Computing the tangent plane and normal at a point

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Write the tangent plane and normal line equations at the given point for the following surface: z=x2+y2z=x^{2}+y^{2}; at the point M0(1,2,5)M_{0}(1,2,5).

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Write the tangent plane and normal line equations at the given point for the following surface: z=arctg⁡yxz=\operatorname {arctg}\dfrac {y}{x}; at the point M0(1,1,π4)M_{0}\left(1, 1, \dfrac {\pi }{4}\right).

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Write the tangent plane and normal line equations at the given point for the following surface: z=y+ln⁡xzz=y+\ln \dfrac {x}{z}; at the point M0(1,1,1)M_{0}(1,1,1).

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Write the tangent plane and normal line equations at the given point for the following surface: 2xz+2yz=82^{\frac{x}{z}}+2^{\frac{y}{z}}=8; at the point M0(2,2,1)M_{0}(2,2,1).

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Write the tangent plane and normal line equations at the given point for the following surface: x=acos⁡ψcos⁡φx=a\cos \psi \cos \varphi, y=bcos⁡ψsin⁡φy=b\cos \psi \sin \varphi, z=csin⁡ψz=c\sin \psi; at the point M0(φ0,ψ0)M_{0}(\varphi_{0}, \psi_{0}).

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Write the tangent plane and normal line equations at the given point for the following surface: x=rcos⁡φx=r\cos \varphi, y=rsin⁡φy=r\sin \varphi, z=rctg⁡αz=r\operatorname {ctg}\alpha; at the point M0(φ0,r0)M_{0}(\varphi_{0}, r_{0}).

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Write the tangent plane and normal line equations at the given point for the following surface: x=ucos⁡vx=u\cos v, y=usin⁡vy=u\sin v, z=avz=av; at the point M0(u0,v0)M_{0}(u_{0}, v_{0}).

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Find the limiting position of the tangent plane to the surface

x=u+v,y=u2+v2,z=u3+v3 x=u+v , \quad y=u^{2}+v^{2} , \quad z=u^{3}+v^{3}

at the point of tangency M(u,v)M(u,v) (u≠v)(u \neq v), as it approaches without bound a point M0(u0,v0)M_{0}(u_{0}, v_{0}) on the boundary curve u=vu=v of the surface.

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Find the tangent plane to the surface x2a2+y2b2+z2c2=1\dfrac {x^{2}}{a^{2}}+\dfrac {y^{2}}{b^{2}}+\dfrac {z^{2}}{c^{2}}=1 at the point (x1,y1,z1)(x_{1},y_{1},z_{1}).

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Find the tangent plane to the surface x2+y2=z2x^{2}+y^{2}=z^{2} at the point (x1,y1,z1)(x_{1},y_{1},z_{1}).

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Find the tangent plane to the surface xy2+z3=12xy^{2}+z^{3}=12 at the point (1,2,2)(1,2,2).

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Find the tangent plane to the surface xn+yn+zn=anx^{n}+y^{n}+z^{n}=a^{n} at the point (x1,y1,z1)(x_{1},y_{1},z_{1}).

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Find the tangent plane to the surface (x2+y2+z2)2=a2(x2−y2+z2)(x^{2}+y^{2}+z^{2})^{2}=a^{2}(x^{2}-y^{2}+z^{2}) at the point (x1,y1,z1)(x_{1},y_{1},z_{1}).

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The equation of an algebraic surface has the form f(x,y,z)=0f(x,y,z)=0, where f(x,y,z)f(x,y,z) is a polynomial. By introducing additionally powers of an auxiliary variable tt, this polynomial can be made homogeneous, after which the equation of the surface takes the form: F(x,y,z,t)=0F(x,y,z,t)=0 at t=1t=1. Prove that the equation of the tangent plane to this surface can be written in the form

∂F∂xX+∂F∂yY+∂F∂zZ+∂F∂t=0, \frac{\partial F}{\partial x}X+\frac{\partial F}{\partial y}Y+\frac{\partial F}{\partial z}Z+\frac{\partial F}{\partial t} = 0,

where, after differentiating, the variable tt is replaced by unity.

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Determine the distance from the origin to the tangent plane of the surface xcos⁡2πzh=ysin⁡2πzhx\cos \dfrac {2\pi z}{h}=y\sin \dfrac {2\pi z}{h}.

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Draw to the surface xyz=1xyz=1 a tangent plane parallel to the plane x+y+z−3=0x+y+z-3=0.

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Find the lines along which the tangent plane to the surface xy=azxy=az at the point (x1,y1,z1)(x_{1},y_{1},z_{1}) meets the surface:

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(a)

the line in the plane x=x1x=x_{1};

(b)

the line in the plane y=y1y=y_{1}.

Find the equation of the tangent plane to the skew helicoid

x=ucos⁡v,y=usin⁡v,z=av. x = u\cos v, \qquad y = u\sin v, \qquad z = av .
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Find the equation of the tangent plane to the surface

x=u+v,y=u2+v2,z=u3+v3 x = u+v, \qquad y = u^{2}+v^{2}, \qquad z = u^{3}+v^{3}

at the point (2,2,2)(2,2,2).

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Prove that the tangent planes to the surface xyz=a3xyz=a^{3} form, together with the coordinate planes, a tetrahedron of constant volume.

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Prove that the planes tangent to the surface x+y+z=a\sqrt{x}+\sqrt{y}+\sqrt{z}=\sqrt{a} cut off, on the coordinate axes, segments whose sum is constant.

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Prove that for the surface

x23+y23+z23=a23 x^{\frac{2}{3}}+y^{\frac{2}{3}}+z^{\frac{2}{3}} = a^{\frac{2}{3}}

the sum of the squares of the segments cut off on the axes by the tangent plane is a constant quantity.

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Prove that the planes tangent to the surface z=xf(yx)z=xf\left(\dfrac {y}{x}\right) all pass through one and the same point.

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Prove that the planes tangent to the surface z=x+f(y−z)z=x+f(y-z) are all parallel to one and the same line.

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Prove that the segment on the axis OzOz cut off by the plane tangent to the surface z+x2+y2+z2=xnf(yx)z+\sqrt{x^{2}+y^{2}+z^{2}}=x^{n}f\left(\dfrac {y}{x}\right) is proportional to the distance from the point of tangency to the origin.

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Find the surface on which the tangents to a helix lie, and prove that the normal to this surface makes a constant angle with the axis OzOz.

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Find the points on the ellipsoid x2a2+y2b2+z2c2=1\dfrac {x^{2}}{a^{2}}+\dfrac {y^{2}}{b^{2}}+\dfrac {z^{2}}{c^{2}}=1 at which the normal makes a given constant angle α\alpha with the axis OxOx.

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Prove that the point of intersection of the normal to the surface x2+y2+z2=xf(yx)x^{2}+y^{2}+z^{2}=xf\left(\dfrac {y}{x}\right) with the plane xOyxOy is equidistant from the origin and from the foot of the normal.

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The segment of the normal to the surface z2=2ax2+y2+bz^{2}=2a\sqrt{x^{2}+y^{2}}+b, lying between the surface and the plane xOyxOy, is projected onto xOyxOy. Prove that the length of the projection is constant.

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Prove the same property (constancy of the length of the projection, onto the plane xOyxOy, of the segment of the normal lying between the surface and this plane) as in the preceding problem, for the normals to the surface

x=vcos⁡u−φ(u)cos⁡u+φ′(u)sin⁡u, x = v\cos u-\varphi (u)\cos u+\varphi '(u)\sin u, y=vsin⁡u−φ(u)sin⁡u−φ′(u)cos⁡u, y = v\sin u-\varphi (u)\sin u-\varphi '(u)\cos u, z=2v. z = \sqrt{2v} .
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From a point MM on the surface

x=rcos⁡φ,y=rsin⁡φ,z2=−r2+f(reφ) x = r\cos \varphi , \qquad y = r\sin \varphi , \qquad z^{2} = -r^{2}+f(re^{\varphi })

a normal MNMN is drawn to a point NN in the plane xOyxOy, and a perpendicular MPMP is dropped onto the plane xOyxOy. Prove that the angle NOPNOP, where OO is the origin, equals π4\dfrac {\pi }{4}.

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Prove that for the surface z2=a2arctg⁡yx+f(x2+y2)z^{2}=a^{2}\arctg \dfrac {y}{x}+f(x^{2}+y^{2}), the area of the triangle NOPNOP, obtained in the same way as in the preceding problem, is a constant quantity.

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From the points of the line

y=x,z=π4, y = x, \qquad z = \frac{\pi }{4},

lying on the surface y=xtg⁡zy=x\tg z, normals are drawn to the surface. Prove that they lie on a hyperbolic paraboloid.

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The same question (prove that the normals, drawn from the points of a given line lying on the surface, to the surface, lie on a hyperbolic paraboloid) as in the preceding problem, for the line

z=h,by=xa2−h2 z = h, \qquad by = x\sqrt{a^{2}-h^{2}}

and the surface b2y2=x2(a2−z2)b^{2}y^{2}=x^{2}(a^{2}-z^{2}).

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Find the locus of the projections of the center of the ellipsoid x2a2+y2b2+z2c2=1\dfrac {x^{2}}{a^{2}}+\dfrac {y^{2}}{b^{2}}+\dfrac {z^{2}}{c^{2}}=1 onto its tangent planes.

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Along the ellipsoid of the preceding problem (with a>b>ca>b>c), another, equal ellipsoid rolls without slipping or spinning, so that at one moment the endpoints of the major semi-axes were in contact. Find the locus of the center of the (rolling) ellipsoid.

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Prove that the surface x2y2+x2z2+y2z2=2xyzx^{2}y^{2}+x^{2}z^{2}+y^{2}z^{2}=2xyz is met by the sphere x2+y2+z2=1x^{2}+y^{2}+z^{2}=1 in four circles.

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Write the equations of the tangent plane and the normal to the surface at the given point.

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(1)

z=xy,(2;1;2)z = x y,(2 ; 1 ; 2);

(2)

z=x2+y2,(1;1;2)z = x^{2}+y^{2},(1 ; 1 ; 2);

(3)

z=2x2−4y2,(−2;1;4)z = 2 x^{2}-4 y^{2},(-2 ; 1 ; 4);

(4)

z=(x−y)2−x+2y,(1;1;1)z = (x-y)^{2}-x+2 y,(1 ; 1 ; 1);

(5)

z=x3−3xy+y3,(1;1;−1)z = x^{3}-3 x y+y^{3},(1 ; 1 ;-1);

(6)

z=x2+y2−xy,(−3;4;17)z = \sqrt{x^{2}+y^{2}}-x y,(-3 ; 4 ; 17);

(7)

z=x2+y4,(0;0;0)z = \sqrt{x^{2}+y^{4}},(0 ; 0 ; 0);

(8)

z=x−y+∣xy∣,(0;0;0)z = x-y+\sqrt{\left|x y\right|},(0 ; 0 ; 0);

(9)

z=ln⁡x2+y2,(0;1;0)z = \ln \sqrt{x^{2}+y^{2}},(0 ; 1 ; 0);

(10)

z=sin⁡(x/y),(π;1;0)z = \sin (x / y),(\pi ; 1 ; 0);

(11)

z=excos⁡y,(1;0;e)z = e^{x \cos y},(1 ; 0 ; e);

(12)

z=arctg⁡(y/x),(1;1;π/4)z = \operatorname {arctg}(y / x),(1 ; 1 ; \pi / 4).

Write the equations of the tangent plane and the normal to the surface at the given point.

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(1)

x2+y2+z2=169,(3;4;−12)x^{2}+y^{2}+z^{2} = 169,(3 ; 4 ;-12);

(2)

xy2+z3=12,(1;2;2)x y^{2}+z^{3} = 12,(1 ; 2 ; 2)

(3)

x3+y3+z3+xyz=6,(1;2;−1)x^{3}+y^{3}+z^{3}+x y z = 6,(1 ; 2 ;-1);

(4)

xyz(z2−x2)=6+y5,(1;1;2)x y z\left(z^{2}-x^{2}\right) = 6+y^{5},(1 ; 1 ; 2);

(5)

x2+y2+z2=x+y+z−4,(2;3;6)\sqrt{x^{2}+y^{2}+z^{2}} = x+y+z-4,(2 ; 3 ; 6);

(6)

ez−z+xy=3e^{z}-z+x y = 3, (2;1;0)(2 ; 1 ; 0);

(7)

z=y+ln⁡(x/z),(1;1;1)z = y+\ln (x / z),(1 ; 1 ; 1);

(8)

2x/z+2y/z=8,(2;2;1)2^{x / z}+2^{y / z} = 8,(2 ; 2 ; 1).

Write the equations of the tangent plane and the normal to the surface at the given point.

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(1)

x=u+v,y=u2+v2,z=u3+v3,(3;5;9)x = u+v, y = u^{2}+v^{2}, z = u^{3}+v^{3},(3 ; 5 ; 9);

(2)

x=u,y=u2−2uv,z=u3−3u2v,(1;3;4)x = u, y = u^{2}-2 u v, z = u^{3}-3 u^{2} v,(1 ; 3 ; 4);

(3)

x=u+ln⁡v,y=v−ln⁡u,z=2u+v,(1;1;3)x = u+\ln v, y = v-\ln u, z = 2 u+v,(1 ; 1 ; 3);

(4)

x=cos⁡uch⁡v,y=sin⁡uch⁡v,z=sh⁡v,(ch⁡1/2;ch⁡1/2;sh⁡1)x = \cos u \operatorname {ch} v, y = \sin u \operatorname {ch} v, z = \operatorname {sh} v,(\operatorname {ch} 1 / \sqrt{2} ; \operatorname {ch} 1 / \sqrt{2} ; \operatorname {sh} 1).

Write the equation of the tangent plane to the surface at its given point (x0;y0;z0)\left(x_{0} ; y_{0} ; z_{0}\right):

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(1)

xn+yn+zn=an,n∈N,a>0x^{n}+y^{n}+z^{n} = a^{n}, n \in N, a > 0

(2)

(x2+y2+z2)2=a2(x2−y2+z2),a≠0\left(x^{2}+y^{2}+z^{2}\right)^{2} = a^{2}\left(x^{2}-y^{2}+z^{2}\right), a \neq 0.

Write the equation of the tangent plane to the surface:

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(1)

x=ucos⁡v,y=usin⁡v,z=ux = u \cos v, y = u \sin v, z = u;

(2)

x=3cos⁡ucos⁡v,y=2cos⁡usin⁡v,z=sin⁡ux = 3 \cos u \cos v, y = 2 \cos u \sin v, z = \sin u, at the point with parameters u=u0,v=v0u = u_{0}, v = v_{0}. Express the coefficients of the resulting equation in terms of the coordinates x0,y0,z0x_{0}, y_{0}, z_{0} of the point of tangency.

Write the equation of the tangent plane to the surface:

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(1)

x=(b+acos⁡ψ)cos⁡φ,y=(b+acos⁡ψ)sin⁡φ,z=asin⁡ψ,b⩾a>0x = (b+a \cos \psi ) \cos \varphi , y = (b+a \cos \psi ) \sin \varphi , z = a \sin \psi , b \geqslant a > 0

(2)

x=sin⁡φcos⁡ψ,y=sin⁡φsin⁡ψ,z=ln⁡tg⁡(φ/2)+cos⁡φx = \sin \varphi \cos \psi , y = \sin \varphi \sin \psi , z = \ln \operatorname {tg}(\varphi / 2)+\cos \varphi at the point with parameters φ=φ0,ψ=ψ0\varphi = \varphi_{0}, \psi = \psi_{0}.

Find the distance from the origin to the tangent plane to the surface z=arctg⁡(y/x)z = \operatorname {arctg}(y / x) at its point (x0;y0;z0)\left(x_{0} ; y_{0} ; z_{0}\right).

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Find the angles that the normal to the surface

z=arctg⁡(x/y) z = \operatorname {arctg}(x / y)

at the point (1/4;1/4;π/4)(1 / 4 ; 1 / 4 ; \pi / 4) makes with the coordinate axes.

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References

[Dem97] Demidovich B.P. Сборник задач и упражнений по математическому анализу. 13-е изд., Издательство Московского университета / Издательство "ЧеРо", 1997.
[ГюКу03] Гюнтер Н.М., Кузьмин Р.О. Сборник задач по высшей математике. 13-е изд., Издательство «Лань», 2003.
[ККЧ+03] Кудрявцев Л.Д., Кутасов А.Д., Чехлов В.И., Шабунин М.И. Функции многих переменных. 2-е изд., ФИЗМАТЛИТ, 2003.