Chapter 3

Integration

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Problem 3A.1

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f:X→[0,∞]f: X \rightarrow [0, \infty ] is an S\mathcal{S}-measurable function such that ∫fdμ<∞\int f d \mu < \infty. Explain why

inf⁡Ef=0 \inf _{E} f = 0

for each set E∈SE \in \mathcal{S} with μ(E)=∞\mu (E) = \infty.

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Problem 3A.2

Suppose XX is a set, S\mathcal{S} is a σ\sigma-algebra on XX, and c∈Xc \in X. Define the Dirac measure δc\delta_{c} on (X,S)(X, \mathcal{S}) by

δc(E)={1 if c∈E0 if c∉E \delta _{c}(E) = \begin{cases} 1 & \text{ if } c \in E \\ 0 & \text{ if } c \notin E\end{cases}

Prove that if f:X→[0,∞]f: X \rightarrow [0, \infty ] is S\mathcal{S}-measurable, then ∫fdδc=f(c)\int f d \delta_{c} = f(c).

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Remark.
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Careful: {c}\left\{ c\right\} may not be in S\mathcal{S}.

Problem 3A.3

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f:X→[0,∞]f: X \rightarrow [0, \infty ] is an S\mathcal{S}-measurable function. Prove that

∫fdμ>0 if and only if μ({x∈X:f(x)>0})>0 \int f d \mu > 0 \text{ if and only if } \mu (\left\{ x \in X: f(x) > 0\right\} ) > 0
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Problem 3A.4

Give an example of a Borel measurable function f:[0,1]→(0,∞)f:[0,1] \rightarrow (0, \infty ) such that L(f,[0,1])=0L(f,[0,1]) = 0.

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Remark.
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Recall that L(f,[0,1])L(f,[0,1]) denotes the lower Riemann integral, which was defined in Section 1A. If λ\lambda is Lebesgue measure on [0,1][0,1], then the previous exercise states that ∫fdλ>0\int f d \lambda > 0 for this function ff, which is what we expect of a positive function. Thus even though both L(f,[0,1])L(f,[0,1]) and ∫fdλ\int f d \lambda are defined by taking the supremum of approximations from below, Lebesgue measure captures the right behavior for this function ff and the lower Riemann integral does not.

Problem 3A.5

Verify the assertion that integration with respect to counting measure is summation (Example 3.6).

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Problem 3A.6

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space, f:X→[0,∞]f: X \rightarrow [0, \infty ] is S\mathcal{S}-measurable, and PP and P′P^{\prime } are S\mathcal{S}-partitions of XX such that each set in P′P^{\prime } is contained in some set in PP. Prove that L(f,P)≤L(f,P′)\mathcal{L}(f, P) \leq \mathcal{L}\left(f, P^{\prime }\right).

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Problem 3A.7

Suppose XX is a set, S\mathcal{S} is the σ\sigma-algebra of all subsets of XX, and w:X→[0,∞]w: X \rightarrow [0, \infty ] is a function. Define a measure μ\mu on (X,S)(X, \mathcal{S}) by

μ(E)=∑x∈Ew(x) \mu (E) = \sum _{x \in E} w(x)

for E⊆XE \subseteq X. Prove that if f:X→[0,∞]f: X \rightarrow [0, \infty ] is a function, then

∫fdμ=∑x∈Xw(x)f(x) \int f d \mu = \sum _{x \in X} w(x) f(x)

where the infinite sums above are defined as the supremum of all sums over finite subsets of EE (first sum) or XX (second sum).

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Problem 3A.8

Suppose λ\lambda denotes Lebesgue measure on R\mathbb {R}. Give an example of a sequence f1,f2,…f_{1}, f_{2}, \ldots of simple Borel measurable functions from R\mathbb {R} to [0,∞)[0, \infty ) such that lim⁡k→∞fk(x)=0\lim_{k \rightarrow \infty } f_{k}(x) = 0 for every x∈Rx \in \mathbb {R} but lim⁡k→∞∫fkdλ=1\lim_{k \rightarrow \infty } \int f_{k} d \lambda = 1.

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Problem 3A.9

Suppose μ\mu is a measure on a measurable space (X,S)(X, \mathcal{S}) and f:X→[0,∞]f: X \rightarrow [0, \infty ] is an S\mathcal{S}-measurable function. Define ν:S→[0,∞]\nu : \mathcal{S} \rightarrow [0, \infty ] by

ν(A)=∫χAfdμ \nu (A) = \int \chi _{A} f d \mu

for A∈SA \in \mathcal{S}. Prove that ν\nu is a measure on (X,S)(X, \mathcal{S}).

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Problem 3A.10

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f1,f2,…f_{1}, f_{2}, \ldots is a sequence of nonnegative S\mathcal{S}-measurable functions. Define f:X→[0,∞]f: X \rightarrow [0, \infty ] by f(x)=∑k=1∞fk(x)f(x) = \sum_{k = 1}^{\infty } f_{k}(x). Prove that

∫fdμ=∑k=1∞∫fkdμ \int f d \mu = \sum _{k = 1}^{\infty } \int f_{k} d \mu
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Problem 3A.11

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f1,f2,…f_{1}, f_{2}, \ldots are S\mathcal{S}-measurable functions from XX to R\mathbb {R} such that ∑k=1∞∫∣fk∣dμ<∞\sum_{k = 1}^{\infty } \int \left|f_{k}\right| d \mu < \infty. Prove that there exists E∈SE \in \mathcal{S} such that μ(X\E)=0\mu (X \backslash E) = 0 and lim⁡k→∞fk(x)=0\lim_{k \rightarrow \infty } f_{k}(x) = 0 for every x∈Ex \in E.

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Problem 3A.12

Show that there exists a Borel measurable function f:R→(0,∞)f: \mathbb {R} \rightarrow (0, \infty ) such that ∫χIfdλ=∞\int \chi_{I} f d \lambda = \infty for every nonempty open interval I⊆RI \subseteq \mathbb {R}, where λ\lambda denotes Lebesgue measure on R\mathbb {R}.

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Problem 3A.13

Give an example to show that the Monotone Convergence Theorem (3.11) can fail if the hypothesis that f1,f2,…f_{1}, f_{2}, \ldots are nonnegative functions is dropped.

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Problem 3A.14

Give an example to show that the Monotone Convergence Theorem can fail if the hypothesis of an increasing sequence of functions is replaced by a hypothesis of a decreasing sequence of functions.

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Remark.
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This exercise shows that the Monotone Convergence Theorem should be called the Increasing Convergence Theorem. However, see Exercise 20.

Problem 3A.15

Suppose λ\lambda is Lebesgue measure on R\mathbb {R} and f:R→[−∞,∞]f: \mathbb {R} \rightarrow [-\infty , \infty ] is a Borel measurable function such that ∫fdλ\int f d \lambda is defined.

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(a)

For t∈Rt \in \mathbb {R}, define ft:R→[−∞,∞]f_{t}: \mathbb {R} \rightarrow [-\infty , \infty ] by ft(x)=f(x−t)f_{t}(x) = f(x-t). Prove that ∫ftdλ=∫fdλ\int f_{t} d \lambda = \int f d \lambda for all t∈Rt \in \mathbb {R}.

(b)

For t∈Rt \in \mathbb {R}, define ft:R→[−∞,∞]f_{t}: \mathbb {R} \rightarrow [-\infty , \infty ] by ft(x)=f(tx)f_{t}(x) = f(t x). Prove that ∫ftdλ=1∣t∣∫fdλ\int f_{t} d \lambda = \frac{1}{\left|t\right|} \int f d \lambda for all t∈R\{0}t \in \mathbb {R} \backslash \left\{ 0\right\}.

Problem 3A.16

Suppose S\mathcal{S} and T\mathcal{T} are σ\sigma-algebras on a set XX and S⊆T\mathcal{S} \subseteq \mathcal{T}. Suppose μ1\mu_{1} is a measure on (X,S),μ2(X, \mathcal{S}), \mu_{2} is a measure on (X,T)(X, \mathcal{T}), and μ1(E)=μ2(E)\mu_{1}(E) = \mu_{2}(E) for all E∈SE \in \mathcal{S}. Prove that if f:X→[0,∞]f: X \rightarrow [0, \infty ] is S\mathcal{S}-measurable, then ∫fdμ1=∫fdμ2\int f d \mu_{1} = \int f d \mu_{2}.

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Problem 3A.17

Suppose that (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f1,f2,…f_{1}, f_{2}, \ldots is a sequence of nonnegative S\mathcal{S}-measurable functions on XX. Define a function f:X→[0,∞]f: X \rightarrow [0, \infty ] by f(x)=lim inf⁡k→∞fk(x)f(x) = \liminf_{k \rightarrow \infty } f_{k}(x).

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(a)

Show that ff is an S\mathcal{S}-measurable function.

(b)

Prove that

∫fdμ≤lim inf⁡k→∞∫fkdμ \int f d \mu \leq \liminf _{k \rightarrow \infty } \int f_{k} d \mu
(c)

Give an example showing that the inequality in (b) can be a strict inequality.

Remark.
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For x1,x2,…x_{1}, x_{2}, \ldots a sequence in [−∞,∞][-\infty , \infty ], define lim inf⁡k→∞xk\liminf_{k \rightarrow \infty } x_{k} by

lim inf⁡k→∞xk=lim⁡k→∞inf⁡{xk,xk+1,…}. \liminf _{k \rightarrow \infty } x_{k} = \lim _{k \rightarrow \infty } \inf \left\{ x_{k}, x_{k+1}, \ldots \right\} .

Note that inf⁡{xk,xk+1,…}\inf \left\{ x_{k}, x_{k+1}, \ldots \right\} is an increasing function of kk; thus the limit above on the right exists in [−∞,∞][-\infty , \infty ].

The result in (b) is called Fatou's Lemma. Some textbooks prove Fatou's Lemma and then use it to prove the Monotone Convergence Theorem. Here we are taking the reverse approach—you should be able to use the Monotone Convergence Theorem to give a clean proof of Fatou's Lemma.

Problem 3A.18

Give an example of a sequence x1,x2,…x_{1}, x_{2}, \ldots of real numbers such that

lim⁡n→∞∑k=1nxk exists in R \lim _{n \rightarrow \infty } \sum _{k = 1}^{n} x_{k} \text{ exists in } \mathbb {R}

but ∫xdμ\int x d \mu is not defined, where μ\mu is counting measure on N\mathbb {N} and xx is the function from N\mathbb {N} to R\mathbb {R} defined by x(k)=xkx(k) = x_{k}.

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Problem 3A.19

Show that if (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f:X→[0,∞)f: X \rightarrow [0, \infty ) is S\mathcal{S}-measurable, then

μ(X)inf⁡Xf≤∫fdμ≤μ(X)sup⁡Xf \mu (X) \inf _{X} f \leq \int f d \mu \leq \mu (X) \sup _{X} f
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Problem 3A.20

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f1,f2,…f_{1}, f_{2}, \ldots is a monotone (meaning either increasing or decreasing) sequence of S\mathcal{S}-measurable functions. Define f:X→[−∞,∞]f: X \rightarrow [-\infty , \infty ] by

f(x)=lim⁡k→∞fk(x) f(x) = \lim _{k \rightarrow \infty } f_{k}(x)

Prove that if ∫∣f1∣dμ<∞\int \left|f_{1}\right| d \mu < \infty, then

lim⁡k→∞∫fkdμ=∫fdμ \lim _{k \rightarrow \infty } \int f_{k} d \mu = \int f d \mu
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Problem 3A.21

Henri Lebesgue wrote the following about his method of integration: I have to pay a certain sum, which I have collected in my pocket. I take the bills and coins out of my pocket and give them to the creditor in the order I find them until I have reached the total sum. This is the Riemann integral. But I can proceed differently. After I have taken all the money out of my pocket I order the bills and coins according to identical values and then I pay the several heaps one after the other to the creditor. This is my integral.

Use 3.15 to explain what Lebesgue meant and to explain why integration of a function with respect to a measure can be thought of as partitioning the range of the function, in contrast to Riemann integration, which depends upon partitioning the domain of the function.

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Remark.
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3.15 (integral of a linear combination of characteristic functions): Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space, E1,…,En∈SE_{1}, \ldots , E_{n} \in \mathcal{S}, and c1,…,cn∈[0,∞]c_{1}, \ldots , c_{n} \in [0, \infty ]. Then ∫(∑k=1nckχEk)dμ=∑k=1nckμ(Ek)\int \left(\sum_{k = 1}^{n} c_{k} \chi_{E_{k}}\right) d \mu = \sum_{k = 1}^{n} c_{k} \mu (E_{k}).

The quote above is taken from page 796 of The Princeton Companion to Mathematics, edited by Timothy Gowers.

Problem 3B.1

Give an example of a sequence f1,f2,…f_{1}, f_{2}, \ldots of functions from N\mathbb {N} to [0,∞)[0, \infty ) such that

lim⁡k→∞fk(m)=0 \lim _{k \rightarrow \infty } f_{k}(m) = 0

for every m∈Nm \in \mathbb {N} but lim⁡k→∞∫fkdμ=1\lim_{k \rightarrow \infty } \int f_{k} d \mu = 1, where μ\mu is counting measure on N\mathbb {N}.

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Problem 3B.2

Give an example of a sequence f1,f2,…f_{1}, f_{2}, \ldots of continuous functions from R\mathbb {R} to [0,1][0,1] such that

lim⁡k→∞fk(x)=0 \lim _{k \rightarrow \infty } f_{k}(x) = 0

for every x∈Rx \in \mathbb {R} but lim⁡k→∞∫fkdλ=∞\lim_{k \rightarrow \infty } \int f_{k} d \lambda = \infty, where λ\lambda is Lebesgue measure on R\mathbb {R}.

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Problem 3B.3

Suppose λ\lambda is Lebesgue measure on R\mathbb {R} and f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} is a Borel measurable function such that ∫∣f∣dλ<∞\int \left|f\right| d \lambda < \infty. Define g:R→Rg: \mathbb {R} \rightarrow \mathbb {R} by

g(x)=∫(−∞,x)fdλ g(x) = \int _{(-\infty , x)} f d \lambda

Prove that gg is uniformly continuous on R\mathbb {R}.

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Problem 3B.4
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(a)

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space with μ(X)<∞\mu (X) < \infty. Suppose that f:X→[0,∞)f: X \rightarrow [0, \infty ) is a bounded S\mathcal{S}-measurable function. Prove that

∫fdμ=inf⁡{∑j=1mμ(Aj)sup⁡Ajf:A1,…,Am is an S-partition of X} \int f d \mu = \inf \left\{ \sum _{j = 1}^{m} \mu \left(A_{j}\right) \sup _{A_{j}} f: A_{1}, \ldots , A_{m} \text{ is an } \mathcal{S} \text{-partition of } X\right\}
(b)

Show that the conclusion of part (a) can fail if the hypothesis that ff is bounded is replaced by the hypothesis that ∫fdμ<∞\int f d \mu < \infty.

(c)

Show that the conclusion of part (a) can fail if the condition that μ(X)<∞\mu (X) < \infty is deleted.

Remark.
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Part (a) of this exercise shows that if we had defined an upper Lebesgue sum, then it could be used to define ∫fdμ\int f d \mu when ff is bounded and μ(X)<∞\mu (X) < \infty. However, parts (b) and (c) show that the hypotheses that ff is bounded and that μ(X)<∞\mu (X) < \infty are needed if defining the integral via the equation above. The definition of the integral via the lower Lebesgue sum does not require these hypotheses, showing the advantage of using the lower Lebesgue sum.

Problem 3B.5

Let λ\lambda denote Lebesgue measure on R\mathbb {R}. Suppose f:R→Rf: \mathbb {R} \rightarrow \mathbb {R} is a Borel measurable function such that ∫∣f∣dλ<∞\int \left|f\right| d \lambda < \infty. Prove that

lim⁡k→∞∫[−k,k]fdλ=∫fdλ \lim _{k \rightarrow \infty } \int _{[-k, k]} f d \lambda = \int f d \lambda
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Problem 3B.6

Let λ\lambda denote Lebesgue measure on R\mathbb {R}. Give an example of a continuous function f:[0,∞)→Rf:[0, \infty ) \rightarrow \mathbb {R} such that lim⁡t→∞∫[0,t]fdλ\lim_{t \rightarrow \infty } \int_{[0, t]} f d \lambda exists (in R\mathbb {R}) but ∫[0,∞)fdλ\int_{[0, \infty )} f d \lambda is not defined.

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Problem 3B.7

Let λ\lambda denote Lebesgue measure on R\mathbb {R}. Give an example of a continuous function f:(0,1)→Rf:(0,1) \rightarrow \mathbb {R} such that lim⁡n→∞∫(1n,1)fdλ\lim_{n \rightarrow \infty } \int_{\left(\frac{1}{n}, 1\right)} f d \lambda exists (in R\mathbb {R}) but ∫(0,1)fdλ\int_{(0,1)} f d \lambda is not defined.

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Problem 3B.8

Verify the assertion in 3.38.

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Remark.
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Setup: suppose a<ba < b and f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is a bounded function. For n∈Nn \in \mathbb {N}, let PnP_{n} be the partition that divides [a,b][a, b] into 2n2^{n} subintervals of equal size, with corresponding closed subintervals I1,…,I2nI_{1}, \ldots , I_{2^{n}}, and let

gn=∑j=12n(inf⁡Ijf)χIjandhn=∑j=12n(sup⁡Ijf)χIj. g_{n} = \sum _{j = 1}^{2^{n}}\left(\inf _{I_{j}} f\right)\chi _{I_{j}} \qquad \text{and} \qquad h_{n} = \sum _{j = 1}^{2^{n}}\left(\sup _{I_{j}} f\right)\chi _{I_{j}}.

Then g1≤g2≤⋯g_{1} \leq g_{2} \leq \cdots is an increasing sequence and h1≥h2≥⋯h_{1} \geq h_{2} \geq \cdots is a decreasing sequence of functions on [a,b][a, b]. Define fL,fU:[a,b]→Rf_{L}, f_{U}:[a, b] \rightarrow \mathbb {R} by

fL(x)=lim⁡n→∞gn(x)andfU(x)=lim⁡n→∞hn(x). f_{L}(x) = \lim _{n \rightarrow \infty } g_{n}(x) \qquad \text{and} \qquad f_{U}(x) = \lim _{n \rightarrow \infty } h_{n}(x).

3.38: {x∈[a,b]:fU(x)≠fL(x)}={x∈[a,b]:f is not continuous at x}\left\{ x \in [a, b]: f_{U}(x) \neq f_{L}(x)\right\} = \left\{ x \in [a, b]: f \text{ is not continuous at } x\right\}.

Problem 3B.9

Verify the assertion in Example 3.41.

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Remark.
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Example 3.41: if ff is a measurable function and ∫∣f∣pdμ<∞\int \left|f\right|^{p} d\mu < \infty for all p>0p > 0, it does not imply that ff is bounded.

Problem 3B.10
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(a)

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space such that μ(X)<∞\mu (X) < \infty. Suppose p,rp, r are positive numbers with p<rp < r. Prove that if f:X→[0,∞)f: X \rightarrow [0, \infty ) is an S\mathcal{S}-measurable function such that ∫frdμ<∞\int f^{r} d \mu < \infty, then ∫fpdμ<∞\int f^{p} d \mu < \infty.

(b)

Give an example to show that the result in part (a) can be false without the hypothesis that μ(X)<∞\mu (X) < \infty.

Problem 3B.11

Suppose (X,S,μ)(X, \mathcal{S}, \mu ) is a measure space and f∈L1(μ)f \in \mathcal{L}^{1}(\mu ). Prove that

{x∈X:f(x)≠0} \left\{ x \in X: f(x) \neq 0\right\}

is the countable union of sets with finite μ\mu-measure.

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Problem 3B.12

Suppose

fk(x)=(1−x)kcos⁡kxx f_{k}(x) = \frac{(1-x)^{k} \cos \frac{k}{x}}{\sqrt{x}}

Prove that lim⁡k→∞∫01fk=0\lim_{k \rightarrow \infty } \int_{0}^{1} f_{k} = 0.

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Problem 3B.13

Give an example of a sequence of nonnegative Borel measurable functions f1,f2,…f_{1}, f_{2}, \ldots on [0,1][0,1] such that both the following conditions hold:

  • lim⁡k→∞∫01fk=0\lim_{k \rightarrow \infty } \int_{0}^{1} f_{k} = 0;

  • sup⁡k≥mfk(x)=∞\sup_{k \geq m} f_{k}(x) = \infty for every m∈Nm \in \mathbb {N} and every x∈[0,1]x \in [0,1].

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Problem 3B.14

Let λ\lambda denote Lebesgue measure on R\mathbb {R}.

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(a)

Let f(x)=1/xf(x) = 1 / \sqrt{x}. Prove that ∫[0,1]fdλ=2\int_{[0,1]} f d \lambda = 2.

(b)

Let f(x)=1/(1+x2)f(x) = 1 /\left(1+x^{2}\right). Prove that ∫Rfdλ=π\int_{\mathbb {R}} f d \lambda = \pi.

(c)

Let f(x)=(sin⁡x)/xf(x) = (\sin x) / x. Show that the integral ∫(0,∞)fdλ\int_{(0, \infty )} f d \lambda is not defined but lim⁡t→∞∫(0,t)fdλ\lim_{t \rightarrow \infty } \int_{(0, t)} f d \lambda exists in R\mathbb {R}.

Problem 3B.15

Prove or give a counterexample: If GG is an open subset of (0,1)(0,1), then χG\chi_{G} is Riemann integrable on [0,1][0,1].

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Problem 3B.16

Suppose f∈L1(R)f \in \mathcal{L}^{1}(\mathbb {R}).

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(a)

For t∈Rt \in \mathbb {R}, define ft:R→Rf_{t}: \mathbb {R} \rightarrow \mathbb {R} by ft(x)=f(x−t)f_{t}(x) = f(x-t). Prove that

lim⁡t→0∥f−ft∥1=0 \lim _{t \rightarrow 0}\left\| f-f_{t}\right\| _{1} = 0
(b)

For t>0t > 0, define ft:R→Rf_{t}: \mathbb {R} \rightarrow \mathbb {R} by ft(x)=f(tx)f_{t}(x) = f(t x). Prove that

lim⁡t→1∥f−ft∥1=0 \lim _{t \rightarrow 1}\left\| f-f_{t}\right\| _{1} = 0