Triangular form and invariant flags
[19/74%]Let represent a linear transformation from an -dimensional linear space into .
Let represent an -dimensional subspace of , and suppose that is invariant relative to . Show that there exists a basis for such that the matrix representation of with respect to and is of the (upper block-triangular) form (where is of dimensions ).
Let and represent subspaces of such that (i.e., essentially disjoint subspaces of whose sum is ). Suppose that both and are invariant relative to . Show that there exists a basis for such that the matrix representation of with respect to and is of the (block-diagonal) form [where the dimensions of equal ].
Suppose is finite-dimensional, and . Prove that if , then has a -dimensional subspace invariant under .
Suppose and is a basis of . Show that the following are equivalent.
The matrix of with respect to is lower triangular.
is invariant under for each .
for each .
A square matrix is called lower triangular if all entries above the diagonal are .
What form does the matrix of a linear transformation have, if the first basis vectors are its eigenvectors?
What form does the matrix of a linear transformation of an -dimensional vector space have, if the basis of an invariant subspace is formed by:
the first basis vectors
the last basis vectors?
Let a linear transformation of an -dimensional vector space possess a chain of pairwise distinct invariant subspaces nested in one another: . Prove that there exists in a basis in which the matrix of the transformation is upper triangular.
Let, in the basis , the matrix of a linear transformation of the space be upper triangular. Prove that the subspaces are invariant with respect to and .
A linear transformation of the space is given by the matrix in the standard basis. Reduce the matrix of the transformation to triangular form, if:
. .
. .
. .
. .
Let be a chain of subspaces of a vector space , invariant with respect to a linear transformation . Suppose the basis is chosen so that the vectors belong to . Show that the matrix is upper block-triangular with diagonal blocks of size , where , .
Let, in some basis, the matrix of a linear transformation be upper block-triangular. Prove that the transformation possesses a chain of invariant subspaces. Express their dimensions in terms of the orders of the diagonal blocks.
Prove that in an -dimensional complex space every linear operator has an invariant subspace of dimension .
Let be a linear operator on a finite-dimensional real space . Prove that has a basis in which the matrix of the operator has the block upper-triangular form
where the square blocks have size at most 2.
Let be a connected solvable topological group and a continuous homomorphism of into the group of nonsingular linear operators on a finite-dimensional complex space .
Prove that:
has a nonzero vector that is an eigenvector for all the operators ;
has a basis such that all the matrices , , are upper triangular in this basis.
Let be an algebraically closed field and a solvable group of nonsingular linear operators on a finite-dimensional vector space over . Prove that there exist a basis of and a normal subgroup of of finite index (depending only on ) such that consists of upper triangular matrices.
Let and be the matrices
Explain why the columns of are a basis for .
Verify that and are each invariant subspaces under .
Describe the structure of without doing any computation.
Now compute the product to determine and .
Let be a linear operator on a space , and suppose that
is a basis for such that has the block-diagonal form
Explain why and must each be invariant subspaces under .
If and are matrices such that
explain why and are each invariant subspaces under .
Recall (Example 4.8.3): if is regarded as the linear operator on defined by matrix multiplication , then with respect to the standard basis , .
For complementary subspaces and of , let be the projector onto along , and let , where the columns of and constitute bases for and , respectively. Prove that if is partitioned as , then
This means that if is a linear operator on , and (the bases making up the columns of ), then the matrix representation of with respect to is , where , , , (each a matrix representation of a restricted operator).
Characterize the matrices of operators А in the basis such that
the subspace is invariant under ;
the subspace is invariant under .
Prove that a linear operator on a space of dimension over an algebraically closed field always has an invariant subspace of dimension .
Show that in a space of dimension over an algebraically closed field every operator А has invariant subspaces of all dimensions from 0 to .