Chapter 12

Limit Theorems

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Problem 12.1

An archer is aiming at a circular target of radius 20 inches. Her arrows hit on average 5 inches away from the center, each shot being independent. Show that the next arrow will miss the target with probability at most 14\frac{1}{4}.

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Problem 12.2

Show that 14\frac{1}{4} is the best possible estimate of the probability of missing the target in Problem 12.1; that is, in certain circumstances, the probability can be equal to or be arbitrarily close to 14\frac{1}{4}.

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Problem 12.3

Show that if a non-negative random variable has finite expectation E[X]\mathbb {E}\left[X\right], then

P({X⩾C})⩽E[X]C \mathbb {P}\left(\{ X \geqslant C\} \right) \leqslant \frac{\mathbb {E}\left[X\right]}{C}

for any C>0C>0.

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Problem 12.4

Prove the following theorem, known as the Chebyshev inequality. - Theorem 12.1 Let XX be a random variable with finite expectation E[X]\mathbb {E}\left[X\right] and finite variance Var⁡[X]\operatorname {Var}\left[X\right]. Then,

P({∣X−E[X]∣⩾C})⩽Var⁡[X]C2 \mathbb {P}\left(\{ \left|X-\mathbb {E}\left[X\right]\right| \geqslant C\} \right) \leqslant \frac{\operatorname {Var}\left[X\right]}{C^{2}}

for any C>0C>0. The Chebyshev inequality provides a very rough estimate, whose strength comes from its universality. It allows us to estimate the likelihood of a deviation of a random variable XX from its mean value E[X]\mathbb {E}\left[X\right] even if nothing is known about the distribution of XX.

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Problem 12.5

A fair coin is tossed independently nn times. Let SnS_{n} be the number of heads obtained. Use the Chebyshev inequality to find a lower bound of the probability that Snn\frac{S_{n}}{n} differs from 12\frac{1}{2} by less than 0.1 when a) n=100n=100, b) n=10,000n=10,000, and c) n=100,000n=100,000.

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Problem 12.6

Find Chebyshev's lower bound of the probability that Snn\frac{S_{n}}{n} in Problem 12.5 differs from 12\frac{1}{2} by less than 0.01 when a) n=100n=100, b) n=n= 10,000 , and c) n=100,000n=100,000.

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Problem 12.7

In the same setting as in Problem 12.5, demonstrate that

lim⁡n→∞P({∣Snn−12∣<ε})=1 \lim _{n \rightarrow \infty } \mathbb {P}\left(\left\{ \left|\frac{S_{n}}{n}-\frac{1}{2}\right|<\varepsilon \right\} \right)=1

for any ε>0\varepsilon >0.

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Problem 12.8

Consider an unfair coin with probability pp of heads. Let SnS_{n} be the number of heads obtained when the coin is tossed independently nn times. Write down a limit similar to that in Problem 12.7 and prove it.

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Problem 12.9

We throw nn dice independently and add the points, denoting the sum by SnS_{n}. Extend the results in Problems 12.7 and 12.8 to this case.

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Problem 12.10

Prove the following weak law of large numbers. - Theorem 12.2 Let X1,…,XnX_{1}, \ldots , X_{n} be independent identically distributed random variables with finite expectation and variance and let Sn=X1+⋯+XnS_{n}=X_{1}+\cdots + X_{n}. We set a=E[Xi]a=\mathbb {E}\left[X_{i}\right], which is the same for each ii. Then,

lim⁡n→∞P({∣Snn−a∣<ε})=1 \lim _{n \rightarrow \infty } \mathbb {P}\left(\left\{ \left|\frac{S_{n}}{n}-a\right|<\varepsilon \right\} \right)=1

for any ε>0\varepsilon >0.

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Problem 12.11

Using the weak law of law of large numbers, prove that for every continuous function f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R},

∑k=0nf(kn)(nk)xk(1−x)k→f(x) \sum _{k=0}^{n} f\left(\frac{k}{n}\right)\binom {n}{k} x^{k}(1-x)^{k} \rightarrow f(x)

uniformly in x∈[0,1]x \in [0,1] as n→∞n \rightarrow \infty.

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Problem 12.12

Let Sn(x)S_{n}(x) denote the number of 1 's among the first nn digits of the binary expansion of x∈[0,1]x \in [0,1]. Show that

lim⁡n→∞Sn(x)n=12 \lim _{n \rightarrow \infty } \frac{S_{n}(x)}{n}=\frac{1}{2}

for all xx 's in a set of Lebesgue measure 1 in [0,1][0,1].

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Problem 12.13

Show that if XX has finite expectation, then E[an]=E[X]\mathbb {E}\left[a_{n}\right]=\mathbb {E}\left[X\right] and

lim⁡n→∞an=E[X] \lim _{n \rightarrow \infty } a_{n}=\mathbb {E}\left[X\right]

with probability 1.

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Problem 12.14

Show that

E[1n∑i=1n(Xi−an)2]=n−1nVar⁡[X]. \mathbb {E}\left[\frac{1}{n} \sum _{i=1}^{n}\left(X_{i}-a_{n}\right)^{2}\right]=\frac{n-1}{n} \operatorname {Var}\left[X\right] .
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Problem 12.15

Show that if XX has finite expectation and variance, then E[σn2]=Var⁡[X]\mathbb {E}\left[\sigma_{n}^{2}\right]= \operatorname {Var}\left[X\right] and

lim⁡n→∞σn2=Var⁡[X] \lim _{n \rightarrow \infty } \sigma _{n}^{2}=\operatorname {Var}\left[X\right]

with probability 1.

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Problem 12.16

Let (Ω,F,P)(\Omega , \mathcal{F}, P) be a probability space, Ω\Omega being the set of all possible outcomes of a random experiment. Take two events A,B∈FA, B \in \mathcal{F} with P(B)≠0\mathbb {P}\left(B\right) \neq 0. If the random experiment is repeated independently nn times, let SnS_{n} be the number of times the outcome is in BB. Among these SnS_{n} outcomes in BB, there will be RnR_{n} outcomes that are also in AA. Show that

lim⁡n→∞RnSn=P(A∣B) \lim _{n \rightarrow \infty } \frac{R_{n}}{S_{n}}=\mathbb {P}\left( A \mid B \right)

with probability 1.

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Problem 12.17

Prove that if a sequence of random variables XnX_{n} converges almost surely to XX, then it converges to XX in probability.

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Problem 12.18

Prove that if a sequence of random variables XnX_{n} converges to XX in probability, then it converges to XX in distribution.

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Problem 12.19

Demonstrate that for every real number xx,

lim⁡n→∞P({Snn⩽x})12π(σ2/n)∫−∞xe−(t−a)2/2(σ2/n)dt=1. \lim _{n \rightarrow \infty } \frac{\mathbb {P}\left(\left\{ \frac{S_{n}}{n} \leqslant x\right\} \right)}{\frac{1}{\sqrt{2 \pi \left(\sigma ^{2} / n\right)}} \int _{-\infty }^{x} e^{-(t-a)^{2} / 2\left(\sigma ^{2} / n\right)} \mathrm{d} t}=1 .
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Problem 12.20

Estimate the probability that the number of heads in 10,000 independent tosses of a fair coin differs by less than 1%1 \% from 5000 .

What is the probability that the number of heads will be greater than 5100 ?

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Problem 12.21

How many independent tosses of a fair coin are required for the probability that the average number of heads differs from 0.5 by less than 1%1 \% to be at least 0.99 ?

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Problem 12.22

Three candidates A,BA, B, and CC are running for President. In order to predict the outcome of the election, a number of people, each selected at random and independently of the others, are asked their choice. The predicted percentage pXp_{X} of votes for a each candidate X∈{A,B,C}X \in \{ A, B, C\} is worked out by dividing the number of people in the sample who are going to vote for XX by the total number of people in the sample. How many people need to be in the sample to substantiate the following claim: For each candidate XX, the probability that the predicted percentage pXp_{X} is correct to within 1%1 \% is at least 0.95?

What sample size will make it possible to make the same claim if there are just two candidates? And when there are nn candidates? (Exclude n=1n=1, even though this case is not uncommon in certain political systems.)

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Problem 12.23

Suppose that a sample consisting of nn men is used in the survey described in Problem 7.22 to establish the likelihood of being a bathroom singer. Each person is asked to toss a die and answer YES or NO. The probability P(Y)\mathbb {P}\left(Y\right) of answering YES is estimated by the average number PnYP_{n} Y of YES answers (that is, the number of YES answers divided by nn ). Because P(Y)\mathbb {P}\left(Y\right) is connected with the probability P(S)\mathbb {P}\left(S\right) of being a bathroom singer by P(Y)=16+23P(S)\mathbb {P}\left(Y\right)=\frac{1}{6}+\frac{2}{3} \mathbb {P}\left(S\right) (see Solution 7.22), the estimate PnSP_{n} S of P(S)\mathbb {P}\left(S\right) is then computed from the formula

PnY=16+23PnS P_{n} Y=\frac{1}{6}+\frac{2}{3} P_{n} S

Estimate the probability that PnSP_{n} S differs from P(S)\mathbb {P}\left(S\right) by more than ε>0\varepsilon >0. Then, find how large a sample is needed to make sure that PnSP_{n} S differs from P(S)\mathbb {P}\left(S\right) by no more than 0.01 with probability at least 0.95 ? Compare this to the sample size needed when the survey question is answered directly without tossing a die.

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