Section III.6

The Hahn-Banach Theorem

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Problem III.6.1

Complete the proof of Lemma 6.3.

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Problem III.6.2

Give the details of the proof of Corollary 6.5.

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Problem III.6.3

Show that c∗c^* is isometrically isomorphic to l1l^1. Are cc and c0c_0 isometrically isomorphic?

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Problem III.6.4

If μ\mu is a Borel measure on [0,1][0,1] and ∫xn dμ(x)=0\int x^n \, d\mu (x) = 0 for all n≥0n \geq 0, show that μ=0\mu = 0.

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Problem III.6.5

If n≥1n \geq 1, show that there is a measure μ\mu on [0,1][0,1] such that for every polynomial pp of degree at most nn,

∫p dμ=∑k=1np(k)(k/n). \int p \, d\mu = \sum _{k=1}^{n} p^{(k)}(k/n).
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Problem III.6.6

If n≥1n \geq 1, does there exist a measure μ\mu on [0,1][0,1] such that p′(0)=∫p dμp'(0) = \int p \, d\mu for every polynomial of degree at most nn?

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Problem III.6.7

Does there exist a measure μ\mu on [0,1][0,1] such that ∫p dμ=p′(0)\int p \, d\mu = p'(0) for every polynomial pp?

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Problem III.6.8

Let KK be a compact subset of C\mathbb {C} and define A(K)A(K) to be {f∈C(K):f is analytic on int K}\left\{ f \in C(K) : f \text{ is analytic on int } K\right\}. (Functions here are complex valued.) Show that if a∈Ka \in K, then there is a probability measure μ\mu supported on ∂K\partial K such that f(a)=∫f dμf(a) = \int f \, d\mu for every ff in A(K)A(K). (A probability measure is a nonnegative measure μ\mu such that ∥μ∥=1\left\| \mu \right\| = 1.)

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Problem III.6.9

If K=cl DK = \mathrm{cl}\, \mathbb {D} (D={∣z∣<1}\mathbb {D} = \left\{ \left|z\right| < 1\right\}) and a∈Ka \in K, find the measure μ\mu whose existence was proved in Exercise 8.

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Problem III.6.10

Let P={p∣∂D:p=an analytic polynomial}P = \left\{ p|\partial \mathbb {D} : p = \text{an analytic polynomial}\right\} and consider PP as a manifold in C(∂D)C(\partial \mathbb {D}). Show that if μ\mu is a real-valued measure on ∂D\partial \mathbb {D} such that ∫p dμ=0\int p \, d\mu = 0 for every pp in PP, then μ=0\mu = 0. Give an example of a complex-valued measure μ\mu such that μ≠0\mu \neq 0 but ∫p dμ=0\int p \, d\mu = 0 for every pp in PP.

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