Chapter 27

Brownian excursions

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Problem 27.1

Let WW be a Brownian motion, x>0x>0, and T=inf⁡{t>0:Wt=x}T=\inf \left\{ t>0: W_{t}=x\right\}. If LtxL_{t}^{x} is the local time at xx, show that the distribution of LTxL_{T}^{x} is an exponential random variable. Determine the parameter of this exponential random variable.

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Problem 27.2

Let WW be a one-dimensional Brownian motion. This exercise asks you to prove that the normalized number of downcrossings by time tt converges to local time at 0 . If a>0a>0, let S0=0S_{0}=0, T0=inf⁡{t:Wt=a}T_{0}=\inf \left\{ t: W_{t}=a\right\}, and for i≥1i \geq 1,

Si=inf⁡{t>Ti−1:Wt=0},Ti=inf⁡{t>Si:Wt=a} S_{i}=\inf \left\{ t>T_{i-1}: W_{t}=0\right\} , \quad T_{i}=\inf \left\{ t>S_{i}: W_{t}=a\right\}

Then Dt(a)D_{t}(a), the number of downcrossings up to time tt, is defined to be sup⁡{k:Sk≤t}\sup \left\{ k: S_{k} \leq t\right\}. Prove that there exists a constant cc such that

lim⁡a→0aDt(a)=cLt0, a.s.  \lim _{a \rightarrow 0} a D_{t}(a)=c L_{t}^{0}, \quad \text{ a.s. }

where Lt0L_{t}^{0} is local time at 0 of WW. Determine cc.

Hint: Use Exercise 18.5.

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Problem 27.3

Let (Xt,P[x])\left(X_{t}, \mathbb {P}[x]\right) be a Brownian motion.

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(1)

Use the reflection principle to find

P0(Xs>−a for all s≤r). \mathbb {P}_{0}\left(X_{s}>-a \text{ for all } s \leq r\right) .

This is the same as Pa(T0>r)\mathbb {P}_{a}\left(T_{0}>r\right), where T0T_{0} is the first time the Brownian motion hits 0.

(2)

Let

A(a,r)={f∈E:sup⁡f(t)>a,σf>r},B(r)={f∈E:σf>r,sup⁡f(t)>0}, A(a, r)=\left\{ f \in \mathcal{E}: \sup f(t)>a, \sigma _{f}>r\right\} , \quad B(r)=\left\{ f \in \mathcal{E}: \sigma _{f}>r, \sup f(t)>0\right\} ,

and

C(a)={f∈E:sup⁡f(t)>a}. C(a)=\left\{ f \in \mathcal{E}: \sup f(t)>a\right\} .

Prove that

m(B(r))=lim⁡a→0m(A(a,r))=lim⁡a→0[m(C(a))×Pa(T0>r)] m(B(r))=\lim _{a \rightarrow 0} m(A(a, r))=\lim _{a \rightarrow 0}\left[m(C(a)) \times \mathbb {P}_{a}\left(T_{0}>r\right)\right]

and use this and (1) to compute m(B(r))m(B(r)). By symmetry, m({f∈E:σf>r})m\left(\left\{ f \in \mathcal{E}: \sigma_{f}>r\right\} \right) will be twice the value of m(B(r))m(B(r)).

Remark.
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Let E\mathcal{E} be the collection of continuous functions ff with domain [0,∞)[0, \infty ) such that there exists a positive real σf\sigma_{f} with f(0)=0f(0)=0, f(σf)=0f\left(\sigma_{f}\right)=0, f(t)≠0f(t) \neq 0 if t∈(0,σf)t \in \left(0, \sigma_{f}\right), and f(t)=0f(t)=0 if t>σft>\sigma_{f} (furnished with the supremum norm). Given a Borel subset AA of E\mathcal{E}, the Brownian motion WW has had an excursion in AA by time tt if there exists a time uu and a function f∈Af \in A such that u+σf≤tu+\sigma_{f} \leq t and Wu+s(ω)=f(s)W_{u+s}(\omega )=f(s) for all s≤σfs \leq \sigma_{f}. Let Kt(A)K_{t}(A) be the number of excursions of WW in AA by time tt. With Tr=inf⁡{t>0:Lt0≥r}T_{r}=\inf \left\{ t>0: L_{t}^{0} \geq r\right\} and Nr(A)=KTr(A)N_{r}(A)=K_{T_{r}}(A), the excursion measure is m(A)=E0[N1(A)]m(A)=\mathbb {E}_{0}\left[N_{1}(A)\right].

Problem 27.4

Let WW be a Brownian motion. Let Et(r)E_{t}(r) be the number of excursions of length larger than rr that have been completed by time tt. An excursion of length larger than rr means that σf>r\sigma_{f}>r. Show that there exists a constant cc such that

lim⁡r→0rEt(r)=cLt0, a.s.  \lim _{r \rightarrow 0} \sqrt{r} E_{t}(r)=c L_{t}^{0}, \quad \text{ a.s. }

Determine cc.

One interesting point here is that this shows that Lt0L_{t}^{0} is determined entirely by the zero set Z(ω)={t:Wt(ω)=0}Z(\omega )=\left\{ t: W_{t}(\omega )=0\right\}.

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Problem 27.5

Let δ>0\delta >0 and Aδ={f∈E:sup⁡t∣f(t)∣>δ}A_{\delta }=\left\{ f \in \mathcal{E}: \sup_{t}\left|f(t)\right|>\delta \right\}. Let S1=inf⁡{t:Kt(Aδ)=1}S_{1}=\inf \left\{ t: K_{t}\left(A_{\delta }\right)=1\right\} and S2=inf⁡{t>S1:Kt(Aδ)=2}S_{2}=\inf \left\{ t>S_{1}: K_{t}\left(A_{\delta }\right)=2\right\}. Thus S1S_{1} and S2S_{2} are the times the first and second excursions in AδA_{\delta } have been completed. Let Y1(t)Y_{1}(t) be the excursion completed at time S1S_{1} and define Y2(t)Y_{2}(t) similarly. To be more precise, if R1=sup⁡{t<S1:Wt=0}R_{1}=\sup \left\{ t<S_{1}: W_{t}=0\right\}, then Y1(s)=WR1+sY_{1}(s)=W_{R_{1}+s} if s≤S1−R1s \leq S_{1}-R_{1} and Y1(s)Y_{1}(s) is equal to 0 for all s≥S1−R1s \geq S_{1}-R_{1}.

Prove that Y1Y_{1} and Y2Y_{2} are independent.

Hint: Use the strong Markov property at time S1S_{1}.

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