Chapter 10

Estimation

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Problem 10.1
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(a)

Consider the joint probability density fX,Z(x,z)=e−zf_{X,Z}(x,z) = e^{-z} for 0≤x≤z0 \leq x \leq z and fX,Z(x,z)=0f_{X,Z}(x,z) = 0 otherwise. Find the pair x,zx,z of values that maximize this density. Find the marginal density fZ(z)f_Z(z) and find the value of zz that maximizes this.

(b)

Let fX,Z,Y(x,z,y)f_{X,Z,Y}(x,z,y) be y2e−yzy^2 e^{-yz} for 0≤x≤z0 \leq x \leq z, 1≤y≤21 \leq y \leq 2 and be 00 otherwise. Conditional on an observation Y=yY = y, find the joint MAP estimate of X,ZX, Z. Find fZ∣Y(z∣y)f_{Z \mid Y}(z \mid y), the marginal density of ZZ conditional on Y=yY = y, and find the MAP estimate of ZZ conditional on Y=yY = y.

Problem 10.2

Let Y=X+ZY = X+Z where XX and ZZ are IID and N(0,1)\mathscr {N}\left(0, 1\right). Let U=Z−XU = Z-X.

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(a)

Explain (using the results of Chapter 3) why YY and UU are jointly Gaussian and why they are statistically independent.

(b)

Without using any matrices, write down the joint probability density of YY and UU. Verify your answer from (3.22).

(c)

Find the MMSE estimate x^(y)\hat{x}(y) of XX conditional on a given sample value yy of YY. You can derive this from first principles, or use (10.9) or Example 10.2.2.

(d)

Show that the estimation error ξ=X−X^(Y)\xi = X-\hat{X}(Y) is equal to −U/2-U/2.

(e)

Write down the probability density of UU conditional on Y=yY = y and that of ξ\xi conditional on X=yX = y.

(f)

Draw a sketch in the x,zx,z plane of the equiprobability contours of XX and ZZ. Explain why these are also equiprobability contours for YY and UU. For some given sample value of YY, say Y=1Y = 1, illustrate the set of points for which x+z=1x+z = 1. For a given point on this line, illustrate the sample value of UU.

Problem 10.3
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(a)

Let X,Z1,Z2,…,ZnX, Z_1, Z_2, \ldots , Z_n be independent zero-mean Gaussian rv's with variances σX2,σZ12,…σZn2\sigma_X^2, \sigma_{Z_1}^2, \ldots \sigma_{Z_n}^2 respectively. Let Yj=hjX+ZjY_j = h_j X+Z_j for j≥1j \geq 1 and let Y→=(Y1,…Yn)T\overrightarrow {Y} = (Y_1, \ldots Y_n)^{\mathrm{T}}. Use (10.9) to show that the MMSE estimate of XX conditional on Y→=y→=(y1,…,yn)T\overrightarrow {Y} = \overrightarrow {y} = (y_1, \ldots , y_n)^{\mathrm{T}} is given by

x^(y→)=∑j=1ngjyj;wheregj=hj/σZj2(1/σX2)+∑i=1nhi2/σZi2. \hat{x}(\overrightarrow {y}) = \sum _{j=1}^{n} g_j y_j; \quad \text{where} \quad g_j = \frac{h_j/\sigma _{Z_j}^2}{(1/\sigma _X^2)+\sum _{i=1}^{n} h_i^2/\sigma _{Z_i}^2}.

Hint: Let the row vector g→T\overrightarrow {g}^{\mathrm{T}} be [KX⋅Y][KY−1][K_{X \cdot Y}][K_Y^{-1}] and multiply g→T\overrightarrow {g}^{\mathrm{T}} by KYK_Y to solve for g→T\overrightarrow {g}^{\mathrm{T}}.

(b)

Let ξ=X−X^(Y→)\xi = X-\hat{X}(\overrightarrow {Y}) and show that (10.29) is valid, i.e., that

1/σξ2=1/σX2+∑i=1nhi2σZi2. 1/\sigma _{\xi }^2 = 1/\sigma _X^2+\sum _{i=1}^{n} \frac{h_i^2}{\sigma _{Z_i}^2}.
(c)

Show that (10.28), i.e., x^(y→)=σξ2∑j=1nhjyj/σZj2\hat{x}(\overrightarrow {y}) = \sigma_{\xi }^2 \sum_{j=1}^{n} h_j y_j/\sigma_{Z_j}^2, is valid.

(d)

Show that the expression in (10.29) is equivalent to the iterative expression in (10.27).

(e)

Show that the expression in (10.28) is equivalent to the iterative expression in (10.25).

Problem 10.4

Let X,Z1,…,ZnX, Z_1, \ldots , Z_n be independent, zero-mean, and Gaussian, satisfying Yi=hiX+ZiY_i = h_i X+Z_i for 1≤i≤n1 \leq i \leq n. The point of this exercise is to show that estimation of XX from Y→1n\overrightarrow {Y}_1^n is essentially no more complex than the same problem with each hi=1h_i = 1.

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(a)

Write out the MMSE estimate and variance of the estimation error from (10.28) and (10.29) where each hi=1h_i = 1.

(b)

For arbitrary numbers h1,…,hnh_1, \ldots , h_n, consider the equations hiYi=hiX+hiZih_i Y_i = h_i X+h_i Z_i. Let Ui=hiYiU_i = h_i Y_i. Write out the MMSE estimate of XX as a function of U1,…,UnU_1, \ldots , U_n, still using the rv's Z1,…,ZnZ_1, \ldots , Z_n. Hint: Note that if you scale each observation UiU_i to Ui/hiU_i/h_i you have the same estimation problem as in (a).

(c)

Now let Wi=hiZiW_i = h_i Z_i. Write out the same MMSE estimate in terms of both Ui,…,UnU_i, \ldots , U_n and W1,…,WnW_1, \ldots , W_n and show that you now have (10.28) with all the hih_i's back in the equation. Hint: You still have the basic equation in (a), but the variance of the ZiZ_i's must be expressed in terms of the WiW_i's. Write out the error variance from (10.29) in the same way.

Problem 10.5
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(a)

Assume that X1∼N(X‾1,σX12)X_1 \sim \mathscr {N}\left(\overline{X}_1, \sigma_{X_1}^2\right) and that for each n≥1n \geq 1, Xn+1=αXn+WnX_{n+1} = \alpha X_n+W_n, where 0<α<10 < \alpha < 1, Wn∼N(0,σW2)W_n \sim \mathscr {N}\left(0, \sigma_W^2\right), and X1,W1,W2,…X_1, W_1, W_2, \ldots, are independent. Show that for each n≥1n \geq 1,

E[Xn]=αn−1X‾1,σXn2=(1−α2(n−1))σW21−α2+α2(n−1)σX12. \mathbb {E}\left[X_n\right] = \alpha ^{n-1} \overline{X}_1, \qquad \sigma _{X_n}^2 = \frac{(1-\alpha ^{2(n-1)})\sigma _W^2}{1-\alpha ^2}+\alpha ^{2(n-1)} \sigma _{X_1}^2.
(b)

Show directly, by comparing the equation σXn2=α2σXn−12+σW2\sigma_{X_n}^2 = \alpha^2 \sigma_{X_{n-1}}^2+\sigma_W^2 for each two adjoining values of nn, that σXn2\sigma_{X_n}^2 moves monotonically from σX12\sigma_{X_1}^2 to σW2/(1−α2)\sigma_W^2/(1-\alpha^2) as n→∞n \rightarrow \infty.

(c)

Assume that sample values of Y1,Y2,…Y_1, Y_2, \ldots, are observed, where Yn=hXn+ZnY_n = h X_n+Z_n and where Z1,Z2,…Z_1, Z_2, \ldots, are IID zero-mean Gaussian rv's with variance σZ2\sigma_Z^2. Assume that Z1,…,W1,…,X1Z_1, \ldots , W_1, \ldots , X_1 are independent and assume h≥0h \geq 0. Rewrite the recursion for the variance of the estimation error in (10.41) for this special case. Show that if h/σZ=0h/\sigma_Z = 0, then σξn2=σXn2\sigma_{\xi_n}^2 = \sigma_{X_n}^2 for each n≥1n \geq 1. Hint: Compare the recursion in (b) to that for σξn2\sigma_{\xi_n}^2.

(d)

Show from the recursion that σξn2\sigma_{\xi_n}^2 is a decreasing function of h/σZh/\sigma_Z for each n≥2n \geq 2. Use this to show that σξn2≤σXn2\sigma_{\xi_n}^2 \leq \sigma_{X_n}^2 for each nn. Explain (without equations) why this result must be true.

(e)

Show that the sequence {σξn2;n≥1}\left\{ \sigma_{\xi_n}^2; n \geq 1\right\} is monotonic in nn. Hint: Use the same technique as in (b). From this and (d), show that λ=lim⁡n→∞σξn2\lambda = \lim_{n \rightarrow \infty } \sigma_{\xi_n}^2 exists. Show that the limit satisfies (10.42) (note that (10.42) must have 22 roots, one positive and one negative, so the limit must be the positive root).

(f)

Show that for each n≥1n \geq 1, σξn2\sigma_{\xi_n}^2 is increasing in σW2\sigma_W^2 and increasing in α\alpha. Note: This increase with α\alpha is surprising, since when α\alpha is close to one, XnX_n changes slowly, so we would expect to be able to track XnX_n well. The problem is that lim⁡nσXn2=σW2/(1−α2)\lim_n \sigma_{X_n}^2 = \sigma_W^2/(1-\alpha^2) so the variance of the untracked XnX_n is increasing without limit as α\alpha approaches 11. Part (g) is somewhat messy, but resolves this issue.

(g)

Show that if the recursion is expressed in terms of β=σW2/(1−α2)\beta = \sigma_W^2/(1-\alpha^2) and α\alpha, then λ\lambda is decreasing in α\alpha for constant β\beta.

Problem 10.6
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(a)

Assume that X→\overrightarrow {X} and Y→\overrightarrow {Y} are zero-mean, jointly Gaussian, jointly non-singular, and related by Y→=[H]X→+Z→\overrightarrow {Y} = [H]\overrightarrow {X}+\overrightarrow {Z}. Show that the MMSE estimate can be expressed as

x→^(y→)=[Kξ][HT][KZ−1]y→. \hat{\overrightarrow {x}}(\overrightarrow {y}) = [K_{\xi }][H^{\mathrm{T}}][K_Z^{-1}]\overrightarrow {y}.

Hint: Recall from (10.9) that x→^(y→)=[G]y→\hat{\overrightarrow {x}}(\overrightarrow {y}) = [G]\overrightarrow {y}. Relate [G][G] and [H][H] by using (3.115).

(b)

Show that

[Kξ−1]=[KX−1]+[HTKZ−1H]. [K_{\xi }^{-1}] = [K_X^{-1}]+[H^{\mathrm{T}} K_Z^{-1} H].

Hint: A reasonable approach is to start with (10.10), i.e., [Kξ]=[KX]−[KX⋅YKY−1KX⋅YT][K_{\xi }] = [K_X]-[K_{X \cdot Y} K_Y^{-1} K_{X \cdot Y}^{\mathrm{T}}]. Premultiply both sides by [KX−1][K_X^{-1}] and post-multiply both sides by [Kξ−1][K_{\xi }^{-1}]. The final product of matrices here can be expressed as [HTKZ−1H][H^{\mathrm{T}} K_Z^{-1} H] by using the hint in (a) on [KZ−1H][K_Z^{-1} H].

Problem 10.7
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(a)

Write out E[(X−g→TY→)2]=σX2−2[KX⋅Y]g→+g→T[KY]g→\mathbb {E}\left[(X-\overrightarrow {g}^{\mathrm{T}} \overrightarrow {Y})^2\right] = \sigma_X^2-2[K_{X \cdot Y}]\overrightarrow {g}+\overrightarrow {g}^{\mathrm{T}}[K_Y]\overrightarrow {g} as a function of g→=(g1,g2,…,gn)T\overrightarrow {g} = (g_1, g_2, \ldots , g_n)^{\mathrm{T}} and take the partial derivative of the function with respect to gig_i for each ii, 1≤i≤n1 \leq i \leq n. Show that the vector of these partial derivatives is −2[KX⋅Y]+2g→T[KY]-2[K_{X \cdot Y}]+2\overrightarrow {g}^{\mathrm{T}}[K_Y].

(b)

Explain why the stationary point here is actually a minimum.

Problem 10.8

For a real inner-product space, show that nn vectors, Y1,…,YnY_1, \ldots , Y_n are linearly dependent if and only if the matrix of inner products, {⟨Yj,Yk⟩;1≤j,k≤n}\left\{ \left\langle Y_j, Y_k \right\rangle ; 1 \leq j,k \leq n\right\}, is singular.

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Problem 10.9

Show that (10.89) to (10.91) agree with (10.11).

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Problem 10.10

Let X→=(X1,…,Xn)T\overrightarrow {X} = (X_1, \ldots , X_n)^{\mathrm{T}} be a zero-mean complex rv with real and imaginary components Xre,j,Xim,jX_{\mathrm{re},j}, X_{\mathrm{im},j}, 1≤j≤n1 \leq j \leq n respectively. Express E[Xre,jXre,k]\mathbb {E}\left[X_{\mathrm{re},j} X_{\mathrm{re},k}\right], E[Xre,jXim,k]\mathbb {E}\left[X_{\mathrm{re},j} X_{\mathrm{im},k}\right], E[Xim,jXim,k]\mathbb {E}\left[X_{\mathrm{im},j} X_{\mathrm{im},k}\right], E[Xim,jXre,k]\mathbb {E}\left[X_{\mathrm{im},j} X_{\mathrm{re},k}\right] as functions of the components of [KX][K_X] and E[X→X→T]\mathbb {E}\left[\overrightarrow {X} \overrightarrow {X}^{\mathrm{T}}\right].

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Problem 10.11

Let Y=Yre+iYimY = Y_{\mathrm{re}}+iY_{\mathrm{im}} be a complex random variable. For arbitrary real numbers a,b,c,da, b, c, d, find complex numbers α\alpha and β\beta such that

ℜ[αY+βY∗]=aYre+bYim, \Re \left[\alpha Y+\beta Y^{*}\right] = aY_{\mathrm{re}}+bY_{\mathrm{im}}, ℑ[αY+βY∗]=cYre+dYim. \Im \left[\alpha Y+\beta Y^{*}\right] = cY_{\mathrm{re}}+dY_{\mathrm{im}}.
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Problem 10.12

Let X→=X→re+iX→im\overrightarrow {X} = \overrightarrow {X}_{\mathrm{re}}+i\overrightarrow {X}_{\mathrm{im}} be a zero-mean, circularly-symmetric, nn dimensional Gaussian complex rv. Let U→=(X→reT,X→imT)T\overrightarrow {U} = (\overrightarrow {X}_{\mathrm{re}}^{\mathrm{T}}, \overrightarrow {X}_{\mathrm{im}}^{\mathrm{T}})^{\mathrm{T}} be the corresponding 2n2n dimensional real rv. Let [Kre]=E[X→reX→reT][K_{\mathrm{re}}] = \mathbb {E}\left[\overrightarrow {X}_{\mathrm{re}} \overrightarrow {X}_{\mathrm{re}}^{\mathrm{T}}\right] and [Kri]=E[X→reX→imT][K_{\mathrm{ri}}] = \mathbb {E}\left[\overrightarrow {X}_{\mathrm{re}} \overrightarrow {X}_{\mathrm{im}}^{\mathrm{T}}\right].

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(a)

Show that

[KU]=[KreKri−KriKre]. [K_U] = \begin{bmatrix} K_{\mathrm{re}} & K_{\mathrm{ri}} \\ -K_{\mathrm{ri}} & K_{\mathrm{re}} \end{bmatrix}.
(b)

Show that

[KU−1]=[BC−CB] [K_U^{-1}] = \begin{bmatrix} B & C \\ -C & B \end{bmatrix}

and find the B,CB, C for which this is true.

(c)

Show that [KX]=2([Kre]−[Kri])[K_X] = 2([K_{\mathrm{re}}]-[K_{\mathrm{ri}}]).

(d)

Show that [KX−1]=12(B−iC)[K_X^{-1}] = \frac{1}{2}(B-iC).

(e)

Define fX(x→)=fU(u→)f_X(\overrightarrow {x}) = f_U(\overrightarrow {u}) for u→=(x→reT,x→imT)T\overrightarrow {u} = (\overrightarrow {x}_{\mathrm{re}}^{\mathrm{T}}, \overrightarrow {x}_{\mathrm{im}}^{\mathrm{T}})^{\mathrm{T}} and show that

fX(x→)=exp⁡(−x→∗[KX−1]x→T)(2π)ndet⁡(KU). f_X(\overrightarrow {x}) = \frac{\exp \left(-\overrightarrow {x}^{*} [K_X^{-1}] \overrightarrow {x}^{\mathrm{T}}\right)}{(2\pi )^n \sqrt{\operatorname {det}\left(K_U\right)}}.
(f)

Show that

det⁡(KU)=det⁡[Kre+iKriKri−iKre−KriKre]. \operatorname {det}\left(K_U\right) = \det \begin{bmatrix} K_{\mathrm{re}}+iK_{\mathrm{ri}} & K_{\mathrm{ri}}-iK_{\mathrm{re}} \\ -K_{\mathrm{ri}} & K_{\mathrm{re}} \end{bmatrix}.

Hint: Recall that elementary row operations do not change the value of a determinant.

(g)

Show that

det⁡(KU)=det⁡[Kre+iKri0−KriKre−iKri]. \operatorname {det}\left(K_U\right) = \det \begin{bmatrix} K_{\mathrm{re}}+iK_{\mathrm{ri}} & 0 \\ -K_{\mathrm{ri}} & K_{\mathrm{re}}-iK_{\mathrm{ri}} \end{bmatrix}.

Hint: Recall that elementary column operations do not change the value of a determinant.

(h)

Show that

det⁡(KU)=2−2n(det⁡(KX))2 \operatorname {det}\left(K_U\right) = 2^{-2n} \left(\operatorname {det}\left(K_X\right)\right)^2

and from this conclude that (3.108) is valid.

Problem 10.13
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(a)

Let XX be a circularly-symmetric, zero-mean, complex Gaussian rv with variance 11. Show that

fX(x)=exp⁡(−x∗x)π. f_X(x) = \frac{\exp (-x^{*} x)}{\pi }.

Recall that the real part and imaginary part each have variance 1/21/2.

(b)

Let X→\overrightarrow {X} be an nn-dimensional, circularly-symmetric, complex Gaussian zero-mean random vector with KX=[In]K_X = [I_n]. Show that

fX(x→)=exp⁡(−x→†x→)πn. f_X(\overrightarrow {x}) = \frac{\exp (-\overrightarrow {x}^{\dagger } \overrightarrow {x})}{\pi ^n}.
(c)

Let Y→=[H]X→\overrightarrow {Y} = [H]\overrightarrow {X} where [H][H] is n×nn \times n and invertible. Show that

fY(y→)=exp⁡[−y→†([H−1])†[H−1]y→]vπn, f_Y(\overrightarrow {y}) = \frac{\exp \left[-\overrightarrow {y}^{\dagger }([H^{-1}])^{\dagger }[H^{-1}]\overrightarrow {y}\right]}{v\pi ^n},

where vv is dy→/dx→d\overrightarrow {y}/d\overrightarrow {x}, the ratio of an incremental 2n2n-dimensional volume element after being transformed by [H][H] to that before being transformed.

(d)

Use this to show that (3.108) is valid.

Problem 10.14
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(a)

Let Y=X2+ZY = X^2+Z, where ZZ is a zero-mean unit variance Gaussian rv. Show that no unbiased estimate of XX exists from observation of YY.

(b)

Let Y=X+ZY = X+Z, where ZZ is uniform over (−1,1)(-1,1) and XX is a parameter lying in (−1,1)(-1,1). Show that x^(y)=y\hat{x}(y) = y is an unbiased estimate of xx. Find a biased estimate x^1(y)\hat{x}_1(y) for which ∣x^1(y)−x∣≤∣x^(y)−x∣\left|\hat{x}_1(y)-x\right| \leq \left|\hat{x}(y)-x\right| for all xx and yy with strict inequality with positive probability for all x∈(−1,1)x \in (-1,1).

Remark.
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For part (a): Consider any x>0x > 0 and compare with −x-x.

Problem 10.15
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(a)

Assume that for each parameter value xx, YY is Gaussian, N(x,σZ2)\mathscr {N}\left(x, \sigma_Z^2\right). Show that vx(y)v_x(y) as defined in (10.103) is equal to (y−x)/σZ2(y-x)/\sigma_Z^2 and show that the Fisher information is equal to 1/σZ21/\sigma_Z^2.

(b)

Show that for ML estimation, the bias is 00 for all xx. Show that the Cramer--Rao bound is satisfied with equality for all xx in this case.

(c)

Consider using the MMSE estimator for the a priori distribution X∼N(0,σX2)X \sim \mathscr {N}\left(0, \sigma_X^2\right). Show that the bias satisfies bx^(x)=−xσZ2/(σZ2+σX2)b_{\hat{x}}(x) = -x\sigma_Z^2/(\sigma_Z^2+\sigma_X^2).

(d)

Show that the MMSE estimator in (c) satisfies the Cramer--Rao bound with equality for each xx. Note that the mean-squared error, as a function of xx, is smaller than that for the ML case for small xx and larger for large xx.

Problem 10.16

Assume that YY is N(0,x)\mathscr {N}\left(0, x\right). Show that Vx(y)V_x(y) as defined in (10.103) is vx(y)=[y2/x−1]/(2x)v_x(y) = [y^2/x-1]/(2x). Verify that Vx(Y)V_x(Y) is zero mean for each xx. Find the Fisher information, J(x)J(x).

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