Discontinuous Solutions. One-Sided Variation
[18/94%]Find the discontinuous solutions with a corner point for the problem of the minimum of the integral
Among the lines going from the point to the point , find the line with a corner point along which the integral
attains its minimum value.
Find the discontinuous solutions with a corner point for the problem of the minimum of the integral
For the problem of the extremum of the integral
find the continuous solutions, as well as the solutions with a corner point.
Among all cylindrical surfaces with generators parallel to , find the one on which the plane , the cone , and the two generators passing through the points and cut off the smallest area.
In the plane , find the curve joining two points and and having the smallest moment of inertia relative to the point . Find the continuous and discontinuous solutions.
Among the lines lying in the upper half-plane and joining the points and , find the one that, when rotated about , gives the smallest surface.
Find the discontinuous solutions (see problem 5988).
Find the curve, lying in the region , joining the points and and forming, when rotated about , the smallest surface.
Among the lines joining the given points and , find the discontinuous solution of the problem of the minimum of the integral
Find the shortest path from the point to the point , lying in the region .
Among the curves joining the points and and lying in the region , find the one that gives the maximum of the integral
under the condition .
The minimum is sought of the integral
in the region , under the condition that at one limit the values of the function and its derivative are given, while at the other limit only the number itself is given. Show that if the extremal meets the boundary curve , then its further continuation makes with the boundary curve the same angle, i.e., the angle of incidence equals the angle of reflection.
Inside a convex region two points and are given. Find the shortest path from to that touches the boundary of .
Find the minimum of the integral
under the conditions ; .
Among the curves joining the points and , find the one that gives an extremal value of the integral
under the condition , .
On the surface the points and are given.
Draw on the surface the shortest line from to , under the condition that the slope of the curve, i.e., , does not exceed a given number (mountain railway).
Join the points and by the shortest path, leaving in a given direction and having curvature not exceeding a given value . The point lies outside the circles of radius tangent to the given direction at the point .
Light travels along a path such that the first variation of the integral
along the path equals zero. Here is the refractive index of the medium.
If a ray passes from one medium into another, then may undergo a sudden change. Derive the condition for the refraction of a light ray when the ray passes from a medium with refractive index into a medium with refractive index (see problem 6055).