Chapter 7

Stochastic Processes

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Problem 36.1

↑\uparrow Suppose that [Xt:t∈T]\left[X_{t}: t \in T\right] is a stochastic process on (Ω,F,P)(\Omega , \mathscr {F}, P) and A∈FA \in \mathscr {F}. Show that there is a countable subset SS of TT for which P[A∥Xt,t∈T]=P[A∥Xt,t∈S]P\left[A \| X_{t}, t \in T\right]= P\left[A \| X_{t}, t \in S\right] with probability 1. Replace AA by a random variable and prove a similar result.

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Problem 36.2

Let TT be arbitrary and let K(s,t)K(s, t) be a real function over T×TT \times T. Suppose that KK is symmetric in the sense that K(s,t)=K(t,s)K(s, t)=K(t, s) and nonnegative-definite in the sense that ∑i,j=1kK(ti,tj)xixj≥0\sum_{i, j=1}^{k} K\left(t_{i}, t_{j}\right) x_{i} x_{j} \geq 0 for k≥1,t1,…,tkk \geq 1, t_{1}, \ldots , t_{k} in TT, and x1,…,xkx_{1}, \ldots , x_{k} real. Show that there exists a process [Xt:t∈T]\left[X_{t}: t \in T\right] for which (Xt1,…,Xtk)\left(X_{t_{1}}, \ldots , X_{t_{k}}\right) has the centered normal distribution with covariances K(ti,tj),i,j=1,…,kK\left(t_{i}, t_{j}\right), i, j=1, \ldots , k.

*This topic may be omitted.

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Problem 36.3

Let LL be a Borel set on the line, let L\mathscr {L} consist of the Borel subsets of LL, and let LTL^{T} consist of all maps from TT into LL. Define the appropriate notion of cylinder, and let LT\mathscr {L}^{T} be the σ\sigma-field generated by the cylinders. State a version of Theorem 36.1 for (LT,LT)\left(L^{T}, \mathscr {L}^{T}\right). Assume TT countable, and prove this theorem not by imitating the previous proof but by observing that LTL^{T} is a subset of RTR^{T} and lies in RT\mathscr {R}^{T}.

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Problem 36.4

Suppose that the random variables X1,X2,…X_{1}, X_{2}, \ldots assume the values 0 and 1 and P[Xn=1P\left[X_{n}=1\right. i.o. ]=1]=1. Let μ\mu be the distribution over ( 0,1 ] of ∑n=1∞Xn/2n\sum_{n=1}^{\infty } X_{n} / 2^{n}. Show that on the unit interval with the measure μ\mu, the digits of the nonterminating dyadic expansion form a stochastic process with the same finite-dimensional distributions as X1,X2,…X_{1}, X_{2}, \ldots.

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Problem 36.5

36.3 ↑ There is an infinite-dimensional version of Fubini's theorem. In the construction in Problem 36.3, let L=I=(0,1),T={1,2,…}L=I=(0,1), T=\left\{ 1,2, \ldots \right\}, let I\mathscr {I} consist of the Borel subsets of II, and suppose that each kk-dimensional distribution is the kk-fold product of Lebesgue measure over the unit interval. Then ITI^{T} is a countable product of copies of ( 0,1 ), its elements are sequences x=(x1,x2,…)x=\left(x_{1}, x_{2}, \ldots \right) of points of ( 0,1 ), and Kolmogorov's theorem ensures the existence on (IT,AT)(I^{T}, \mathscr {A}^{T}) of a product probability measure π:π[x:xi≤αi,i≤n]=α1⋯αn\pi : \pi \left[x: x_{i} \leq \alpha_{i}, i \leq n\right]=\alpha_{1} \cdots \alpha_{n} for 0≤αi≤10 \leq \alpha_{i} \leq 1. Let InI^{n} denote the nn-dimensional unit cube.

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(a)

Define ψ:In×IT→IT\psi : I^{n} \times I^{T} \rightarrow I^{T} by

ψ((x1,…,xn),(y1,y2,…))=(x1,…,xn,y1,y2,…). \psi \left(\left(x_{1}, \ldots , x_{n}\right),\left(y_{1}, y_{2}, \ldots \right)\right)=\left(x_{1}, \ldots , x_{n}, y_{1}, y_{2}, \ldots \right).

Show that ψ\psi is measurable In×IT/IT\mathscr {I}^{n} \times \mathscr {I}^{T} / \mathscr {I}^{T} and ψ−1\psi^{-1} is measurable IT/In×IT\mathscr {I}^{T} / \mathscr {I}^{n} \times \mathscr {I}^{T}. Show that ψ−1(λn×π)=π\psi^{-1}\left(\lambda_{n} \times \pi \right)=\pi, where λn\lambda_{n} is nn-dimensional Lebesgue measure restricted to InI^{n}.

(b)

Let ff be a furiction measurable IT\mathscr {I}^{T} and, for simplicity, bounded. Define

fn(xn+1,xn+2,…)=∫01⋯∫01f(y1,…,yn,xn+1,…)dy1⋯dyn f_{n}\left(x_{n+1}, x_{n+2}, \ldots \right)=\int _{0}^{1} \cdots \int _{0}^{1} f\left(y_{1}, \ldots , y_{n}, x_{n+1}, \ldots \right) d y_{1} \cdots d y_{n}

in other words, integrate out the coordinates one by one. Show by Problem 34.18, martingale theory, and the zero-one law that

fn(xn+1,xn+2,…)→∫If(y)π(dy)(36.30) f_{n}\left(x_{n+1}, x_{n+2}, \ldots \right) \rightarrow \int _{I} f(y) \pi (d y) \tag {36.30}

except for xx in a set of π\pi-measure 0.

(c)

Adopting the point of view of part (a), let gn(x1,…,xn)g_{n}\left(x_{1}, \ldots , x_{n}\right) be the result of integrating the variable (yn+1,yn+2,…)\left(y_{n+1}, y_{n+2}, \ldots \right) out (with respect to π\pi ) from f(x1,…,xn,yn+1,…)f\left(x_{1}, \ldots , x_{n}, y_{n+1}, \ldots \right). This may suggestively be written as

gn(x1,…,xn)=∫01∫01⋯f(x1,…,xn,yn+1,yn+2,…)dyn+1dyn+2⋯ g_{n}\left(x_{1}, \ldots , x_{n}\right)=\int _{0}^{1} \int _{0}^{1} \cdots f\left(x_{1}, \ldots , x_{n}, y_{n+1}, y_{n+2}, \ldots \right) d y_{n+1} d y_{n+2} \cdots

Show that gn(x1,…,xn)→f(x1,x2,…)g_{n}\left(x_{1}, \ldots , x_{n}\right) \rightarrow f\left(x_{1}, x_{2}, \ldots \right) except for xx in a set of π\pi-measure 0.

Problem 36.6
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(a)

Let TT be an interval of the line. Show that RT\mathscr {R}^{T} fails to contain the sets of: linear functions, polynomials, constants, nondecreasing functions, functions of bounded variation, differentiable functions, analytic functions, functions con- tinuous at a fixed t0t_{0}, Borel measurable functions. Show that it fails to contain the set of functions that: vanish somewhere in TT, satisfy x(s)<x(t)x(s)<x(t) for some pair with s<ts<t, have a local maximum anywhere, fail to have a local maximum.

(b)

Let CC be the set of continuous functions on T=[0,∞)T=[0, \infty ). Show that A∈RrA \in \mathscr {R}^{r} and A⊂CA \subset C imply that A=∅A=\varnothing. Show, on the other hand, that A∈RTA \in \mathscr {R}^{T} and C⊂AC \subset A do not imply that A=RTA=R^{T}.

Problem 36.7

Not all systems of finite-dimensional distributions can be realized by stochastic processes for which Ω\Omega is the unit interval. Show that there is on the unit interval with Lebesgue measure no process [Xt:t≥0]\left[X_{t}: t \geq 0\right] for which the XtX_{t} are independent and assume the values 0 and 1 with probability 12\frac{1}{2} each. Compare Problem 1.1.

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Problem 36.8

Here is an application of the existence theorem in which TT is not a subset of the line. Let (N,N,ν)(N, \mathscr {N}, \nu ) be a measure space, and take TT to consist of the N\mathscr {N}-sets of finite ν\nu-measure. The problem is to construct a generalized Poisson process, a stochastic process [XA:A∈T]\left[X_{A}: A \in T\right] such that (i) XAX_{A} has the Poisson distribution with mean ν(A)\nu (A) and (ii) XA1,…,XAnX_{A_{1}}, \ldots , X_{A_{n}} are independent if A1,…,AnA_{1}, \ldots , A_{n} are disjoint. Hint: To define the finite-dimensional distributions, generalize this construction: For A,BA, B in TT, consider independent random variables Y1,Y2,Y3Y_{1}, Y_{2}, Y_{3} having Poisson distributions with means ν(A∩Bc),ν(A∩B),ν(Ac∩B)\nu \left(A \cap B^{c}\right), \nu (A \cap B), \nu \left(A^{c} \cap B\right), take μA,B\mu_{A, B} to be the distribution of (Y1+Y2,Y2+Y3)\left(Y_{1}+Y_{2}, Y_{2}+Y_{3}\right).

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Problem 37.1

36.2 ↑ Show that K(s,t)=min⁡{s,t}K(s, t)=\min \left\{ s, t\right\} is nonnegative-definite; use Problem 36.2 to prove the existence of a process with the finite-dimensional distributions prescribed for Brownian motion.

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Problem 37.2

Let X(t)X(t) be independent, standard normal variables, one for each dyadic rational tt (Theorem 20.4; the unit interval can be used as the probability space). Let W(0)=0W(0)=0 and W(n)=∑k=1nX(k)W(n)=\sum_{k=1}^{n} X(k). Suppose that W(t)W(t) is already defined for dyadic rationals of rank η\eta, and put

W(2k+12n+1)=12W(k2n)+12W(k+12n)+121+n/2X(2k+12n+1). W\left(\frac{2 k+1}{2^{n+1}}\right)=\frac{1}{2} W\left(\frac{k}{2^{n}}\right)+\frac{1}{2} W\left(\frac{k+1}{2^{n}}\right)+\frac{1}{2^{1+n / 2}} X\left(\frac{2 k+1}{2^{n+1}}\right).

Prove by induction that the W(t)W(t) for dyadic tt have the finite-dimensional distributions prescribed for Brownian motion. Now construct a Brownian motion with continuous paths by the argument leading to Theorem 37.1. This avoids an appeal to Kolmogorov's existence theorem.

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Problem 37.3

↑ For each nn define new variables Wn(t)W_{n}(t) by setting Wn(k/2n)=W(k/2n)W_{n}\left(k / 2^{n}\right)=W\left(k / 2^{n}\right) for dyadics of order nn and interpolating linearly in between. Set δn=sup⁡t≤n∣Wn+1(t)−Wn(t)∣\delta_{n}= \sup_{t \leq n}\left|W_{n+1}(t)-W_{n}(t)\right|, and show that

δn=max⁡0≤k<n2n∣W(2k+12n+1)−[12W(k2n)+12W(k+12n)]∣. \delta _{n}=\max _{0 \leq k<n 2^{n}}\left|W\left(\frac{2 k+1}{2^{n+1}}\right)-\left[\frac{1}{2} W\left(\frac{k}{2^{n}}\right)+\frac{1}{2} W\left(\frac{k+1}{2^{n}}\right)\right]\right|.

The construction in the preceding problem makes it clear that the difference here is normal with variance 1/2n+21 / 2^{n+2}. Find positive xnx_{n} such that ∑xn\sum x_{n} and ∑P(δn≥xn)\sum \mathbb {P}\left(\delta_{n} \geq x_{n}\right) both converge, and conclude that outside a set of probability 0, Wn(t,ω)W_{n}(t, \omega ) converges uniformly over bounded intervals. Replace W(t,ω)W(t, \omega ) by lim⁡nWn(t,ω)\lim_{n} W_{n}(t, \omega ). This gives another construction of a Brownian motion with continuous paths.

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Problem 37.4

36.6 ↑ Let T=[0,∞)T=[0, \infty ), and let PP be a probability measure on (RT,RT)(R^{T}, \mathscr {R}^{T}) having the finite-dimensional distributions prescribed for Brownian motion. Let CC consist of the continuous elements of RTR^{T}.

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(a)

Show that P∗(C)=0P_{*}(C)=0, or P∗(RT−C)=1P^{*}\left(R^{T}-C\right)=1 (see (3.9) and (3.10)). Thus completing (RT,RT,P)(R^{T}, \mathscr {R}^{T}, P) will not give CC probability 1.

(b)

Show that P∗(C)=1P^{*}(C)=1.

Problem 37.5

Suppose that [Wt:t≥0]\left[W_{t}: t \geq 0\right] is some stochastic process having independent, stationary increments satisfying E[Wt]=0\mathbb {E}\left[W_{t}\right]=0 and E[Wt2]=t\mathbb {E}\left[W_{t}^{2}\right]=t. Show that if the finite-dimensional distributions are preserved by the transformation (37.11), then they must be those of Brownian motion.

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Problem 37.6

Show that ⋂t>0σ[Ws:s≥t]\bigcap_{t>0} \sigma \left[W_{s}: s \geq t\right] contains only sets of probability 0 and 1. Do the same for ⋂ϵ>0σ[Wt:0<t<ϵ]\bigcap_{\epsilon >0} \sigma \left[W_{t}: 0<t<\epsilon \right]; give examples of sets in this σ\sigma-field.

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Problem 37.7

Show by a direct argument that W(⋅,ω)W(\cdot , \omega ) is with probability 1\mathbf{1} of unbounded variation on [0,1][0,1] : Let Yn=∑i=12n∣W(i2−n)−W((i−1)2−n)∣Y_{n}=\sum_{i=1}^{2^{n}}\left|W\left(i 2^{-n}\right)-W\left((i-1) 2^{-n}\right)\right|. Show that YnY_{n} has mean 2n/2E[∣W1∣]2^{n / 2} \mathbb {E}\left[\left|W_{1}\right|\right] and variance at most Var⁡[∣W1∣]\operatorname {Var}\left[\left|W_{1}\right|\right]. Conclude that ∑P(Yn<n)<∞\sum \mathbb {P}\left(Y_{n}<n\right)<\infty.

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Problem 37.8

Show that the Poisson process as defined by ( 23.5 ) is measurable.

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Problem 37.9

Show that for T=[0,∞)T=[0, \infty ) the coordinate-variable process [Zt:t∈T]\left[Z_{t}: t \in T\right] on (RT,RT)\left(R^{T}, \mathscr {R}^{T}\right) is not measurable.

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Problem 37.10

Extend Theorem 37.4 to the set [t:W(t,ω)=α][t: W(t, \omega )=\alpha ].

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Problem 37.11

Let τα\tau_{\alpha } be the first time the Brownian motion hits α>0:τα=inf⁡[t:Wt≥α]\alpha >0: \tau_{\alpha }=\inf \left[t: W_{t} \geq \alpha \right]. Show that the distribution of τα\tau_{\alpha } has over (0,∞)(0, \infty ) the density

hα(t)=α2π1t3/2e−α2/2t.(37.46) h_{\alpha }(t)=\frac{\alpha }{\sqrt{2 \pi }} \frac{1}{t^{3 / 2}} e^{-\alpha ^{2} / 2 t}. \tag {37.46}

Show that E[τα]=∞\mathbb {E}\left[\tau_{\alpha }\right]=\infty. Show that τα\tau_{\alpha } has the same distribution as α2/N2\alpha^{2} / N^{2}, where NN is a standard normal variable.

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Problem 37.12
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(a)

↑\uparrow Show by the strong Markov property that τα\tau_{\alpha } and τα+β−τα\tau_{\alpha +\beta }-\tau_{\alpha } are independent and that the latter has the same distribution as τβ\tau_{\beta }. Conclude that hα∗hβ=hα+βh_{\alpha } * h_{\beta }=h_{\alpha +\beta }. Show that βτα\beta \tau_{\alpha } has the same distribution as ταβ\tau_{\alpha \sqrt{\beta }}.

(b)

Show that each hαh_{\alpha } is stable-see Problem 28.10.

Problem 37.13

↑\uparrow Suppose that X1,X2,…X_{1}, X_{2}, \ldots are independent and each has the distribution (37.46).

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(a)

Show that (X1+⋯+Xn)/n2\left(X_{1}+\cdots +X_{n}\right) / n^{2} also has the distribution (37.46). Contrast this with the law of large numbers.

(b)

Show that P(n−2max⁡k≤nXk≤x)→exp⁡(−α2/πx)\mathbb {P}\left(n^{-2} \max_{k \leq n} X_{k} \leq x\right) \rightarrow \exp (-\alpha \sqrt{2 / \pi x}) for x>0x>0. Relate this to Theorem 14.3.

Problem 37.14

37.11↑37.11 \uparrow Let ρ(s,t)\rho (s, t) be the probability that a Brownian path has at least one zero in (s,t)(s, t). From (37.46) and the Markov property deduce

ρ(s,t)=2πarccos⁡st.(37.47) \rho (s, t)=\frac{2}{\pi } \arccos \sqrt{\frac{s}{t}}. \tag {37.47}

Hint: Condition with respect to WsW_{s}.

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Problem 37.15

↑\uparrow

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(a)

Show that the probability of no zero in (t,1)(t, 1) is (2/π)arcsin⁡t(2 / \pi ) \arcsin \sqrt{t} and hence that the position of the last zero preceding 1 is distributed over (0,1)(0,1) with density π−1(t(1−t))−1/2\pi^{-1}(t(1-t))^{-1 / 2}.

(b)

Similarly calculate the distribution of the position of the first zero following time 1.

(c)

Calculate the joint distribution of the two zeros in (a) and (b).

Problem 37.16
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(a)

Show by Theorem 37.8 that inf⁡s≤u≤tYn(u)\inf_{s \leq u \leq t} Y_{n}(u) and inf⁡s≤u≤tZn(u)\inf_{s \leq u \leq t} Z_{n}(u) both converge in distribution to inf⁡s≤u≤tW(u)\inf_{s \leq u \leq t} W(u) for 0≤s≤t≤10 \leq s \leq t \leq 1. Prove a similar result for the supremum.

(b)

Let An(s,t)A_{n}(s, t) be the event that SkS_{k}, the position at time kk in a symmetric random walk, is 0 for at least one kk in the range sn≤k≤tns n \leq k \leq t n, and show that P(An(s,t))→(2/π)arccos⁡s/t\mathbb {P}\left(A_{n}(s, t)\right) \rightarrow (2 / \pi ) \arccos \sqrt{s / t}.

(c)

Let TnT_{n} be the maximum kk such that k≤nk \leq n and Sk=0S_{k}=0. Show that Tn/nT_{n} / n has asymptotically the distribution with density π−1(t(1−t))−1/2\pi^{-1}(t(1-t))^{-1 / 2} over (0,1)(0,1). As this density is larger at the ends of the interval than in the middle, the last time during a night's play a gambler was even is more likely to be either early or late than to be around midnight.

Problem 37.17

↑\uparrow Show that ρ(s,t)=ρ(t−1,s−1)=ρ(cs,ct)\rho (s, t)=\rho \left(t^{-1}, s^{-1}\right)=\rho (c s, c t). Check this by (37.47) and also by the fact that the transformations (37.11) and (37.12) preserve the properties of Brownian motion.

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Problem 37.18

Deduce by the reflection principle that (Mt,Wt)(M_{t}, W_{t}) has density

2(2y−x)t2πtexp⁡[−(2y−x)22t] \frac{2(2 y-x)}{t \sqrt{2 \pi t}} \exp \left[-\frac{(2 y-x)^{2}}{2 t}\right]

on the set where y≥0y \geq 0 and y≥xy \geq x. Now deduce from Theorem 37.8 the corresponding limit theorem for symmetric random walk.

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Problem 37.19

Show by means of the transformation (37.12) that for positive aa and bb the probability is 1 that the process is within the boundary −at<W1<bt-a t<W_{1}<b t for all sufficiently large tt. Show that a/(a+b)a /(a+b) is the probability that it last touches above rather than below.

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Problem 37.20

The martingale calculation used for (37.39) also works for slanting boundaries. For positive a,b,ra, b, r, let τ\tau be the smallest tt such that either Wt=−a+rtW_{t}=-a+r t or Wt=b+rtW_{t}=b+r t, and let p(a,b,r)p(a, b, r) be the probability that the exit is through the upper barrier-that Wτ=b+rτW_{\tau }=b+r \tau.

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(a)

For the martingale Yθ,tY_{\theta , t} in the proof of Lemma 2, show that E[Yθ,t]=1\mathbb {E}\left[Y_{\theta , t}\right]=1. Operating formally at first, conclude that

E[eθWτ−θ2τ/2]=1(37.48) \mathbb {E}\left[e^{\theta W_{\tau }-\theta ^{2} \tau / 2}\right]=1 \tag {37.48}

Take θ=2r\theta =2 r, and note that θWτ−12θ2τ\theta W_{\tau }-\frac{1}{2} \theta^{2} \tau is then 2rb2 r b if the exit is above (probability p(a,b,r)p(a, b, r) ) and −2ra-2 r a if the exit is below (probability 1−p(a,b,r)1-p(a, b, r) ). Deduce

p(a,b,r)=1−e2rae2rb−e−2ra p(a, b, r)=\frac{1-e^{2 r a}}{e^{2 r b}-e^{-2 r a}}
(b)

Show that p(a,b,r)→a/(a+b)p(a, b, r) \rightarrow a /(a+b) as r→0r \rightarrow 0, in agreement with (37.39).

(c)

It remains to justify (37.48) for θ=2r\theta =2 r. From E[Yθ,t]=1\mathbb {E}\left[Y_{\theta , t}\right]=1 deduce

E[e2r(Wσ−r2σ)]=1(37.49) \mathbb {E}\left[e^{2 r\left(W_{\sigma }-r^{2} \sigma \right)}\right]=1 \tag {37.49}

for nonrandom σ\sigma. By the arguments in the proofs of Lemmas 2 and 3, show that (37.49) holds for simple stopping times σ\sigma, for bounded ones, for σ=τ∧n\sigma =\tau \wedge n, for σ=τ\sigma =\tau.