Renewal–reward processes
[7/100%]If is an irreducible positive recurrent Markov chain, and is a bounded function on the integers, show that
where is the stationary distribution of .
Let be an alternating renewal process, with interarrival pairs . Show that
Is this limit valid for an arbitrary joint distribution of independent pairs ?
Let be the current lifetime (or age) of a renewal process with a typical interarrival time . Show that
Find the corresponding limit for the excess lifetime.
Let and be distinct states of an irreducible discrete-time Markov chain with stationary distribution . Show that
where is the first passage time to the state . [Hint: Consider the times of return to having made an intermediate visit to .]
Use the result of Exercise (10.5.2) to show that the limiting distribution function as of the total life of a renewal process is
where is the density function of a typical interarrival time , and . The integrand is called the size-biased (or length-biased) density for .
Let be exponentially distributed with parameter . Show that
John's garage offers him the choice of two tyre replacement plans.
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The garage undertakes to replace all the tyres of his car at the normal price whenever one of the tyres requires replacing.
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The garage undertakes to replace all the tyres of his car at of the normal price two years after they have last been replaced. However, if any tyre needs replacing earlier, the garage will then replace all the tyres at a price that is higher than the normal price. Assuming that a new tyre has an exponentially distributed lifetime with mean 8 years, determine the long run average cost per year under the two options. Which option should John choose if his car is new?
A machine is repaired at time , and its uptime after any repair is exponentially distributed with parameter , at which point it breaks down (assume the usual independence). Following any repair at time , say, it is inspected at times , and instantly repaired if found to be broken (the inspection schedule is then restarted). Show that the long run proportion of time that is working (the 'uptime ratio') is .