Section 11.4

G/M/1

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Problem 11.4.1

Consider G/M(μ)/1\mathrm{G} / \mathrm{M}(\mu ) / 1, and let αj=E[(μX)je−μX/j!]\alpha_{j} = \mathbb {E}\left[(\mu X)^{j} e^{-\mu X} / j!\right] where XX is a typical interarrival time. Suppose the traffic intensity ρ\rho is less than 1. Show that the equilibrium distribution π\pi of the imbedded chain at moments of arrivals satisfies

πn=∑i=0∞αiπn+i−1 for n≥1 \pi _{n} = \sum _{i = 0}^{\infty } \alpha _{i} \pi _{n+i-1} \quad \text{ for } n \geq 1

Look for a solution of the form πn=θn\pi_{n} = \theta^{n} for some θ\theta, and deduce that the unique stationary distribution is given by πj=(1−η)ηj\pi_{j} = (1-\eta ) \eta^{j} for j≥0j \geq 0, where η\eta is the smallest positive root of the equation s=MX(μ(s−1))s = M_{X}(\mu (s-1)).

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Problem 11.4.2

Consider a G/M(μ)/1\mathrm{G} / \mathrm{M}(\mu ) / 1 queue in equilibrium. Let η\eta be the smallest positive root of the equation x=MX(μ(x−1))x = M_{X}(\mu (x-1)) where MXM_{X} is the moment generating function of an interarrival time. Show that the mean number of customers ahead of a new arrival is η(1−η)−1\eta (1-\eta )^{-1}, and the mean waiting time is η{μ(1−η)}−1\eta \left\{ \mu (1-\eta )\right\}^{-1}.

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Problem 11.4.3

Consider D(1)/M(μ)/1\mathrm{D}(1) / \mathrm{M}(\mu ) / 1 where μ>1\mu > 1. Show that the continuous-time queue length Q(t)Q(t) does not converge in distribution as t→∞t \rightarrow \infty, even though the imbedded chain at the times of arrivals is ergodic.

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