Section 1B

Definition of Vector Space

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Problem 1B.1

Prove that −(−v)=v-(-v) = v for every v∈Vv \in V.

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Problem 1B.2

Suppose a∈F,v∈Va \in \mathbf{F}, v \in V, and av=0a v = 0. Prove that a=0a = 0 or v=0v = 0.

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Problem 1B.3

Suppose v,w∈Vv, w \in V. Explain why there exists a unique x∈Vx \in V such that v+3x=wv+3 x = w.

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Problem 1B.4

The empty set is not a vector space. The empty set fails to satisfy only one of the requirements listed in the definition of a vector space (1.20). Which one?

Definition 1.20 (vector space): a vector space is a set VV along with an addition on VV and a scalar multiplication on VV such that the following properties hold. Commutativity: u+v=v+uu+v = v+u for all u,v∈Vu, v \in V. Associativity: (u+v)+w=u+(v+w)(u+v)+w = u+(v+w) and (ab)v=a(bv)(a b) v = a(b v) for all u,v,w∈Vu, v, w \in V and for all a,b∈Fa, b \in \mathbf{F}. Additive identity: there exists an element 0∈V0 \in V such that v+0=vv+0 = v for all v∈Vv \in V. Additive inverse: for every v∈Vv \in V, there exists w∈Vw \in V such that v+w=0v+w = 0. Multiplicative identity: 1v=v1 v = v for all v∈Vv \in V. Distributive properties: a(u+v)=au+ava(u+v) = a u+a v and (a+b)v=av+bv(a+b) v = a v+b v for all a,b∈Fa, b \in \mathbf{F} and all u,v∈Vu, v \in V.

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Problem 1B.5

Show that in the definition of a vector space (1.20), the additive inverse condition can be replaced with the condition that

0v=0 for all v∈V 0 v = 0 \text{ for all } v \in V

Here the 0 on the left side is the number 0, and the 0 on the right side is the additive identity of VV.

Definition 1.20 (vector space): a vector space is a set VV along with an addition on VV and a scalar multiplication on VV such that the following properties hold. Commutativity: u+v=v+uu+v = v+u for all u,v∈Vu, v \in V. Associativity: (u+v)+w=u+(v+w)(u+v)+w = u+(v+w) and (ab)v=a(bv)(a b) v = a(b v) for all u,v,w∈Vu, v, w \in V and for all a,b∈Fa, b \in \mathbf{F}. Additive identity: there exists an element 0∈V0 \in V such that v+0=vv+0 = v for all v∈Vv \in V. Additive inverse: for every v∈Vv \in V, there exists w∈Vw \in V such that v+w=0v+w = 0. Multiplicative identity: 1v=v1 v = v for all v∈Vv \in V. Distributive properties: a(u+v)=au+ava(u+v) = a u+a v and (a+b)v=av+bv(a+b) v = a v+b v for all a,b∈Fa, b \in \mathbf{F} and all u,v∈Vu, v \in V.

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Remark.
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The phrase a "condition can be replaced" in a definition means that the collection of objects satisfying the definition is unchanged if the original condition is replaced with the new condition.

Problem 1B.6

Let ∞\infty and −∞-\infty denote two distinct objects, neither of which is in R\mathbb {R}. Define an addition and scalar multiplication on R∪{∞,−∞}\mathbb {R} \cup \left\{ \infty ,-\infty \right\} as you could guess from the notation. Specifically, the sum and product of two real numbers is as usual, and for t∈Rt \in \mathbb {R} define

t∞={−∞ if t<0,0 if t=0,∞ if t>0,t(−∞)={∞ if t<0,0 if t=0,−∞ if t>0, t \infty = \begin{cases} -\infty & \text{ if } t < 0, \\ 0 & \text{ if } t = 0, \\ \infty & \text{ if } t > 0, \end{cases} \qquad t(-\infty ) = \begin{cases} \infty & \text{ if } t < 0, \\ 0 & \text{ if } t = 0, \\ -\infty & \text{ if } t > 0, \end{cases}

and

t+∞=∞+t=∞+∞=∞t+(−∞)=(−∞)+t=(−∞)+(−∞)=−∞∞+(−∞)=(−∞)+∞=0 \begin{aligned} t+\infty & = \infty +t = \infty +\infty = \infty \\ t+(-\infty ) & = (-\infty )+t = (-\infty )+(-\infty ) = -\infty \\ \infty +(-\infty ) & = (-\infty )+\infty = 0 \end{aligned}

With these operations of addition and scalar multiplication, is R∪{∞,−∞}\mathbb {R} \cup \left\{ \infty ,-\infty \right\} a vector space over R\mathbb {R}? Explain.

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Problem 1B.7

Suppose SS is a nonempty set. Let VSV^{S} denote the set of functions from SS to VV. Define a natural addition and scalar multiplication on VSV^{S}, and show that VSV^{S} is a vector space with these definitions.

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Problem 1B.8

Suppose VV is a real vector space.

  • The complexification of VV, denoted by VCV_{\mathrm{C}}, equals V×VV \times V. An element of VCV_{\mathrm{C}} is an ordered pair (u,v)(u, v), where u,v∈Vu, v \in V, but we write this as u+ivu+i v.

  • Addition on VCV_{\mathrm{C}} is defined by

    (u1+iv1)+(u2+iv2)=(u1+u2)+i(v1+v2) \left(u_{1}+i v_{1}\right)+\left(u_{2}+i v_{2}\right) = \left(u_{1}+u_{2}\right)+i\left(v_{1}+v_{2}\right)

    for all u1,v1,u2,v2∈Vu_{1}, v_{1}, u_{2}, v_{2} \in V.

  • Complex scalar multiplication on VCV_{\mathrm{C}} is defined by

    (a+bi)(u+iv)=(au−bv)+i(av+bu) (a+b i)(u+i v) = (a u-b v)+i(a v+b u)

    for all a,b∈Ra, b \in \mathbb {R} and all u,v∈Vu, v \in V.

Prove that with the definitions of addition and scalar multiplication as above, VCV_{\mathrm{C}} is a complex vector space.

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Remark.
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Think of VV as a subset of VCV_{\mathrm{C}} by identifying u∈Vu \in V with u+i0u+i 0. The construction of VCV_{\mathrm{C}} from VV can then be thought of as generalizing the construction of Cn\mathbb {C}^{n} from Rn\mathbb {R}^{n}.