Grace's theorem on apolar polynomials

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Let

f(z)=a0+(n1)a1z+(n2)a2z2+⋯+(nn−1)an−1zn−1+anzn f(z) = a_0+\binom {n}{1}a_1z+\binom {n}{2}a_2z^2+\cdots +\binom {n}{n-1}a_{n-1}z^{n-1}+a_nz^n

be an arbitrary polynomial of degree nn and let ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n be arbitrary points in the complex plane. The expression

A(ζ1,ζ2,…,ζn)f(z)=1n!Aζ1Aζ2…Aζnf(z) A(\zeta _1, \zeta _2, \ldots , \zeta _n)f(z) = \frac{1}{n!}A_{\zeta _1}A_{\zeta _2}\ldots A_{\zeta _n}f(z)

is a symmetric multilinear function of the variables ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n, which we can write as follows:

A(ζ1,ζ2,…,ζn)f(z)=a0Σ0+a1Σ1+a2Σ2+⋯+an−1Σn−1+anΣn. A(\zeta _1, \zeta _2, \ldots , \zeta _n)f(z) = a_0\Sigma _0+a_1\Sigma _1+a_2\Sigma _2+\cdots +a_{n-1}\Sigma _{n-1}+a_n\Sigma _n.

Here Σ0,Σ1,Σ2,…,Σn−1,Σn\Sigma_0, \Sigma_1, \Sigma_2, \ldots , \Sigma_{n-1}, \Sigma_n are the elementary symmetric functions of ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n:

Σ0=1,Σ1=ζ1+ζ2+⋯+ζn, \Sigma _0=1, \qquad \Sigma _1=\zeta _1+\zeta _2+\cdots +\zeta _n, Σ2=ζ1ζ2+ζ1ζ3+⋯+ζn−1ζn,…,Σn=ζ1ζ2…ζn. \Sigma _2=\zeta _1\zeta _2+\zeta _1\zeta _3+\cdots +\zeta _{n-1}\zeta _n, \qquad \ldots , \qquad \Sigma _n=\zeta _1\zeta _2\ldots \zeta _n.

If the last kk of the numbers ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n (and only these) lie at infinity, then we set Σ0=Σ1=⋯=Σk−1=0\Sigma_0=\Sigma_1=\cdots =\Sigma_{k-1}=0, Σk=1\Sigma_k=1, Σk+1=ζ1+ζ2+⋯+ζn−k\Sigma_{k+1}=\zeta_1+\zeta_2+\cdots +\zeta_{n-k}, Σk+2=ζ1ζ2+ζ1ζ3+⋯+ζn−k−1ζn−k,…,Σn=ζ1ζ2…ζn−k\Sigma_{k+2}=\zeta_1\zeta_2+\zeta_1\zeta_3+\cdots +\zeta_{n-k-1}\zeta_{n-k}, \ldots , \Sigma_n=\zeta_1\zeta_2\ldots \zeta_{n-k}.

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Let

f(z)=a0+(n1)a1z+(n2)a2z2+⋯+(nn−1)an−1zn−1+anzn f(z) = a_0+\binom {n}{1}a_1z+\binom {n}{2}a_2z^2+\cdots +\binom {n}{n-1}a_{n-1}z^{n-1}+a_nz^n

be an arbitrary polynomial of degree nn with zeros z1,z2,…,znz_1, z_2, \ldots , z_n and

g(z)=b0+(n1)b1z+(n2)b2z2+⋯+(nn−1)bn−1zn−1+bnzn g(z) = b_0+\binom {n}{1}b_1z+\binom {n}{2}b_2z^2+\cdots +\binom {n}{n-1}b_{n-1}z^{n-1}+b_nz^n

an arbitrary polynomial of degree nn with zeros ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n. Calculate A(ζ1,ζ2,…,ζn)f(z)A(\zeta_1, \zeta_2, \ldots , \zeta_n)f(z) and A(z1,z2,…,zn)g(z)A(z_1, z_2, \ldots , z_n)g(z).

If the two polynomials are related in such a manner that

A(ζ1,ζ2,…,ζn)f(z)=0 A(\zeta _1, \zeta _2, \ldots , \zeta _n)f(z) = 0

or, equivalently [solution 139], A(z1,z2,…,zn)g(z)=0A(z_1, z_2, \ldots , z_n)g(z)=0, then the two polynomials f(z)f(z) and g(z)g(z) are termed apolar. The term suggests the vanishing of the nnth polar Aζ1Aζ2…Aζnf(z)A_{\zeta_1}A_{\zeta_2}\ldots A_{\zeta_n}f(z). The condition of apolarity is

a0bn−(n1)a1bn−1+(n2)a2bn−2−⋯+(−1)n−1(nn−1)an−1b1+(−1)nanb0=0. a_0b_n-\binom {n}{1}a_1b_{n-1}+\binom {n}{2}a_2b_{n-2}-\cdots +(-1)^{n-1}\binom {n}{n-1}a_{n-1}b_1+(-1)^na_nb_0=0.

[139.] The two systems z1,z2,…,znz_1, z_2, \ldots , z_n and ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n are also termed mutually apolar.

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What is the geometrical significance of the apolarity of z1,ζ1z_1, \zeta_1, and that of z1,z2z_1, z_2 and ζ1,ζ2\zeta_1, \zeta_2?

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Which are the systems ζ1,ζ2,…,ζn\zeta_1, \zeta_2, \ldots , \zeta_n, that are apolar to the system consisting of the roots of the equation zn−1=0z^n-1=0?

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Let z1,z2,…,znz_1, z_2, \ldots , z_n be an arbitrary system of points. There are nn systems ζ,ζ,…,ζ\zeta ,\zeta ,\ldots ,\zeta of coincident points that are apolar to the given system. Which are they?

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The polynomial of degree nn

f(z)=1−z+czn f(z) = 1-z+cz^n

is apolar to any system of numbers whose sum is nn and product is 00.

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Let the two polynomials f(z)f(z) and g(z)g(z) of degree nn be apolar to each other. Every circular domain that contains all the zeros of one polynomial also contains at least one zero of the other.

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Let the two polynomials f(z)f(z) and g(z)g(z) of degree nn be apolar to each other. The two smallest convex polygons that contain all the zeros of f(z)f(z) and g(z)g(z) respectively have at least one common point. More generally, the two smallest circular-arc polygons that are circularly convex with respect to the same point and that contain all the zeros of f(z)f(z) and g(z)g(z) respectively, also have at least one common point.

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The polynomial

1−z+czn 1-z+cz^n

always has one zero in the circle ∣z∣≤2\left|z\right| \leq 2.

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The polynomial

1−z+czn 1-z+cz^n

always has one zero in the circle ∣z−1∣≤1\left|z-1\right| \leq 1.

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The polynomial of k+1k+1 terms

1−z+c2zν2+c3zν3+⋯+ckzνk,1=ν1<ν2<ν3<⋯<νk 1-z+c_2z^{\nu _2}+c_3z^{\nu _3}+\cdots +c_kz^{\nu _k}, \qquad 1=\nu _1<\nu _2<\nu _3<\cdots <\nu _k

always has one zero in the circle

∣z∣≤[(1−1ν2)(1−1ν3)⋯(1−1νk)]−1, \left|z\right| \leq \left[\left(1-\frac{1}{\nu _2}\right)\left(1-\frac{1}{\nu _3}\right)\cdots \left(1-\frac{1}{\nu _k}\right)\right]^{-1},

and hence in the circle

∣z∣≤k. \left|z\right| \leq k.

(Generalization of 147.)

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If a polynomial of degree nn assumes the same value at two points aa and bb, a≠ba \neq b, then its derivative has at least one zero in the circular disc with center at the midpoint of the line segment abab and radius (∣a−b∣/2)cot⁡(π/n)(\left|a-b\right|/2)\cot (\pi /n). (Analogue of Rolle's theorem in the complex domain.)

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References

[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.