Section 1B

Riemann Integral Is Not Good Enough

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Problem 1B.1

Define f:[0,1]→Rf:[0,1] \rightarrow \mathbb {R} as follows:

f(a)={0 if a is irrational 1n if a is rational and n is the smallest positive integer  such that a=mn for some integer m f(a) = \begin{cases} 0 & \text{ if } a \text{ is irrational } \\ \frac{1}{n} & \text{ if } a \text{ is rational and } n \text{ is the smallest positive integer } \\ & \text{ such that } a = \frac{m}{n} \text{ for some integer } m\end{cases}

Show that ff is Riemann integrable and compute ∫01f\int_{0}^{1} f.

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Problem 1B.2

Suppose f:[a,b]→Rf:[a, b] \rightarrow \mathbb {R} is a bounded function. Prove that ff is Riemann integrable if and only if

L(−f,[a,b])=−L(f,[a,b]) L(-f,[a, b]) = -L(f,[a, b])
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Problem 1B.3

Suppose f,g:[a,b]→Rf, g:[a, b] \rightarrow \mathbb {R} are bounded functions. Prove that

L(f,[a,b])+L(g,[a,b])≤L(f+g,[a,b]) L(f,[a, b])+L(g,[a, b]) \leq L(f+g,[a, b])

and

U(f+g,[a,b])≤U(f,[a,b])+U(g,[a,b]) U(f+g,[a, b]) \leq U(f,[a, b])+U(g,[a, b])
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Problem 1B.4

Give an example of bounded functions f,g:[0,1]→Rf, g:[0,1] \rightarrow \mathbb {R} such that

L(f,[0,1])+L(g,[0,1])<L(f+g,[0,1]) L(f,[0,1])+L(g,[0,1]) < L(f+g,[0,1])

and

U(f+g,[0,1])<U(f,[0,1])+U(g,[0,1]) U(f+g,[0,1]) < U(f,[0,1])+U(g,[0,1])
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Problem 1B.5

Give an example of a sequence of continuous real-valued functions f1,f2,…f_{1}, f_{2}, \ldots on [0,1][0,1] and a continuous real-valued function ff on [0,1][0,1] such that

f(x)=lim⁡k→∞fk(x) f(x) = \lim _{k \rightarrow \infty } f_{k}(x)

for each x∈[0,1]x \in [0,1] but

∫01f≠lim⁡k→∞∫01fk \int _{0}^{1} f \neq \lim _{k \rightarrow \infty } \int _{0}^{1} f_{k}
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