Chapter 42

Lévy processes

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Problem 42.1

Let α∈(0,2)\alpha \in (0,2) and let XX be a Lévy process where b=σ=0b=\sigma =0 in the Lévy-Khintchine formula and the Lévy measure is m(dx)=c∣x∣−1−αdxm(d x)=c|x|^{-1-\alpha } d x. Show that if a>0a>0 and Yt=a1/αXatY_{t}=a^{1 / \alpha } X_{a t}, then YY has the same law as XX. The process XX is known as a symmetric stable process of index α\alpha.

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Problem 42.2

Suppose Wt=(Wt1,Wt2)W_{t}=\left(W_{t}^{1}, W_{t}^{2}\right) is a two-dimensional Brownian motion started at 0 . Let τs=\tau_{s}= inf⁡{t>0:Wt1>s}\inf \left\{ t>0: W_{t}^{1}>s\right\}. Prove that Wτt2W_{\tau_{t}}^{2} is a Lévy process and determine the Lévy measure.

Hint: Use scaling to make a guess.

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Problem 42.3

Let WW be a one-dimensional Brownian motion and let L0L^{0} be the local time at 0 . Let TtT_{t} be the inverse of L0L^{0}, that is, Tt=inf⁡{s:Ls0≥t}T_{t}=\inf \left\{ s: L_{s}^{0} \geq t\right\}. Show TtT_{t} is a Lévy process and determine the Lévy measure.

Hint: Use scaling to get started.

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Problem 42.4

Let WtW_{t} be a one-dimensional Brownian motion, LtyL_{t}^{y} the local time at level yy, and TtT_{t} the inverse local time at 0 , that is, Tt=inf⁡{s:Ls0≥t}T_{t}=\inf \left\{ s: L_{s}^{0} \geq t\right\}. Let x>0x>0 be fixed. Prove that LTtxL_{T_{t}}^{x} is a Lévy process.

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Problem 42.5

Let XX be a Lévy process with Lévy measure mm. Prove that if AA and BB are disjoint closed sets, then

Ex[∑s≤t  1A(Xs−)  1B(Xs)]=Ex[∫0t  1A(Xs)m(B−Xs)ds] \mathbb {E}_{x}\left[\sum _{s \leq t} \; \mathbb {1}_{A}\left(X_{s-}\right) \; \mathbb {1}_{B}\left(X_{s}\right)\right]=\mathbb {E}_{x}\left[\int _{0}^{t} \; \mathbb {1}_{A}\left(X_{s}\right) m\left(B-X_{s}\right) d s\right]

for each xx, where B−y={z−y:z∈B}B-y=\left\{ z-y: z \in B\right\}. This is the Lévy system formula in the case of Lévy processes. There is an analogous formula for Hunt processes.

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Problem 42.6

A stable subordinator XX of order α∈(0,1)\alpha \in (0,1) is a Lévy process whose characteristic function is given by (42.6), where b=σ2=0b=\sigma^{2}=0 and m(dx)=c  1(x>0)∣x∣−α−1dxm(d x)=c \; \mathbb {1}_{(x>0)}|x|^{-\alpha -1} d x. Suppose XX is a stable subordinator of index α\alpha and WW is a Brownian motion. Show that, up to a deterministic time change, the process Zt=WXtZ_{t}=W_{X_{t}} is a symmetric stable process of index 2α2 \alpha.

Hint: Start by using scaling.

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Problem 42.7

Let ZtZ_{t} be a symmetric stable process of order α∈(0,2)\alpha \in (0,2). Show that if ε>0\varepsilon >0, then

lim⁡t→∞∣Zt∣tα+ε=0, a.s.  \lim _{t \rightarrow \infty } \frac{\left|Z_{t}\right|}{t^{\alpha +\varepsilon }}=0, \quad \text{ a.s. }
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