Section 3.4

Integration of trigonometric functions

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Problem 1991

Compute using the recursion formula. Find the following integral: ∫cos⁡5x dx\displaystyle \int \cos^{5}x\, dx.

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Problem 1992

Find the integral: ∫sin⁡6x dx\displaystyle \int \sin^{6}x\, dx.

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Problem 1993

Find the integral: ∫cos⁡6x dx\displaystyle \int \cos^{6}x\, dx.

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Problem 1994

Find the integral: ∫sin⁡2xcos⁡4x dx\displaystyle \int \sin^{2}x\cos^{4}x\, dx.

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Problem 1995

Find the integral: ∫sin⁡4xcos⁡5x dx\displaystyle \int \sin^{4}x\cos^{5}x\, dx.

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Problem 1996

Find the integral: ∫sin⁡5xcos⁡5x dx\displaystyle \int \sin^{5}x\cos^{5}x\, dx.

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Problem 1997

Find the integral: ∫sin⁡3xcos⁡4x dx\displaystyle \int \dfrac {\sin^{3}x}{\cos^{4}x}\, dx.

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Problem 1998

Find the integral: ∫cos⁡4xsin⁡3x dx\displaystyle \int \dfrac {\cos^{4}x}{\sin^{3}x}\, dx.

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Problem 1999

Find the integral: ∫dxsin⁡3x\displaystyle \int \dfrac {dx}{\sin^{3}x}.

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Problem 2000

Find the integral: ∫dxcos⁡3x\displaystyle \int \dfrac {dx}{\cos^{3}x}.

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Problem 2001

Find the integral: ∫dxsin⁡4xcos⁡4x\displaystyle \int \dfrac {dx}{\sin^{4}x\cos^{4}x}.

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Problem 2002

Find the integral: ∫dxsin⁡3xcos⁡5x\displaystyle \int \dfrac {dx}{\sin^{3}x\cos^{5}x}.

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Problem 2003

Find the integral: ∫dxsin⁡xcos⁡4x\displaystyle \int \dfrac {dx}{\sin x\cos^{4}x}.

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Problem 2004

Find the integral: ∫tg⁡5x dx\displaystyle \int \operatorname {tg}^{5}x\, dx.

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Problem 2005

Find the integral: ∫ctg⁡6x dx\displaystyle \int \operatorname {ctg}^{6}x\, dx.

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Problem 2006

Find the integral: ∫sin⁡4xcos⁡8x dx\displaystyle \int \dfrac {\sin^{4}x}{\cos^{8}x}\, dx.

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Problem 2007

Find the integral: ∫dxsin⁡3xcos⁡5x\displaystyle \int \dfrac {dx}{\sqrt{\sin^{3}x\cos^{5}x}}.

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Problem 2008

Find the integral: ∫dxcos⁡xsin⁡2x3\displaystyle \int \dfrac {dx}{\cos x\sqrt[3]{\sin^{2}x}}.

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Problem 2009

Find the integral: ∫dxtg⁡x\displaystyle \int \dfrac {dx}{\sqrt{\operatorname {tg}x}}.

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Problem 2010

Find the integral: ∫dxtg⁡x3\displaystyle \int \dfrac {dx}{\sqrt[3]{\operatorname {tg}x}}.

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Problem 2011

Derive recursion formulas for the following integrals:

(1) In=∫sin⁡nx dxI_{n}=\displaystyle \int \sin^{n}x\, dx;

(2) Kn=∫cos⁡nx dxK_{n}=\displaystyle \int \cos^{n}x\, dx (n>2n>2). and use the resulting formulas to compute ∫sin⁡6x dx\displaystyle \int \sin^{6}x\, dx and ∫cos⁡8x dx\displaystyle \int \cos^{8}x\, dx.

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(a)
(b)
Problem 2012

Derive recursion formulas for the following integrals:

(1) In=∫dxsin⁡nxI_{n}=\displaystyle \int \dfrac {dx}{\sin^{n}x};

(2) Kn=∫dxcos⁡nxK_{n}=\displaystyle \int \dfrac {dx}{\cos^{n}x} (n>2n>2). and use the resulting formulas to compute ∫dxsin⁡5x\displaystyle \int \dfrac {dx}{\sin^{5}x} and ∫dxcos⁡7x\displaystyle \int \dfrac {dx}{\cos^{7}x}.

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(a)
(b)
Problem 2013

Using the formulas

Isin⁡αsin⁡β=12[cos⁡(α−β)−cos⁡(α+β)]; \text{I}\quad \sin \alpha \sin \beta =\frac{1}{2}\left[\cos (\alpha -\beta )-\cos (\alpha +\beta )\right] ; IIcos⁡αcos⁡β=12[cos⁡(α+β)+cos⁡(α−β)]; \text{II}\quad \cos \alpha \cos \beta =\frac{1}{2}\left[\cos (\alpha +\beta )+\cos (\alpha -\beta )\right] ; IIIsin⁡αcos⁡β=12[sin⁡(α−β)+sin⁡(α+β)] \text{III}\quad \sin \alpha \cos \beta =\frac{1}{2}\left[\sin (\alpha -\beta )+\sin (\alpha +\beta )\right]

to compute the following integrals. Find the integral: ∫sin⁡5xcos⁡x dx\displaystyle \int \sin 5x\cos x\, dx.

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Problem 2014

Find the integral: ∫cos⁡xcos⁡2xcos⁡3x dx\displaystyle \int \cos x\cos 2x\cos 3x\, dx.

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Problem 2015

Find the integral: ∫sin⁡xsin⁡x2sin⁡x3 dx\displaystyle \int \sin x\sin \dfrac {x}{2}\sin \dfrac {x}{3}\, dx.

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Problem 2016

Find the integral: ∫sin⁡xsin⁡(x+a)sin⁡(x+b) dx\displaystyle \int \sin x\sin (x+a)\sin (x+b)\, dx.

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Problem 2017

Find the integral: ∫cos⁡2axcos⁡2bx dx\displaystyle \int \cos^{2}ax\cos^{2}bx\, dx.

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Problem 2018

Find the integral: ∫sin⁡32xcos⁡23x dx\displaystyle \int \sin^{3}2x\cos^{2}3x\, dx.

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Problem 2019

Find the integral: ∫dxsin⁡(x+a)sin⁡(x+b)\displaystyle \int \dfrac {dx}{\sin (x+a)\sin (x+b)}.

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Problem 2020

Find the integral: ∫dxsin⁡(x+a)cos⁡(x+b)\displaystyle \int \dfrac {dx}{\sin (x+a)\cos (x+b)}.

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Problem 2021

Find the integral: ∫dxcos⁡(x+a)cos⁡(x+b)\displaystyle \int \dfrac {dx}{\cos (x+a)\cos (x+b)}.

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Problem 2022

Find the integral: ∫dxsin⁡x−sin⁡a\displaystyle \int \dfrac {dx}{\sin x-\sin a}.

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Problem 2023

Find the integral: ∫dxcos⁡x+cos⁡a\displaystyle \int \dfrac {dx}{\cos x+\cos a}.

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Problem 2024

Find the integral: ∫tg⁡xtg⁡(x+a) dx\displaystyle \int \operatorname {tg}x\operatorname {tg}(x+a)\, dx.

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Problem 2025

For an integral of the form ∫R(sin⁡x,cos⁡x) dx\displaystyle \int R(\sin x,\cos x)\, dx (where RR is a rational function), the general case can be reduced to the integral of a rational function by the substitution tg⁡x2=t\operatorname {tg}\dfrac {x}{2}=t.

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(a)

If the identity R(−sin⁡x,cos⁡x)≡−R(sin⁡x,cos⁡x)R(-\sin x,\cos x)\equiv -R(\sin x,\cos x) holds, or R(sin⁡x,−cos⁡x)≡−R(sin⁡x,cos⁡x)R(\sin x,-\cos x)\equiv -R(\sin x,\cos x) holds, then it is best to use the substitution cos⁡x=t\cos x=t or, correspondingly, sin⁡x=t\sin x=t.

(b)

If the identity R(−sin⁡x,−cos⁡x)≡R(sin⁡x,cos⁡x)R(-\sin x,-\cos x)\equiv R(\sin x,\cos x) holds, then it is best to use the substitution tg⁡x=t\operatorname {tg}x=t.

Find the integral: ∫dx2sin⁡x−cos⁡x+5\displaystyle \int \dfrac {dx}{2\sin x-\cos x+5}.

Problem 2026

Find the integral: ∫dx(2+cos⁡x)sin⁡x\displaystyle \int \dfrac {dx}{(2+\cos x)\sin x}.

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Problem 2027

Find the integral: ∫sin⁡2xsin⁡x+2cos⁡x dx\displaystyle \int \dfrac {\sin^{2}x}{\sin x+2\cos x}\, dx.

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Problem 2028

Find the integral: ∫dx1+εcos⁡x\displaystyle \int \dfrac {dx}{1+\varepsilon \cos x}:

(1) 0<ε<10<\varepsilon <1;

(2) ε>1\varepsilon >1.

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(b)
Problem 2029

Find the integral: ∫sin⁡2x1+sin⁡2x dx\displaystyle \int \dfrac {\sin^{2}x}{1+\sin^{2}x}\, dx.

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Problem 2030

Find the integral: ∫dxa2sin⁡2x+b2cos⁡2x\displaystyle \int \dfrac {dx}{a^{2}\sin^{2}x+b^{2}\cos^{2}x}.

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Problem 2031

Find the integral: ∫cos⁡2x dx(a2sin⁡2x+b2cos⁡2x)2\displaystyle \int \dfrac {\cos^{2}x\, dx}{(a^{2}\sin^{2}x+b^{2}\cos^{2}x)^{2}}.

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Problem 2032

Find the integral: ∫sin⁡xcos⁡xsin⁡x+cos⁡x dx\displaystyle \int \dfrac {\sin x\cos x}{\sin x+\cos x}\, dx.

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Problem 2033

Find the integral: ∫dx(asin⁡x+bcos⁡x)2\displaystyle \int \dfrac {dx}{(a\sin x+b\cos x)^{2}}.

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Problem 2034

Find the integral: ∫sin⁡x dxsin⁡3x+cos⁡3x\displaystyle \int \dfrac {\sin x\, dx}{\sin^{3}x+\cos^{3}x}.

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Problem 2035

Find the integral: ∫dxsin⁡4x+cos⁡4x\displaystyle \int \dfrac {dx}{\sin^{4}x+\cos^{4}x}.

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Problem 2036

Find the integral: ∫sin⁡2xcos⁡2xsin⁡8x+cos⁡8x dx\displaystyle \int \dfrac {\sin^{2}x\cos^{2}x}{\sin^{8}x+\cos^{8}x}\, dx.

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Problem 2037

Find the integral: ∫sin⁡2x−cos⁡2xsin⁡4x+cos⁡4x dx\displaystyle \int \dfrac {\sin^{2}x-\cos^{2}x}{\sin^{4}x+\cos^{4}x}\, dx.

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Problem 2038

Find the integral: ∫sin⁡xcos⁡x1+sin⁡4x dx\displaystyle \int \dfrac {\sin x\cos x}{1+\sin^{4}x}\, dx.

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Problem 2039

Find the integral: ∫dxsin⁡6x+cos⁡6x\displaystyle \int \dfrac {dx}{\sin^{6}x+\cos^{6}x}.

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Problem 2040

Find the integral: ∫dx(sin⁡2x+2cos⁡2x)2\displaystyle \int \dfrac {dx}{(\sin^{2}x+2\cos^{2}x)^{2}}.

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Problem 2041

Find the integral: ∫dxasin⁡x+bcos⁡x\displaystyle \int \dfrac {dx}{a\sin x+b\cos x} (first reduce the denominator to the form of a logarithm).

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Problem 2042

Prove that ∫a1sin⁡x+b1cos⁡xasin⁡x+bcos⁡x dx=Ax+Bln⁡∣asin⁡x+bcos⁡x∣+C\displaystyle \int \dfrac {a_{1}\sin x+b_{1}\cos x}{a\sin x+b\cos x}\, dx=Ax+B\ln \left|a\sin x+b\cos x\right|+C, where AA, BB, CC are constants.

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Problem 2043

Find the integral: ∫sin⁡x−cos⁡xsin⁡x+2cos⁡x dx\displaystyle \int \dfrac {\sin x-\cos x}{\sin x+2\cos x}\, dx.

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Problem 2043.1
[NO TASK]
Problem 2044

Find the integral: ∫dx3+5tg⁡x\displaystyle \int \dfrac {dx}{3+5\operatorname {tg}x}.

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Problem 2045

Find the integral: ∫a1sin⁡x+b1cos⁡x(asin⁡x+bcos⁡x)2 dx\displaystyle \int \dfrac {a_{1}\sin x+b_{1}\cos x}{(a\sin x+b\cos x)^{2}}\, dx.

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Problem 2046

Prove that: ∫a1sin⁡x+b1cos⁡x+c1asin⁡x+bcos⁡x+c dx=Ax+Bln⁡∣asin⁡x+bcos⁡x+c∣+C∫dxasin⁡x+bcos⁡x+c\displaystyle \int \dfrac {a_{1}\sin x+b_{1}\cos x+c_{1}}{a\sin x+b\cos x+c}\, dx=Ax+B\ln \left|a\sin x+b\cos x+c\right|+C\displaystyle \int \dfrac {dx}{a\sin x+b\cos x+c}, where AA, BB, CC are all constant coefficients.

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Problem 2047

Find the integral: ∫sin⁡x+2cos⁡x−3sin⁡x−2cos⁡x+3 dx\displaystyle \int \dfrac {\sin x+2\cos x-3}{\sin x-2\cos x+3}\, dx.

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Problem 2048

Find the integral: ∫sin⁡x dx2+sin⁡x+cos⁡x\displaystyle \int \dfrac {\sin x\, dx}{\sqrt{2}+\sin x+\cos x}.

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Problem 2049

Find the integral: ∫2sin⁡x+cos⁡x3sin⁡x+4cos⁡x−2 dx\displaystyle \int \dfrac {2\sin x+\cos x}{3\sin x+4\cos x-2}\, dx.

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Problem 2050

Prove that: ∫a1sin⁡2x+2b1sin⁡xcos⁡x+c1cos⁡2xasin⁡x+bcos⁡x dx=Asin⁡x+Bcos⁡x+C∫dxasin⁡x+bcos⁡x\displaystyle \int \dfrac {a_{1}\sin^{2}x+2b_{1}\sin x\cos x+c_{1}\cos^{2}x}{a\sin x+b\cos x}\, dx=A\sin x+B\cos x+C\displaystyle \int \dfrac {dx}{a\sin x+b\cos x}, where AA, BB, CC are all constant coefficients.

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Problem 2051

Find the integral: ∫sin⁡2x−4sin⁡xcos⁡x+3cos⁡2xsin⁡x+cos⁡x dx\displaystyle \int \dfrac {\sin^{2}x-4\sin x\cos x+3\cos^{2}x}{\sin x+\cos x}\, dx.

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Problem 2052

Find the integral: ∫sin⁡2x−sin⁡xcos⁡x+2cos⁡2xsin⁡x+2cos⁡x dx\displaystyle \int \dfrac {\sin^{2}x-\sin x\cos x+2\cos^{2}x}{\sin x+2\cos x}\, dx.

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Problem 2053

Prove that if (a−c)2+b2≠0(a-c)^{2}+b^{2}\neq 0, then

∫a1sin⁡x+b1cos⁡xasin⁡2x+2bsin⁡xcos⁡x+ccos⁡2x dx=A∫du1k1u12+λ1+B∫du2k2u22+λ2, \int \dfrac {a_{1}\sin x+b_{1}\cos x}{a\sin ^{2}x+2b\sin x\cos x+c\cos ^{2}x}\, dx=A\int \dfrac {du_{1}}{k_{1}u_{1}^{2}+\lambda _{1}}+B\int \dfrac {du_{2}}{k_{2}u_{2}^{2}+\lambda _{2}} ,

where AA, BB are undetermined coefficients, λ1\lambda_{1}, λ2\lambda_{2} are the roots of the equation below

∣a−λbbc−λ∣=0(λ1≠λ2) \begin{vmatrix} a-\lambda & b \\ b & c-\lambda \end{vmatrix}=0\quad (\lambda _{1}\neq \lambda _{2})

and

ui=(a−λi)sin⁡x+bcos⁡x,ki=1a−λi(i=1,2). u_{i}=(a-\lambda _{i})\sin x+b\cos x ,\quad k_{i}=\dfrac {1}{a-\lambda _{i}}\quad (i=1,2) .
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Problem 2054

Find the integral: ∫2sin⁡x−cos⁡x3sin⁡2x+4cos⁡2x dx\displaystyle \int \dfrac {2\sin x-\cos x}{3\sin^{2}x+4\cos^{2}x}\, dx.

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Problem 2055

Find the integral: ∫sin⁡x+cos⁡x2sin⁡2x−4sin⁡xcos⁡x+5cos⁡2x dx\displaystyle \int \dfrac {\sin x+\cos x}{2\sin^{2}x-4\sin x\cos x+5\cos^{2}x}\, dx.

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Problem 2056

Evaluate the integral: ∫sin⁡x−2cos⁡x1+4sin⁡xcos⁡x dx\displaystyle \int \dfrac {\sin x-2\cos x}{1+4\sin x\cos x}\, dx.

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Problem 2057

Prove that

∫dx(asin⁡x+bcos⁡x)n=Asin⁡x+Bcos⁡x(asin⁡x+bcos⁡x)n−1+C∫dx(asin⁡x+bcos⁡x)n−2, \int \dfrac {dx}{(a\sin x+b\cos x)^{n}}=\dfrac {A\sin x+B\cos x}{(a\sin x+b\cos x)^{n-1}}+C\int \dfrac {dx}{(a\sin x+b\cos x)^{n-2}} ,

where AA, BB, CC are undetermined coefficients.

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Problem 2058

Evaluate ∫dx(sin⁡x+2cos⁡x)3\displaystyle \int \dfrac {dx}{(\sin x+2\cos x)^{3}}.

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Problem 2059

If nn is a natural number greater than 11, prove that

∫dx(a+bcos⁡x)n=Asin⁡x(a+bcos⁡x)n−1+B∫dx(a+bcos⁡x)n−1+C∫dx(a+bcos⁡x)n−2(∣a∣≠∣b∣), \int \dfrac {dx}{(a+b\cos x)^{n}}=\dfrac {A\sin x}{(a+b\cos x)^{n-1}}+B\int \dfrac {dx}{(a+b\cos x)^{n-1}}+C\int \dfrac {dx}{(a+b\cos x)^{n-2}}\quad (\left|a\right|\neq \left|b\right|) ,

and find the coefficients AA, BB and CC.

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Problem 2060

Evaluate the integral: ∫sin⁡x dxcos⁡x1+sin⁡2x\displaystyle \int \dfrac {\sin x\, dx}{\cos x\sqrt{1+\sin^{2}x}}.

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Problem 2061

Evaluate the integral: ∫sin⁡2xcos⁡2xtg⁡x dx\displaystyle \int \dfrac {\sin^{2}x}{\cos^{2}x\sqrt{\operatorname {tg}x}}\, dx.

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Problem 2062

Evaluate the integral: ∫sin⁡x dx2+sin⁡2x\displaystyle \int \dfrac {\sin x\, dx}{\sqrt{2+\sin 2x}}.

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Problem 2063

Evaluate the integral: ∫dx(1+εcos⁡x)2\displaystyle \int \dfrac {dx}{(1+\varepsilon \cos x)^{2}} (0<ε<10<\varepsilon <1).

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Problem 2064

Evaluate the integral: ∫cos⁡n−1x+a2sin⁡n+1x−a2 dx\displaystyle \int \dfrac {\cos^{n-1}\dfrac {x+a}{2}}{\sin^{n+1}\dfrac {x-a}{2}}\, dx.

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Problem 2065

Derive a recurrence formula for the integral In=∫(sin⁡x−a2sin⁡x+a2)n dx\displaystyle I_{n}=\int \left(\dfrac {\sin \dfrac {x-a}{2}}{\sin \dfrac {x+a}{2}}\right)^{n}\, dx (nn a natural number).

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