Section 2.10

Taylor's Formula

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Problem 1376

Express the polynomial

P(x)=1+3x+5x2−2x3 P(x)=1+3x+5x^{2}-2x^{3}

as a polynomial in positive integer powers of the binomial x+1x+1.

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Problem 1377

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

1+x+x21−x+x2 up to the term in x4. What is f(4)(0)? \frac{1+x+x^{2}}{1-x+x^{2}} \text{ up to the term in } x^{4} \text{. What is } f^{(4)}(0) \text{?}
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Problem 1378

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

(1+x)100(1−2x)40(1+2x)60 up to the term in x2. \frac{(1+x)^{100}}{(1-2x)^{40}(1+2x)^{60}} \text{ up to the term in } x^{2} \text{.}
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Problem 1379

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

am+xm (a>0) up to the term in x2. \sqrt[m]{a^{m}+x} \ (a>0) \text{ up to the term in } x^{2} \text{.}
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Problem 1380

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

1−2x+x3−1−3x+x23 up to the term in x3. \sqrt{1-2x+x^{3}}-\sqrt[3]{1-3x+x^{2}} \text{ up to the term in } x^{3} \text{.}
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Problem 1381

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

e2x−x2 up to the term in x5. e^{2x-x^{2}} \text{ up to the term in } x^{5} \text{.}
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Problem 1382

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

xex−1 up to the term in x4. \frac{x}{e^{x}-1} \text{ up to the term in } x^{4} \text{.}
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Problem 1383

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

sin⁡x33 up to the term in x13. \sqrt[3]{\sin x^{3}} \text{ up to the term in } x^{13} \text{.}
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Problem 1384

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

ln⁡cos⁡x up to the term in x6. \ln \cos x \text{ up to the term in } x^{6} \text{.}
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Problem 1385

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

sin⁡(sin⁡x) up to the term in x3. \sin (\sin x) \text{ up to the term in } x^{3} \text{.}
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Problem 1386

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

tg⁡x up to the term in x5. \tg x \text{ up to the term in } x^{5} \text{.}
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Problem 1387

Write out the expansion of the following function in positive integer powers of the variable xx, up to the term of the indicated order:

ln⁡sin⁡xx up to the term in x6. \ln \frac{\sin x}{x} \text{ up to the term in } x^{6} \text{.}
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Problem 1388

Find the first three terms of the expansion of the function f(x)=xf(x)=\sqrt{x} in positive integer powers of the difference (x−1)(x-1).

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Problem 1389

Expand the function f(x)=xx−1f(x)=x^{x}-1 in positive integer powers of (x−1)(x-1) up to the term containing (x−1)3(x-1)^{3}.

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Problem 1390

In a neighborhood of the point x=0x=0, approximate the function

y=ach⁡xa (a>0) y=a\ch \frac{x}{a} \ (a>0)

by a second-order parabola.

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Problem 1391

Expand the function f(x)=1+x2−x (x>0)f(x)=\sqrt{1+x^{2}}-x \ (x>0) in positive integer powers of 1x\dfrac {1}{x}, up to the term in 1x3\dfrac {1}{x^{3}}.

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Problem 1392

Expand the function f(h)=ln⁡(x+h) (x>0)f(h)=\ln (x+h) \ (x>0) in positive integer powers of the increment hh, up to the term in hnh^{n} (nn a natural number).

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Problem 1393

Let:

f(x+h)=f(x)+hf′(x)+⋯+hnn!f(n)(x+θh) (0<θ<1). \begin{align} f(x+h) & =f(x)+hf'(x)+\cdots +\frac{h^{n}}{n!}f^{(n)}(x+\theta h) \ (0<\theta <1) . \end{align}

and f(n+1)(x)≠0f^{(n+1)}(x) \neq 0. Prove that:

lim⁡h→0θ=1n+1. \lim _{h \to 0}\theta =\frac{1}{n+1} .
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Problem 1393.1
[NO TASK]
Problem 1393.2
[NO TASK]
Problem 1393.3
[NO TASK]
Problem 1394

Estimate the absolute error of the following approximate formulas:

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(a)

ex≈1+x+x22!+⋯+xnn!e^{x} \approx 1+x+\dfrac {x^{2}}{2!}+\cdots +\dfrac {x^{n}}{n!} for 0⩽x⩽10 \leqslant x \leqslant 1;

(b)

sin⁡x≈x−x36\sin x \approx x-\dfrac {x^{3}}{6} for ∣x∣⩽12\left|x\right| \leqslant \dfrac {1}{2};

(c)

tg⁡x≈x+x33\tg x \approx x+\dfrac {x^{3}}{3} for ∣x∣⩽0.1\left|x\right| \leqslant 0.1;

(d)

1+x≈1+x2−x28\sqrt{1+x} \approx 1+\dfrac {x}{2}-\dfrac {x^{2}}{8} for 0⩽x⩽10 \leqslant x \leqslant 1.

Problem 1395

For what values of xx is the approximate formula

cos⁡x=1−x22 \cos x=1-\frac{x^{2}}{2}

accurate to 0.00010.0001.

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Problem 1395.1
[NO TASK]
Problem 1396

Using Taylor's formula, compute approximately, and estimate the error:

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(a)

303\sqrt[3]{30};

(b)

2505\sqrt[5]{250};

(c)

400015\sqrt[15]{4000};

(d)

e\sqrt{e};

(e)

sin⁡18°\sin 18°;

(f)

ln⁡1.2\ln 1.2;

(g)

arctg⁡0.8\arctg 0.8;

(h)

arcsin⁡0.45\arcsin 0.45;

(i)

(1.1)1.2(1.1)^{1.2}.

Problem 1397

Compute:

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(a)

ee to within 10−910^{-9};

(b)

sin⁡1°\sin 1° to within 10−810^{-8};

(c)

cos⁡9°\cos 9° to within 10−510^{-5};

(d)

5\sqrt{5} to within 10−410^{-4};

(e)

log⁡1011\log_{10}11 to within 10−510^{-5}.

Problem 1398

Using expansions I--V, find the following limits:

lim⁡x→0cos⁡x−e−x22x4. \lim _{x \to 0}\frac{\cos x-e^{-\frac{x^{2}}{2}}}{x^{4}} .
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Problem 1399

Using expansions I--V, find the following limits:

lim⁡x→0exsin⁡x−x(1+x)x3. \lim _{x \to 0}\frac{e^{x}\sin x-x(1+x)}{x^{3}} .
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Problem 1400

Using expansions I--V, find the following limits:

lim⁡x→+∞x32(x+1+x−1−2x). \lim _{x \to +\infty }x^{\frac{3}{2}}(\sqrt{x+1}+\sqrt{x-1}-2\sqrt{x}) .
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Problem 1401

Using expansions I--V, find the following limits:

lim⁡x→+∞(x5+x56−x6−x56). \lim _{x \to +\infty }(\sqrt[6]{x^{5}+x^{5}}-\sqrt[6]{x^{6}-x^{5}}) .
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Problem 1402

Using expansions I--V, find the following limits:

lim⁡x→+∞[(x3−x2+x2)e1x−x6+1]. \lim _{x \to +\infty }\left[\left(x^{3}-x^{2}+\frac{x}{2}\right)e^{\frac{1}{x}}-\sqrt{x^{6}+1}\right] .
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Problem 1403

Using expansions I--V, find the following limits:

lim⁡x→+0ax+a−x−2x2 (a>0). \lim _{x \to +0}\frac{a^{x}+a^{-x}-2}{x^{2}} \ (a>0) .
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Problem 1404

Using expansions I--V, find the following limits:

lim⁡x→∞[x−x2ln⁡(1+1x)]. \lim _{x \to \infty }\left[x-x^{2}\ln \left(1+\frac{1}{x}\right)\right] .
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Problem 1405

Using expansions I--V, find the following limits:

lim⁡x→0(1x−1sin⁡x). \lim _{x \to 0}\left(\frac{1}{x}-\frac{1}{\sin x}\right) .
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Problem 1406

Using expansions I--V, find the following limits:

lim⁡x→01x(1x−ctg⁡x). \lim _{x \to 0}\frac{1}{x}\left(\frac{1}{x}-\ctg x\right) .
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Problem 1406.1
[NO TASK]
Problem 1406.2
[NO TASK]
Problem 1406.3
[NO TASK]
Problem 1407

As x→0x \to 0, find the leading term of the form CxnCx^{n} (CC a constant) of the infinitesimal yy, given:

y=tg⁡(sin⁡x)−sin⁡(tg⁡x). y=\tg (\sin x)-\sin (\tg x) .
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Problem 1408

As x→0x \to 0, find the leading term of the form CxnCx^{n} (CC a constant) of the infinitesimal yy, given:

y=(1+x)x−1. y=(1+x)^{x}-1 .
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Problem 1409

As x→0x \to 0, find the leading term of the form CxnCx^{n} (CC a constant) of the infinitesimal yy, given:

y=1−(1+x)1xe. y=1-\frac{(1+x)^{\frac{1}{x}}}{e} .
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Problem 1410

For what choice of coefficients aa and bb is the quantity

x−(a+bcos⁡x)sin⁡x x-(a+b\cos x)\sin x

an infinitesimal of order 55 with respect to xx?

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Problem 1410.1
[NO TASK]
Problem 1410.2
[NO TASK]
Problem 1411

For small ∣x∣\left|x\right|, derive simple approximate formulas for the following expressions:

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(a)

1R2−1(R+x)2 (R>0)\dfrac {1}{R^{2}}-\dfrac {1}{(R+x)^{2}} \ (R>0);

(b)

1+x1−x3−1−x1+x3\sqrt[3]{\dfrac {1+x}{1-x}}-\sqrt[3]{\dfrac {1-x}{1+x}};

(c)

Ax[1−(1+x100)−n]\dfrac {A}{x}\left[1-\left(1+\dfrac {x}{100}\right)^{-n}\right];

(d)

ln⁡2ln⁡(1+x100)\dfrac {\ln 2}{\ln \left(1+\dfrac {x}{100}\right)}.

Problem 1412

For small absolute value of xx, derive an approximate formula of the form

x=αsin⁡x+βtg⁡x x=\alpha \sin x+\beta \tg x

accurate to the x5x^{5} term.

Apply this formula to the approximate computation of the arc length for a small angle.

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Problem 1413

Estimate the relative error of the following Chebyshev rule: a circular arc is approximately equal to the sum of the two equal legs of an isosceles triangle standing on the chord subtended by the arc, whose height is 43\sqrt{\dfrac {4}{3}} times the sagitta of the circular segment.

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