Section 1.7

Permutations

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Problem 1.7.1

Fifteen schoolchildren sit on fifteen numbered chairs. Every minute a kind teacher reseats them according to the following scheme:

(123456789101112131415351081114156131497212). \begin{pmatrix} 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 \\ 3 & 5 & 10 & 8 & 11 & 14 & 15 & 6 & 13 & 1 & 4 & 9 & 7 & 2 & 12 \end{pmatrix}.

After how many minutes will all the schoolchildren be back in their original seats for the first time?

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Remark.
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A permutation of a set is a listing of the elements of this set in an arbitrary order. More rigorously, a permutation of a set is a one-to-one mapping of this set onto itself (i.e., a bijection). It is convenient to depict a permutation ff as a directed graph whose vertices are the elements of the set and whose edges go from the vertex aka_k to the vertex f(ak)f(a_k). The permutation of the set {a1,a2,…,an}\{ a_1, a_2, \ldots , a_n\} that takes aka_k to f(ak)f(a_k) is written in the form

(a1a2…anf(a1)f(a2)…f(an)); \begin{pmatrix} a_1 & a_2 & \ldots & a_n \\ f(a_1) & f(a_2) & \ldots & f(a_n) \end{pmatrix};

usually ak=ka_k = k for all k∈Rnk \in \mathscr {R}_n. The inverse permutation of ff is the permutation f−1f^{-1} written in the form

(f(a1)f(a2)…f(an)a1a2…an). \begin{pmatrix} f(a_1) & f(a_2) & \ldots & f(a_n) \\ a_1 & a_2 & \ldots & a_n \end{pmatrix}.

A cycle (of length nn) is a permutation of the form

(a1a2…an−1ana2a3…ana1). \begin{pmatrix} a_1 & a_2 & \ldots & a_{n-1} & a_n \\ a_2 & a_3 & \ldots & a_n & a_1 \end{pmatrix}.

This permutation is briefly denoted by (a1a2…an)(a_1a_2\ldots a_n).

The composition of permutations ff and gg is the permutation f∘gf\circ g defined by the formula (f∘g)(x):=f(g(x))(f\circ g)(x) := f(g(x)).

Problem 1.7.2

Find the compositions of permutations of the set of digits

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(1)

(12)∘(13)(12)\circ (13);

(2)

(12)∘(23)(12)\circ (23);

(3)

(23)∘(12)(23)\circ (12);

(4)

(123)∘(132)(123)\circ (132);

(5)

(12)∘(13)∘(12)(12)\circ (13)\circ (12);

(6)

(12345)∘(12)(12345)\circ (12);

(7)

(12345)∘(56789)(12345)\circ (56789).

Give the answer as a composition of disjoint cycles. For example, (123)∘(234)=(12)∘(34)(123)\circ (234) = (12)\circ (34).

From now on, the composition sign is omitted.

Problem 1.7.3

For every permutation ff there exists k>0k>0 for which fk=idf^k = \mathrm{id} (i.e., for which, after the kk-fold application of the permutation ff, every element is mapped to itself).

The order of a permutation ff is the least k>0k>0 for which fk=idf^k = \mathrm{id}.

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Problem 1.7.4

Do there exist permutations of a 9-element set of orders 7,10,12,117, 10, 12, 11?

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Problem 1.7.5

What is the order of a composition of disjoint cycles of n1,…,nkn_1, \ldots , n_k elements, respectively?

The permutations of an (n1+…+nk)(n_1+\ldots +n_k)-element set from Problem 1.7.5 are called permutations of type ⟨n1,…,nk⟩\langle n_1, \ldots , n_k \rangle. For example, the permutations (14)(253)(14)(253), (15)(432)(15)(432) are of type ⟨2,3⟩\langle 2,3 \rangle, while the permutation (1)(3)(245)(1)(3)(245) is of a different type, ⟨1,1,3⟩\langle 1,1,3 \rangle.

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Problem 1.7.6

Find the number of permutations of type

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(1)

⟨2,3⟩\langle 2,3 \rangle;

(2)

⟨3,3⟩\langle 3,3 \rangle;

(3)

⟨1,2,3,4⟩\langle 1,2,3,4 \rangle.

Problem 1.7.7

Every permutation can be represented as a composition of

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(1)

disjoint cycles;

(2)

transpositions, i.e., permutations each of which swaps some two elements and leaves the rest in place (in other words, cycles of length 2);

(3)

transpositions (1i)(1i), i=2,3,…,ni=2,3,\ldots ,n.

Problem 1.7.8

Find two permutations whose compositions yield every permutation of an nn-element set.

Permutations aa and bb are called conjugate if a=xbx−1a = xbx^{-1} for some permutation xx.

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Problem 1.7.9
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(1)

Permutations aa and bb are conjugate if and only if their types are the same.

(2)

Let aa and xx be arbitrary permutations of an nn-element set. Then

xax−1=(x(1)x(2)…x(n)x(a(1))x(a(2))…x(a(n))). xax^{-1} = \begin{pmatrix} x(1) & x(2) & \ldots & x(n) \\ x(a(1)) & x(a(2)) & \ldots & x(a(n)) \end{pmatrix}.

In other words, the cycle decomposition of the permutation xax−1xax^{-1} is obtained from the cycle decomposition of the permutation aa by replacing each element with its xx-image: if a=∏j=1q(ij1,ij2,…,ijsj)a = \displaystyle \prod_{j=1}^{q}(i_{j1},i_{j2},\ldots ,i_{js_j}), then

xax−1=∏j=1q(x(ij1),x(ij2),…,x(ijsj)). xax^{-1} = \prod _{j=1}^{q}(x(i_{j1}),x(i_{j2}),\ldots ,x(i_{js_j})).
(3)

Find gf−1g−1fgf^{-1}g^{-1}f for f:=(1,2,…,N)f := (1,2,\ldots ,N) and g:=(N,N+1,…,L)g := (N,N+1,\ldots ,L).