Local times
[10/0%]Suppose is with compact support and
Show that is and .
Let be the jointly continuous local times of a Brownian motion . Show
Show the null set can be taken to be independent of . Thus there is no need to take a subsequence to get almost sure convergence to .
Let be a Brownian motion and fix . Show that the function is continuous, a.s., but that the function is not continuous.
Let be a filtration satisfying the usual conditions. Suppose is a Brownian motion and , where for all , a.s., and is an increasing continuous adapted process such that increases only at those times when . Suppose also that , where for all , a.s., and is an increasing continuous adapted process that increases only when . Show that and , a.s., for all .
Let be a Brownian motion and the local time at 0 . Since is increasing, for each there is a Lebesgue-Stieltjes measure . Show that the support of is equal to .
Since Theorem 14.1(2) states that does not increase when is not equal to 0 , what you need to show is that with probability one, if and , then .
Use Tanaka's formula to show that if is the local time of Brownian motion at level , , and , then
If is the local time of a Brownian motion at 0 , show that has the same law as .
Let be a Brownian motion with local times . Set . Let . Prove that there exist constants such that if is any finite stopping time,
The constants can depend on , but not on .
Hint: Use Exercise 12.11.
This exercise defines the local time of a continuous martingale. If is a continuous martingale, then is a submartingale and so equals a martingale plus an increasing process. The increasing process is called the local time of at 0 .
Prove the analog of Tanaka's formula.
Define the local time of at . Prove that is jointly continuous in and .
Prove that
if is non-negative and measurable.
This exercise is a complement to Exercise 7.8. Let be a Brownian motion and let us define , the zero set. Let and let . Fix and let be any countable covering of by closed intervals such that the interiors of the 's are pairwise disjoint and the length of each is less than or equal to . We write .
Let . Since has the same law of the maximum of Brownian motion, there exists a (depending on ) such that
for each . Write
Show that this implies that the Hausdorff dimension of is at least .