Section 32

Bilinear and quadratic functions

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Problem 32.1

Form the matrix of the given bilinear form and write the corresponding quadratic form in an nn-dimensional vector space:

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(1)

x1y1(n=1)x_{1} y_{1} \quad (n = 1),

(2)

x1y1(n=2)x_{1} y_{1} \quad (n = 2)

(3)

2x1y1−x1y2−x2y1−5x2y2(n=2)2x_{1} y_{1} - x_{1} y_{2} - x_{2} y_{1} - 5x_{2} y_{2} \quad (n = 2)

(4)

x1y2−3x1y3+7x2y3+x2y1−3x3y1+7x3y2+x3y3(n=3)x_{1} y_{2} - 3x_{1} y_{3} + 7x_{2} y_{3} + x_{2} y_{1} - 3x_{3} y_{1} + 7x_{3} y_{2} + x_{3} y_{3} \quad (n = 3)

(5)

∑i=1nxiyi\sum_{i = 1}^{n} x_{i} y_{i}

(6)

∑i=1nxiyn−i+1\sum_{i = 1}^{n} x_{i} y_{n - i + 1}

(7)

∑∣i−j∣⩽1xiyj\sum_{\left|i - j\right| \leqslant 1} x_{i} y_{j}

Problem 32.2

Recover the symmetric bilinear form in an nn-dimensional vector space from the given quadratic form and form its matrix:

?
(1)

−3x12(n=1)- 3x_{1}^{2} \quad (n = 1)

(2)

−18x1x2+9x22(n=2)- 18x_{1} x_{2} + 9x_{2}^{2} \quad (n = 2)

(3)

x12+4x1x2+4x1x3+5x22+12x2x3+7x32(n=3)x_{1}^{2} + 4x_{1} x_{2} + 4x_{1} x_{3} + 5x_{2}^{2} + 12x_{2} x_{3} + 7x_{3}^{2} \quad (n = 3)

(4)

2x12−6x1x2−3x22(n=3)2x_{1}^{2} - 6x_{1} x_{2} - 3x_{2}^{2} \quad (n = 3)

(5)

∑i=1n−1xixi+1\sum_{i = 1}^{n - 1} x_{i} x_{i + 1}

Problem 32.3

Write the quadratic form having the given matrix:

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(1)

A47\mathbf{A}_{47}. A47=[5−2−28]\mathbf{A}_{47} = \left[\begin{smallmatrix} 5 & -2 \\ -2 & 8 \end{smallmatrix}\right].

(2)

A37\mathbf{A}_{37}. A37=[−455−4]\mathbf{A}_{37} = \left[\begin{smallmatrix} -4 & 5 \\ 5 & -4 \end{smallmatrix}\right].

(3)

A307\mathbf{A}_{307}. A307=[4242−30404]\mathbf{A}_{307} = \left[\begin{smallmatrix} 4 & 2 & 4 \\ 2 & -3 & 0 \\ 4 & 0 & 4 \end{smallmatrix}\right].

(4)

A280\mathbf{A}_{280}. A280=[021282120]\mathbf{A}_{280} = \left[\begin{smallmatrix} 0 & 2 & 1 \\ 2 & 8 & 2 \\ 1 & 2 & 0 \end{smallmatrix}\right].

(5)

A484\mathbf{A}_{484}. A484=[111111−1−11−11−11−1−11]\mathbf{A}_{484} = \left[\begin{smallmatrix} 1 & 1 & 1 & 1 \\ 1 & 1 & -1 & -1 \\ 1 & -1 & 1 & -1 \\ 1 & -1 & -1 & 1 \end{smallmatrix}\right].

(6)

A471\mathbf{A}_{471}. A471=[2−100−12−1−10−1200−102]\mathbf{A}_{471} = \left[\begin{smallmatrix} 2 & -1 & 0 & 0 \\ -1 & 2 & -1 & -1 \\ 0 & -1 & 2 & 0 \\ 0 & -1 & 0 & 2 \end{smallmatrix}\right].

(7)

A593\mathbf{A}_{593}. A593=[20−1000020−100−102−1000−1−12−10000−12−10000−12]\mathbf{A}_{593} = \left[\begin{smallmatrix} 2 & 0 & -1 & 0 & 0 & 0 \\ 0 & 2 & 0 & -1 & 0 & 0 \\ -1 & 0 & 2 & -1 & 0 & 0 \\ 0 & -1 & -1 & 2 & -1 & 0 \\ 0 & 0 & 0 & -1 & 2 & -1 \\ 0 & 0 & 0 & 0 & -1 & 2 \end{smallmatrix}\right].

(8)

A634\mathbf{A}_{634}. A634=[0100…001010…000101…00………………0000…010000…10]\mathbf{A}_{634} = \left[\begin{smallmatrix} 0 & 1 & 0 & 0 & \ldots & 0 & 0 \\ 1 & 0 & 1 & 0 & \ldots & 0 & 0 \\ 0 & 1 & 0 & 1 & \ldots & 0 & 0 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & 0 & 0 & \ldots & 0 & 1 \\ 0 & 0 & 0 & 0 & \ldots & 1 & 0 \end{smallmatrix}\right].

Problem 32.4
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(1)

Recover the symmetric bilinear function from the quadratic function it generates.

(2)

Prove that any bilinear function b(x,y)\mathrm{b}(x, y) can be uniquely represented as a sum b(x,y)=b+(x,y)+b−(x,y)\mathrm{b}(x, y) = \mathrm{b}_{ + }(x, y) + \mathrm{b}_{ - }(x, y), where b+(x,y)=b+(y,x)\mathrm{b}_{ + }(x, y) = \mathrm{b}_{ + }(y, x), and b−(x,y)=−b−(y,x)\mathrm{b}_{ - }(x, y) = - \mathrm{b}_{ - }(y, x). Prove that then b(x,x)=b+(x,x)\mathrm{b}(x, x) = \mathrm{b}_{ + }(x, x).

Problem 32.5

How will the matrix of a bilinear (quadratic) function change if the basis e1,…,ene_{1}, \ldots , e_{n} is changed as follows:

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(1)

swap the ii-th and jj-th basis vectors

(2)

multiply the ii-th basis vector by a number λ≠0\lambda \neq 0

(3)

replace the vector eie_{i} by ei+λej(i≠j)e_{i} + \lambda e_{j}(i \neq j)

(4)

arrange the basis vectors in reverse order?

Problem 32.6

A quadratic function and a linear transformation have the same matrices in some basis. What must the transition matrix from this basis to another basis be, in order that the matrices of the quadratic function and the linear transformation coincide in the other basis as well?

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Problem 32.7

A quadratic function is given in the basis e1,…,ene_{1}, \ldots , e_{n}. Write this quadratic function in the basis e1′,…,en′e_{1}^{\prime }, \ldots , e_{n}^{\prime }:

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(1)

25x12−14x1x2+2x22,e1′=e1+e2,e2′=−e1+e225x_{1}^{2} - 14x_{1} x_{2} + 2x_{2}^{2}, \quad e_{1}^{\prime } = e_{1} + e_{2}, \quad e_{2}^{\prime } = - e_{1} + e_{2}

(2)

3x12+10x1x2+9x22,e1′=2e1−e2,e2′=e1−e23x_{1}^{2} + 10x_{1} x_{2} + 9x_{2}^{2}, \quad e_{1}^{\prime } = 2e_{1} - e_{2}, \quad e_{2}^{\prime } = e_{1} - e_{2}

(3)

4x12−12x1x2+9x22,e1′=14e1−16e2,e2′=14e1+16e24x_{1}^{2} - 12x_{1} x_{2} + 9x_{2}^{2}, \quad e_{1}^{\prime } = \frac{1}{4} e_{1} - \frac{1}{6} e_{2}, \quad e_{2}^{\prime } = \frac{1}{4} e_{1} + \frac{1}{6} e_{2}

(4)

x12+4x1x2+4x1x3−x32,e1′=e1+e2+e3,e2′=2e1−−e2+e3,e3′=−e1+2e2−3e3x_{1}^{2} + 4x_{1} x_{2} + 4x_{1} x_{3} - x_{3}^{2}, \quad e_{1}^{\prime } = e_{1} + e_{2} + e_{3}, \quad e_{2}^{\prime } = 2e_{1} - - e_{2} + e_{3}, \quad e_{3}^{\prime } = - e_{1} + 2e_{2} - 3e_{3}

(5)

x12+2x1x2−x1x3−x22+2x2x3+x32,e1′=2e1−e3,e2′=−e1+2e2−e3,e3′=−e2+e3x_{1}^{2} + 2x_{1} x_{2} - x_{1} x_{3} - x_{2}^{2} + 2x_{2} x_{3} + x_{3}^{2}, \quad e_{1}^{\prime } = 2e_{1} - e_{3}, \quad e_{2}^{\prime } = - e_{1} + 2e_{2} - e_{3}, \quad e_{3}^{\prime } = - e_{2} + e_{3}

(6)

5x12+5x22+3x32+2x1x2+22x1x3+22x2x3,e1′=e1+e2−22e3,e2′=e1−e2,e3′=2e1+2e2+e35x_{1}^{2} + 5x_{2}^{2} + 3x_{3}^{2} + 2x_{1} x_{2} + 2\sqrt{2} x_{1} x_{3} + 2\sqrt{2} x_{2} x_{3}, e_{1}^{\prime } = e_{1} + e_{2} - 2\sqrt{2} e_{3}, \quad e_{2}^{\prime } = e_{1} - e_{2}, \quad e_{3}^{\prime } = \sqrt{2} e_{1} + \sqrt{2} e_{2} + e_{3}

(7)

∑i=1n−1xixi+1,ei′=ei+ei+1+…+en,i=1,2,…,n\sum_{i = 1}^{n - 1} x_{i} x_{i + 1}, \quad e_{i}^{\prime } = e_{i} + e_{i + 1} + \ldots + e_{n}, \quad i = 1, 2, \ldots , n.

Problem 32.8

Reduce the given quadratic form to canonical form using Lagrange's method or elementary transformations of its matrix. Find the rank, the positive and negative indices of inertia, and the signature of this form:

?
(1)

4x12+4x1x2+5x224x_{1}^{2} + 4x_{1} x_{2} + 5x_{2}^{2}

(2)

x12−x1x2−x22x_{1}^{2} - x_{1} x_{2} - x_{2}^{2}

(3)

−x1x2- x_{1} x_{2}

(4)

25x12+30x1x2+9x2225x_{1}^{2} + 30x_{1} x_{2} + 9x_{2}^{2}

(5)

2x1x2−x12−2x222x_{1} x_{2} - x_{1}^{2} - 2x_{2}^{2}

(6)

24x1x2−16x12−9x2224x_{1} x_{2} - 16x_{1}^{2} - 9x_{2}^{2}

(7)

x12+4x1x3+x22+2x2x3+4x32x_{1}^{2} + 4x_{1} x_{3} + x_{2}^{2} + 2x_{2} x_{3} + 4x_{3}^{2}

(8)

x12+2x1x2+2x1x3−3x22−6x2x3−4x32x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} - 3x_{2}^{2} - 6x_{2} x_{3} - 4x_{3}^{2}

(9)

2x12+8x1x2+4x1x3+9x22+19x322x_{1}^{2} + 8x_{1} x_{2} + 4x_{1} x_{3} + 9x_{2}^{2} + 19x_{3}^{2}

(10)

9x12−12x1x2−6x1x3+4x22+4x2x3+x329x_{1}^{2} - 12x_{1} x_{2} - 6x_{1} x_{3} + 4x_{2}^{2} + 4x_{2} x_{3} + x_{3}^{2}

(11)

8x12+8x22+x32+16x1x2+4x1x3+4x2x38x_{1}^{2} + 8x_{2}^{2} + x_{3}^{2} + 16x_{1} x_{2} + 4x_{1} x_{3} + 4x_{2} x_{3}

(12)

(р) x1x2+x2x3+x1x3x_{1} x_{2} + x_{2} x_{3} + x_{1} x_{3}

(13)

x12+2x22+2x32+3x42+2x1x2+2x2x3+2x3x4x_{1}^{2} + 2x_{2}^{2} + 2x_{3}^{2} + 3x_{4}^{2} + 2x_{1} x_{2} + 2x_{2} x_{3} + 2x_{3} x_{4}

(14)

x12−2x1x3+x22−2x2x4+x32−2x3x5+x42−2x4x6+x52+x62x_{1}^{2} - 2x_{1} x_{3} + x_{2}^{2} - 2x_{2} x_{4} + x_{3}^{2} - 2x_{3} x_{5} + x_{4}^{2} - 2x_{4} x_{6} + x_{5}^{2} + x_{6}^{2}

(15)

x1x2+2x2x3−3x3x4x_{1} x_{2} + 2x_{2} x_{3} - 3x_{3} x_{4}

(16)

x1x2+x2x3−x12−x22−x32x_{1} x_{2} + x_{2} x_{3} - x_{1}^{2} - x_{2}^{2} - x_{3}^{2}.

Problem 32.9

Determine which quadratic forms from problem 32.8 are positive definite, negative definite, semidefinite:

?
(1)

4x12+4x1x2+5x224x_{1}^{2} + 4x_{1} x_{2} + 5x_{2}^{2}

(2)

x12−x1x2−x22x_{1}^{2} - x_{1} x_{2} - x_{2}^{2}

(3)

−x1x2- x_{1} x_{2}

(4)

25x12+30x1x2+9x2225x_{1}^{2} + 30x_{1} x_{2} + 9x_{2}^{2}

(5)

2x1x2−x12−2x222x_{1} x_{2} - x_{1}^{2} - 2x_{2}^{2}

(6)

24x1x2−16x12−9x2224x_{1} x_{2} - 16x_{1}^{2} - 9x_{2}^{2}

(7)

x12+4x1x3+x22+2x2x3+4x32x_{1}^{2} + 4x_{1} x_{3} + x_{2}^{2} + 2x_{2} x_{3} + 4x_{3}^{2}

(8)

x12+2x1x2+2x1x3−3x22−6x2x3−4x32x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} - 3x_{2}^{2} - 6x_{2} x_{3} - 4x_{3}^{2}

(9)

2x12+8x1x2+4x1x3+9x22+19x322x_{1}^{2} + 8x_{1} x_{2} + 4x_{1} x_{3} + 9x_{2}^{2} + 19x_{3}^{2}

(10)

9x12−12x1x2−6x1x3+4x22+4x2x3+x329x_{1}^{2} - 12x_{1} x_{2} - 6x_{1} x_{3} + 4x_{2}^{2} + 4x_{2} x_{3} + x_{3}^{2}

(11)

8x12+8x22+x32+16x1x2+4x1x3+4x2x38x_{1}^{2} + 8x_{2}^{2} + x_{3}^{2} + 16x_{1} x_{2} + 4x_{1} x_{3} + 4x_{2} x_{3}

(12)

(р) x1x2+x2x3+x1x3x_{1} x_{2} + x_{2} x_{3} + x_{1} x_{3}

(13)

x12+2x22+2x32+3x42+2x1x2+2x2x3+2x3x4x_{1}^{2} + 2x_{2}^{2} + 2x_{3}^{2} + 3x_{4}^{2} + 2x_{1} x_{2} + 2x_{2} x_{3} + 2x_{3} x_{4}

(14)

x12−2x1x3+x22−2x2x4+x32−2x3x5+x42−2x4x6+x52+x62x_{1}^{2} - 2x_{1} x_{3} + x_{2}^{2} - 2x_{2} x_{4} + x_{3}^{2} - 2x_{3} x_{5} + x_{4}^{2} - 2x_{4} x_{6} + x_{5}^{2} + x_{6}^{2}

(15)

x1x2+2x2x3−3x3x4x_{1} x_{2} + 2x_{2} x_{3} - 3x_{3} x_{4}

(16)

x1x2+x2x3−x12−x22−x32x_{1} x_{2} + x_{2} x_{3} - x_{1}^{2} - x_{2}^{2} - x_{3}^{2}.

Problem 32.10

Reduce the given bilinear form to canonical form:

?
(1)

x1y1+x1y2+x2y1+3x2y2x_{1} y_{1} + x_{1} y_{2} + x_{2} y_{1} + 3x_{2} y_{2}

(2)

x1y1−x1y2−x2y1+x2y2x_{1} y_{1} - x_{1} y_{2} - x_{2} y_{1} + x_{2} y_{2}

(3)

13x1y1−5x1y2−5x2y1+2x2y213x_{1} y_{1} - 5x_{1} y_{2} - 5x_{2} y_{1} + 2x_{2} y_{2}

(4)

−x1y2−x2y1+x2y2- x_{1} y_{2} - x_{2} y_{1} + x_{2} y_{2}

(5)

x1y2+x2y1+x1y3+x3y1+x2y3+x3y2x_{1} y_{2} + x_{2} y_{1} + x_{1} y_{3} + x_{3} y_{1} + x_{2} y_{3} + x_{3} y_{2}

(6)

x1y1+2x2y2+3x3y3+x1y2+x2y1+x1y3+x3y1+2x2y3+2x3y2x_{1} y_{1} + 2x_{2} y_{2} + 3x_{3} y_{3} + x_{1} y_{2} + x_{2} y_{1} + x_{1} y_{3} + x_{3} y_{1} + 2x_{2} y_{3} + 2x_{3} y_{2}

(7)

x1y1+x1y2+x2y1+x2y3x_{1} y_{1} + x_{1} y_{2} + x_{2} y_{1} + x_{2} y_{3}.

Problem 32.11

Prove that a nonsymmetric bilinear function cannot be reduced to diagonal form.

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Problem 32.12

Reduce a quadratic form depending on a real parameter λ\lambda to canonical form for all possible values of λ\lambda:

?
(1)

3x12−2x1x2+λx223x_{1}^{2} - 2x_{1} x_{2} + \lambda x_{2}^{2}

(2)

8x12+λx1x2+2x228x_{1}^{2} + \lambda x_{1} x_{2} + 2x_{2}^{2}

(3)

2x12+8x1x2+4x1x3+6x22+λx322x_{1}^{2} + 8x_{1} x_{2} + 4x_{1} x_{3} + 6x_{2}^{2} + \lambda x_{3}^{2}

(4)

x12+x22+4x32+λx42+4x1x3+2x1x4+2x2x3+2x2x4+5x3x4x_{1}^{2} + x_{2}^{2} + 4x_{3}^{2} + \lambda x_{4}^{2} + 4x_{1} x_{3} + 2x_{1} x_{4} + 2x_{2} x_{3} + 2x_{2} x_{4} + 5x_{3} x_{4}

(5)

3x22+6x1x2+2x1x3+4x2x3+λx2x4+x32+x3x4+x423x_{2}^{2} + 6x_{1} x_{2} + 2x_{1} x_{3} + 4x_{2} x_{3} + \lambda x_{2} x_{4} + x_{3}^{2} + x_{3} x_{4} + x_{4}^{2}.

Problem 32.13

Reduce the given quadratic form to canonical form in an nn-dimensional space:

?
(1)

x12+2∑i=2nxi2−2∑i=1n−1xixi+1x_{1}^{2} + 2\sum_{i = 2}^{n} x_{i}^{2} - 2\sum_{i = 1}^{n - 1} x_{i} x_{i + 1}

(2)

x12+2∑i=1n−1(−1)ixixi+1x_{1}^{2} + 2\sum_{i = 1}^{n - 1}(- 1)^{i} x_{i} x_{i + 1}

(3)

∑i=1nxi2+∑1⩽i<j⩽nxixj\sum_{i = 1}^{n} x_{i}^{2} + \sum_{1 \leqslant i < j \leqslant n} x_{i} x_{j}

(4)

∑1⩽i<j⩽nxixj\sum_{1 \leqslant i < j \leqslant n} x_{i} x_{j}

(5)

−∑i=1nixi2+2∑1⩽i<j⩽nixixj- \sum_{i = 1}^{n} ix_{i}^{2} + 2\sum_{1 \leqslant i < j \leqslant n} ix_{i} x_{j}

(6)

∑i=1n((i−1)2+1)xi2+2∑1⩽i<j⩽nixixj\sum_{i = 1}^{n}\left((i - 1)^{2} + 1\right) x_{i}^{2} + 2\sum_{1 \leqslant i < j \leqslant n} ix_{i} x_{j}.

Problem 32.14

Prove that for the positive definiteness of a quadratic function k(x)\mathrm{k}(x) any one of the following conditions is necessary and sufficient:

?
(1)

k(ei)>0(i=1,…,n)\mathrm{k}\left(e_{i}\right) > 0(i = 1, \ldots , n) for any basis e1,…,ene_{1}, \ldots , e_{n}

(2)

k(x)\mathrm{k}(x) reduces to diagonal form with positive coefficients

(3)

k(x)\mathrm{k}(x) reduces to the canonical form ξ12+…+ξn2\xi_{1}^{2} + \ldots + \xi_{n}^{2}.

Problem 32.15

Show that for the positive definiteness of a quadratic function, the positivity of all diagonal elements of its matrix in some basis is necessary but not sufficient.

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Problem 32.16

Prove that a quadratic form is negative definite if and only if the signs of the principal minors of its matrix alternate as follows:

Δ1<0,Δ2>0,Δ3<0,…,sign⁡Δn=(−1)n. \Delta _{1} < 0, \Delta _{2} > 0, \Delta _{3} < 0, \ldots , \operatorname {sign} \Delta _{n} = (- 1)^{n}.
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Problem 32.17

Let the rank of a quadratic function k(x)\mathrm{k}(x) in an nn-dimensional vector space L\mathcal{L} equal rr. Prove the statements:

?
(1)

in L\mathcal{L} there exists a basis in which the principal minors Δk\Delta_{k} of the matrix of the function k(x)\mathrm{k}(x) are nonzero for k=1,…,rk = 1, \ldots , r and equal zero for k=r+1,…,nk = r + 1, \ldots , n.

(2)

let in some basis the principal minors Δk(k=1,…,r)\Delta_{k}(k = 1, \ldots , r) of the matrix of the function k(x)\mathrm{k}(x) be nonzero. Then k(x)\mathrm{k}(x) reduces to the diagonal form ∑k=1rΔkΔk−1ξk2(Δ0=1)\sum_{k = 1}^{r} \frac{\Delta_{k}}{\Delta_{k - 1}} \xi_{k}^{2}\left(\Delta_{0} = 1\right) and to the canonical form ∑k=1rεkξk2\sum_{k = 1}^{r} \varepsilon_{k} \xi_{k}^{2}, where εk=sign⁡ΔkΔk−1(k=1,…,r)\varepsilon_{k} = \operatorname {sign} \frac{\Delta_{k}}{\Delta_{k - 1}}(k = 1, \ldots , r).

Problem 32.18

For which values of the parameter λ\lambda is the given quadratic form positive definite, negative definite, or semidefinite:

?
(1)

λx12−4x1x2+(λ+3)x22\lambda x_{1}^{2} - 4x_{1} x_{2} + (\lambda + 3) x_{2}^{2}

(2)

−9x12+6λx1x2−x22- 9x_{1}^{2} + 6\lambda x_{1} x_{2} - x_{2}^{2}

(3)

λx12+8x22+x32+16x1x2+4x1x3+4x2x3\lambda x_{1}^{2} + 8x_{2}^{2} + x_{3}^{2} + 16x_{1} x_{2} + 4x_{1} x_{3} + 4x_{2} x_{3}

(4)

x12+2λx1x2+2x1x3+4x22−λx32+2x2x3x_{1}^{2} + 2\lambda x_{1} x_{2} + 2x_{1} x_{3} + 4x_{2}^{2} - \lambda x_{3}^{2} + 2x_{2} x_{3}

(5)

(4−λ)x12+(4−λ)x22−(2+λ)x32+4x1x2−8x1x3+8x2x3(4 - \lambda ) x_{1}^{2} + (4 - \lambda ) x_{2}^{2} - (2 + \lambda ) x_{3}^{2} + 4x_{1} x_{2} - 8x_{1} x_{3} + 8x_{2} x_{3}?

Problem 32.19

Let k(x)\mathrm{k}(x) be a quadratic function on a vector space L\mathcal{L}. Is the set of all vectors xx from L\mathcal{L} for which k(x)⩾0(k(x)⩽0)\mathrm{k}(x) \geqslant 0(\mathrm{k}(x) \leqslant 0) a linear subspace of L\mathcal{L}? Consider the examples k(x)=x12+x22−x32(n=3)\mathrm{k}(x) = x_{1}^{2} + x_{2}^{2} - x_{3}^{2}(n = 3) and h(x)=x12+x22(n=3)\mathrm{h}(x) = x_{1}^{2} + x_{2}^{2}(n = 3).

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Problem 32.20
?
(1)

In the matrix of a positive definite quadratic form, one diagonal element was increased. Prove that the determinant of the matrix increased.

(2)

Prove that in the matrix of a positive definite quadratic form the largest element in absolute value is positive.

Problem 32.21
?
(1)

Prove that in the vector space of real square matrices of order nn the function k(X)=tr⁡(XTX)\mathrm{k}(X) = \operatorname {tr}\left(X^{T} X\right) is a positive definite quadratic function.

(2)

Prove that in the vector space of real square matrices of order nn the function k(X)=tr⁡(X2)\mathrm{k}(X) = \operatorname {tr}\left(X^{2}\right) is a quadratic function. Find its rank and signature.

Problem 32.22

Prove that the function

I(f,g)=∫−11f(t)g(t)dt I(f, g) = \int _{ - 1}^{1} f(t) g(t) dt

is a symmetric bilinear function in the space of polynomials of degree at most nn. Reduce it to canonical form for n=3n = 3.

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Problem 32.23

Prove that the rank of a bilinear function equals 1 if and only if this function is the product of two nonzero linear functions.

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Problem 32.24

Prove that for a quadratic function to be representable as the product of two real linear functions, it is necessary and sufficient that either the rank of this quadratic function not exceed 1, or the rank equal 2 with signature equal to zero.

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Problem 32.25

Under what necessary and sufficient condition can the quadratic functions k(x)\mathrm{k}(x) and −k(x)- \mathrm{k}(x) be reduced to one and the same canonical form?

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Problem 32.26
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(1)

Let b(x,y)\mathrm{b}(x, y) be a bilinear function on a vector space L\mathcal{L}. Call the function b(x,y)\mathrm{b}(x, y) invariant with respect to a linear transformation φ\varphi of the space L\mathcal{L} if b(φ(x),φ(y))=b(x,y)\mathrm{b}(\varphi (x), \varphi (y)) = \mathrm{b}(x, y) for all x,y∈Lx, y\in \mathcal{L}. Prove that b\mathrm{b} is invariant with respect to φ\varphi if and only if their matrices (BB and AA, respectively) in some basis satisfy the equality ATBA=BA^{T} BA = B.

(2)

Find all linear transformations of a two-dimensional space with respect to which the bilinear form is invariant:

(1) x1y1+x2y2x_{1} y_{1} + x_{2} y_{2}

(2) x1y1−x2y2x_{1} y_{1} - x_{2} y_{2}

Problem 32.27

A quadratic (bilinear) function is written in an orthonormal basis of an nn-dimensional Euclidean space. Find an orthonormal basis in which the given function has diagonal form, and write this diagonal form.

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(1)

n=2n = 2, −4x12+10x1x2−4x22- 4x_{1}^{2} + 10x_{1} x_{2} - 4x_{2}^{2}

(2)

n=2n = 2, 43x12−2x1x2+34x22\frac{4}{3} x_{1}^{2} - 2x_{1} x_{2} + \frac{3}{4} x_{2}^{2}

(3)

n=2n = 2, 7x12+43x1x2+3x227x_{1}^{2} + 4\sqrt{3} x_{1} x_{2} + 3x_{2}^{2}

(4)

n=2n = 2, −x1y1+3x1y2+3x2y1−9x2y2- x_{1} y_{1} + 3x_{1} y_{2} + 3x_{2} y_{1} - 9x_{2} y_{2}

(5)

n=2n = 2, −x1y1+12x1y2+12x2y1−x2y2n=3:- x_{1} y_{1} + \frac{1}{2} x_{1} y_{2} + \frac{1}{2} x_{2} y_{1} - x_{2} y_{2} n = 3:

(6)

n=3n = 3, −x12+x1x2−x22- x_{1}^{2} + x_{1} x_{2} - x_{2}^{2}

(7)

n=3n = 3, 2x12−4x1x2+9x22+4x2x3+2x322x_{1}^{2} - 4x_{1} x_{2} + 9x_{2}^{2} + 4x_{2} x_{3} + 2x_{3}^{2}

(8)

n=3n = 3, x1y1−x1y2−x2y1+2x2y2−x2y3−x3y2+x3y3x_{1} y_{1} - x_{1} y_{2} - x_{2} y_{1} + 2x_{2} y_{2} - x_{2} y_{3} - x_{3} y_{2} + x_{3} y_{3}

(9)

n=3n = 3, 2x1y2+2x2y1−2x1y3−2x3y1+4x2y2+4x2y3+4x3y2−3x3y32x_{1} y_{2} + 2x_{2} y_{1} - 2x_{1} y_{3} - 2x_{3} y_{1} + 4x_{2} y_{2} + 4x_{2} y_{3} + 4x_{3} y_{2} - 3x_{3} y_{3}

(10)

n=3n = 3, (р) 2x12+4x1x2−2x1x3−x22+4x2x3+2x322x_{1}^{2} + 4x_{1} x_{2} - 2x_{1} x_{3} - x_{2}^{2} + 4x_{2} x_{3} + 2x_{3}^{2}

(11)

n=3n = 3, 3x12−2x1x2−2x1x3+3x22−2x2x3+3x323x_{1}^{2} - 2x_{1} x_{2} - 2x_{1} x_{3} + 3x_{2}^{2} - 2x_{2} x_{3} + 3x_{3}^{2}

(12)

n=3n = 3, 3x12+8x1x2−8x1x3−7x22−8x2x3+3x323x_{1}^{2} + 8x_{1} x_{2} - 8x_{1} x_{3} - 7x_{2}^{2} - 8x_{2} x_{3} + 3x_{3}^{2}

(13)

n=3n = 3, x12−x1x2+x1x3+x22+x2x3+x32x_{1}^{2} - x_{1} x_{2} + x_{1} x_{3} + x_{2}^{2} + x_{2} x_{3} + x_{3}^{2}

(14)

n=3n = 3, 4x12+4x1x2−12x1x3+x22−6x2x3+9x324x_{1}^{2} + 4x_{1} x_{2} - 12x_{1} x_{3} + x_{2}^{2} - 6x_{2} x_{3} + 9x_{3}^{2}

(15)

n=3n = 3, x1y2+x2y1−2x1y3−2x3y1−x1y1−x2y2+2x2y3+2x3y2−4x3y3x_{1} y_{2} + x_{2} y_{1} - 2x_{1} y_{3} - 2x_{3} y_{1} - x_{1} y_{1} - x_{2} y_{2} + 2x_{2} y_{3} + 2x_{3} y_{2} - 4x_{3} y_{3}

(16)

n=3n = 3, x1y2+x2y1+x1y3+x3y1+x2y2−x3y3n=4x_{1} y_{2} + x_{2} y_{1} + x_{1} y_{3} + x_{3} y_{1} + x_{2} y_{2} - x_{3} y_{3} n = 4:

(17)

n=4n = 4, x12+2x1x2+2x1x3+2x1x4+x22−2x2x3−2x2x4+x32−−2x3x4+x42x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} + 2x_{1} x_{4} + x_{2}^{2} - 2x_{2} x_{3} - 2x_{2} x_{4} + x_{3}^{2} - - 2x_{3} x_{4} + x_{4}^{2}

(18)

n=4n = 4, x12−2x1x2+6x1x3+8x1x4+4x22−2x2x4−6x3x4+x42x_{1}^{2} - 2x_{1} x_{2} + 6x_{1} x_{3} + 8x_{1} x_{4} + 4x_{2}^{2} - 2x_{2} x_{4} - 6x_{3} x_{4} + x_{4}^{2}

(19)

n=4n = 4, 2x12−4x1x2+4x1x3+6x22−6x2x3+2x2x4+6x32+2x3x4+4x422x_{1}^{2} - 4x_{1} x_{2} + 4x_{1} x_{3} + 6x_{2}^{2} - 6x_{2} x_{3} + 2x_{2} x_{4} + 6x_{3}^{2} + 2x_{3} x_{4} + 4x_{4}^{2}

(20)

n=4n = 4, x12+2x1x2+2x1x3+2x1x4−x22−x32−x42x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} + 2x_{1} x_{4} - x_{2}^{2} - x_{3}^{2} - x_{4}^{2}

(21)

n=4n = 4, 12x1y2+12x2y1+12x3y4+12x4y3\frac{1}{2} x_{1} y_{2} + \frac{1}{2} x_{2} y_{1} + \frac{1}{2} x_{3} y_{4} + \frac{1}{2} x_{4} y_{3}

(22)

n=4n = 4, 3x12−8x1x2−3x22−x32+4x3x4−4x423x_{1}^{2} - 8x_{1} x_{2} - 3x_{2}^{2} - x_{3}^{2} + 4x_{3} x_{4} - 4x_{4}^{2}

(23)

n=4n = 4, ∑i=1nxi2+∑1⩽i<j⩽nxixj\sum_{i = 1}^{n} x_{i}^{2} + \sum_{1 \leqslant i < j \leqslant n} x_{i} x_{j}

(24)

n=4n = 4, ∑i,j=1n(−1)i+jxiyj\sum_{i, j = 1}^{n}(- 1)^{i + j} x_{i} y_{j}

(25)

n=4n = 4, ∑i=12n−1xix2n−i\sum_{i = 1}^{2n - 1} x_{i} x_{2n - i}

(26)

n=4n = 4, ∑i=12nxi2+∑i=12nxix2n−i+1\sum_{i = 1}^{2n} x_{i}^{2} + \sum_{i = 1}^{2n} x_{i} x_{2n - i + 1}

(27)

n=4n = 4, ∑i=1n−1xixi+1\sum_{i = 1}^{n - 1} x_{i} x_{i + 1}.

Problem 32.28

Find the canonical form, rank, and signature of each of the quadratic and bilinear forms of problem 32. 27:

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(1)

n=2n = 2, −4x12+10x1x2−4x22- 4x_{1}^{2} + 10x_{1} x_{2} - 4x_{2}^{2}

(2)

n=2n = 2, 43x12−2x1x2+34x22\frac{4}{3} x_{1}^{2} - 2x_{1} x_{2} + \frac{3}{4} x_{2}^{2}

(3)

n=2n = 2, 7x12+43x1x2+3x227x_{1}^{2} + 4\sqrt{3} x_{1} x_{2} + 3x_{2}^{2}

(4)

n=2n = 2, −x1y1+3x1y2+3x2y1−9x2y2- x_{1} y_{1} + 3x_{1} y_{2} + 3x_{2} y_{1} - 9x_{2} y_{2}

(5)

n=2n = 2, −x1y1+12x1y2+12x2y1−x2y2n=3:- x_{1} y_{1} + \frac{1}{2} x_{1} y_{2} + \frac{1}{2} x_{2} y_{1} - x_{2} y_{2} n = 3:

(6)

n=3n = 3, −x12+x1x2−x22- x_{1}^{2} + x_{1} x_{2} - x_{2}^{2}

(7)

n=3n = 3, 2x12−4x1x2+9x22+4x2x3+2x322x_{1}^{2} - 4x_{1} x_{2} + 9x_{2}^{2} + 4x_{2} x_{3} + 2x_{3}^{2}

(8)

n=3n = 3, x1y1−x1y2−x2y1+2x2y2−x2y3−x3y2+x3y3x_{1} y_{1} - x_{1} y_{2} - x_{2} y_{1} + 2x_{2} y_{2} - x_{2} y_{3} - x_{3} y_{2} + x_{3} y_{3}

(9)

n=3n = 3, 2x1y2+2x2y1−2x1y3−2x3y1+4x2y2+4x2y3+4x3y2−3x3y32x_{1} y_{2} + 2x_{2} y_{1} - 2x_{1} y_{3} - 2x_{3} y_{1} + 4x_{2} y_{2} + 4x_{2} y_{3} + 4x_{3} y_{2} - 3x_{3} y_{3}

(10)

n=3n = 3, (р) 2x12+4x1x2−2x1x3−x22+4x2x3+2x322x_{1}^{2} + 4x_{1} x_{2} - 2x_{1} x_{3} - x_{2}^{2} + 4x_{2} x_{3} + 2x_{3}^{2}

(11)

n=3n = 3, 3x12−2x1x2−2x1x3+3x22−2x2x3+3x323x_{1}^{2} - 2x_{1} x_{2} - 2x_{1} x_{3} + 3x_{2}^{2} - 2x_{2} x_{3} + 3x_{3}^{2}

(12)

n=3n = 3, 3x12+8x1x2−8x1x3−7x22−8x2x3+3x323x_{1}^{2} + 8x_{1} x_{2} - 8x_{1} x_{3} - 7x_{2}^{2} - 8x_{2} x_{3} + 3x_{3}^{2}

(13)

n=3n = 3, x12−x1x2+x1x3+x22+x2x3+x32x_{1}^{2} - x_{1} x_{2} + x_{1} x_{3} + x_{2}^{2} + x_{2} x_{3} + x_{3}^{2}

(14)

n=3n = 3, 4x12+4x1x2−12x1x3+x22−6x2x3+9x324x_{1}^{2} + 4x_{1} x_{2} - 12x_{1} x_{3} + x_{2}^{2} - 6x_{2} x_{3} + 9x_{3}^{2}

(15)

n=3n = 3, x1y2+x2y1−2x1y3−2x3y1−x1y1−x2y2+2x2y3+2x3y2−4x3y3x_{1} y_{2} + x_{2} y_{1} - 2x_{1} y_{3} - 2x_{3} y_{1} - x_{1} y_{1} - x_{2} y_{2} + 2x_{2} y_{3} + 2x_{3} y_{2} - 4x_{3} y_{3}

(16)

n=3n = 3, x1y2+x2y1+x1y3+x3y1+x2y2−x3y3n=4x_{1} y_{2} + x_{2} y_{1} + x_{1} y_{3} + x_{3} y_{1} + x_{2} y_{2} - x_{3} y_{3} n = 4:

(17)

n=4n = 4, x12+2x1x2+2x1x3+2x1x4+x22−2x2x3−2x2x4+x32−−2x3x4+x42x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} + 2x_{1} x_{4} + x_{2}^{2} - 2x_{2} x_{3} - 2x_{2} x_{4} + x_{3}^{2} - - 2x_{3} x_{4} + x_{4}^{2}

(18)

n=4n = 4, x12−2x1x2+6x1x3+8x1x4+4x22−2x2x4−6x3x4+x42x_{1}^{2} - 2x_{1} x_{2} + 6x_{1} x_{3} + 8x_{1} x_{4} + 4x_{2}^{2} - 2x_{2} x_{4} - 6x_{3} x_{4} + x_{4}^{2}

(19)

n=4n = 4, 2x12−4x1x2+4x1x3+6x22−6x2x3+2x2x4+6x32+2x3x4+4x422x_{1}^{2} - 4x_{1} x_{2} + 4x_{1} x_{3} + 6x_{2}^{2} - 6x_{2} x_{3} + 2x_{2} x_{4} + 6x_{3}^{2} + 2x_{3} x_{4} + 4x_{4}^{2}

(20)

n=4n = 4, x12+2x1x2+2x1x3+2x1x4−x22−x32−x42x_{1}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} + 2x_{1} x_{4} - x_{2}^{2} - x_{3}^{2} - x_{4}^{2}

(21)

n=4n = 4, 12x1y2+12x2y1+12x3y4+12x4y3\frac{1}{2} x_{1} y_{2} + \frac{1}{2} x_{2} y_{1} + \frac{1}{2} x_{3} y_{4} + \frac{1}{2} x_{4} y_{3}

(22)

n=4n = 4, 3x12−8x1x2−3x22−x32+4x3x4−4x423x_{1}^{2} - 8x_{1} x_{2} - 3x_{2}^{2} - x_{3}^{2} + 4x_{3} x_{4} - 4x_{4}^{2}

(23)

n=4n = 4, ∑i=1nxi2+∑1⩽i<j⩽nxixj\sum_{i = 1}^{n} x_{i}^{2} + \sum_{1 \leqslant i < j \leqslant n} x_{i} x_{j}

(24)

n=4n = 4, ∑i,j=1n(−1)i+jxiyj\sum_{i, j = 1}^{n}(- 1)^{i + j} x_{i} y_{j}

(25)

n=4n = 4, ∑i=12n−1xix2n−i\sum_{i = 1}^{2n - 1} x_{i} x_{2n - i}

(26)

n=4n = 4, ∑i=12nxi2+∑i=12nxix2n−i+1\sum_{i = 1}^{2n} x_{i}^{2} + \sum_{i = 1}^{2n} x_{i} x_{2n - i + 1}

(27)

n=4n = 4, ∑i=1n−1xixi+1\sum_{i = 1}^{n - 1} x_{i} x_{i + 1}.

Problem 32.29

Prove that a quadratic form is positive definite if and only if all the characteristic numbers of its matrix are positive, and negative definite if and only if they are negative.

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Problem 32.30

Let all the characteristic numbers of a real symmetric matrix AA belong to the interval [a,b]\left[a, b\right]. Prove that the quadratic form with matrix A−λEA - \lambda E is positive definite for λ<a\lambda < a and negative definite for λ>b\lambda > b.

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Problem 32.31

Prove that a quadratic form is positive definite if and only if all the coefficients of the characteristic polynomial of its matrix are nonzero and the signs of these coefficients alternate, with the constant term positive.

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Problem 32.32
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(1)

Prove that the linear transformation φ\varphi of a Euclidean space associated with a symmetric bilinear function b(x,y)\mathrm{b}(x, y) given on it is self-adjoint.

(2)

Let in some basis ee a bilinear function b(x,y)\mathrm{b}(x, y) have symmetric matrix BB, and let the Gram matrix of the basis ee equal Γ\Gamma. Find the matrix of the transformation associated with the function b(x,y)\mathrm{b}(x, y).

Problem 32.33

In a basis ee of a Euclidean space, a quadratic form is given. Find, in the same basis, the matrix of the transformation associated with it, if the Gram matrix of the basis ee equals Γ\Gamma:

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(1)

4x12+16x1x2+6x22,Γ=A564x_{1}^{2} + 16x_{1} x_{2} + 6x_{2}^{2}, \quad \Gamma = \mathbf{A}_{56}. A56=[1113]\mathbf{A}_{56} = \left[\begin{smallmatrix} 1 & 1 \\ 1 & 3 \end{smallmatrix}\right].

(2)

4x12−6x1x2−5x22,Γ=A554x_{1}^{2} - 6x_{1} x_{2} - 5x_{2}^{2}, \quad \Gamma = \mathbf{A}_{55}. A55=[2335]\mathbf{A}_{55} = \left[\begin{smallmatrix} 2 & 3 \\ 3 & 5 \end{smallmatrix}\right].

(3)

2x1x2−x22,Γ=A92x_{1} x_{2} - x_{2}^{2}, \quad \Gamma = \mathbf{A}_{9}. A9=[9−5−53]\mathbf{A}_{9} = \left[\begin{smallmatrix} 9 & -5 \\ -5 & 3 \end{smallmatrix}\right].

(4)

2x12+4x1x2−2x1x3−x22+4x2x3+2x32,Γ=A2072x_{1}^{2} + 4x_{1} x_{2} - 2x_{1} x_{3} - x_{2}^{2} + 4x_{2} x_{3} + 2x_{3}^{2}, \quad \Gamma = \mathbf{A}_{207}. A207=[12025−20−25]\mathbf{A}_{207} = \left[\begin{smallmatrix} 1 & 2 & 0 \\ 2 & 5 & -2 \\ 0 & -2 & 5 \end{smallmatrix}\right].

(5)

5x12+x22+4x32+2x1x2+4x1x3+4x2x3,Γ=A3085x_{1}^{2} + x_{2}^{2} + 4x_{3}^{2} + 2x_{1} x_{2} + 4x_{1} x_{3} + 4x_{2} x_{3}, \quad \Gamma = \mathbf{A}_{308}. A308=[5−12−110204]\mathbf{A}_{308} = \left[\begin{smallmatrix} 5 & -1 & 2 \\ -1 & 1 & 0 \\ 2 & 0 & 4 \end{smallmatrix}\right].

(6)

x12+x22+x32+x42+2x1x2+2x1x3+2x1x4−2x2x3−−2x2x4−2x3x4,Γ=A471x_{1}^{2} + x_{2}^{2} + x_{3}^{2} + x_{4}^{2} + 2x_{1} x_{2} + 2x_{1} x_{3} + 2x_{1} x_{4} - 2x_{2} x_{3} - - 2x_{2} x_{4} - 2x_{3} x_{4}, \quad \Gamma = \mathbf{A}_{471}. A471=[2−100−12−1−10−1200−102]\mathbf{A}_{471} = \left[\begin{smallmatrix} 2 & -1 & 0 & 0 \\ -1 & 2 & -1 & -1 \\ 0 & -1 & 2 & 0 \\ 0 & -1 & 0 & 2 \end{smallmatrix}\right].

Problem 32.34

Let in some basis ee of an nn-dimensional Euclidean space with Gram matrix Γ\Gamma a quadratic function k(x)\mathrm{k}(x) have matrix BB. Prove that an orthonormal basis in which k(x)\mathrm{k}(x) is diagonal, and its diagonal coefficients in this basis, are found as the solution of the generalized eigenvalue-eigenvector problem: Bξ=λΓξB\xi = \lambda \Gamma \xi (ξ∈Rn\xi \in \mathbb {R}^{n}).

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Problem 32.35

Let M−r\mathcal{M} - r-dimensional linear subspace of an nn-dimensional Euclidean space. The function k(x)\mathrm{k}(x) equals the square of the length of the orthogonal projection of the vector xx onto the subspace M\mathcal{M}. Prove that the function k(x)\mathrm{k}(x) is quadratic. Find the diagonal form that this function has in some orthonormal basis.

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Problem 32.36

Verify that at least one of the two given quadratic forms is sign-definite. Find a change of coordinates reducing these two forms simultaneously to diagonal form, and write this diagonal form for both forms.

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(1)

f=x12+2x1x2+3x22\mathrm{f} = x_{1}^{2} + 2x_{1} x_{2} + 3x_{2}^{2}, g=4x12+16x1x2+6x22\mathrm{g} = 4x_{1}^{2} + 16x_{1} x_{2} + 6x_{2}^{2}

(2)

f=2x12−3x1x2−52x22, g=2x12+6x1x2+5x22\mathrm{f} = 2x_{1}^{2} - 3x_{1} x_{2} - \frac{5}{2} x_{2}^{2}, \quad \mathrm{~ g} = 2x_{1}^{2} + 6x_{1} x_{2} + 5x_{2}^{2}

(3)

f=11x12−6x1x2+x22, g=13x12−10x1x2+3x22\mathrm{f} = 11x_{1}^{2} - 6x_{1} x_{2} + x_{2}^{2}, \quad \mathrm{~ g} = 13x_{1}^{2} - 10x_{1} x_{2} + 3x_{2}^{2}

(4)

f=9x12−10x1x2+3x22, g=2x1x2−x22\mathrm{f} = 9x_{1}^{2} - 10x_{1} x_{2} + 3x_{2}^{2}, \quad \mathrm{~ g} = 2x_{1} x_{2} - x_{2}^{2}

(5)

f=x12−2x1x2+x22, g=17x12+8x1x2+x22\mathrm{f} = x_{1}^{2} - 2x_{1} x_{2} + x_{2}^{2}, \quad \mathrm{~ g} = 17x_{1}^{2} + 8x_{1} x_{2} + x_{2}^{2}

(6)

f=x12+2x1x2+5x22, g=2x1x2−72x12−x22\mathrm{f} = x_{1}^{2} + 2x_{1} x_{2} + 5x_{2}^{2}, \quad \mathrm{~ g} = 2x_{1} x_{2} - \frac{7}{2} x_{1}^{2} - x_{2}^{2}

(7)

f=(1+46)x12+26x1x2, g=5x12+4x1x2+x22\mathrm{f} = (1 + 4\sqrt{6}) x_{1}^{2} + 2\sqrt{6} x_{1} x_{2}, \quad \mathrm{~ g} = 5x_{1}^{2} + 4x_{1} x_{2} + x_{2}^{2}

(8)

f=(1+2ma2+a)x12+2a2+ax1x2, g=(1+m2)x12+2mx1x2+x22\mathrm{f} = \left(1 + 2m\sqrt{a^{2} + a}\right) x_{1}^{2} + 2\sqrt{a^{2} + a} x_{1} x_{2}, \quad \mathrm{~ g} = \left(1 + m^{2}\right) x_{1}^{2} + 2mx_{1} x_{2} + x_{2}^{2}, where mm and aa are real parameters, a2+a⩾0a^{2} + a \geqslant 0

(9)

f=5x12+2x1x2+4x1x3+x22+4x2x3+4x32, g=5x12−−2x1x2+4x1x3+x22+2x32\mathrm{f} = 5x_{1}^{2} + 2x_{1} x_{2} + 4x_{1} x_{3} + x_{2}^{2} + 4x_{2} x_{3} + 4x_{3}^{2}, \quad \mathrm{~ g} = 5x_{1}^{2} - - 2x_{1} x_{2} + 4x_{1} x_{3} + x_{2}^{2} + 2x_{3}^{2}

(10)

f=15x22−4x32−10x1x2−8x1x3+22x2x3, g=x12−−2x1x3+4x22+4x2x3+5x32\mathrm{f} = 15x_{2}^{2} - 4x_{3}^{2} - 10x_{1} x_{2} - 8x_{1} x_{3} + 22x_{2} x_{3}, \quad \mathrm{~ g} = x_{1}^{2} - - 2x_{1} x_{3} + 4x_{2}^{2} + 4x_{2} x_{3} + 5x_{3}^{2}

(11)

(р) f=6x12+6x1x3+x22−6x2x3+6x32, g=2x12+2x1x3+x22−2x2x3+2x32\mathrm{f} = 6x_{1}^{2} + 6x_{1} x_{3} + x_{2}^{2} - 6x_{2} x_{3} + 6x_{3}^{2}, \mathrm{~ g} = 2x_{1}^{2} + 2x_{1} x_{3} + x_{2}^{2} - 2x_{2} x_{3} + 2x_{3}^{2}

(12)

f=2x12−2x1x2−2x1x3+x22+2x32, g=9x12−12x1x2−24x1x3+4x22+16x2x3+16x32\mathrm{f} = 2x_{1}^{2} - 2x_{1} x_{2} - 2x_{1} x_{3} + x_{2}^{2} + 2x_{3}^{2}, \quad \mathrm{~ g} = 9x_{1}^{2} - 12x_{1} x_{2} - 24x_{1} x_{3} + 4x_{2}^{2} + 16x_{2} x_{3} + 16x_{3}^{2}

(13)

f=x12+7x22+16x32+19x42−4x1x2+10x1x3−−10x1x4−26x2x3+8x2x4−2x3x4, g=−x12+2x1x2−2x22+4x2x3−5x32+6x3x4−10x42\mathrm{f} = x_{1}^{2} + 7x_{2}^{2} + 16x_{3}^{2} + 19x_{4}^{2} - 4x_{1} x_{2} + 10x_{1} x_{3} - - 10x_{1} x_{4} - 26x_{2} x_{3} + 8x_{2} x_{4} - 2x_{3} x_{4}, \quad \mathrm{~ g} = - x_{1}^{2} + 2x_{1} x_{2} - 2x_{2}^{2} + 4x_{2} x_{3} - 5x_{3}^{2} + 6x_{3} x_{4} - 10x_{4}^{2}

(14)

f=x12−4x2x3+4x32−4x3x4+4x42, g=x12−2x1x2+2x22−2x2x3+2x32−2x3x4+2x42\mathrm{f} = x_{1}^{2} - 4x_{2} x_{3} + 4x_{3}^{2} - 4x_{3} x_{4} + 4x_{4}^{2}, \quad \mathrm{~ g} = x_{1}^{2} - 2x_{1} x_{2} + 2x_{2}^{2} - 2x_{2} x_{3} + 2x_{3}^{2} - 2x_{3} x_{4} + 2x_{4}^{2}.

Problem 32.37

Prove that if among the linear combinations of two quadratic functions there is a positive definite one, then these two functions are simultaneously reducible to diagonal form. Show by an example that this condition is not necessary.

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Problem 32.38

In some basis ee of an nn-dimensional vector space, the quadratic functions f\mathrm{f} and g\mathrm{g} have matrices FF and GG, respectively. Let, in the basis e′\mathbf{e}^{\prime } given by the transition matrix SS from the basis ee, the function gg have canonical form ∑i=1nξi′2\sum_{i = 1}^{n}{\xi_{i}^{\prime }}^{2}, and the function f\mathrm{f} have diagonal form ∑i=1nλiξi2\sum_{i = 1}^{n} \lambda_{i}{\xi_{i}}^{2}. Prove that:

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(1)

det⁡(F−λG)=(det⁡S)2(λ1−λ)…(λn−λ)\operatorname {det}(F - \lambda G) = (\operatorname {det} S)^{2}\left(\lambda_{1} - \lambda \right) \ldots \left(\lambda_{n} - \lambda \right)

(2)

the vectors of the basis e′\mathbf{e}^{\prime } are found from the system of equations (F−−λG)ξ=(F - - \lambda G) \xi = o for each root λ\lambda of the equation det⁡(F−λG)=0\operatorname {det}(F - \lambda G) = 0.

Problem 32.39

Without finding the change of coordinates that reduces a positive definite quadratic form gg to canonical form, and a quadratic form ff to diagonal form, find this diagonal form of f\mathrm{f}.

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(1)

f=x12+2x1x2+x22, g=10x12+6x1x2+x22\mathrm{f} = x_{1}^{2} + 2x_{1} x_{2} + x_{2}^{2}, \quad \mathrm{~ g} = 10x_{1}^{2} + 6x_{1} x_{2} + x_{2}^{2}

(2)

f=89x12−42x1x2+5x22, g=41x12−18x1x2+2x22\mathrm{f} = 89x_{1}^{2} - 42x_{1} x_{2} + 5x_{2}^{2}, \quad \mathrm{~ g} = 41x_{1}^{2} - 18x_{1} x_{2} + 2x_{2}^{2}

(3)

f=7x1x2+31x22, g=x12+2x1x2+2x22\mathrm{f} = 7x_{1} x_{2} + 31x_{2}^{2}, \quad \mathrm{~ g} = x_{1}^{2} + 2x_{1} x_{2} + 2x_{2}^{2}

(4)

f=8x12−5x1x2+12x22, g=x12−x1x2+12x22\mathrm{f} = 8x_{1}^{2} - 5x_{1} x_{2} + \frac{1}{2} x_{2}^{2}, \quad \mathrm{~ g} = x_{1}^{2} - x_{1} x_{2} + \frac{1}{2} x_{2}^{2}.

Problem 32.40

Show that:

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(1)

if b(x,y)\mathrm{b}(\mathbf{x}, \mathbf{y}) is a bilinear function in an nn-dimensional complex arithmetic space, then the function h(x,y)=b(x,y‾)\mathrm{h}(\mathbf{x}, \mathbf{y}) = \mathrm{b}(\mathbf{x}, \overline{\mathbf{y}}) is Hermitian bilinear

(2)

if b (x, y) is a Hermitian bilinear function in the space Cn\mathcal{C}_{n}, then b(x,y)=h(x,y‾)\mathrm{b}(\mathbf{x}, \mathbf{y}) = \mathrm{h}(\mathbf{x}, \overline{\mathbf{y}}) is a bilinear function.

Problem 32.41

Reduce the following quadratic forms to canonical form:

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(1)

4x12−12ix1x2−9x224x_{1}^{2} - 12ix_{1} x_{2} - 9x_{2}^{2}

(2)

9x12+24(i+1)x1x2+16x229x_{1}^{2} + 24(i + 1) x_{1} x_{2} + 16x_{2}^{2}

(3)

x1x2x_{1} x_{2}

(4)

ε2x12−εx1x2+x22,ε=e2πi/3\varepsilon^{2} x_{1}^{2} - \varepsilon x_{1} x_{2} + x_{2}^{2}, \varepsilon = e^{2\pi i / 3}

(5)

(1+i)x12+(2+2i)x1x3+ix22+3x32(1 + i) x_{1}^{2} + (2 + 2i) x_{1} x_{3} + ix_{2}^{2} + 3x_{3}^{2}

(6)

x12+(2−2i)x1x2+2x1x3+2ix22+(2+2i)x2x3+(1+i)x32x_{1}^{2} + (2 - 2i) x_{1} x_{2} + 2x_{1} x_{3} + 2ix_{2}^{2} + (2 + 2i) x_{2} x_{3} + (1 + i) x_{3}^{2}

(7)

−x12−4ix1x2−(2−2i)x1x3+4x22−(4+4i)x2x3+2ix32- x_{1}^{2} - 4ix_{1} x_{2} - (2 - 2i) x_{1} x_{3} + 4x_{2}^{2} - (4 + 4i) x_{2} x_{3} + 2ix_{3}^{2}.

Problem 32.42

Form the matrices of the given Hermitian bilinear forms in an nn-dimensional space:

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(1)

−ix1yˉ1(n=1)- ix_{1} \bar{y}_{1} \quad (n = 1)

(2)

−ix1yˉ1(n=2)- ix_{1} \bar{y}_{1} \quad (n = 2)

(3)

3x1yˉ1+4ix1yˉ2−5x2yˉ1+ix2yˉ2(n=2)3x_{1} \bar{y}_{1} + 4ix_{1} \bar{y}_{2} - 5x_{2} \bar{y}_{1} + ix_{2} \bar{y}_{2} \quad (n = 2)

(4)

−3ix1yˉ1+2x1yˉ2+2x2yˉ1+(1−i)x2yˉ2(n=2)- 3ix_{1} \bar{y}_{1} + 2x_{1} \bar{y}_{2} + 2x_{2} \bar{y}_{1} + (1 - i) x_{2} \bar{y}_{2} \quad (n = 2)

(5)

(1+i)x1yˉ2+(1+i)x2yˉ1−5x2yˉ2(n=2)(1 + i) x_{1} \bar{y}_{2} + (1 + i) x_{2} \bar{y}_{1} - 5x_{2} \bar{y}_{2} \quad (n = 2)

(6)

(1+i)x1yˉ2+(1−i)x2yˉ1−5x2yˉ2(n=2)(1 + i) x_{1} \bar{y}_{2} + (1 - i) x_{2} \bar{y}_{1} - 5x_{2} \bar{y}_{2} \quad (n = 2)

(7)

x1yˉ1−3x2yˉ2+(2+i)x3yˉ3−ix1yˉ2+(4+i)x3yˉ1(n=3)x_{1} \bar{y}_{1} - 3x_{2} \bar{y}_{2} + (2 + i) x_{3} \bar{y}_{3} - ix_{1} \bar{y}_{2} + (4 + i) x_{3} \bar{y}_{1} \quad (n = 3)

(8)

2x1yˉ1−6x2yˉ2+(1+32)x3yˉ3+3x1yˉ2+3x2yˉ1+(2−5i)x1yˉ3+(2+5i)x3yˉ1+4ix2yˉ3−4ix3yˉ2(n=3)2x_{1} \bar{y}_{1} - 6x_{2} \bar{y}_{2} + (1 + 3\sqrt{2}) x_{3} \bar{y}_{3} + 3x_{1} \bar{y}_{2} + 3x_{2} \bar{y}_{1} + (2 - 5i) x_{1} \bar{y}_{3} + (2 + 5i) x_{3} \bar{y}_{1} + 4ix_{2} \bar{y}_{3} - 4ix_{3} \bar{y}_{2} \quad (n = 3)

(9)

∑i=1nxiyˉi\sum_{i = 1}^{n} x_{i} \bar{y}_{i}

Problem 32.43

Which of the Hermitian bilinear forms in problem 32. 42 are symmetric? Write the corresponding Hermitian quadratic forms.

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Problem 32.44

Write the Hermitian quadratic form having the given matrix:

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(1)

A47\mathbf{A}_{47}. A47=[5−2−28]\mathbf{A}_{47} = \left[\begin{smallmatrix} 5 & -2 \\ -2 & 8 \end{smallmatrix}\right].

(2)

A79\mathbf{A}_{79} (при ε=e2\pii/3\varepsilon = e^{2\pii / 3}). A79=[0εε−10]\mathbf{A}_{79} = \left[\begin{smallmatrix} 0 & \varepsilon \\ \varepsilon^{-1} & 0 \end{smallmatrix}\right].

(3)

A280\mathbf{A}_{280}. A280=[021282120]\mathbf{A}_{280} = \left[\begin{smallmatrix} 0 & 2 & 1 \\ 2 & 8 & 2 \\ 1 & 2 & 0 \end{smallmatrix}\right].

(4)

A491\mathbf{A}_{491}. A491=[3102i13−2i002i11−2i011]\mathbf{A}_{491} = \left[\begin{smallmatrix} 3 & 1 & 0 & 2 i \\ 1 & 3 & -2 i & 0 \\ 0 & 2 i & 1 & 1 \\ -2 i & 0 & 1 & 1 \end{smallmatrix}\right].

Problem 32.45

A Hermitian quadratic form is written in an orthonormal basis of an nn-dimensional unitary space. Find an orthonormal basis in which the given Hermitian quadratic form has diagonal form, and write this diagonal form:

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(1)

2∣x1∣2+ix1xˉ2−ix2xˉ1+2∣x2∣2(n=2)2\left|x_{1}\right|^{2} + ix_{1} \bar{x}_{2} - ix_{2} \bar{x}_{1} + 2\left|x_{2}\right|^{2} \quad (n = 2)

(2)

∣x1∣2+(3−4i)x1xˉ2+(3+4i)x2xˉ1+∣x2∣2(n=2)\left|x_{1}\right|^{2} + (3 - 4i) x_{1} \bar{x}_{2} + (3 + 4i) x_{2} \bar{x}_{1} + \left|x_{2}\right|^{2} \quad (n = 2)

(3)

∣x1∣2+εx1xˉ2+εˉx2xˉ1+∣x2∣2(ε=e2\pii/3)(n=2)\left|x_{1}\right|^{2} + \varepsilon x_{1} \bar{x}_{2} + \bar{\varepsilon } x_{2} \bar{x}_{1} + \left|x_{2}\right|^{2} \quad \left(\varepsilon = e^{2\pii / 3}\right) \quad (n = 2)

(4)

3∣x1∣2+3∣x2∣2−5∣x3∣2−ix1xˉ2+ix2xˉ1(n=3)3\left|x_{1}\right|^{2} + 3\left|x_{2}\right|^{2} - 5\left|x_{3}\right|^{2} - ix_{1} \bar{x}_{2} + ix_{2} \bar{x}_{1} \quad (n = 3)

(5)

∣x1∣2+∣x2∣2+∣x3∣2+x1xˉ2+x2xˉ1+ix1xˉ3−ix3xˉ1+ix2xˉ3−−ix3xˉ2(n=3)\left|x_{1}\right|^{2} + \left|x_{2}\right|^{2} + \left|x_{3}\right|^{2} + x_{1} \bar{x}_{2} + x_{2} \bar{x}_{1} + ix_{1} \bar{x}_{3} - ix_{3} \bar{x}_{1} + ix_{2} \bar{x}_{3} - - ix_{3} \bar{x}_{2} \quad (n = 3)

(6)

12∣x1∣2−(1+i)x1xˉ2−(1−i)x2xˉ1+2x1xˉ3+2x3xˉ1+(3+3i)x1xˉ4+(3−3i)x4xˉ1+12∣x2∣2+(1−i)x2xˉ3+(1+i)x3xˉ2−−2x2xˉ4−2x4xˉ2+8∣x3∣2−(1+i)x3xˉ4−(1−i)x4xˉ3+8∣x4∣2(n=4)12\left|x_{1}\right|^{2} - (1 + i) x_{1} \bar{x}_{2} - (1 - i) x_{2} \bar{x}_{1} + 2x_{1} \bar{x}_{3} + 2x_{3} \bar{x}_{1} + (3 + 3i) x_{1} \bar{x}_{4} + (3 - 3i) x_{4} \bar{x}_{1} + 12\left|x_{2}\right|^{2} + (1 - i) x_{2} \bar{x}_{3} + (1 + i) x_{3} \bar{x}_{2} - - 2x_{2} \bar{x}_{4} - 2x_{4} \bar{x}_{2} + 8\left|x_{3}\right|^{2} - (1 + i) x_{3} \bar{x}_{4} - (1 - i) x_{4} \bar{x}_{3} + 8\left|x_{4}\right|^{2} (n = 4).

Problem 32.46

Recover the symmetric Hermitian bilinear function h(x,y)\mathrm{h}(x, y) from the Hermitian quadratic function k(x)=h(x,x)\mathrm{k}(x) = \mathrm{h}(x, x).

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Problem 32.47

Prove that in the vector space of complex matrices of order nn the function k(X)=tr⁡(X⋅XˉT)\mathrm{k}(X) = \operatorname {tr}\left(X\cdot \bar{X}^{T}\right) is a positive definite Hermitian quadratic function.

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