Problem 4422

Problems in Mathematical Analysis · 8.17

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Problem 4422

Prove

div⁡a→(M)=lim⁡d(S)→01V∬Sa→⋅n→ dS, \operatorname {div}\overrightarrow {a}(M) = \lim _{d(S)\to 0} \dfrac {1}{V}\iint _{S} \overrightarrow {a}\cdot \overrightarrow {n}\, dS ,

where SS is a closed surface enclosing the point MM and bounding a volume VV, n→\overrightarrow {n} is the outward normal of the surface SS, and d(S)d(S) is the diameter of the surface SS.

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Problem 4422.1
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