Generators, resolvents and the Hille-Yosida framework
[10/10%]Prove that the assertion of first-edition Problem 363 ceases to be true in the case .
Show that and commute and that
Show that for any we have
Hint: Approximate by a Riemann sum.
Show that if is a contraction semigroup and is the resolvent, then
Show that if is a bounded operator and , then is a strongly continuous semigroup of operators with infinitesimal generator . (We cannot assert that the are contractions.)
Prove that if is dissipative, the domain of is dense in , and the range of is dense in , then defined in (37.12) is a closed extension of that is dissipative and the range of is equal to . Show there is only one such closed extension of .
If the range of equals for a single value of , then the range of equals for every value of .
Hint: Define as the inverse of , then use (37.3) to define for other values of .
Let be a strongly continuous semigroup of contraction operators and let be the infinitesimal generator. Show that is dense in for every positive integer .
Suppose that is a strongly continuous semigroup, but not necessarily of contractions. Thus and in norm if , but we do not assume . Prove that there exist constants such that for all .
Hint: Use the uniform boundedness principle from functional analysis to prove there exists such that if . Then use the semigroup property.
Show that if the resolvent operator is a symmetric operator, then the transition operators are also symmetric: if , then .