Section 8.2

Problems to Solve

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Problem 8.3

Prove that the operator A−1A^{-1}, which is the inverse to the linear operator AA, is also linear.

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Problem 8.4

Let X=CmX = \mathbb {C}^{m} endowed with any norm. Prove that for a linear operator AA : X→XX \rightarrow X the following statements are equivalent:

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(1)

Ker⁡A={0}\operatorname {Ker} A = \left\{ 0\right\}.

(2)

The operator AA has an algebraic inverse.

(3)

The operator AA has a continuous inverse.

(4)

The matrix which represents the operator AA is nondegenerate.

(5)

The equation Ax=yA x = y has a solution for every y∈Xy \in X.

Problem 8.5

Let A∈L(l2)A \in \mathcal{L}\left(l_{2}\right) be defined by the formula Ax=(x1,x22,…,xnn,…),x∈l2A x = \left(x_{1}, \frac{x_{2}}{2}, \ldots , \frac{x_{n}}{n}, \ldots \right), x \in l_{2}. Prove that the range R(A)R(A) is not a closed set in l2l_{2}.

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Problem 8.6

Let XX be a Banach space, A∈L(X),∥A∥<1A \in \mathcal{L}(X),\left\| A\right\| < 1. Prove that the operator I+AI+A is continuously invertible, and find (I+A)−1(I+A)^{-1}.

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Problem 8.7

Let XX be an NLS, A,B∈L(X)A, B \in \mathcal{L}(X) are continuously invertible. Prove that the operator ABA B is continuously invertible and (AB)−1=B−1A−1(A B)^{-1} = B^{-1} A^{-1}.

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Problem 8.8
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(1)

Let XX be a Banach space, A,B∈L(X),AA, B \in \mathcal{L}(X), A is continuously invertible with continuous inverse operator A−1,∥B∥<∥A−1∥−1A^{-1},\left\| B\right\| < \left\| A^{-1}\right\|^{-1}. Prove that A+BA+B is continuously invertible, and find (A+B)−1(A+B)^{-1}.

(2)

Prove that the set of continuously invertible operators is open in L(X)\mathcal{L}(X).

Problem 8.9

Let XX be an NLS. Prove that the operator A∈L(X)A \in \mathcal{L}(X) is continuously invertible if and only if A2A^{2} is continuously invertible.

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Problem 8.10

Denote by X0X_{0} and X1X_{1} the space {x∈C1([0,1])∣x(0)=0}\left\{ x \in C^{1}(\left[0,1\right]) \mid x(0) = 0\right\} endowed with norms ∥x∥0=max⁡t∈[0,1]∣x(t)∣\left\| x\right\|_{0} = \max_{t \in [0,1]}\left|x(t)\right| and ∥x∥1=max⁡t∈[0,1]∣x(t)∣+max⁡t∈[0,1]∣x′(t)∣\left\| x\right\|_{1} = \max_{t \in [0,1]}\left|x(t)\right|+\max_{t \in [0,1]}\left|x^{\prime }(t)\right|, respectively.

Let Ai:C([0,1])→Xi,(Aix)(t)=∫0tx(s)ds,i=0,1A_{i}: C(\left[0,1\right]) \rightarrow X_{i},\left(A_{i} x\right)(t) = \int_{0}^{t} x(s) d s, i = 0,1. Find Ai−1A_{i}^{-1}. Prove that A1−1A_{1}^{-1} is continuous, and A0−1A_{0}^{-1} is not bounded.

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Problem 8.11

Let X1X_{1} be the space from problem 8.10∘8.10^{\circ }. Prove that each of the following operators A:X1→C([0,1])A: X_{1} \rightarrow C(\left[0,1\right]) is continuously invertible, and find A−1A^{-1}.

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(1)

(Ax)(t)=2x′(t)−3x(t)(A x)(t) = 2 x^{\prime }(t)-3 x(t);

(2)

(Ax)(t)=x′(t)−tx(t)(A x)(t) = x^{\prime }(t)-t x(t);

(3)

(Ax)(t)=x′(t)+etx(t)(A x)(t) = x^{\prime }(t)+e^{t} x(t);

(4)

(Ax)(t)=x′(t)+2t2x(t)(A x)(t) = x^{\prime }(t)+2 t^{2} x(t);

(5)

(Ax)(t)=etx′(t)−2tx(t);(A x)(t) = e^{t} x^{\prime }(t)-2 t x(t) ;

(6)

(Ax)(t)=(t+1)x′(t)+tx(t)(A x)(t) = (t+1) x^{\prime }(t)+t x(t);

(7)

(Ax)(t)=x′(t)+α(t)x(t)(A x)(t) = x^{\prime }(t)+\alpha (t) x(t), α∈C([0,1])\alpha \in C(\left[0,1\right]).

Problem 8.12

Let K(t,s)=f(t)g(s)K(t, s) = f(t) g(s), where f,g∈C([0,1])f, g \in C(\left[0,1\right]) and ∫01f(t)g(t)dt≠1\int_{0}^{1} f(t) g(t) d t \neq 1. Prove that the operator A:C([0,1])→C([0,1])A: C(\left[0,1\right]) \rightarrow C(\left[0,1\right]), where

(Ax)(t)=x(t)−∫01K(t,s)x(s)ds,t∈[0,1] (A x)(t) = x(t)-\int _{0}^{1} K(t, s) x(s) d s, t \in [0,1]

is continuously invertible. Find A−1A^{-1}.

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Problem 8.13

Let K(t,s)=f(t)g(s)K(t, s) = f(t) g(s), where f,g∈C([0,1])f, g \in C(\left[0,1\right]). Prove that the operator A:C([0,1])→C([0,1])A: C(\left[0,1\right]) \rightarrow C(\left[0,1\right]), where (Ax)(t)=x(t)−∫0tK(t,s)x(s)ds,t∈[0,1](A x)(t) = x(t)-\int_{0}^{t} K(t, s) x(s) d s, t \in [0,1], is continuously invertible. Find A−1A^{-1}.

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Problem 8.14

In the space C([0,1])C(\left[0,1\right]) the operators AA and BB are defined by the formulas (Ax)(t)=(t+1)x(t),(Bx)(t)=x(t2),t∈[0,1](A x)(t) = (t+1) x(t),(B x)(t) = x\left(t^{2}\right), t \in [0,1]. Find (AB)−1(A B)^{-1} and (BA)−1(B A)^{-1}.

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Problem 8.15

Let XX be an NLS, A,BA∈L(X)A, B A \in \mathcal{L}(X) be continuously invertible. Prove that the operator BB is also continuously invertible.

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Problem 8.16

Let XX be an NLS, A,B∈L(X)A, B \in \mathcal{L}(X).

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(1)

Let (I−AB)−1∈L(X)(I-A B)^{-1} \in \mathcal{L}(X). Prove that (I−BA)−1∈L(X)(I-B A)^{-1} \in \mathcal{L}(X).

(2)

Prove that the property (AB)−1∈L(X)(A B)^{-1} \in \mathcal{L}(X) does not imply that (BA)−1(B A)^{-1} exists.

Problem 8.17

Let XX be an NLS, A,B∈L(X)A, B \in \mathcal{L}(X).

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(1)

Let the operators ABA B and BAB A have algebraic inverses. Does it imply that the operators AA and BB have algebraic inverses?

(2)

Let the operators ABA B and BAB A be continuously invertible. Does it imply that the operators AA and BB are continuously invertible?

Problem 8.18

Let XX be an NLS. Prove that if for an operator A∈L(X)A \in \mathcal{L}(X) there exists a sequence {xn:n≥1}⊂X\left\{ x_{n}: n \geq 1\right\} \subset X such that ∥xn∥=1\left\| x_{n}\right\| = 1 and Axn→0,n→∞A x_{n} \rightarrow 0, n \rightarrow \infty, then AA is not continuously invertible.

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Problem 8.19

Prove that the operator A:C([0,1])→C([0,1])A: C(\left[0,1\right]) \rightarrow C(\left[0,1\right]), defined by the formula (Ax)(t)=α(t)x(t),α∈C([0,1])(A x)(t) = \alpha (t) x(t), \alpha \in C(\left[0,1\right]), is continuously invertible if and only if α(t)≠0,t∈[0,1]\alpha (t) \neq 0, t \in [0,1].

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Problem 8.20

Let the operators Ai:C([0,1])→Ci([0,1]),i=0,1A_{i}: C(\left[0,1\right]) \rightarrow C^{i}(\left[0,1\right]), i = 0,1, be defined by the formula (Aix)(t)=∫0tet−sx(s)ds\left(A_{i} x\right)(t) = \int_{0}^{t} e^{t-s} x(s) d s. For each of the cases i=0,1i = 0,1 answer the following questions:

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(1)

Does Ai−1A_{i}^{-1} exist?

(2)

Is Ai−1A_{i}^{-1} continuous on its domain?

(3)

Is AiA_{i} continuously invertible?

Problem 8.21

Let A,B:C([−1,1])→C([−1,1])A, B: C(\left[-1,1\right]) \rightarrow C(\left[-1,1\right]), where (Ax)(t)=x(t2),(Bx)(t)=x(t3),t∈[−1,1](A x)(t) = x\left(t^{2}\right),(B x)(t) = x\left(t^{3}\right), t \in [-1,1]. Prove that A−1A^{-1} does not exist, while BB is continuously invertible. Find B−1B^{-1}.

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Problem 8.22

Let X2={x∈C2([0,1]):x(0)=x(1)=0}X_{2} = \left\{ x \in C^{2}(\left[0,1\right]): x(0) = x(1) = 0\right\} with a norm ∥x∥2=∑k=02max⁡t∈[0,1]∣x(k)(t)∣\left\| x\right\|_{2} = \sum_{k = 0}^{2} \max_{t \in [0,1]}\left|x^{(k)}(t)\right|, The operator A:X2→C([0,1])A: X_{2} \rightarrow C(\left[0,1\right]) is defined by the formula (Ax)(t)=x′′(t)−4x(t),t∈[0,1](A x)(t) = x^{\prime \prime }(t)-4 x(t), t \in [0,1]. Find A−1A^{-1} and prove that AA is continuously invertible.

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Problem 8.23

Let X3={x∈C3([0,1]):x(0)=x′(0)=x′′(0)=0},∥x∥3=∑k=03max⁡t∈[0,1]∣x(k)(t)∣X_{3} = \left\{ x \in C^{3}(\left[0,1\right]) \quad : \quad x(0) = x^{\prime }(0) = x^{\prime \prime }(0) = 0\right\} ,\left\| x\right\|_{3} = \sum_{k = 0}^{3} \max_{t \in [0,1]}\left|x^{(k)}(t)\right|, the operator A:X3→C([0,1])A: X_{3} \rightarrow C(\left[0,1\right]) is defined by the formula (Ax)(t)=x′′′(t)−x′′(t),t∈[0,1](A x)(t) = x^{\prime \prime \prime }(t)-x^{\prime \prime }(t), t \in [0,1]. Find A−1A^{-1} and prove that AA is continuously invertible.

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Problem 8.24

Is the operator A:l2→l2A: l_{2} \rightarrow l_{2} continuously invertible if

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(1)

Ax=(x1,x3,x2,x4,x5,…)A x = \left(x_{1}, x_{3}, x_{2}, x_{4}, x_{5}, \ldots \right);

(2)

Ax=(x1+x2,x2−x3,x3,x4,…)A x = \left(x_{1}+x_{2}, x_{2}-x_{3}, x_{3}, x_{4}, \ldots \right);

(3)

Ax=(x1+x2,x3,2x1+2x2,x4,…)A x = \left(x_{1}+x_{2}, x_{3}, 2 x_{1}+2 x_{2}, x_{4}, \ldots \right);

(4)

Ax=(0,x1,x2,…)A x = \left(0, x_{1}, x_{2}, \ldots \right);

(5)

Ax=(x2,x3,x4,x5,…)A x = \left(x_{2}, x_{3}, x_{4}, x_{5}, \ldots \right);

(6)

Ax=(x1−x2,x2,x3,…)A x = \left(x_{1}-x_{2}, x_{2}, x_{3}, \ldots \right);

(7)

Ax=(x1+x2+x3,x1−x2+x3,x1+x2−x3,x4,x5,…)A x = \left(x_{1}+x_{2}+x_{3}, x_{1}-x_{2}+x_{3}, x_{1}+x_{2}-x_{3}, x_{4}, x_{5}, \ldots \right)?

Find the operator A−1A^{-1}, if it exists.

Problem 8.25

Let A:C([0,1])→C([0,1]),(Ax)(t)=∫01(ts+t2s2)x(s)dsA: C(\left[0,1\right]) \rightarrow C(\left[0,1\right]),(A x)(t) = \int_{0}^{1}\left(t s+t^{2} s^{2}\right) x(s) d s. Prove that the operator A−1A^{-1} does not exist.

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Problem 8.26

Let A:C([−1,1])→C([−1,1]),(Ax)(t)=12(x(t)+x(−t))A: C(\left[-1,1\right]) \rightarrow C(\left[-1,1\right]),(A x)(t) = \frac{1}{2}(x(t)+x(-t)). Does A−1A^{-1} exist?

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Problem 8.27

Let XX be a Banach space with respect to the norms ∥⋅∥1\left\| \cdot \right\|_{1} and ∥⋅∥2\left\| \cdot \right\|_{2}. Assume that ∥⋅∥2\left\| \cdot \right\|_{2} can be estimated by ∥⋅∥1\left\| \cdot \right\|_{1}, i.e., there exists c>0c > 0 such that ∥x∥2≤c∥x∥1,x∈X\left\| x\right\|_{2} \leq c\left\| x\right\|_{1}, x \in X. Prove that the norms ∥⋅∥1\left\| \cdot \right\|_{1} and ∥⋅∥2\left\| \cdot \right\|_{2} are equivalent. Is the completeness of the space in both norms essential?

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Problem 8.28

What conditions on the function α∈C([a,b])\alpha \in C(\left[a, b\right]) imply that

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(1)

∥x∥α=max⁡a≤t≤bα(t)∣x(t)∣\left\| x\right\|_{\alpha } = \max_{a \leq t \leq b} \alpha (t)\left|x(t)\right| is a norm in C([a,b])C(\left[a, b\right])?

(2)

Convergence in the norm ∥x∥α\left\| x\right\|_{\alpha } is equivalent to the uniform convergence in C([a,b])C(\left[a, b\right])?

(3)

The space C([a,b])C(\left[a, b\right]) with the norm ∥x∥α\left\| x\right\|_{\alpha } is complete?

Problem 8.29

Let μ(T)<+∞,M\mu (T) < +\infty , M be a subspace of L2(T,μ)L_{2}(T, \mu ), and M⊂L∞(T,μ)M \subset L_{\infty }(T, \mu ). Prove that

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(1)

∃C>0∀x∈M:∥x∥∞≤C∥x∥2\exists C > 0 \forall x \in M:\left\| x\right\|_{\infty } \leq C\left\| x\right\|_{2};

(2)

dim⁡M<+∞\operatorname {dim} M < +\infty.

Problem 8.30

Let {en:n≥1}\left\{ e_{n}: n \geq 1\right\} be a Schauder basis in a Banach space XX with a norm ∥⋅∥\left\| \cdot \right\| (see problem 1.89). For x=∑i=1∞αi(x)eix = \sum_{i = 1}^{\infty } \alpha_{i}(x) e_{i} we put Pkx=∑i=1kαi(x)ei,k≥1P_{k} x = \sum_{i = 1}^{k} \alpha_{i}(x) e_{i}, k \geq 1, and ∣∣∣x∣∣∣=sup⁡k≥1∥Pkx∥,x∈X||| x ||| = \sup_{k \geq 1}\left\| P_{k} x \right\| , x \in X. Prove that

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(1)

(X,∣∣∣⋅∣∣∣)(X,|||\cdot |||) is a Banach space;

(2)

The norms ∣∣∣⋅∣∣∣|||\cdot ||| and ∥⋅∥\left\| \cdot \right\| are equivalent.

(3)

αi∈X∗,i≥1\alpha_{i} \in X^{*}, i \geq 1, and Pk∈L(X),k≥1P_{k} \in \mathcal{L}(X), k \geq 1, and there exists C>0C > 0 such that ∥Pk∥≤C\left\| P_{k}\right\| \leq C for all k≥1;k \geq 1 ;

(4)

∃C>0∀m>k∀λ1,…,λm∈K:∥∑i=1kλiei∥≤C∥∑i=1mλiei∥\exists C > 0 \forall m > k \forall \lambda_{1}, \ldots , \lambda_{m} \in \mathbb {K}:\left\| \sum_{i = 1}^{k} \lambda_{i} e_{i}\right\| \leq C\left\| \sum_{i = 1}^{m} \lambda_{i} e_{i}\right\|.

Problem 8.31

Let {en:n≥1}\left\{ e_{n}: n \geq 1\right\} be a Schauder basis in a Banach space XX.

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(1)

Prove that a sequence {xn=∑i=1∞αi(xn)ei:n≥1}⊂X\left\{ x_{n} = \sum_{i = 1}^{\infty } \alpha_{i}\left(x_{n}\right) e_{i}: n \geq 1\right\} \subset X converges to x=∑i=1∞αi(x)eix = \sum_{i = 1}^{\infty } \alpha_{i}(x) e_{i} in XX if and only if the following conditions are fulfilled:

(a) ∀i≥1:αi(xn)→αi(x),n→∞;\forall i \geq 1: \alpha_{i}\left(x_{n}\right) \rightarrow \alpha_{i}(x), n \rightarrow \infty ;

(b) sup⁡n≥1∥∑i=k+1∞αi(xn)ei∥→0,k→∞\sup_{n \geq 1}\left\| \sum_{i = k+1}^{\infty } \alpha_{i}\left(x_{n}\right) e_{i}\right\| \rightarrow 0, k \rightarrow \infty.

(2)

Derive from item (1) the convergence criterion in lp,1≤p<+∞l_{p}, 1 \leq p < +\infty.

Problem 8.32

Let {en:n≥1}\left\{ e_{n}: n \geq 1\right\} be a Schauder basis in a Banach space X,∥en∥=1,n≥1X,\left\| e_{n}\right\| = 1, n \geq 1, sup⁡n≥1∥Pn∥=C<+∞\sup_{n \geq 1}\left\| P_{n}\right\| = C < +\infty, where Pnx=∑i=1nαi(x)eiP_{n} x = \sum_{i = 1}^{n} \alpha_{i}(x) e_{i} for x=∑i=1∞αi(x)eix = \sum_{i = 1}^{\infty } \alpha_{i}(x) e_{i}. Prove that any sequence {vn:n≥1}⊂X\left\{ v_{n}: n \geq 1\right\} \subset X such that ∑n≥1∥en−vn∥<12C\sum_{n \geq 1}\left\| e_{n}-v_{n}\right\| < \frac{1}{2 C} is also a Schauder basis in XX.

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