Alternative bases for recursive function classes

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(a)

Prove that the function fn+1f^{n+1}, arising from the partial functions gng^{n} and hn+2h^{n+2} by means of the primitive recursion operator, can be obtained by means of a special recursion of the form:

{F(x,0)=x,F(x,y+1)=G(F(x,y)) \begin{cases} F(x, 0) = x, \\ F(x, y+1) = G(F(x, y)) \end{cases}

and superpositions from the functions gn,hn+2,o,s,Imng^{n}, h^{n+2}, o, s, I_{m}^{n} and c,l,rc, l, r from problem III.1.13.

(b)

Prove that the function f(x)f(x), obtained from aa and h(x,y)h(x, y) by means of the primitive recursion operator, can be obtained by means of iteration and superpositions from the functions a,h,o,s,Imna, h, o, s, I_{m}^{n} and c,l,rc, l, r from problem III.1.13.

Prove that the function fnf^{n}, obtained from the partial function gn+1g^{n+1} by means of the μ\mu-operator, can be obtained from the functions g,Imng, I_{m}^{n} and c,l,rc, l, r from problem III.1.13 by means of superpositions and a μ\mu-operator of the special form.

F(x)=μy[G(x,y)=0]. F(x) = \mu y \left[G(x, y) = 0\right].
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Prove that the function fn+1f^{n+1}, obtained by means of the primitive recursion operator from everywhere defined functions gng^{n} and hn+2h^{n+2}, can be obtained from these functions and the functions +,\symdiff,s,o,Imn+, \symdiff , s, o, I_{m}^{n} and c,l,r,βc, l, r, \beta from problems III.1.13, III.1.17, by means of superpositions and a μ\mu-operator of the special form from problem III.1.29.

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Prove that:

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(a)

i(ax+b)=b⋅ax−1a−1\mathbf{i}(ax+b) = b \cdot \dfrac {a^{x} - 1}{a - 1} for a>1a > 1;

(b)

i(1+[x2])=sg⁡x\mathbf{i}\left(1 + \left[\dfrac {x}{2}\right]\right) = \operatorname {sg} x;

(c)

i(x+1+[x+12]−[x2])=2x\symdiff1\mathbf{i}\left(x + 1 + \left[\dfrac {x+1}{2}\right] - \left[\dfrac {x}{2}\right]\right) = 2x \symdiff 1;

(d)

i(sg⁡‾ x+2x)=2x−1\symdiffsg⁡‾ x\mathbf{i}(\overline{\operatorname {sg}}\, x + 2x) = 2^{x-1} \symdiff \overline{\operatorname {sg}}\, x;

(e)

i(x+1+4x+1)=x2+x\mathbf{i}(x + 1 + \sqrt{4x+1}) = x^{2} + x;

(f)

i(x+1+2[x])=x2\mathbf{i}\left(x + 1 + 2\left[\sqrt{x}\right]\right) = x^{2}.

Prove that every primitive recursive function can be obtained from the functions s(x)=x+1s(x) = x+1 and q(x)=x\symdiff[x]2q(x) = x \symdiff \left[\sqrt{x}\right]^{2} by means of the operations of substitution, iteration, and addition of two functions (R. Robinson's theorem).

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Prove that:

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(a)

I11(f(x))=f(I11(x))=f(f−1(f(x)))=f(x)I_{1}^{1}(f(x)) = f(I_{1}^{1}(x)) = f(f^{-1}(f(x))) = f(x);

(b)

f−1(f(f−1(x)))=f−1(x)f^{-1}(f(f^{-1}(x))) = f^{-1}(x).

Prove that:

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(a)

if f−1(x)f^{-1}(x) is defined at some point aa, then

f(f−1(a))=a; f(f^{-1}(a)) = a;
(b)

if f−1(x)f^{-1}(x) is everywhere defined, then

f(f−1(x))=I11(x); f(f^{-1}(x)) = I_{1}^{1}(x);
(c)

there exists f(x)f(x) such that f−1(x)f^{-1}(x) is everywhere defined, but

f−1(f(x))≠I11(x). f^{-1}(f(x)) \neq I_{1}^{1}(x).

Let f(x)=μy[h(x,y)=0]f(x) = \mu y \left[h(x, y) = 0\right]. Prove that f(x)f(x) can be obtained from h,s(x)=x+1h, s(x) = x+1, and q(x)=x\symdiff[x]2q(x) = x \symdiff \left[\sqrt{x}\right]^{2} by means of the operations of substitution, inversion, and addition of two functions.

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Prove that every partial recursive function can be obtained from s(x)=x+1s(x) = x+1, q(x)=x\symdiff[x]2q(x) = x \symdiff \left[\sqrt{x}\right]^{2} by means of the operations of substitution, inversion, and addition of two functions (Yu. Robinson's theorem).

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Let the function ff be partial recursive but not general recursive. Prove that the domain of definition of the function f−1f^{-1} is primitive recursive.

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References

[LaMa02] Lavrov I.A., Maksimova L.L. Задачи по теории множеств, математической логике и теории алгоритмов. 5-е изд., Физматлит, 2002.