Section 8.1

Adjoint operators in a Banach space

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Problem 8.1

Prove Theorem 8.1.

Theorem 8.1 (F. Riesz, 1910): the norm of the operator A′A^{\prime } equals the norm of the operator AA, i.e., the conjugation operation preserves the norm.

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Problem 8.2

Let X,Y,ZX, Y, Z be normed spaces, A,B∈B(X,Y)A, B \in \mathcal{B}(X, Y), C∈B(Y,Z),α,β∈CC \in \mathcal{B}(Y, Z), \alpha , \beta \in \mathbb {C}. Prove that

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(a)

(αA+βB)′=αA′+βB′(\alpha A+\beta B)^{\prime } = \alpha A^{\prime }+\beta B^{\prime }; \quad

(b)

(CA)′=A′C′(C A)^{\prime } = A^{\prime } C^{\prime }.

Problem 8.3

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y), and let a sequence gn⇀∗gg_{n} \stackrel{*}{\rightharpoonup } g in Y∗Y^{*}. Prove that A′gn⇀∗A′gA^{\prime } g_{n} \stackrel{*}{\rightharpoonup } A^{\prime } g in X∗X^{*}.

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Problem 8.4

Find the adjoint operators in the following cases.

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(a)

XX is an arbitrary normed space, A=λI,λ∈CA = \lambda I, \lambda \in \mathbb {C}.

(b)

XX is a finite-dimensional space over the field C\mathbb {C}, the operator AA is written as a matrix MM in some linear basis. Let the same basis be chosen in the space X∗=XX^{*} = X. Find the matrix of the operator A′A^{\prime }.

(c)

XX and YY are Banach spaces, X⊂YX \subset Y as a linear subspace, ∥⋅∥Y≺∥⋅∥X\left\| \cdot \right\|_{Y} \prec \left\| \cdot \right\|_{X} on X,J∈B(X,Y)X, J \in \mathcal{B}(X, Y) is the embedding operator, i.e., J:x↦xJ: x \mapsto x;

(d)

X=X0⊕X1X = X_{0} \oplus X_{1} is a Banach space, X0,X1X_{0}, X_{1} are its closed subspaces, P∈B(X)P \in \mathcal{B}(X) is the operator of projection onto X0X_{0} along X1X_{1}.

Problem 8.5

Find the adjoint operator A′A^{\prime } for the operator AA in the spaces lp,p∈[1,∞)l_{p}, p \in [1, \infty ), and c0c_{0}:

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(a)

A(x1,x2,…)=(x2,x3,…)A\left(x_{1}, x_{2}, \ldots \right) = \left(x_{2}, x_{3}, \ldots \right), i.e., A=TlA = T_{l} is the left shift;

(b)

A(x1,x2,…)=(0,x1,x2,…)A\left(x_{1}, x_{2}, \ldots \right) = \left(0, x_{1}, x_{2}, \ldots \right), i.e., A=TrA = T_{r} is the right shift;

(c)

A(x1,x2,…)=(λ1x1,λ2x2,…),{λn}n=1∞∈l∞A\left(x_{1}, x_{2}, \ldots \right) = \left(\lambda_{1} x_{1}, \lambda_{2} x_{2}, \ldots \right),\left\{ \lambda_{n}\right\}_{n = 1}^{\infty } \in l_{\infty };

(d)

A(x1,x2,…)=(x2,x32,…,xn+1n,…)A\left(x_{1}, x_{2}, \ldots \right) = \left(x_{2}, \frac{x_{3}}{2}, \ldots , \frac{x_{n+1}}{n}, \ldots \right).

Problem 8.6

Find the adjoint operator A′A^{\prime } for the following operators AA:

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(a)

A∈B(C[0,1]),(Ax)(t)=a(t)x(t),a∈C[0,1];A \in \mathcal{B}(C[0,1]),(A x)(t) = a(t) x(t), a \in C[0,1] ;

(b)

A∈B(Lp[0,1]),p∈[1,∞),(Ax)(t)=a(t)x(t),a∈L∞[0,1]A \in \mathcal{B}\left(L_{p}[0,1]\right), p \in [1, \infty ),(A x)(t) = a(t) x(t), a \in L_{\infty }[0,1];

(c)

A∈B(Lp[0,1]),p∈[1,∞),(Ax)(t)=∫0tx(s)dsA \in \mathcal{B}\left(L_{p}[0,1]\right), p \in [1, \infty ),(A x)(t) = \int_{0}^{t} x(s) d s;

(d)

A∈B(Lp[0,1]),p∈[1,∞)A \in \mathcal{B}\left(L_{p}[0,1]\right), p \in [1, \infty ),

(Ax)(t)={x(t+a), if t+a⩽1x(t+a−1), if t+a>1 (A x)(t) = \begin{cases} x(t+a), & \text{ if } t+a \leqslant 1 \\ x(t+a-1), & \text{ if } t+a > 1 \end{cases}

where a∈[0,1]a \in [0,1];

(e)

A∈B(C[0,1]),(Ax)(t)=∫01K(t,s)x(s)dsA \in \mathcal{B}(C[0,1]),(A x)(t) = \int_{0}^{1} K(t, s) x(s) d s, where K∈C([0,1]2)K \in C\left([0,1]^{2}\right);

(f)

A∈B(C[0,2])A \in \mathcal{B}(C[0,2]),

(Ax)(t)={x(t), if t∈[0,1],x(1), if t∈[1,2]; (A x)(t) = \begin{cases} x(t), & \text{ if } t \in [0,1], \\ x(1), & \text{ if } t \in [1,2] ; \end{cases}
(g)

A∈B(C1[0,1],C[0,1]),(Ax)(t)=x′(t)A \in \mathcal{B}\left(C^{1}[0,1], C[0,1]\right),(A x)(t) = x^{\prime }(t);

(h)

A∈B(C[0,1]),(Ax)(t)=x(0)+tx(1)+t2∫01x(s)dsA \in \mathcal{B}(C[0,1]),(A x)(t) = x(0)+t x(1)+t^{2} \int_{0}^{1} x(s) d s.

Problem 8.7

Find the adjoint operator A′A^{\prime } for the operator AA in the space C[a,b]:(Ax)(t)=∑i=1nαi(t)fi(x)C[a, b]:(A x)(t) = \sum_{i = 1}^{n} \alpha_{i}(t) f_{i}(x), where αi∈C[a,b]\alpha_{i} \in C[a, b], fi∈(C[a,b])∗f_{i} \in (C[a, b])^{*}, fi(x)=∫abx(t)dwi(t),wi∈BV0[0,1]f_{i}(x) = \int_{a}^{b} x(t) d w_{i}(t), w_{i} \in B V_{0}[0,1].

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Problem 8.8

Let the operator SS in c0∗=l1c_{0}^{*} = l_{1} be given by the formula S:(x1,x2,x3,…)↦(∑k=1∞xk,x2,x3,…)S:\left(x_{1}, x_{2}, x_{3}, \ldots \right) \mapsto \left(\sum_{k = 1}^{\infty } x_{k}, x_{2}, x_{3}, \ldots \right). Prove that SS is a linear isomorphism in l1l_{1}, but is not the adjoint of any operator T∈B(c0)T \in \mathcal{B}\left(c_{0}\right).

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Problem 8.9

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y). Denote the canonical embeddings πX:X↪X∗∗,πY:Y↪Y∗∗\pi_{X}: X \hookrightarrow X^{* *}, \pi_{Y}: Y \hookrightarrow Y^{* *}. Prove that A′′∘πX=πY∘AA^{\prime \prime } \circ \pi_{X} = \pi_{Y} \circ A.

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Problem 8.10

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y). Prove that

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(a)

if Im⁡A‾=Y\overline{\operatorname {Im} A} = Y, then Ker⁡A′={0}\operatorname {Ker} A^{\prime } = \left\{ 0\right\};

(b)

if Ker⁡A′‾={0}\overline{\operatorname {Ker} A^{\prime }} = \left\{ 0\right\}, then Im⁡A‾=Y\overline{\operatorname {Im} A} = Y;

(c)

if Im⁡A′‾=X∗\overline{\operatorname {Im} A^{\prime }} = X^{*}, then Ker⁡A={0}\operatorname {Ker} A = \left\{ 0\right\};

(d)

if XX is reflexive and Ker⁡A={0}\operatorname {Ker} A = \left\{ 0\right\}, then Im⁡A′‾=X∗\overline{\operatorname {Im} A^{\prime }} = X^{*}. Give an example of a non-reflexive space XX and an operator A∈B(X)A \in \mathcal{B}(X) with Ker⁡A={0}\operatorname {Ker} A = \left\{ 0\right\} and Im⁡A′‾≠X∗\overline{\operatorname {Im} A^{\prime }} \neq X^{*}.

Problem 8.11

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y). Prove that (Im⁡A)⊥=Ker⁡A′(\operatorname {Im} A)^{\perp } = \operatorname {Ker} A^{\prime }, and (Ker⁡A)⊥⊇Im⁡A′‾(\operatorname {Ker} A)^{\perp } \supseteq \overline{\operatorname {Im} A^{\prime }} (recall that for an arbitrary set M⊂XM \subset X the set M⊥={f∈X∗:f(x)=0 for every x∈M}M^{\perp } = \left\{ f \in X^{*}: f(x) = 0 \text{ for every } x \in M\right\}). Give an example where the last inclusion is strict.

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Problem 8.12

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y). Prove that if AA is a surjection, then (Ker⁡A)⊥=Im⁡A′(\operatorname {Ker} A)^{\perp } = \operatorname {Im} A^{\prime }.

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Problem 8.13

Let XX and YY be Banach spaces, A∈B(X,Y)A \in \mathcal{B}(X, Y). Prove that (Im⁡A′)⊥=Ker⁡A,(Ker⁡A′)⊥=Im⁡A‾\left(\operatorname {Im} A^{\prime }\right)^{\perp } = \operatorname {Ker} A,\left(\operatorname {Ker} A^{\prime }\right)^{\perp } = \overline{\operatorname {Im} A} (here for a set M⊂X∗M \subset X^{*} we denote M⊥={x∈X:f(x)=0 for every f∈M}M^{\perp } = \left\{ x \in X: f(x) = 0\text{ for every }f \in M\right\}).

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Problem 8.14

Let XX and YY be Banach spaces, An→sAA_{n} \xrightarrow {s} A in B(X,Y)\mathcal{B}(X, Y). Does the sequence {An′}n=1∞\left\{ A_{n}^{\prime }\right\}_{n = 1}^{\infty } converge strongly to A′A^{\prime } in B(Y∗,X∗)\mathcal{B}\left(Y^{*}, X^{*}\right)? Does it converge weakly? Answer the same questions under the assumption that XX or YY is reflexive.

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