Center, Diameters. Simplification of Equations of Second-Order Curves
[33/67%]Let be the midpoint of a chord of the curve , and let and be the endpoints of the chord. Prove that
The polynomial , homogenized by introducing powers of the variable , becomes the ternary quadratic form . Its partial derivatives with respect to , and are given by: ; ; . Their values at are denoted by , and . For brevity one also writes , .
Prove that the midpoints of the chords of the curve parallel to the line lie on the line , or, in full form:
(The diameter conjugate to the given direction.)
Show that when the origin is translated to the point , the equation passes into the equation
If , all the diameters pass through the point where the lines , intersect. Show that when the origin is translated to the point chosen in this way, the equation passes into the following one:
Here is the value of at , .
Translate the origin to the center of the curve and set up the new equation of the curve.
Simplify the equation of the curve
by translating the origin to the center.
Simplify the equation of the curve
by translating the origin to that center of it whose abscissa equals one.
Show that the line passes through the centers of the curves
and
Find the axes of symmetry of the ellipse
Find the foci (with respect to the old coordinate axes) of the hyperbola .
Determine the eccentricity of the curve
Simplify the equation of the curve
by translating the origin to the center, and then rotating the axes through the appropriate angle.
The same, for the curve .
Simplify the equation of the parabola
by rotating the axes so that the new equation contains no , and then translating the origin so that only two terms remain in the final equation.
Prove that when , (so that one may set ), the identity holds
where , , .
Prove that in the identity of the preceding problem, the number can be chosen so that the lines and are mutually perpendicular, provided only that the numbers and are not proportional to the numbers and .
Simplify the equation of the curve
using the identity:
choosing so that the lines and are mutually perpendicular. Here the formulas for the coordinate transformation have the form:
By the same method, simplify the equation of the parabola
Simplify the equation of the parabola
For given , and , and a suitably chosen value of , the identity holds
where and are real or imaginary coefficients. Prove that such values of are the roots of the equation
The equation
represents a pair of lines, real or imaginary, if and only if the discriminant equals zero. Using this, prove that under any coordinate transformation the quantity does not change.
The discriminant of the quadratic form in three variables is defined as the determinant of the coefficients of , and in the formulas expressing its partial derivatives: . Its minor is the discriminant of the quadratic form in two variables .
Using the invariance of the quantities , and the discriminant , prove that when , the equation
reduces, after simplification, to the form
Here and are the roots of the equation .
Prove that the equation , when and , can be reduced to the form
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .
Reduce the equation of the following line to its simplest form: .