Subsection 11.2

Determining the type and location of a surface given by a general equation of the second order (11.19-11.23)

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Problem 11.19

Using the result of problem 11. 18, determine the type of the surface given, in a general Cartesian coordinate system, by the equation:

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(1)

(x+y+z)(x−y+125z)=1(x + y + z)(x - y + 125z) = 1

(2)

(x+y)(x+y+1)=1(x + y)(x + y + 1) = 1

(3)

(x+y)(x+y+1)=x−y(x + y)(x + y + 1) = x - y

(4)

(x+y+z+1)(x−y+z)=x+z+1(x + y + z + 1)(x - y + z) = x + z + 1

(5)

(x+y+z+1)(x−y+z)=x+2z+1(x + y + z + 1)(x - y + z) = x + 2z + 1

(6)

(x+y)(x−y)=z(x + y)(x - y) = z

(7)

(x+y+z)(x−y+z)=0(x + y + z)(x - y + z) = 0

(8)

(x+2y)(x+2y+1)=z(x + 2y)(x + 2y + 1) = z

(9)

(x+y)(x−75y)=z2(x + y)(x - 75y) = z^{2}

(10)

(x+y)2=3x+z(x + y)^{2} = 3x + z

(11)

(x+2y+3z)(2x+3y+4z)+(3x+4y+75z)2=1(x + 2y + 3z)(2x + 3y + 4z) + (3x + 4y + 75z)^{2} = 1

(12)

(x+2y+3z)(2x+3y+4z)−(3x+4y+75z)2=1(x + 2y + 3z)(2x + 3y + 4z) - (3x + 4y + 75z)^{2} = 1

(13)

(x+y)z−x2−x=0(x + y) z - x^{2} - x = 0

(14)

(x+y+z)2+(x+2y+3z)2+(2x−y+z)2=0(x + y + z)^{2} + (x + 2y + 3z)^{2} + (2x - y + z)^{2} = 0

(15)

(x+y+z)2+(x+2y+3z)2+(2x+3y+4z)2=0(x + y + z)^{2} + (x + 2y + 3z)^{2} + (2x + 3y + 4z)^{2} = 0

(16)

(x+y+z)2+(x−2y+z)2=0(x + y + z)^{2} + (x - 2y + z)^{2} = 0

(17)

(x+y+z)2+(x+y)2+(y+z)2=1987(x + y + z)^{2} + (x + y)^{2} + (y + z)^{2} = 1987

(18)

(x+y+z)2+(x+y)2=1987(x + y + z)^{2} + (x + y)^{2} = 1987

(19)

(x+y+z)2+(x+y)2+(2x+2y+z)2=1(x + y + z)^{2} + (x + y)^{2} + (2x + 2y + z)^{2} = 1

(20)

(x+y)2+z2+1=0(x + y)^{2} + z^{2} + 1 = 0.

Problem 11.20

In a general Cartesian coordinate system a hyperboloid is given by the equation (x+y+z)(x−y+z)−(2x−y+2z)2=1(x + y + z)(x - y + z) - (2x - y + 2z)^{2} = 1. Find the equation of its asymptotic cone.

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Problem 11.21

A surface is given in a general Cartesian coordinate system by an equation containing a parameter kk. Determine the type of the surface for all values of kk.

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(1)

x12+x22+4x32+4x1x3+2x2x3+2x1+2x2+5x3+k=0x_{1}^{2} + x_{2}^{2} + 4x_{3}^{2} + 4x_{1} x_{3} + 2x_{2} x_{3} + 2x_{1} + 2x_{2} + 5x_{3} + k = 0

(2)

2x12+kx22+8x1x2+4x1x3−4x1−8x2−4x3=02x_{1}^{2} + kx_{2}^{2} + 8x_{1} x_{2} + 4x_{1} x_{3} - 4x_{1} - 8x_{2} - 4x_{3} = 0

(3)

3x12+2x22+2x32+4x1x2−2x1x3+4x1+4x2+4x3+k=03x_{1}^{2} + 2x_{2}^{2} + 2x_{3}^{2} + 4x_{1} x_{2} - 2x_{1} x_{3} + 4x_{1} + 4x_{2} + 4x_{3} + k = 0

(4)

kx12+8x22+x32+16x1x2+4x1x3+4x2x3−4x1−4x2+2x3=0kx_{1}^{2} + 8x_{2}^{2} + x_{3}^{2} + 16x_{1} x_{2} + 4x_{1} x_{3} + 4x_{2} x_{3} - 4x_{1} - 4x_{2} + 2x_{3} = 0

(5)

3x22+x32+6x1x2+2x1x3+4x2x3+kx2+x3+1=03x_{2}^{2} + x_{3}^{2} + 6x_{1} x_{2} + 2x_{1} x_{3} + 4x_{2} x_{3} + kx_{2} + x_{3} + 1 = 0

(6)

(р) x12−2x22−3x32−4x1x2−6x1x3−2x1+4x2+6x3+k=0x_{1}^{2} - 2x_{2}^{2} - 3x_{3}^{2} - 4x_{1} x_{2} - 6x_{1} x_{3} - 2x_{1} + 4x_{2} + 6x_{3} + k = 0.

Problem 11.22

A surface is given by an equation in a rectangular Cartesian coordinate system. Find the canonical coordinate system and the canonical equation of this surface. Determine the type of the surface.

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(1)

2x2+9y2+2z2−4xy+4yz−1=02x^{2} + 9y^{2} + 2z^{2} - 4xy + 4yz - 1 = 0

(2)

4y2−3z2+4xy−4xz+8yz=04y^{2} - 3z^{2} + 4xy - 4xz + 8yz = 0

(3)

x2+y2+4z2−2xy+4xz−4yz−2x+2y+2z=0x^{2} + y^{2} + 4z^{2} - 2xy + 4xz - 4yz - 2x + 2y + 2z = 0

(4)

x2+y2+z2−xy+xz+yz+3x+3y−3z=0x^{2} + y^{2} + z^{2} - xy + xz + yz + 3x + 3y - 3z = 0

(5)

x2−3z2−4yz−4y+2z+5=0x^{2} - 3z^{2} - 4yz - 4y + 2z + 5 = 0

(6)

x2+y2+z2−2xy−4x+4y+3=0x^{2} + y^{2} + z^{2} - 2xy - 4x + 4y + 3 = 0

(7)

y2+2xz+2x+2z+1=0y^{2} + 2xz + 2x + 2z + 1 = 0

(8)

x2+2y2+5z2+4yz+20y+20z−10=0x^{2} + 2y^{2} + 5z^{2} + 4yz + 20y + 20z - 10 = 0

(9)

−x2+5y2+5z2+8yz+2x+12y+24z+36=0- x^{2} + 5y^{2} + 5z^{2} + 8yz + 2x + 12y + 24z + 36 = 0

(10)

2x2+5y2+5z2+6yz+4x+16y+16z+10=02x^{2} + 5y^{2} + 5z^{2} + 6yz + 4x + 16y + 16z + 10 = 0

(11)

4x2+4y2−4xy−12x−12y−5z+1=04x^{2} + 4y^{2} - 4xy - 12x - 12y - 5z + 1 = 0

(12)

x2+y2+z2+2xy−12x+4y+6z−3=0x^{2} + y^{2} + z^{2} + 2xy - 12x + 4y + 6z - 3 = 0

(13)

4x2+9y2−12xy+2x+10y+1=04x^{2} + 9y^{2} - 12xy + 2x + 10y + 1 = 0

(14)

6xy−8y2−z2+60y+2z+89=06xy - 8y^{2} - z^{2} + 60y + 2z + 89 = 0

(15)

5x2+8y2+4xy+2x+44y−36z+65=05x^{2} + 8y^{2} + 4xy + 2x + 44y - 36z + 65 = 0

(16)

(р) −x2+y2+z2−2yz+2x+3y−5z+1=0- x^{2} + y^{2} + z^{2} - 2yz + 2x + 3y - 5z + 1 = 0

(17)

9y2+16z2+24yz+5x+10y+5z+11=09y^{2} + 16z^{2} + 24yz + 5x + 10y + 5z + 11 = 0

(18)

16x2+9y2−z2−24xy−9x−12y+4z+71=016x^{2} + 9y^{2} - z^{2} - 24xy - 9x - 12y + 4z + 71 = 0

(19)

2x2+2y2+z2−10xy+20x−8y+29=02x^{2} + 2y^{2} + z^{2} - 10xy + 20x - 8y + 29 = 0

(20)

−x2+7y2−24yz+2x+120y=0- x^{2} + 7y^{2} - 24yz + 2x + 120y = 0

(21)

x2−4y2−4z2+10yz+2x+2y+2z+3=0x^{2} - 4y^{2} - 4z^{2} + 10yz + 2x + 2y + 2z + 3 = 0

(22)

3x2+4xy+8x+8y−4z=03x^{2} + 4xy + 8x + 8y - 4z = 0

(23)

−x2−9y2+6xy+50x−50y−15z−100=0- x^{2} - 9y^{2} + 6xy + 50x - 50y - 15z - 100 = 0

(24)

(р) 4x2+y2+9z2+4xy−12xz−6yz+2x+6y−6z−5=04x^{2} + y^{2} + 9z^{2} + 4xy - 12xz - 6yz + 2x + 6y - 6z - 5 = 0.

Problem 11.23

A surface is given in a rectangular Cartesian coordinate system by an equation containing a parameter kk. For the given value of kk, find the canonical coordinate system and the canonical equation of the surface. Determine the type of the surface for all possible values of kk. If the surface is a line, a plane, or a pair of planes, find the linear equations of these sets in the original coordinate system.

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(1)

5x2+5y2+3z2+2xy+22xz+22yz+26x+34y+102z+49=05x^{2} + 5y^{2} + 3z^{2} + 2xy + 2\sqrt{2} xz + 2\sqrt{2} yz + 26x + 34y + 10\sqrt{2} z + 49 = 0;

(2)

2x2+9y2+2z2−4xy+4yz+4x+2y−4z−1=02x^{2} + 9y^{2} + 2z^{2} - 4xy + 4yz + 4x + 2y - 4z - 1 = 0

(3)

4y2−3z2+4xy−4xz+8yz+4x−2z+k=04y^{2} - 3z^{2} + 4xy - 4xz + 8yz + 4x - 2z + k = 0;

(1) k=−1k = - 1;

(2) k=5k = 5;

(3) k=11k = 11.

(4)

2x2+2y2+2z2+2xy+2xz+2yz+4x−4y+4=02x^{2} + 2y^{2} + 2z^{2} + 2xy + 2xz + 2yz + 4x - 4y + 4 = 0

(5)

3x2+3y2+3z2−2xy−2xz−2yz−8x+8y+k=03x^{2} + 3y^{2} + 3z^{2} - 2xy - 2xz - 2yz - 8x + 8y + k = 0

(1) k=4k = 4;

(2) k=8k = 8.

(6)

x2+y2+4z2−2xy+4xz−4yz−12x+12y−24z+6=0x^{2} + y^{2} + 4z^{2} - 2xy + 4xz - 4yz - 12x + 12y - 24z + 6 = 0

(7)

x2+y2+4z2−2xy+4xz−4yz+24y−24z+12=0x^{2} + y^{2} + 4z^{2} - 2xy + 4xz - 4yz + 24y - 24z + 12 = 0

(8)

x2+y2+4z2−2xy+4xz−4yz+5x+y−2z=0x^{2} + y^{2} + 4z^{2} - 2xy + 4xz - 4yz + 5x + y - 2z = 0

(9)

2x2+2y2+2z2−2xy+2xz+2yz−6x−6y−12z+k=02x^{2} + 2y^{2} + 2z^{2} - 2xy + 2xz + 2yz - 6x - 6y - 12z + k = 0

(1) k=15k = 15;

(2) k=18k = 18.

(10)

2x2+2y2+2z2−2xy+2xz+2yz+18z+18=02x^{2} + 2y^{2} + 2z^{2} - 2xy + 2xz + 2yz + 18z + 18 = 0;

(11)

x2+2y2+z2−2xy−2yz+6x−6y+k=0x^{2} + 2y^{2} + z^{2} - 2xy - 2yz + 6x - 6y + k = 0

(1) k=8k = 8;

(2) k=9k = 9.

(12)

x2+2y2+z2−2xy−2yz+18x−6y+6z−18=0x^{2} + 2y^{2} + z^{2} - 2xy - 2yz + 18x - 6y + 6z - 18 = 0

(13)

3x2−7y2+3z2+8xy−8yz−8xz−4x+6y+8z+k=03x^{2} - 7y^{2} + 3z^{2} + 8xy - 8yz - 8xz - 4x + 6y + 8z + k = 0;

(1) k=−12k = - 12;

(2) k=−3k = - 3;

(3) k=6k = 6.

(14)

2y2−3z2−23xy−4xz+43yz+50z+k=02y^{2} - 3z^{2} - 2\sqrt{3} xy - 4xz + 4\sqrt{3} yz + 50z + k = 0;

(1) k=−75k = - 75;

(2) k=−70k = - 70;

(3) k=−80k = - 80.

(15)

2x2+2y2+2z2+8xy+8xz−8yz−8x−4y+8z+k=02x^{2} + 2y^{2} + 2z^{2} + 8xy + 8xz - 8yz - 8x - 4y + 8z + k = 0;

(1) k=−4k = - 4;

(2) k=2k = 2;

(3) k=8k = 8.

(16)

4x2+4y2−2z2+4xy−8xz+8yz+12x−12y+24z+k=04x^{2} + 4y^{2} - 2z^{2} + 4xy - 8xz + 8yz + 12x - 12y + 24z + k = 0;

(1) k=−42k = - 42;

(2) k=−36k = - 36;

(3) k=−30k = - 30.

(17)

8y2+4xy+2xz+4yz+4x+8y+k=08y^{2} + 4xy + 2xz + 4yz + 4x + 8y + k = 0

(1) k=0k = 0;

(2) k=−9k = - 9.

(18)

8y2+4xy+2xz+4yz+8x+6y+4z+6=08y^{2} + 4xy + 2xz + 4yz + 8x + 6y + 4z + 6 = 0

(19)

4x2+y2+9z2+4xy−12xz−6yz+11x+3y−z+1=04x^{2} + y^{2} + 9z^{2} + 4xy - 12xz - 6yz + 11x + 3y - z + 1 = 0

(20)

4x2+y2+9z2+4xy−12xz−6yz+6x−2y−6z+11=04x^{2} + y^{2} + 9z^{2} + 4xy - 12xz - 6yz + 6x - 2y - 6z + 11 = 0

(21)

4x2+y2+9z2+4xy−12xz−6yz+4x+2y−6z+k=04x^{2} + y^{2} + 9z^{2} + 4xy - 12xz - 6yz + 4x + 2y - 6z + k = 0;

(1) k=1k = 1;

(2) k=−13k = - 13.

(22)

−x2+10y2−z2−8xy+6xz+8yz+24x−8y−16z+k=0- x^{2} + 10y^{2} - z^{2} - 8xy + 6xz + 8yz + 24x - 8y - 16z + k = 0;

(1) k=−26k = - 26;

(2) k=−14k = - 14;

(3) k=−2k = - 2.

(23)

2x2−y2+2z2+4xy−2xz+4yz+10x−2y−2z+k=02x^{2} - y^{2} + 2z^{2} + 4xy - 2xz + 4yz + 10x - 2y - 2z + k = 0;

(1) k=2k = 2;

(2) k=5k = 5;

(3) k=8k = 8.

(24)

x2+y2−2z2+10xy+4xz−4yz+13x+11y+2z+6=0x^{2} + y^{2} - 2z^{2} + 10xy + 4xz - 4yz + 13x + 11y + 2z + 6 = 0.

(25)

x2+y2−2z2+10xy+4xz−4yz+24x−12z+k=0x^{2} + y^{2} - 2z^{2} + 10xy + 4xz - 4yz + 24x - 12z + k = 0;

(1) k=−12k = - 12;

(2) k=−6k = - 6.