Section 13.1

Interpolation. Error Theory

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Problem 5188

Assuming that the numbers written down are accurate only to the last significant digit, find approximate values of the following quantities:

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(a)

0,53784⋅42,465780{,}53784 \cdot 42{,}46578;

(b)

0,234+4,3758+15,372⋅0,37620{,}234 + 4{,}3758 + 15{,}372 \cdot 0{,}3762;

(c)

2,375+0,3754,578\sqrt{2{,}375} + \frac{0{,}375}{4{,}578}.

Problem 5189

An angle measured with a goniometer turned out to equal 32∘13′25′′±10′′32^{\circ }13'25'' \pm 10''. What is the relative error?

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Problem 5190

The side of a square is approximately 1 m1 \, \text{m}. To what degree of precision must it be measured so that the error in the area is no more than 1 cm21 \, \text{cm}^{2}?

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Problem 5191

A pendulum about 2 m2 \, \text{m} long completed about 400 oscillations. Knowing that its length was measured to within 1 mm1 \, \text{mm} and the total duration of the oscillations was measured to within 0,5 s0{,}5 \, s, determine to what precision the value of the acceleration gg can be found from this data, and also find out which measurement error affects the result more strongly.

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Problem 5192

In measuring the span length of a bridge under construction, a baseline was laid out on one bank of the river, equal to 200 m±0,01 m200 \, \text{m} \pm 0{,}01 \, \text{m}. The angles between the baseline and the directions from its endpoints to a point across the river were measured. They turned out to be 90∘±1′90^{\circ }\pm 1' and 60∘±1′60^{\circ }\pm 1'. To what degree of precision can the span length of the bridge be determined from this data?

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Problem 5193

For what value of the angle is the relative error in computing a leg of a right triangle from a given leg and the opposite angle especially small, if the error in measuring the given leg is neglected?

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Problem 5194

In the field of view of a level's telescope, two horizontal lines are visible. When viewing through this telescope a vertical staff with decimeter graduations, 10 divisions of the staff are visible between the crosshairs when the staff is at a distance of 50 m50 \, \text{m}. When the staff is moved to another point, 25±0,225 \pm 0{,}2 divisions are visible between the same crosshairs. What is the distance to the new position of the staff?

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Problem 5195

In five-place logarithm tables, decimal logarithms of numbers are given to within 12⋅10−5\frac{1}{2} \cdot 10^{-5}. How large can the error be in finding a number from its logarithm, if the number lies between 300 and 400?

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Problem 5196

The same question applied to a table of logarithms of sines and logarithms of tangents, if the angle is about 45∘45^{\circ }.

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Problem 5197

The perimeter length of a regular inscribed 96-gon, which Archimedes used in computing π\pi, is expressed for r=1r=1 by the formula

P=962−2+2+2+3. P = 96 \sqrt{2 - \sqrt{2 + \sqrt{2 + \sqrt{2 + \sqrt{3}}}}}.

If one computes directly from this formula, wishing to obtain PP to within 0,0010{,}001, to what precision must the quantities under the radicals be computed?

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Problem 5198

The hypsometric formula, by which one determines the height of a place above the ground, is as follows:

p=p0e−h18 400(1−at). p = p_{0} e^{-\frac{h}{18\, 400(1-at)}}.

Here p0p_{0} is the pressure at the earth's surface, pp is the pressure at the given place at height hh, a=1273a = \frac{1}{273}, tt is the temperature in Celsius. Determine what the error is in determining the height, if t=0∘t=0^{\circ }, and the value p=500 mmp = 500 \, \text{mm} to within 1 mm1 \, \text{mm}.

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Problem 5199

Find a polynomial in xx, of as low a degree as possible, taking at x=2,4,5,10x=2, 4, 5, 10 respectively the values 3,7,9,193, 7, 9, 19.

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Problem 5200

Find a polynomial in xx, of as low a degree as possible, taking at x=2,4,5,10,15x=2, 4, 5, 10, 15 respectively the values 3,7,9,19,03, 7, 9, 19, 0.

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Problem 5201

Find a polynomial in xx, of as low a degree as possible, taking at x=1,2,3,4,5x=1,2,3,4,5, respectively the values 2,1,−1,5,02, 1, -1, 5, 0.

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Problem 5202

Find a polynomial f(x)f(x), of as low a degree as possible, taking at x=−2,−1,0,1,2x = -2, -1, 0, 1, 2 the same values as the function y=sin⁡πx2y = \sin \dfrac {\pi x}{2}. Determine the value of the difference f(x)−yf(x) - y at the values xx equal to 12,53,10\dfrac {1}{2}, \dfrac {5}{3}, 10.

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Problem 5203

Find a polynomial f(x)f(x), of as low a degree as possible, taking at x=−2,−43,0,43,2x=-2, -\dfrac {4}{3}, 0, \dfrac {4}{3}, 2 the same values as the function y=cos⁡πx4y = \cos \dfrac {\pi x}{4}. Determine the values of the difference f(x)−yf(x) - y at the values xx equal to −1,3,10-1, 3, 10.

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Problem 5204

For the function y=x3−3x2+5x−7y = x^{3} - 3x^{2} + 5x - 7 at x=0x=0, the values of the differences Δy0=+3\Delta y_{0} = +3, Δ2y0=0\Delta^{2} y_{0} = 0, Δ3y0=5\Delta^{3} y_{0} = 5 have been computed, corresponding to an increment h0=1h_{0}=1 of the argument. It is required to compute the differences Δy0‾\overline{\Delta y_{0}}, Δ2y0‾\overline{\Delta^{2} y_{0}}, Δ3y0‾\overline{\Delta^{3} y_{0}}, corresponding to an increment of the argument h1=110h_{1} = \dfrac {1}{10}.

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Problem 5205

For the function y=2x4−x3+3x2−1y = 2x^{4} - x^{3} + 3x^{2} - 1 at x=0x=0, the differences Δy0=4\Delta y_{0} = 4, Δ2y0=28\Delta^{2} y_{0} = 28, Δ3y0=66\Delta^{3} y_{0} = 66, Δ4y0=48\Delta^{4} y_{0} = 48 have been computed, corresponding to an increment h0=1h_{0}=1 of the argument. It is required to compute the differences Δy0‾\overline{\Delta y_{0}}, Δ2y0‾\overline{\Delta^{2} y_{0}}, Δ3y0‾\overline{\Delta^{3} y_{0}}, Δ4y0‾\overline{\Delta^{4} y_{0}}, corresponding to an increment of the argument h1=110h_{1} = \dfrac {1}{10}.

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Problem 5206

Find the equation of the line for which the sum of the squares of the distances to the points (3,2)(3,2), (7,5)(7,5), (12,9)(12,9), (−3,−2)(-3,-2) would be smallest.

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Problem 5207

Find the equation of a second-order parabola such that the sum of the squares of the vertical distances to it from the points (−3,4)(-3,4), (−2,2)(-2,2), (−1,1)(-1,1), (0,0)(0,0), (1,1)(1,1), (2,2)(2,2), (3,3)(3,3) would be smallest.

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Problem 5208

Using the table

xxln⁡x\ln x1010Δln⁡x10^{10} \Delta \ln x1010Δ2ln⁡x10^{10} \Delta ^{2} \ln x
1, 0053{,}0021660594, 319, 184{,}7−4 291,3-4\, 291{,}3
1, 0063{,}0025979784, 314, 893{,}4−4 282,8-4\, 282{,}8

compute ln⁡1005,237\ln 1005{,}237, determining the precision of the computation. The numbers in the table are given to within 12\frac{1}{2} of the last digit.

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Problem 5209

Using the table of problem 5208, find xx given ln⁡x=3,002268651\ln x = 3{,}002268651.

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Problem 5210

Using the table

uuln⁡sh⁡u\ln \operatorname {sh} u105Δln⁡sh⁡u10^{5} \Delta \ln \operatorname {sh} uln⁡ch⁡u\ln \operatorname {ch} u105Δln⁡ch⁡u10^{5} \Delta \ln \operatorname {ch} u
0{,}5009{,}7169294{,}00{,}0521720{,}1
0{,}5019{,}7178693{,}80{,}0523720{,}1
0{,}5029{,}7187993{,}70{,}0525720{,}1
0{,}5039{,}7197393{,}50{,}0527720{,}2
0{,}5049{,}7206693{,}30{,}0529720{,}2

find sh⁡0,50235\operatorname {sh} 0{,}50235.

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Problem 5211

Find the root of the equation ch⁡u=1,1287\operatorname {ch} u = 1{,}1287. See the table of problem 5210.

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Problem 5212

Using the data of the table

xxsin⁡x\sin x
41∘41^{\circ }0{,}6560590290
42∘42^{\circ }0{,}6691306064
43∘43^{\circ }0{,}6819983601
44∘44^{\circ }0{,}6946583705

compute, with the greatest possible precision, sin⁡41∘20′\sin 41^{\circ }20'.

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Problem 5213

Using the data of the table

φ\varphiF(φ)=∫0φdφ1−12sin⁡2φF(\varphi ) = \int _{0}^{\varphi } \dfrac {d\varphi }{\sqrt{1 - \frac{1}{2}\sin ^{2}\varphi }}
21,0∘21{,}0^{\circ }0{,}3706344
21,5∘21{,}5^{\circ }0{,}3796626
22,0∘22{,}0^{\circ }0{,}3887052
22,5∘22{,}5^{\circ }0{,}3977625

(table 13.1) compute F(φ)F(\varphi ) at φ=21∘15′\varphi = 21^{\circ }15'.

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Problem 5214

Using the data of the table

φ\varphiF(φ)=∫0φdφ1−12sin⁡2φF(\varphi ) = \int _{0}^{\varphi } \dfrac {d\varphi }{\sqrt{1 - \frac{1}{2}\sin ^{2}\varphi }}
28,0∘28{,}0^{\circ }0{,}49846361
28,5∘28{,}5^{\circ }0{,}50772435
29,0∘29{,}0^{\circ }0{,}51700422
29,5∘29{,}5^{\circ }0{,}52630357

(table 13.2) compute the root of the equation F(φ)=0,5F(\varphi ) = 0{,}5.

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Problem 5215

Using the data of the table

xxψ(x)=dln⁡Γ(1+x)dx\psi (x) = \dfrac {d \ln \Gamma (1+x)}{dx}
0{,}710{,}2164501462
0{,}720{,}2242928871
0{,}730{,}2320769593
0{,}740{,}2398032061

(table 13.3) compute ψ(0,715)\psi (0{,}715). To estimate the error one should take into account that ψ′(x)=1(x+1)2+1(x+2)2+…\psi '(x) = \dfrac {1}{(x+1)^{2}} + \dfrac {1}{(x+2)^{2}} + \ldots

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Problem 5216

Using the data of the table

xxψ(x)=dln⁡Γ(1+x)dx\psi (x) = \dfrac {d \ln \Gamma (1+x)}{dx}
0{,}830{,}3068612
0{,}840{,}3140589
0{,}850{,}3212000
0{,}860{,}3282922

(table 13.4) compute the root of the equation ψ(x)=0,31\psi (x) = 0{,}31.

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Problem 5217

Using a table of values of reciprocals of integers and an interpolation formula taken up through the fourth differences inclusive, find the value of the fraction 112,5\dfrac {1}{12{,}5} by means of the formulas:

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(a)

Newton--Gregory, with y0=112y_{0} = \dfrac {1}{12}, y1=113y_{1} = \dfrac {1}{13}, y2=114,…y_{2} = \dfrac {1}{14}, \ldots;

(b)

Newton--Gauss, and

(c)

Newton--Bessel, comparing the results obtained with the exact value.

Remark.
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Newton--Gregory formula: yx=y0+xΔy0+x(x−1)2!Δ2y0+x(x−1)(x−2)3!Δ3y0+…y_{x} = y_{0} + x \Delta y_{0} + \dfrac {x(x-1)}{2!}\Delta^{2} y_{0} + \dfrac {x(x-1)(x-2)}{3!}\Delta^{3} y_{0} + \ldots

Newton--Gauss formula: yx=y0+xΔy0+x(x−1)2!Δ2y−1+x(x2−1)3!Δ3y−1+…y_{x} = y_{0} + x \Delta y_{0} + \dfrac {x(x-1)}{2!}\Delta^{2} y_{-1} + \dfrac {x(x^{2}-1)}{3!}\Delta^{3} y_{-1} + \ldots

Newton--Bessel formula: yx=12(y0+y1)+(x−12)Δy0+x(x−1)2!⋅Δ2y−1+Δ2y02+…y_{x} = \dfrac {1}{2}(y_{0}+y_{1}) + \left(x - \dfrac {1}{2}\right)\Delta y_{0} + \dfrac {x(x-1)}{2!} \cdot \dfrac {\Delta^{2} y_{-1} + \Delta^{2} y_{0}}{2} + \ldots

Here y0,y1,…,yny_{0}, y_{1}, \ldots , y_{n} are the values of yy at x=a,a+h,…,a+nhx=a, a+h, \ldots , a+nh; the quantities Δy0,Δ2y0,…\Delta y_{0}, \Delta^{2} y_{0}, \ldots are the successive differences.

Problem 5218

A similar question for the value 12,25\sqrt{12{,}25}; y0=12y_{0} = \sqrt{12}, y1=13y_{1} = \sqrt{13}, y2=14,…y_{2} = \sqrt{14}, \ldots

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Problem 5219

Of 1000 born, the number surviving to age 20, 30, 40, 50, 60 years is respectively 560, 530, 480, 400, and 300 people. How many people out of 1000 survive to age 35 and 45?

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Problem 5220

In a certain locality, the numbers of people whose ages fall into three consecutive five-year periods are as follows:

37 237,40 118,42 652. 37\, 237, \quad 40\, 118, \quad 42\, 652.

How many people are at the age of the middle year of the second five-year period?

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Problem 5221

The numbers of people in the ages 25--30, 30--35, 35--40, 40--45 years are respectively as follows:

458 572,441 424,423 123,402 918. 458\, 572, \quad 441\, 424, \quad 423\, 123, \quad 402\, 918.

How many people are in their 38th year?

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Problem 5222

A table contains, in one column, 20 consecutive values of a function. The sums of three consecutive columns are as follows: 630 611630\, 611, 1 946 9351\, 946\, 935, 3 246 3193\, 246\, 319. With what number does the fourth column begin?

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