Section 14.11

Applications to Problems of Mathematical Physics

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Problem 5720

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=azw = az; a>0a > 0.

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Remark.
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A plane, irrotational motion of an incompressible fluid is characterized by an analytic function w(z)=φ(x,y)+iψ(x,y)w(z) = \varphi (x,y)+i\psi (x,y), where φ\varphi is the velocity potential, and ψ\psi is the stream function. The projections of velocity onto the coordinate axes, vxv_{x} and vyv_{y}, equal the partial derivatives ∂φ∂x\dfrac {\partial \varphi }{\partial x} and ∂φ∂y\dfrac {\partial \varphi }{\partial y}. Hence dwdz=vx−ivy\dfrac {dw}{dz} = v_{x}-iv_{y}. Every fluid particle moves along a streamline ψ(x,y)=C\psi (x,y) = C. The difference of the values of ψ\psi at two points represents the volume of fluid flowing per unit time through a cylinder of unit height whose walls lie on the line joining the given points in the plane XOYXOY. Any streamline, or part of one, may be replaced by a solid wall without disturbing the fluid motion.

Problem 5721

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=iazw = iaz; a>0a > 0.

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Problem 5722

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=z2w = z^{2}.

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Problem 5723

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=1zw = \dfrac {1}{z}.

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Problem 5724

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=1z2w = \dfrac {1}{z^{2}}.

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Problem 5725

Find the lines of equal potential, the streamlines, and the magnitude of the velocity and its components on the axes, if the fluid motion is determined by the motion function w=ln⁡zw = \ln z.

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Problem 5726

The velocity potential has the form

φ=ln⁡∣z2−a2∣−ln⁡∣z2+a2∣. \varphi = \ln \left|z^{2}-a^{2}\right|-\ln \left|z^{2}+a^{2}\right|.

Find the equation of the streamlines, and show that the arcs of the circle ∣z∣=a\left|z\right| = a and the coordinate axes outside the points z=±az = \pm a, z=±iaz = \pm ia are streamlines.

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Problem 5727

The stream function has the form

ψ=ln⁡(r4−2a2r2cos⁡2θ+a4), \psi = \ln (r^{4}-2a^{2}r^{2}\cos 2\theta +a^{4}),

where z=reθiz = re^{\theta i}. Find the potential φ\varphi.

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Problem 5728

The stream function is determined by the equation:

th⁡πxa⋅tg⁡ψ=tg⁡πya;a>0. \th \frac{\pi x}{a}\cdot \tg \psi = \tg \frac{\pi y}{a}; \quad a > 0.

Find the motion function ww.

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Problem 5729

The streamlines are the circles x2+y2=2axx^{2}+y^{2} = 2ax. Find the ratio of the fluid velocity at the points (2a,0)(2a,0) and (a,a)(a,a).

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Problem 5730

The same question (problem 5729, the ratio of the fluid velocity at two points) for the lemniscate r2=a2cos⁡2θr^{2} = a^{2}\cos 2\theta and the points (a,0)(a,0) and (a38,a8)\left(a\sqrt{\dfrac {3}{8}}, \dfrac {a}{\sqrt{8}}\right).

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Problem 5731

For a source z=az = a of strength EE, find the streamlines and the lines of equal potential.

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Remark.
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Call the flux through a closed contour CC the quantity of fluid EE flowing per unit time through a cylinder of unit height whose base lies along the contour CC. The quantity EE is given by the formula:

E=∫Cvx dy−vy dx. E = \int _{C} v_{x}\, dy-v_{y}\, dx.

The circulation of the velocity along the same contour CC is called the quantity Γ=∫Cvx dx+vy dy\Gamma = \int_{C} v_{x}\, dx+v_{y}\, dy. Since Γ+iE=∫Cdwdz⋅dz\Gamma +iE = \int_{C} \dfrac {dw}{dz}\cdot dz, EE and Γ\Gamma are conveniently found by means of residues. If w=E2πln⁡(z−a)w = \dfrac {E}{2\pi }\ln (z-a), where EE is real, then the point aa is called a source of strength EE. If w=Γ2πiln⁡(z−a)w = \dfrac {\Gamma }{2\pi i}\ln (z-a), where Γ\Gamma is real, then the point aa is called a vortex of intensity Γ\Gamma.

Problem 5732

The fluid motion is produced by a source of strength EE (problem 5731), placed at the point aa. Prove that the flux through a simple closed contour CC equals zero if the point aa is outside the contour, and equals EE if the point aa is inside the contour.

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Problem 5733

Under the same conditions (problem 5732), prove that the circulation along any closed contour equals zero.

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Problem 5734

Obtain the corresponding results (problems 5732--5733) for the motion produced by a vortex of intensity Γ\Gamma at the point aa (problem 5731).

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Problem 5735

The fluid motion is produced by a source EE and a vortex Γ\Gamma, placed at the point aa (problem 5731). Prove that the streamlines are logarithmic spirals.

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Problem 5736

The motion function is w=ln⁡sh⁡πzw = \ln \sh \pi z. Find the flux through the circle 2∣z∣=32\left|z\right| = 3 and the circulation along it.

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Problem 5737

The motion function is w=2iln⁡(z2−a2)w = 2i\ln (z^{2}-a^{2}). Find the circulation along the circles ∣z−a∣=a\left|z-a\right| = a; ∣z+a∣=a\left|z+a\right| = a.

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Problem 5738

The motion function is w=ln⁡(z2+z−2)w = \ln (z^{2}+z^{-2}). What are the sources?

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Problem 5739

Prove that the real axis is a streamline, if the motion is created by sources of strength EE, placed at the points a±bia \pm bi.

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Problem 5740

Prove that the reflection in the real axis of a vortex Γ\Gamma at the point a+bia+bi is a vortex −Γ-\Gamma at the point a−bia-bi.

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Remark.
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Remark. If a streamline CC divides the plane into two parts, and the motion is created by sources and vortices, then the collection of sources and vortices on one side of the line CC is called the reflection of the sources and vortices on the other side of the same line.

Problem 5741

At the point aa outside the disk ∣z∣=R\left|z\right| = R there is a source EE. Prove that its reflection in the circle (problem 5740) consists of two sources: a source EE at the point R2a‾\dfrac {R^{2}}{\overline{a}} and a source of strength −E-E at the point z=0z = 0.

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Problem 5742

A vortex of intensity Γ\Gamma is placed outside the disk ∣z∣=R\left|z\right| = R. Prove that its reflection in the circle (problem 5740) is a vortex −Γ-\Gamma at the point R2a‾\dfrac {R^{2}}{\overline{a}}.

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Problem 5743

Find the fluid motion outside the disk ∣z∣=1\left|z\right| = 1, produced by a source of strength EE at the point aa, where a>1a > 1.

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Problem 5744

The same (problem 5743) for a vortex of intensity Γ\Gamma.

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Problem 5745

Find the fluid motion in the domain ∣z∣>1\left|z\right| > 1, Im(z)>0\mathrm{Im}\left(z\right) > 0, produced by a vortex at the point z=aiz = ai, a>1a > 1, of intensity Γ\Gamma.

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Problem 5746

The positive parts of the coordinate axes are impermeable walls. Only at the point z=1z = 1 is there a point source (more precisely, a source along a slit perpendicular to the plane XOYXOY and passing through z=1z = 1), from which, in a space of height 11, QQ units flow into the first quadrant per second. Find the fluid motion.

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Problem 5747

Find the fluid motion in the region 0<y<x30 < y < x\sqrt{3}, produced by a source of strength EE at the point z=aeπi6z = ae^{\frac{\pi i}{6}}; a>0a > 0.

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Problem 5748

Find the fluid motion in the first quadrant, if at the points z=1z = 1 and z=iz = i in the walls of the quadrant there are point sources through which, respectively, QQ units of volume of fluid flow in and out per second.

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Problem 5749

Sources of strength ±Ea\pm \dfrac {E}{a} are located at the points z=±az = \pm a, where a→0a \to 0 (a dipole). Find the limiting fluid motion.

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Problem 5750

On a circle, impermeable to fluid elsewhere, two sources of strength EE and −E-E are placed. Prove that the streamlines inside the disk are arcs of circles passing through both sources.

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Problem 5751

Two vortices Γ\Gamma and −Γ-\Gamma are placed at two points. Prove that in the motion produced by them, the streamlines are circles.

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Problem 5752

The fluid motion is produced by a stream from infinity, with velocity equal to aa and directed in the negative direction of the axis OxOx, and by a source E=1E = 1 at the origin. Prove that the fluid issuing from the source fills the region inside the curve xtg⁡2πay=yx\tg 2\pi ay = y.

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Problem 5753

The motion in the half-plane y>0y > 0 is produced by a source at the point z=aiz = ai. Prove that the streamlines are the hyperbolas x2−y2+a2=Cxyx^{2}-y^{2}+a^{2} = Cxy.

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Problem 5754

The fluid motion is created by the superposition of sources at z=0,±πi,±2πi,…z = 0, \pm \pi i, \pm 2\pi i, \ldots with strength E=2πE = 2\pi each. Prove that the velocity of motion tends to unity as one recedes from OYOY, and is directed away from the axis OYOY almost perpendicularly to it.

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Problem 5755

At the same points (problem 5754) there are vortices of intensity Γ\Gamma. Prove that at points far from the axis OYOY the velocity in magnitude is close to Γ2π\dfrac {\Gamma }{2\pi }, and in direction is almost parallel to the axis OYOY.

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Problem 5756

The fluid motion is created by the superposition of sources of strength E=2πE = 2\pi at the points z=0,±πi,±2πi,…z = 0, \pm \pi i, \pm 2\pi i, \ldots and a stream of velocity v>1v > 1, parallel to the negative direction of the axis OXOX. Prove that the greatest abscissa of the points reached by the fluid from the sources equals 12ln⁡v+1v−1\dfrac {1}{2}\ln \dfrac {v+1}{v-1}.

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Problem 5757

Prove that, under the conditions of the previous problem (problem 5756), the region filled by the fluid from the source z=0z = 0 is bounded by the curve cth⁡x⋅tg⁡y=tg⁡vy\cth x\cdot \tg y = \tg vy, the distance between whose branches tends to 2πv+1\dfrac {2\pi }{v+1} as x→−∞x \to -\infty.

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Problem 5758

A source of strength E=2πE = 2\pi is located at the point z=aiz = ai, where 0<a<π20 < a < \dfrac {\pi }{2}. Prove that the motion it creates in the strip 0<y<π20 < y < \dfrac {\pi }{2} has motion function:

w=ln⁡sh⁡((z+ia)sh⁡(z−ia)). w = \ln \sh \left((z+ia)\sh (z-ia)\right).
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Problem 5759

A source of strength E=2πE = 2\pi is located at the point z0=a+biz_{0} = a+bi, where a>0a > 0; 0<b<π20 < b < \dfrac {\pi }{2}. Prove that the motion function it creates in the domain 0<y<π20 < y < \dfrac {\pi }{2}; x>0x > 0, is given by the formula:

w=ln⁡(sh⁡(z−z0)sh⁡(z+z0)sh⁡(z−z0‾)sh⁡(z+z0‾)). w = \ln \left(\sh (z-z_{0})\sh (z+z_{0})\sh (z-\overline{z_{0}})\sh (z+\overline{z_{0}})\right).
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Problem 5760

The fluid motion in the region ∣z∣>1\left|z\right| > 1, produced by a source of strength EE at the point a>1a > 1, is characterized by the function w=E2πln⁡(z+1z−a−1a)w = \dfrac {E}{2\pi }\ln \left(z+\dfrac {1}{z}-a-\dfrac {1}{a}\right). Setting E=2πb(a+1a)E = 2\pi b\left(a+\dfrac {1}{a}\right) and a→∞a \to \infty, find the motion arising from flow past the disk ∣z∣<1\left|z\right| < 1 by a stream whose velocity at infinity is v∞=vv_{\infty } = v and is directed toward the negative axis OXOX.

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Problem 5761

Along the real axis there is an impermeable wall. At a distance hh from it there is a vortex of intensity Γ\Gamma. Prove that it moves parallel to the axis OXOX with velocity Γ4πh\dfrac {\Gamma }{4\pi h}.

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Remark.
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If the fluid motion in a simply connected domain, determined by a function w(z)w(z), is produced by a vortex of intensity Γ\Gamma, located at the given moment at the point z=az = a, then this vortex is displaced with velocity

dadt=(dw1dz‾)z=a, \frac{da}{dt} = \left(\overline{\frac{dw_{1}}{dz}}\right)_{z=a},

where

w1=w−Γ2πiln⁡(z−a)=φ(x,y)+iψ(x,y). w_{1} = w-\frac{\Gamma }{2\pi i}\ln (z-a) = \varphi (x,y)+i\psi (x,y).

The trajectory of the vortex is given by the equation

ψ(ξ,η)=C,where a=ξ+iη, \psi (\xi ,\eta ) = C, \quad \text{where } a = \xi +i\eta ,

and the fluid velocity at infinity is assumed to be zero.

Problem 5762

Prove that a vortex, placed inside an impermeable circle, moves along a concentric circle.

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Problem 5763

The motion in the region x>0x > 0, y>0y > 0 is produced by a vortex of intensity Γ\Gamma, placed at the point (ξ,η)(\xi ,\eta ). Prove that the trajectory of the vortex is expressed by the equation ξ−2+η−2=C\xi^{-2}+\eta^{-2} = C, and the components of the velocity of the vortex are given by the formulas:

dξdt=Γξ24πη(ξ2+η2);dηdt=−Γη24πξ(ξ2+η2). \frac{d\xi }{dt} = \frac{\Gamma \xi ^{2}}{4\pi \eta (\xi ^{2}+\eta ^{2})}; \quad \frac{d\eta }{dt} = -\frac{\Gamma \eta ^{2}}{4\pi \xi (\xi ^{2}+\eta ^{2})}.
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Problem 5764

Prove that the motion function produced by an infinite chain of vortices, each of intensity Γ=2π\Gamma = 2\pi, placed at the points z=0,±π,±2π,…z = 0, \pm \pi , \pm 2\pi , \ldots, is expressed by the formula

w(z)=−iln⁡sin⁡z. w(z) = -i\ln \sin z.
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Problem 5765

Find the motion function produced by the presence of vortices of two kinds: a) with intensity Γ\Gamma at the points l(n+14)+hi2l\left(n+\dfrac {1}{4}\right)+\dfrac {hi}{2}, b) with intensity −Γ-\Gamma at the points l(n−14)−hi2l\left(n-\dfrac {1}{4}\right)-\dfrac {hi}{2}. Here n=0,1,2,3,…n = 0,1,2,3,\ldots.

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Problem 5766

Find the velocity of a vortex of intensity Γ\Gamma, placed between parallel walls, at a distance hh from one of them, if the distance between the walls is dd.

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Problem 5767

Find the motion in the region −π2<x<π2-\dfrac {\pi }{2} < x < \dfrac {\pi }{2}, if at the point (0,0)(0,0) there is a source of strength QQ.

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Remark.
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If in the identity w(z)=u(x,y)+iv(x,y)w(z) = u(x,y)+iv(x,y); z=x+iyz = x+iy, one introduces a new variable ζ=ξ+iη\zeta = \xi +i\eta, setting

z=φ(ζ)=p(ξ,η)+iq(ξ,η), z = \varphi (\zeta ) = p(\xi ,\eta )+iq(\xi ,\eta ),

then, denoting the quantities w(z)w(z), u(x,y)u(x,y), v(x,y)v(x,y), expressed in terms of ζ\zeta, ξ\xi, and η\eta, by w1(ζ)w_{1}(\zeta ), u1(ξ,η)u_{1}(\xi ,\eta ), v1(ξ,η)v_{1}(\xi ,\eta ), we obtain w1(ζ)=u1(ξ,η)+iv1(ξ,η)w_{1}(\zeta ) = u_{1}(\xi ,\eta )+iv_{1}(\xi ,\eta ). After this, the domain SS in the plane zz goes into a domain S1S_{1} in the plane ζ\zeta, and the streamlines v(x,y)=Cv(x,y) = C go into the streamlines v1(ξ,η)=Cv_{1}(\xi ,\eta ) = C.

Thus, a conformal mapping makes it possible, from the motion in the domain SS, given by the function w(z)w(z), to find the motion in the domain S1S_{1} by means of the function w1(ζ)w_{1}(\zeta ).

Problem 5768

Find the motion in the region −π2<x<π2-\dfrac {\pi }{2} < x < \dfrac {\pi }{2} (problem 5767), if the source is located at the point (π2,h)\left(\dfrac {\pi }{2},h\right).

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Problem 5769

Find the motion function for symmetric, continuous flow past a cylinder with circular base ∣z∣=a\left|z\right| = a, if the velocity of the stream at infinity equals vv and is directed toward the negative axis OXOX. (One method of solution: map the region ∣z∣>a\left|z\right| > a, Im(z)>0\mathrm{Im}\left(z\right) > 0 onto the upper half-plane of a new variable.)

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Problem 5770

Find the motion function for flow past the segment between the points z=±iz = \pm i by the same stream as before (problem 5769). The flow sought is continuous and symmetric.

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Problem 5771

The function w(z)=a(z+R2z)+Γ2πiln⁡zw(z) = a\left(z+\dfrac {R^{2}}{z}\right)+\dfrac {\Gamma }{2\pi i}\ln z gives an asymmetric, continuous flow past the disk ∣z∣=R\left|z\right| = R. Find v∞v_{\infty }, the circulation along the circle, and the points where the velocity is zero.

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Problem 5772

Find the motion function for the flow of fluid from the half-plane y>0y > 0 into the half-plane y<0y < 0 through an opening in the wall y=0y = 0 between the points z=±1z = \pm 1. The velocity at infinity equals zero.

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Problem 5773

Find the stream function w(z)w(z) for continuous, symmetric flow past an elliptic cylinder with cross-section b2x2+a2y2=a2b2b^{2}x^{2}+a^{2}y^{2} = a^{2}b^{2} by a stream having, at infinity, velocity vx=vv_{x} = v; vy=0v_{y} = 0.

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Problem 5774

Prove that the function w=iln⁡(1+z−1)w = i\ln (1+z^{-1}) gives the flow of fluid past a region bounded by a line and a circle, under the condition v∞=0v_{\infty } = 0.

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Problem 5775

Find the function giving flow past the half-disk ∣z+43∣<23\left|z+\dfrac {4}{3}\right| < \dfrac {2}{3}, Im(z)>0\mathrm{Im}\left(z\right) > 0, under the condition at infinity vx=−vv_{x} = -v, vy=0v_{y} = 0.

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Problem 5776

Show that the function w=2iδln⁡Rzw = 2i\delta \ln \dfrac {R}{z} determines the electric field outside a circular cylinder ∣z∣=R\left|z\right| = R, on which a charge equal to δ\delta is uniformly distributed for a cylinder of unit height.

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Remark.
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A plane electrostatic field, in the absence of continuously distributed charges, is characterized by an analytic function w(z)=u(x,y)+iv(x,y)w(z) = u(x,y)+iv(x,y). Here

idwdz=Ex−iEy, i\frac{dw}{dz} = E_{x}-iE_{y},

where ExE_{x} and EyE_{y} are the projections of the electric force onto the coordinate axes. The equation u(x,y)=Cu(x,y) = C gives the lines of force, and v(x,y)=Cv(x,y) = C gives the equipotential lines. Inside and on the boundary of a conductor the potential vv must be constant. The density of electricity at any point of the contour of a conductor is given, up to sign, by the formula: σ=14π∣dwdz∣\sigma = \dfrac {1}{4\pi }\left|\dfrac {dw}{dz}\right|.

Problem 5777

Find the lines of force and the equipotential lines in the previous problem (problem 5776).

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Problem 5778

Find the force field between the surfaces of two cylinders with circular bases ∣z∣=1\left|z\right| = 1, ∣z−1∣=4\left|z-1\right| = 4, if the potential on the first equals 11, and on the second, zero.

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Problem 5779

On an isolated cylinder with circular cross-section ∣z−2i∣=1\left|z-2i\right| = 1, the density of electricity is σ=1\sigma = 1. How does it distribute if a plane, parallel to the generator and intersecting the plane XOYXOY along the real axis, is grounded (electrostatic induction)?

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Problem 5780

On the cylinder ∣z−5∣=4\left|z-5\right| = 4 the potential equals 11, and on the cylinder ∣z+5∣=4\left|z+5\right| = 4 it equals zero. Find the greatest and least densities of electricity on both cylinders.

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Problem 5781

At the point z=2z = 2 there is a point charge δ\delta. The imaginary axis is grounded. What is the potential at the point z=1z = 1?

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Problem 5782

Representing the equation of the parabola y2=2pxy^{2} = 2px in parametric form:

x=2pu2,y=2pu, x = 2pu^{2}, \qquad y = 2pu,

prove that the function ww, defined by the identity z=2p(w2+iw)z = 2p(w^{2}+iw), gives the field outside the parabola, in which the potential on the parabola itself equals zero and in which there are no charges.

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Problem 5783

Find the field outside the ellipse

x=acos⁡u,y=bsin⁡u, x = a\cos u, \qquad y = b\sin u,

representing one of the equipotential lines of the field.

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Problem 5784

The potential equals ν0\nu_{0} at the points of the line z=x+ihz = x+ih and equals zero on the real axis. Find the function w(z)w(z) giving the electrostatic field.

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Problem 5785

On the line 3x2+4y2=123x^{2}+4y^{2} = 12 the potential equals one, and on the segment between the foci it equals zero. Find the potential at the point z=iz = i.

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Problem 5786

Find the greatest and least densities on the ellipse of the previous problem (problem 5785).

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Problem 5787

On the line z=x>1z = x > 1 the potential equals ν0\nu_{0}, and on the line z=x<−1z = x < -1 it equals −ν0-\nu_{0}. Find the function w(z)w(z) giving the electrostatic field.

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Problem 5788

On the line z=iyz = iy, where y>1y > 1, the potential equals 11, and on the real axis it equals zero. Find the density distribution of electricity on the axis OXOX.

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Problem 5789

The potential equals π\pi on the polygonal line consisting of the lines:

z=x+πi;x<0andz=iy;y>π. z = x+\pi i; \quad x < 0 \quad \text{and} \quad z = iy; \quad y > \pi .

On the axis OXOX the potential equals zero. Find the electrostatic field in the region bounded by the indicated lines, using the Christoffel--Schwarz integral.

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Remark.
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If on a contour CC there is a charge qq, and if the region outside the contour is mapped conformally onto the region outside the disk ∣ζ∣=1\left|\zeta \right| = 1 by an analytic function

z=a1ζ+a0+∑n=1∞a−nζ−n, z = a_{1}\zeta +a_{0}+\sum _{n=1}^{\infty } a_{-n}\zeta ^{-n},

then the field outside CC is given by the function

w=2iqln⁡w0ζ(z), w = 2iq\ln \frac{w_{0}}{\zeta (z)},

where w0w_{0} is some constant.

Problem 5790

Find the field outside the ellipse b2x2+a2y2=a2b2b^{2}x^{2}+a^{2}y^{2} = a^{2}b^{2}.

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Problem 5791

Find the field outside the square −1<x<1-1 < x < 1, −1<y<1-1 < y < 1, on which a charge qq is placed.

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Problem 5792

On the circle ∣z∣=1\left|z\right| = 1 the temperature is 0°0°, and on the circle ∣z−1∣=52\left|z-1\right| = \dfrac {5}{2} it is 100°100°. Find the temperature tt in the annulus between the circles.

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Remark.
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The plane problem of the steady-state distribution of heat inside a homogeneous body is given by an analytic function

w(z)=u(x,y)+iv(x,y), w(z) = u(x,y)+iv(x,y),

where v(x,y)v(x,y) is the temperature at the point (x,y)(x,y). The equation v(x,y)=Cv(x,y) = C gives the isothermal lines, and u(x,y)=Cu(x,y) = C the heat-flow lines.

Problem 5793

On the circle ∣z−5i∣=4\left|z-5i\right| = 4 the temperature is 100°100°, and on the axis OXOX it is zero. Find the temperature tt at the point z=i+1z = i+1.

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Problem 5794

Find the temperature distribution in the region 0<φ<π0 < \varphi < \pi, r>ar > a, where z=reφiz = re^{\varphi i}, if the temperature equals zero on the real axis and one on the half-circle z=aeφiz = ae^{\varphi i}, 0<φ<π0 < \varphi < \pi.

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Problem 5795

Find the heat distribution inside the half-disk ∣z∣<1\left|z\right| < 1, 0<arg⁡z<π0 < \arg z < \pi, if the temperature equals zero on the semicircle and one on the diameter.

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Problem 5796

The same problem (problem 5795), but for a sector of a circle: 0<φ<α0 < \varphi < \alpha, 0<r<a0 < r < a, where z=reφiz = re^{\varphi i}, with the temperature 0°0° on the radii and 1°1° on the arc of the circle.

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