Path independence, exact differentials and potential fields

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In R2\mathbb {R}^{2}, consider the region A\mathcal{A} defined by x2+y2>1x^2+y^2 > 1. Find differentiable real valued functions ff and gg on A\mathcal{A} such that ∂f/∂x=∂g/∂y\partial f/\partial x = \partial g/\partial y but there is no real valued function hh on A\mathcal{A} such that f=∂h/∂yf = \partial h/\partial y and g=∂h/∂xg = \partial h/\partial x.

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(1)

Show that if u,v:R2→Ru, v : \mathbb {R}^{2} \rightarrow \mathbb {R} are continuously differentiable and ∂u∂y=∂v∂x\dfrac {\partial u}{\partial y} = \dfrac {\partial v}{\partial x}, then u=∂f∂xu = \dfrac {\partial f}{\partial x}, v=∂f∂yv = \dfrac {\partial f}{\partial y} for some f:R2→Rf : \mathbb {R}^{2} \rightarrow \mathbb {R}.

(2)

Prove there is no f:R2∖{0}→Rf : \mathbb {R}^{2} \setminus \left\{ 0\right\} \rightarrow \mathbb {R} such that

∂f∂x=−yx2+y2and∂f∂y=xx2+y2. \frac{\partial f}{\partial x} = \frac{-y}{x^2+y^2} \quad \text{and} \quad \frac{\partial f}{\partial y} = \frac{x}{x^2+y^2}.

Let the vector field FF in R3\mathbb {R}^{3} have the form

F(r)=g(∥r∥)r(r≠(0,0,0)), F(r) = g(\left\| r\right\| ) r \qquad (r \neq (0,0,0)),

where gg is a real valued smooth function on (0,∞)(0,\infty ) and ∥⋅∥\left\| \cdot \right\| denotes the Euclidean norm. (FF is undefined at (0,0,0)(0,0,0).) Prove that

∫CF⋅ds=0 \int _C F \cdot ds = 0

for any smooth closed path CC in R3\mathbb {R}^{3} that does not pass through the origin.

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For the paths indicated in problem 4248, compute ∫OAx dy+y dx\displaystyle \int_{OA} x\, dy+y\, dx, where OO is the origin of coordinates, the coordinates of point AA are (1,2)(1,2), and:

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(a)

OAOA is a straight segment;

(b)

OAOA is a parabola with axis OyOy;

(c)

OAOA is the broken line made up of the segment OBOB on the OxOx axis and the segment BABA parallel to the OyOy axis.

Verify that the integrand is a total differential, and compute the following curve integral: ∫(−1,2)(2,3)x dy+y dx\displaystyle \int_{(-1,2)}^{(2,3)} x\, dy+y\, dx.

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Verify that the integrand is a total differential, and compute the following curve integral: ∫(0,1)(3,−4)x dx+y dy\displaystyle \int_{(0,1)}^{(3,-4)} x\, dx+y\, dy.

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Verify that the integrand is a total differential, and compute the following curve integral: ∫(0,1)(2,3)(x+y) dx+(x−y) dy\displaystyle \int_{(0,1)}^{(2,3)} (x+y)\, dx+(x-y)\, dy.

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Verify that the integrand is a total differential, and compute the following curve integral: ∫(1,−1)(1,1)(x−y)(dx−dy)\displaystyle \int_{(1,-1)}^{(1,1)} (x-y)(dx-dy).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γxdy+ydx,A(−1;3),B(2;2)\int_{\Gamma } x d y+y d x, A(-1 ; 3), B(2 ; 2).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γxdx+ydy,A(−1;0),B(−3;4)\int_{\Gamma } x d x+y d y, A(-1 ; 0), B(-3 ; 4).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γ(x+y)dx+(x−y)dy,A(2;−1),B(1;0)\int_{\Gamma }(x+y) d x+(x-y) d y, A(2 ;-1), B(1 ; 0).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γ2xydx+x2dy,A(0;0),B(−2;−1)\int_{\Gamma } 2 x y d x+x^{2} d y, A(0 ; 0), B(-2 ;-1).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γ(x4+4xy3)dx+(6x2y2−5y4)dy,A(−2;−1),B(0;3)\int_{\Gamma }\left(x^{4}+4 x y^{3}\right) d x+\left(6 x^{2} y^{2}-5 y^{4}\right) d y, A(-2 ;-1), B(0 ; 3).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γ(x2+2xy−y2)dx+(x2−2xy−y2)dy,A(3;0),A(0;−3)\int_{\Gamma }\left(x^{2}+2 x y-y^{2}\right) d x+\left(x^{2}-2 x y-y^{2}\right) d y, \quad A(3 ; 0), \quad A(0 ;-3).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γ(3x2−2xy+y2)dx+(2xy−x2−3y2)dy\int_{\Gamma }\left(3 x^{2}-2 x y+y^{2}\right) d x+\left(2 x y-x^{2}-3 y^{2}\right) d y,

A(−1;2),B(1;−2) A(-1 ; 2), B(1 ;-2)
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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γf(x+y)(dx+dy),f(t)\int_{\Gamma } f(x+y)(d x+d y), f(t) — a continuous function, A(0;0)A(0 ; 0), B(x0;y0)B\left(x_{0} ; y_{0}\right).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γφ(x)dx+ψ(y)dy,φ(t),ψ(t)\int_{\Gamma } \varphi (x) d x+\psi (y) d y, \quad \varphi (t), \quad \psi (t) — continuous functions, A(x1;y1),B(x2;y2)A\left(x_{1} ; y_{1}\right), B\left(x_{2} ; y_{2}\right).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γexcos⁡ydx−exsin⁡ydy,A(0;0),B(x0;y0)\int_{\Gamma } e^{x} \cos y d x-e^{x} \sin y d y, A(0 ; 0), B\left(x_{0} ; y_{0}\right).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γxdx+y2dy−z3dz,A(−1;0;2),B(0;1;−2)\int_{\Gamma } x d x+y^{2} d y-z^{3} d z, A(-1 ; 0 ; 2), B(0 ; 1 ;-2).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γyzdx+xzdy+xydz,A(2;−1;0),B(1;2;3)\int_{\Gamma } y z d x+x z d y+x y d z, A(2 ;-1 ; 0), B(1 ; 2 ; 3).

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Having verified that the integrand is an exact differential, compute the curvilinear integral along the curve Γ\Gamma with initial point AA and terminal point BB. ∫Γxdx+ydy+zdzx2+y2+z2,A∈S1,B∈S2\int_{\Gamma } \frac{x d x+y d y+z d z}{\sqrt{x^{2}+y^{2}+z^{2}}}, A \in S_{1}, B \in S_{2}, where S1S_{1} — the sphere x2+y2+z2=R12,S2x^{2}+y^{2} + z^{2} = R_{1}^{2}, S_{2} — the sphere x2+y2+z2=R22(R1>0,R2>0)x^{2}+y^{2}+z^{2} = R_{2}^{2}\left(R_{1} > 0, R_{2} > 0\right).

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Find the function uu from the given exact differential of this function. du=x2dx+y2dyd u = x^{2} d x+y^{2} d y.

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Find the function uu from the given exact differential of this function. du=(e2y−5y3ex)dx+(2xe2y−15y2ex)dyd u = \left(e^{2 y}-5 y^{3} e^{x}\right) d x+\left(2 x e^{2 y}-15 y^{2} e^{x}\right) d y.

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Find the function uu from the given exact differential of this function. du=ex−y[(1+x+y)dx+(1−x−y)dy]d u = e^{x-y}[(1+x+y) d x+(1-x-y) d y].

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Find the function uu from the given exact differential of this function. du=2x(1−ey)(1+x2)2dx+(e21+x2+1)dyd u = \frac{2 x\left(1-e^{y}\right)}{\left(1+x^{2}\right)^{2}} d x+\left(\frac{e^{2}}{1+x^{2}}+1\right) d y.

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Find the function uu from the given exact differential of this function. du=dx+dy+dzx+y+zd u = \frac{d x+d y+d z}{x+y+z}.

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Find the function uu from the given exact differential of this function. du=yzdx+xzdy+xydz1+x2y2z2d u = \frac{y z d x+x z d y+x y d z}{1+x^{2} y^{2} z^{2}}.

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Find the function uu from the given exact differential of this function. du=(x2−2yz)dx+(y2−2xz)dy+(z2−2xy)dzd u = \left(x^{2}-2 y z\right) d x+\left(y^{2}-2 x z\right) d y+\left(z^{2}-2 x y\right) d z.

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Find the function uu from the given exact differential of this function. du=(1−1y+yz)dx+(xz+xy2)dy−xyz2dzd u = \left(1-\frac{1}{y}+\frac{y}{z}\right) d x+\left(\frac{x}{z}+\frac{x}{y^{2}}\right) d y-\frac{x y}{z^{2}} d z.

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Find the function uu from the given exact differential of this function. du=(x+y−z)dx+(x+y−z)dy+(x+y+z)dzx2+y2+z2+2xyd u = \frac{(x+y-z) d x+(x+y-z) d y+(x+y+z) d z}{x^{2}+y^{2}+z^{2}+2 x y}

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What condition must the differentiable function F(x;y)F(x ; y) satisfy in order for the curvilinear integral

∫ΓABF(x;y)(ydx+xdy) \int _{\Gamma _{A B}} F(x ; y)(y d x+x d y)

to be independent of the path of integration ΓAB\Gamma_{A B}?

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Find the work done by the field F=−μr/r3,r=(x;y),r=∣r∣,μ=\mathbf{F} = -\mu \mathbf{r} / r^{3}, \mathbf{r} = (x ; y), r = \left|\mathbf{r}\right|, \mu = const:

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(1)

along the arc ABA B of the parabola y=x2−1y = x^{2}-1, where A(x1;y1),B(x2;y2)A\left(x_{1} ; y_{1}\right), B\left(x_{2} ; y_{2}\right);

(2)

along the arc ABA B of a smooth curve Γ\Gamma not passing through the origin, where A(x1;y1),B(x2;y2)A\left(x_{1} ; y_{1}\right), B\left(x_{2} ; y_{2}\right).

Find the work done by the field of central forces F=f(r)r\mathbf{F} = f(r) \mathbf{r}, where r=xi+yj+zk,r=∣r∣,f(r)\mathbf{r} = x \mathbf{i} + y \mathbf{j}+z \mathbf{k}, r = \left|\mathbf{r}\right|, f(r) is a function continuous for r>0r > 0, along a smooth contour Γ\Gamma with initial point A(x1;y1;z1)A\left(x_{1} ; y_{1} ; z_{1}\right) and terminal point B(x2;y2;z2)B\left(x_{2} ; y_{2} ; z_{2}\right), not containing the origin.

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Let (p;v)(p ; v) be the coordinates determining, on the plane OpvO p v, the state of one mole of an ideal gas (pressure and volume). The equation of state of one mole of such a gas has the form pv=RTp v = R T, where R=R = const >0,T> 0, T is the absolute temperature. When passing from the state (p1;v1)\left(p_{1} ; v_{1}\right) to the state (p2;v2)\left(p_{2} ; v_{2}\right) along the curve Γ\Gamma, the amount of heat received (or given off) by the gas is determined by the formula

Q=∫ΓcpRpdv+cvRvdp Q = \int _{\Gamma } \frac{c_{p}}{R} p d v+\frac{c_{v}}{R} v d p

where cv=const,cp=cv+Rc_{v} = \mathrm{const}, c_{p} = c_{v}+R. The curve given by the equation pvγ=p v^{\gamma } = const, where γ=cp/cv\gamma = c_{p} / c_{v}, is called an adiabat (and the process of change of state along this curve — adiabatic).

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(1)

Find the heat received by the gas in an isothermal process, i.e., along the curve pv=RT=p v = R T = const, when passing from the state (p1;v1)\left(p_{1} ; v_{1}\right) to the state (p2;v2)\left(p_{2} ; v_{2}\right).

(2)

Prove that in an adiabatic process the gas neither receives nor gives off heat.

(3)

Let pvγ=C1,pvγ=C2p v^{\gamma } = C_{1}, p v^{\gamma } = C_{2} be two adiabats, Γ(T)\Gamma (T) — the segment of the isotherm pv=RTp v = R T cut off by them, Q(T)Q(T) — the amount of heat received by the gas on Γ(T)\Gamma (T). Prove that for all isotherms Q(T)T=\frac{Q(T)}{T} = const.

(4)

A Carnot cycle is a closed contour formed by two adiabats and two isotherms pv=RT1p v = R T_{1} and pv=RT2,T2>T1p v = R T_{2}, T_{2} > T_{1}. Let this contour be oriented starting from the point with the greatest pressure along the isotherm pv=RT2p v = R T_{2}. Let QQ be the total heat received by the gas over the Carnot cycle, and Q2Q_{2} — over the isotherm pv=RT2p v = R T_{2}. Prove that the efficiency of the cycle η=Q/Q2\eta = Q / Q_{2} is given by the formula η=(T2−T1)/T2\eta = \left(T_{2}-T_{1}\right) / T_{2}.

Which of the indicated fields are potential in R3R^{3} :

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(1)

a=x2i+y2j+z2k\mathbf{a} = x^{2} \mathbf{i}+y^{2} \mathbf{j}+z^{2} \mathbf{k};

(2)

a=xzi+zyj+yxk\mathbf{a} = x z \mathbf{i}+z y \mathbf{j}+y x \mathbf{k}

(3)

a=(ax+y+bz)i+(2x+cy+dz)j+(bx+dy+cz)k\mathbf{a} = (a x+y+b z) \mathbf{i}+(2 x+c y+d z) \mathbf{j}+(b x+d y+c z) \mathbf{k};

(4)

a=yzcos⁡xyi+xzcos⁡xyj+sin⁡xyk?\mathbf{a} = y z \cos x y \mathbf{i}+x z \cos x y \mathbf{j}+\sin x y \mathbf{k}?

Is the field H=2I−yi+xjx2+y2,(x;y)≠(0;0)\mathbf{H} = 2 I \frac{-y \mathbf{i}+x \mathbf{j}}{x^{2}+y^{2}}, \quad (x ; y) \neq (0 ; 0), potential:

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(1)

in the half-space x>0x > 0;

(2)

in all of space except the axis OzO z?

Verify that the field H=2I(−yi+xj)/(x2+y2)\mathbf{H} = 2 I(-y \mathbf{i}+x \mathbf{j}) /\left(x^{2}+y^{2}\right) is potential in the half-space y>0y > 0, and find its potential.

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Verify the potentiality and find the potential of the field:

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(1)

a=(y+z)i+(z+x)j+(x+y)k;\mathbf{a} = (y+z) \mathbf{i}+(z+x) \mathbf{j}+(x+y) \mathbf{k} ;

(2)

a=yzi+zxj+xyk1+x2y2z2\mathbf{a} = \frac{y z \mathbf{i}+z x \mathbf{j}+x y \mathbf{k}}{1+x^{2} y^{2} z^{2}};

(3)

a=yi+xj+ezk\mathbf{a} = y \mathbf{i}+x \mathbf{j}+e^{z} \mathbf{k};

(4)

a=r/r;\mathbf{a} = \mathbf{r} / r ;

(5)

a=rr(r=xi+yj+zk,r=∣r∣)\mathbf{a} = r \mathbf{r}(\mathbf{r} = x \mathbf{i}+y \mathbf{j}+z \mathbf{k}, r = \left|\mathbf{r}\right|).

Let f(r),r>0f(r), r > 0, be a differentiable function. Prove that the (central) field a=f(r)r\mathbf{a} = f(r) \mathbf{r} is potential for r>0(r=xi+yj+zk,r=∣r∣)r > 0(\mathbf{r} = x \mathbf{i} + y \mathbf{j}+z \mathbf{k}, r = \left|\mathbf{r}\right|). Find the potential of a\mathbf{a}.

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Prove that the potential uu of a continuously differentiable field a satisfies the equation Δu=div⁡a\Delta u = \operatorname {div} \mathbf{a}.

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Prove that if the field a is potential in a region Ω\Omega that is star-shaped (see problem 30) with respect to the point M0(r0)M_{0}\left(r_{0}\right), then its potential at the point M(r)M(\mathbf{r}) is given by the formula

u(r)=∫01(a(r0+t(r−r0)),r−r0)dt+ const . u(\mathbf{r}) = \int _{0}^{1}\left(\mathbf{a}\left(\mathbf{r}_{0}+t\left(\mathbf{r}-\mathbf{r}_{0}\right)\right), \mathbf{r}-\mathbf{r}_{0}\right) d t+\text{ const }.
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Prove that the positions of stable equilibrium of a particle in a potential force field F=−grad⁡u\mathbf{F} = -\operatorname {grad} u are located at the points of minimum of the potential uu.

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Prove that a potential field has no closed vector lines.

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Is the field a potential, solenoidal, if (r=xi+yj+zk,r=∣r∣)(\mathbf{r} = x \mathbf{i}+y \mathbf{j}+z \mathbf{k}, r = \left|\mathbf{r}\right|) :

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(1)

a=r/r3\mathbf{a} = \mathbf{r} / r^{3};

(2)

a=r/r?\mathbf{a} = \mathbf{r} / r?

Prove the harmonicity of the plane field

a=r/r2,r=(x;y),r=∣r∣ \mathbf{a} = \mathbf{r} / r^{2}, \quad \mathbf{r} = (x ; y), \quad r = \left|\mathbf{r}\right|
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Prove the harmonicity of the gravitational field of a point mass and of the Coulomb field of a point charge.

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Prove that the potential of a harmonic field is a harmonic function, i.e. Δu=0\Delta u = 0.

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Let the velocity field v\mathbf{v} of a moving continuous medium be potential. Prove that if the medium is incompressible, then the potential uu of the field v\mathbf{v} is harmonic (one may use the fact that the volumetric flow rate of the medium through any closed surface equals zero).

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References

[deSi04] de Souza P.N., Silva J. Berkeley Problems in Mathematics. 3rd ed., Springer, 2004.
[Dem97] Demidovich B.P. Сборник задач и упражнений по математическому анализу. 13-е изд., Издательство Московского университета / Издательство "ЧеРо", 1997.
[ККЧ+03] Кудрявцев Л.Д., Кутасов А.Д., Чехлов В.И., Шабунин М.И. Функции многих переменных. 2-е изд., ФИЗМАТЛИТ, 2003.