x-y+z = 0.

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Problem 469

The points A(2,1,1)A(2,1,1) and B(1,2,2)B(1,2,2) are projected from the origin onto the plane x+y+z=10x+y+z = 10. Find the coordinates of the projections A′A' and B′B' and the distance ∣A′B′∣\left|A'B'\right| between these points.

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Problem 470

Through the point (2,1,3)(2,1,3) draw a line parallel to the plane x+y+z=ax+y+z = a and intersecting the line

{x=y,y=2z. \begin{cases} x = y, \\ y = 2z. \end{cases}
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Problem 471

Through the point (1,2,1)(1,2,1) draw a line perpendicular to the plane x+2y−z=0x+2y-z = 0.

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Problem 472

Through the point (2,1,1)(2,1,1) draw a line parallel to the planes 2x−y+1=02x-y+1 = 0, y−1=0y-1 = 0.

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Problem 473

Through the point (−1,2,1)(-1,2,1) draw a line parallel to the line

{x+y−2z−1=0,x+2y−z+1=0. \begin{cases} x+y-2z-1 = 0, \\ x+2y-z+1 = 0. \end{cases}
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Problem 474

Through the point (2,1,1)(2,1,1) draw a line parallel to the planes x−y+z+2=0x-y+z+2 = 0, x+y+2z−1=0x+y+2z-1 = 0.

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Problem 475

Through the point (2,2,1)(2,2,1) draw a plane perpendicular to the line x+2y−z+1=0x+2y-z+1 = 0, 2x+y−z=02x+y-z = 0.

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Problem 476

Through the point (1,1,2)(1,1,2) draw a plane parallel to the lines

x+12=y−11=z+12andx+11=y−12=z+11. \dfrac {x+1}{2} = \dfrac {y-1}{1} = \dfrac {z+1}{2} \qquad \text{and} \qquad \dfrac {x+1}{1} = \dfrac {y-1}{2} = \dfrac {z+1}{1}.
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Problem 477

Through the point (1,2,1)(1,2,1) draw a plane parallel to the lines

{x+2y−z+1=0,x−y+z−1=0and{2x−y+z=0,x−y+z=0. \begin{cases} x+2y-z+1 = 0, \\ x-y+z-1 = 0 \end{cases} \qquad \text{and} \qquad \begin{cases} 2x-y+z = 0, \\ x-y+z = 0. \end{cases}
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Problem 478

Through the line

{2x−y+z−1=0,x+y−z=0 \begin{cases} 2x-y+z-1 = 0, \\ x+y-z = 0 \end{cases}

and the point (2,1,1)(2,1,1) draw a plane.

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Problem 479

Through the line

{x−1=0,x+2y−z−1=0 \begin{cases} x-1 = 0, \\ x+2y-z-1 = 0 \end{cases}

draw a plane perpendicular to the plane x+y+z=0x+y+z = 0.

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Problem 480

Find the projection of the line

{x−y−z=0,x−5y+z=10 \begin{cases} x-y-z = 0, \\ x-5y+z = 10 \end{cases}

onto the plane x+2y+3z=2x+2y+3z = 2 and determine the angle formed by this projection with the plane xOyxOy.

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Problem 481

Through the axis OzOz draw a plane making an angle of 60∘60^{\circ } with the plane 2x+y−5z=72x+y-\sqrt{5}z = 7.

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Problem 482

Through the line x=y=zx = y = z draw a plane making an angle of 45∘45^{\circ } with the plane x=yx = y.

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Problem 483

The line x−12=y−23=z1\dfrac {x-1}{2} = \dfrac {y-2}{3} = \dfrac {z}{1} is projected from the point (5,5,5)(5,5,5) onto the plane xOyxOy. Find the equations of the projection.

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Problem 484

Through the point (1,2,−1)(1,2,-1) draw a line intersecting both lines

x−12=y+16=z+33andx−23=y1=z+3−1. \dfrac {x-1}{2} = \dfrac {y+1}{6} = \dfrac {z+3}{3} \qquad \text{and} \qquad \dfrac {x-2}{3} = \dfrac {y}{1} = \dfrac {z+3}{-1}.
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Problem 485

Through the line

{x+y+z=0,2x−y+3z=0 \begin{cases} x+y+z = 0, \\ 2x-y+3z = 0 \end{cases}

draw a plane parallel to the line x=2y=3zx = 2y = 3z.

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Problem 486

Find the equation of the plane perpendicular to the plane z=0z = 0 and passing through the perpendicular dropped from the point (1,−1,1)(1,-1,1) to the line

{x=0,y−z+1=0. \begin{cases} x = 0, \\ y-z+1 = 0. \end{cases}
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Problem 487

Find the equation and the length of the altitude of the triangle cut off on the plane 3x−y+4z−12=03x-y+4z-12 = 0 by the coordinate planes; the altitude is dropped from the vertex lying on OzOz.

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Problem 488

Find the point of intersection of the line

x−12=y+11=z+32 \dfrac {x-1}{2} = \dfrac {y+1}{1} = \dfrac {z+3}{2}

with the plane x+y−z+1=0x+y-z+1 = 0.

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Problem 489

Find the projection of the point (2,1,1)(2,1,1) onto the plane x+y+3z+5=0x+y+3z+5 = 0.

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Problem 490

Find the projection of the point (2,3,1)(2,3,1) onto the line

{x=t−7,y=2t−2,z=3t−2. \begin{cases} x = t-7, \\ y = 2t-2, \\ z = 3t-2. \end{cases}
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Problem 491

Find the equations of the projection of the line

{2x−y+z−1=0,x+y−z+1=0 \begin{cases} 2x-y+z-1 = 0, \\ x+y-z+1 = 0 \end{cases}

onto the plane x+2y−z=0x+2y-z = 0.

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Problem 492

Find the reflection of the point (−1,2,0)(-1,2,0) in the plane x+2y−z+1=0x+2y-z+1 = 0.

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Problem 493

Determine λ\lambda so that the lines x−11=y+12=z−1λ\dfrac {x-1}{1} = \dfrac {y+1}{2} = \dfrac {z-1}{\lambda } and x+11=y−11=z1\dfrac {x+1}{1} = \dfrac {y-1}{1} = \dfrac {z}{1} intersect.

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Problem 494

Find the lines perpendicular to the line

{y−z+1=0,x+2z=0 \begin{cases} y-z+1 = 0, \\ x+2z = 0 \end{cases}

and lying in the plane x+y+z+1=0x+y+z+1 = 0.

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Problem 495

Through the point of intersection of the plane x+y+z=2x+y+z = 2 and the line

{2y=x,z=−1 \begin{cases} 2y = x, \\ z = -1 \end{cases}

draw a line lying in the given plane and perpendicular to the given line.

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Problem 496

Find the equations and the length of the perpendicular dropped from the point (0,−1,1)(0,-1,1) to the line

{y+1=0,x+2z−7=0. \begin{cases} y+1 = 0, \\ x+2z-7 = 0. \end{cases}
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Problem 497

The line x=2y=3zx = 2y = 3z and the point (0,0,1)(0,0,1) are given. From this point a perpendicular is dropped to the given line, and the given line itself together with the perpendicular dropped onto it are projected onto the plane xOzxOz. Find the angle between the projections.

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Problem 498

Find the point symmetric to the point (x0,y0,z0)(x_{0}, y_{0}, z_{0}) with respect to the line xl=ym=zn\dfrac {x}{l} = \dfrac {y}{m} = \dfrac {z}{n}.

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Problem 499

Find the plane passing through the origin and through the perpendicular dropped from the point (1,−1,0)(1,-1,0) to the line

{x=z+3,y=−2z−3. \begin{cases} x = z+3, \\ y = -2z-3. \end{cases}
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Problem 500

Find the equations of the common perpendicular to the lines

{x+4z+1=0,x−4y+9=0and{y=0,x+2z+4=0. \begin{cases} x+4z+1 = 0, \\ x-4y+9 = 0 \end{cases} \qquad \text{and} \qquad \begin{cases} y = 0, \\ x+2z+4 = 0. \end{cases}
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Problem 501

The lines

x=y=zandx−11=y−1−1=z2 x = y = z \qquad \text{and} \qquad \dfrac {x-1}{1} = \dfrac {y-1}{-1} = \dfrac {z}{2}

and the common perpendicular to them are projected onto the plane xOyxOy. Determine the angles between the projections.

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Problem 502

Find the plane in which the lines

x−11=y+1−1=z−12andx−1−1=y+12=z−11 \dfrac {x-1}{1} = \dfrac {y+1}{-1} = \dfrac {z-1}{2} \qquad \text{and} \qquad \dfrac {x-1}{-1} = \dfrac {y+1}{2} = \dfrac {z-1}{1}

lie.

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Problem 503

Find the plane in which the lines

{2x+3y−z−1=0,x+y−3z=0and{x+5y+4z−3=0,x+2y+2z−1=0. \begin{cases} 2x+3y-z-1 = 0, \\ x+y-3z = 0 \end{cases} \qquad \text{and} \qquad \begin{cases} x+5y+4z-3 = 0, \\ x+2y+2z-1 = 0. \end{cases}

lie.

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Problem 504

Find the plane in which the lines

{x=2t−1,y=3t+2,z=2t−3and{x=2t+3,y=3t−1,z=2t+1. \begin{cases} x = 2t-1, \\ y = 3t+2, \\ z = 2t-3 \end{cases} \qquad \text{and} \qquad \begin{cases} x = 2t+3, \\ y = 3t-1, \\ z = 2t+1. \end{cases}

lie.

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Problem 505

Prove that the distance from the point M(x,y,z)M(x,y,z) to the line passing through the point A(a,b,c)A(a,b,c) can be expressed by the formula d=∣r→×P→∣∣P→∣d = \dfrac {\left|\overrightarrow {r} \times \overrightarrow {P}\right|}{\left|\overrightarrow {P}\right|}, where r→=AM→\overrightarrow {r} = \overrightarrow {AM}, and P→\overrightarrow {P} is any vector directed along the line.

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Problem 506

Using the previous result, prove that the distance dd from the point M(x1,y1,z1)M(x_{1},y_{1},z_{1}) to the line

x−al=y−bm=z−cn \dfrac {x-a}{l} = \dfrac {y-b}{m} = \dfrac {z-c}{n}

can be expressed by the formula

d2=1l2+m2+n2((m(x1−a)−l(y1−b))2+(n(x1−a)−l(z1−c))2+(n(y1−b)−m(z1−c))2). d^{2} = \dfrac {1}{l^{2}+m^{2}+n^{2}}\Bigl(\bigl(m(x_{1}-a)-l(y_{1}-b)\bigr)^{2}+\bigl(n(x_{1}-a)-l(z_{1}-c)\bigr)^{2}+\bigl(n(y_{1}-b)-m(z_{1}-c)\bigr)^{2}\Bigr).
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Problem 507

Find the distance from the point (3,−1,2)(3,-1,2) to the line

{2x−y+z−4=0,x+y−z+1=0. \begin{cases} 2x-y+z-4 = 0, \\ x+y-z+1 = 0. \end{cases}
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Problem 508

Prove that the distance between two nonparallel lines can be expressed by the formula

d=(r→1×r→2)⋅r→3∣r→1×r→2∣, d = \dfrac {(\overrightarrow {r}_{1} \times \overrightarrow {r}_{2}) \cdot \overrightarrow {r}_{3}}{\left|\overrightarrow {r}_{1} \times \overrightarrow {r}_{2}\right|},

where r→1\overrightarrow {r}_{1} and r→2\overrightarrow {r}_{2} are any vectors lying on the given lines, and r→3\overrightarrow {r}_{3} is a vector going from a point on one line to a point on the other line.

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Problem 509

Prove that the length dd of the common perpendicular to the lines

x−al=y−bm=z−cnandx−a1l1=y−b1m1=z−c1n1 \dfrac {x-a}{l} = \dfrac {y-b}{m} = \dfrac {z-c}{n} \qquad \text{and} \qquad \dfrac {x-a_{1}}{l_{1}} = \dfrac {y-b_{1}}{m_{1}} = \dfrac {z-c_{1}}{n_{1}}

can be represented by the formula

d=∣a1−ab1−bc1−clmnl1m1n1∣(lm1−l1m)2+(mn1−m1n)2+(ln1−l1n)2. d = \dfrac {\begin{vmatrix} a_{1}-a & b_{1}-b & c_{1}-c \\ l & m & n \\ l_{1} & m_{1} & n_{1} \end{vmatrix}}{\sqrt{(lm_{1}-l_{1}m)^{2}+(mn_{1}-m_{1}n)^{2}+(ln_{1}-l_{1}n)^{2}}}.
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Problem 510

Find the distance between the lines

{x+y−z−1=0,2x+y−z−2=0and{x+2y−z−2=0,x+2y+2z+4=0. \begin{cases} x+y-z-1 = 0, \\ 2x+y-z-2 = 0 \end{cases} \qquad \text{and} \qquad \begin{cases} x+2y-z-2 = 0, \\ x+2y+2z+4 = 0. \end{cases}
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Problem 511

Find the distance between the lines x=y=zx = y = z and

{x−1=0,y−2=0. \begin{cases} x-1 = 0, \\ y-2 = 0. \end{cases}
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Problem 512

Prove that the distance hh between parallel lines can be expressed by the formula

h=∣r→×P→∣∣P→∣, h = \dfrac {\left|\overrightarrow {r} \times \overrightarrow {P}\right|}{\left|\overrightarrow {P}\right|},

where r→\overrightarrow {r} is a vector going from a point on one line to a point on the other line, and P→\overrightarrow {P} is a vector parallel to the given lines.

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Problem 513

Prove that the distance between the lines

x−al=y−bm=z−cnandx−a1l=y−b1m=z−c1n \dfrac {x-a}{l} = \dfrac {y-b}{m} = \dfrac {z-c}{n} \qquad \text{and} \qquad \dfrac {x-a_{1}}{l} = \dfrac {y-b_{1}}{m} = \dfrac {z-c_{1}}{n}

can be expressed by the formula

h2=1l2+m2+n2((m(a1−a)−l(b1−b))2+(n(b1−b)−m(c1−c))2+(l(c1−c)−n(a1−a))2). h^{2} = \dfrac {1}{l^{2}+m^{2}+n^{2}}\Bigl(\bigl(m(a_{1}-a)-l(b_{1}-b)\bigr)^{2}+\bigl(n(b_{1}-b)-m(c_{1}-c)\bigr)^{2}+\bigl(l(c_{1}-c)-n(a_{1}-a)\bigr)^{2}\Bigr).
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Problem 514

Find the distance between the parallel lines

{x=t+1,y=2t−1,z=tand{x=t+2,y=2t−1,z=t+1. \begin{cases} x = t+1, \\ y = 2t-1, \\ z = t \end{cases} \qquad \text{and} \qquad \begin{cases} x = t+2, \\ y = 2t-1, \\ z = t+1. \end{cases}
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Problem 515

If the vectors r→1\overrightarrow {r}_{1} and r→2\overrightarrow {r}_{2} have equal length and lie on given intersecting lines, then the vectors r→1±r→2\overrightarrow {r}_{1} \pm \overrightarrow {r}_{2} are parallel to the bisectors of the angles between the lines. Starting from this remark, prove that the bisectors of the angles between the lines

x−al=y−bm=z−cnandx−al1=y−bm1=z−cn1 \dfrac {x-a}{l} = \dfrac {y-b}{m} = \dfrac {z-c}{n} \qquad \text{and} \qquad \dfrac {x-a}{l_{1}} = \dfrac {y-b}{m_{1}} = \dfrac {z-c}{n_{1}}

can be represented by the equations

x=a+(lΔ±l1Δ1)t,y=b+(mΔ±m1Δ1)t, x = a+\left(\dfrac {l}{\Delta } \pm \dfrac {l_{1}}{\Delta _{1}}\right)t, \qquad y = b+\left(\dfrac {m}{\Delta } \pm \dfrac {m_{1}}{\Delta _{1}}\right)t, z=c+(nΔ±n1Δ1)t, z = c+\left(\dfrac {n}{\Delta } \pm \dfrac {n_{1}}{\Delta _{1}}\right)t,

where

Δ=l2+m2+n2,Δ1=l12+m12+n12. \Delta = \sqrt{l^{2}+m^{2}+n^{2}}, \qquad \Delta _{1} = \sqrt{l_{1}^{2}+m_{1}^{2}+n_{1}^{2}}.
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Problem 516

Find the bisectors of the angles between the lines

x−36=y+2−3=z−12andx−314=y+2−5=z−12. \dfrac {x-3}{6} = \dfrac {y+2}{-3} = \dfrac {z-1}{2} \qquad \text{and} \qquad \dfrac {x-3}{14} = \dfrac {y+2}{-5} = \dfrac {z-1}{2}.
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Problem 517

Find the bisectors of the angles between the lines

x−13=y−28=z−31andx−14=y−27=z−33. \dfrac {x-1}{3} = \dfrac {y-2}{8} = \dfrac {z-3}{1} \qquad \text{and} \qquad \dfrac {x-1}{4} = \dfrac {y-2}{7} = \dfrac {z-3}{3}.
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Problem 518

Draw the bisectors of the angles between the lines

x10=y11=z2andx1=y2=z−2 \dfrac {x}{10} = \dfrac {y}{11} = \dfrac {z}{2} \qquad \text{and} \qquad \dfrac {x}{1} = \dfrac {y}{2} = \dfrac {z}{-2}

and find the angles into which the projections of the bisectors onto the plane xOzxOz divide the projections of the angles onto the same plane.

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Problem 519

Find the lines that intersect the lines

{x+y−z−1=0,x−y+z+1=0and{2x−y+z−1=0,x+y−z+1=0 \begin{cases} x+y-z-1 = 0, \\ x-y+z+1 = 0 \end{cases} \qquad \text{and} \qquad \begin{cases} 2x-y+z-1 = 0, \\ x+y-z+1 = 0 \end{cases}

and are parallel to the plane x+y+z=0x+y+z = 0.

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Problem 520

Find the lines that intersect the three lines:

{x=0,y=0,{x=1,z=0,{y−1=0,z+1=0. \begin{cases} x = 0, \\ y = 0, \end{cases} \qquad \begin{cases} x = 1, \\ z = 0, \end{cases} \qquad \begin{cases} y-1 = 0, \\ z+1 = 0. \end{cases}
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Problem 521

Prove that the planes passing through the edges of a trihedral angle and the bisectors of the opposite faces intersect along a line.

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Problem 522

Three mutually perpendicular lines are rigidly attached to a solid body. Initially they were directed along the axes OxOx, OyOy, OzOz, and then came to lie along the axes Ox1Ox_{1}, Oy1Oy_{1}, Oz1Oz_{1}. The cosines of the angles between the axes are given by the table:

x1x_{1}y1y_{1}z1z_{1}
xxa1a_{1}b1b_{1}c1c_{1}
yya2a_{2}b2b_{2}c2c_{2}
zza3a_{3}b3b_{3}c3c_{3}

Prove that such a displacement of the body could have been achieved by a rotation about a line, and find that line.

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Problem 523

The coordinates xx, yy, zz pass into the coordinates x1x_{1}, y1y_{1}, z1z_{1} by the formulas: 9x1=4x+7y−4z9x_{1} = 4x+7y-4z, 9y1=x+4y+8z9y_{1} = x+4y+8z, 9z1=8x−4y+z9z_{1} = 8x-4y+z. Then by the same formulas the coordinates x1x_{1}, y1y_{1}, z1z_{1} pass into the coordinates x2x_{2}, y2y_{2}, z2z_{2}, and so on. Prove that x4=xx_{4} = x, y4=yy_{4} = y, z4=zz_{4} = z.

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Problem 524

The coordinates xx, yy, zz pass into the coordinates x1x_{1}, y1y_{1}, z1z_{1} by the formulas:

9x1=(5cos⁡φ+4)x+(−4cos⁡φ+3sin⁡φ+4)y+(−2cos⁡φ+6sin⁡φ+2)z, 9x_{1} = (5\cos \varphi +4)x+(-4\cos \varphi +3\sin \varphi +4)y+(-2\cos \varphi +6\sin \varphi +2)z, 9y1=(−4cos⁡φ−3sin⁡φ+4)x+(5cos⁡φ+4)y+(−2cos⁡φ+6sin⁡φ+2)z, 9y_{1} = (-4\cos \varphi -3\sin \varphi +4)x+(5\cos \varphi +4)y+(-2\cos \varphi +6\sin \varphi +2)z, 9z1=(−2cos⁡φ+6sin⁡φ+2)x+(−2cos⁡φ−6sin⁡φ+2)y+(8cos⁡φ+1)z. 9z_{1} = (-2\cos \varphi +6\sin \varphi +2)x+(-2\cos \varphi -6\sin \varphi +2)y+(8\cos \varphi +1)z.

Then by the same formulas the coordinates x1x_{1}, y1y_{1}, z1z_{1} pass into the coordinates x2x_{2}, y2y_{2}, z2z_{2}, and so on. Prove that the coordinates xnx_{n}, yny_{n}, znz_{n} are expressed in terms of xx, yy, zz by the same formulas as x1x_{1}, y1y_{1}, z1z_{1}, except that the angle φ\varphi is replaced by nφn\varphi.

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