Section V.1

Duality

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Problem V.1.1

Show that wk is the smallest topology on X\mathcal{X} such that each x∗x^* in X∗\mathcal{X}^* is continuous.

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Problem V.1.2

Show that wk* is the smallest topology on X∗\mathcal{X}^* such that for each xx in X\mathcal{X}, x∗↦⟨x,x∗⟩x^* \mapsto \left\langle x, x^* \right\rangle is continuous.

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Problem V.1.3

Prove Theorem 1.3.

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Problem V.1.4

Let X\mathcal{X} be a complex LCS and let XR∗\mathcal{X}^*_{\mathbb {R}} denote the collection of all continuous real linear functionals on X\mathcal{X}. Use the elements of XR∗\mathcal{X}^*_{\mathbb {R}} to define seminorms on X\mathcal{X} and let σ(X,XR∗)\sigma (\mathcal{X}, \mathcal{X}^*_{\mathbb {R}}) be the corresponding topology. Show that σ(X,X∗)=σ(X,XR∗)\sigma (\mathcal{X}, \mathcal{X}^*) = \sigma (\mathcal{X}, \mathcal{X}^*_{\mathbb {R}}).

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Problem V.1.5

Prove the remainder of Proposition 1.7.

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Problem V.1.6

If A⊆XA \subseteq \mathcal{X}, show that AA is weakly bounded if and only if A∘A^\circ is absorbing in X∗\mathcal{X}^*.

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Problem V.1.7

Let X\mathcal{X} be a normed space and let {xn}\left\{ x_n\right\} be a sequence in X\mathcal{X} such that xn→xx_n \to x weakly. Show that there is a sequence {yn}\left\{ y_n\right\} such that yn∈co⁡{x1,x2,…,xn}y_n \in \operatorname {co}\left\{ x_1, x_2, \dots , x_n\right\} and ∥yn−x∥→0\left\| y_n - x\right\| \to 0.

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Problem V.1.8

If H\mathcal{H} is a Hilbert space and {hn}\left\{ h_n\right\} is a sequence in H\mathcal{H} such that hn→hh_n \to h weakly and ∥hn∥→∥h∥\left\| h_n\right\| \to \left\| h\right\|, then ∥hn−h∥→0\left\| h_n - h\right\| \to 0. (The same type of result is true for LpL^p-spaces if 1<p<∞1 < p < \infty. See W.P. Novinger [1972].)

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Problem V.1.9

If X\mathcal{X} is a normed space show that the norm on X\mathcal{X} is lower semicontinuous for the weak topology and the norm of X∗\mathcal{X}^* is lower semicontinuous for the weak-star topology.

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Problem V.1.10

Suppose X\mathcal{X} is an infinite-dimensional normed space. If S={x∈X:∥x∥=1}S = \left\{ x \in \mathcal{X} : \left\| x\right\| = 1\right\}, then the weak closure of SS is {x:∥x∥≤1}\left\{ x : \left\| x\right\| \leq 1\right\}.

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