Fourier integral representation

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For different values of xx, find the Dirichlet discontinuous multiplier

D(x)=2π∫0+∞sin⁡λcos⁡λx dλλ, D(x)=\dfrac {2}{\pi }\int _{0}^{+\infty }\sin \lambda \cos \lambda x\, \dfrac {d\lambda }{\lambda } ,

and sketch the graph of the function y=D(x)y=D(x).

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Represent the function by its Fourier integral:

f(x)={1,if ∣x∣<1;0,if ∣x∣>1. f(x)= \begin{cases} 1, & \text{if } \left|x\right|<1; \\ 0, & \text{if } \left|x\right|>1. \end{cases}
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Represent the function by its Fourier integral:

f(x)={sgn⁡x,if ∣x∣<1;0,if ∣x∣>1. f(x)= \begin{cases} \operatorname {sgn}x, & \text{if } \left|x\right|<1; \\ 0, & \text{if } \left|x\right|>1. \end{cases}
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Represent the function by its Fourier integral:

f(x)=sgn⁡(x−a)−sgn⁡(x−b)(b>a). f(x)=\operatorname {sgn}(x-a)-\operatorname {sgn}(x-b) \quad (b>a).
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Represent the function by its Fourier integral:

f(x)={h(1−∣x∣a),if ∣x∣⩽a;0,if ∣x∣>a. f(x)= \begin{cases} h\left(1-\dfrac {\left|x\right|}{a}\right), & \text{if } \left|x\right| \leqslant a; \\ 0, & \text{if } \left|x\right|>a. \end{cases}
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Represent the function by its Fourier integral:

f(x)=1a2+x2(a>0). f(x)=\dfrac {1}{a^{2}+x^{2}} \quad (a>0).
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Represent the function by its Fourier integral:

f(x)=xa2+x2(a>0). f(x)=\dfrac {x}{a^{2}+x^{2}} \quad (a>0).
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Represent the function by its Fourier integral:

f(x)={sin⁡x,if ∣x∣⩽π;0,if ∣x∣>π. f(x)= \begin{cases} \sin x, & \text{if } \left|x\right| \leqslant \pi ; \\ 0, & \text{if } \left|x\right|>\pi . \end{cases}
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Represent by a Fourier integral the function

f(x)={cos⁡x,if ∣x∣⩽π2;0,if ∣x∣>π2. f(x)= \begin{cases} \cos x , & \text{if } \left|x\right| \leqslant \dfrac {\pi }{2}; \\ 0 , & \text{if } \left|x\right|>\dfrac {\pi }{2}. \end{cases}
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Represent by a Fourier integral the function

f(t)={Asin⁡ωt,if ∣t∣⩽2πnω;0,if ∣t∣>2πnω(n a natural number). f(t)= \begin{cases} A\sin \omega t , & \text{if } \left|t\right| \leqslant \dfrac {2\pi n}{\omega }; \\ 0 , & \text{if } \left|t\right|>\dfrac {2\pi n}{\omega } \end{cases} \quad (n \text{ a natural number}) .
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Represent by a Fourier integral the function

f(x)=e−α∣x∣(α>0). f(x)=e^{-\alpha \left|x\right|} \quad (\alpha >0) .
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Represent by a Fourier integral the function

f(x)=e−α∣x∣cos⁡βx(α>0). f(x)=e^{-\alpha \left|x\right|}\cos \beta x \quad (\alpha >0) .
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Represent by a Fourier integral the function

f(x)=e−α∣x∣sin⁡βx(α>0). f(x)=e^{-\alpha \left|x\right|}\sin \beta x \quad (\alpha >0) .
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Represent by a Fourier integral the function

f(x)=e−x2. f(x)=e^{-x^{2}} .
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Represent by a Fourier integral the function

f(x)=xe−x2. f(x)=xe^{-x^{2}} .
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Represent by a Fourier integral the function

f(x)=e−x(0<x<+∞). f(x)=e^{-x} \quad (0<x<+\infty ) .
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(a)

Extend it as an even function;

(b)

Extend it as an odd function.

Find the functions φ(x)\varphi (x) and ψ(x)\psi (x), if

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(a)

∫0+∞φ(y)cos⁡xy dy=11+x2\displaystyle \int_{0}^{+\infty }\varphi (y)\cos xy\, dy=\dfrac {1}{1+x^{2}};

(b)

∫0+∞ψ(y)sin⁡xy dy=e−x\displaystyle \int_{0}^{+\infty }\psi (y)\sin xy\, dy=e^{-x} (x>0x>0).

By splitting the interval (−∞,∞)(-\infty ,\infty ) into the parts (−∞,x−h)(-\infty ,x-h), (x−h,x)(x-h,x), (x,x+h)(x,x+h), (x+h,∞)(x+h,\infty ), where hh is an arbitrarily chosen number, prove the equality:

lim⁡n→∞1π∫−∞∞f(u)sin⁡n(u−x)u−x du=f(x). \lim _{n \rightarrow \infty } \frac{1}{\pi } \int _{-\infty }^{\infty } f(u) \frac{\sin n(u-x)}{u-x}\, du = f(x) .

Here, for simplicity, it is assumed that f(x)f(x) is continuous everywhere, f′(x)f'(x) exists everywhere and is bounded on every given interval, and ∫−∞∞f(u) du\int_{-\infty }^{\infty } f(u)\, du is absolutely convergent.

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Under the same conditions on f(x)f(x) as in the preceding problem, prove Fourier's formula:

f(x)=12π∫−∞∞du∫−∞∞f(v)cos⁡u(v−x) dv. f(x) = \frac{1}{2\pi } \int _{-\infty }^{\infty } du \int _{-\infty }^{\infty } f(v) \cos u(v-x)\, dv .
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Show that the Fourier integral (see the preceding problem) remains valid also in the case when f(x)f(x) has finite discontinuities at isolated points, provided the earlier conditions are preserved at the remaining points. In that case, at the points of discontinuity the value of the integral equals 12(f(x+0)+f(x−0))\dfrac {1}{2}\left(f(x+0)+f(x-0)\right), where f(x+0)f(x+0) and f(x−0)f(x-0) are the limits from the right and from the left of f(ξ)f(\xi ) as ξ→x\xi \rightarrow x.

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Represent as a Fourier integral the function

f(x)={e−mx,x>0;emx,x<0;m>0. f(x) = \begin{cases} e^{-mx}, & x > 0; \\ e^{mx}, & x < 0; \quad m > 0 . \end{cases}
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Represent as a Fourier integral the function

f(x)={e−mx,x>0;−emx,x<0;m>0. f(x) = \begin{cases} e^{-mx}, & x > 0; \\ -e^{mx}, & x < 0; \quad m > 0 . \end{cases}
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Represent as a Fourier integral the function

f(x)={e−mx,x>0;0,x<0;m>0. f(x) = \begin{cases} e^{-mx}, & x > 0; \\ 0, & x < 0; \quad m > 0 . \end{cases}
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Represent as a Fourier integral the function

f(x)={1,∣x∣<τ;0,∣x∣>τ. f(x) = \begin{cases} 1, & \left|x\right| < \tau ; \\ 0, & \left|x\right| > \tau . \end{cases}
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Represent as a Fourier integral the function

f(x)={1,0<x<τ;−1,−τ<x<0;0,∣x∣>τ. f(x) = \begin{cases} 1, & 0 < x < \tau ; \\ -1, & -\tau < x < 0; \\ 0, & \left|x\right| > \tau . \end{cases}
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Represent as a Fourier integral the function

f(x)={A(1−∣x−x0∣a),∣x−x0∣<a;0,∣x−x0∣>a. f(x) = \begin{cases} A\left(1-\dfrac {\left|x-x_{0}\right|}{a}\right), & \left|x-x_{0}\right| < a; \\ 0, & \left|x-x_{0}\right| > a . \end{cases}
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Represent as a Fourier integral the function

f(x)={e−kxsin⁡ωx,x>0;0,x<0;k>0. f(x) = \begin{cases} e^{-kx}\sin \omega x, & x > 0; \\ 0, & x < 0; \quad k > 0 . \end{cases}
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Represent as a Fourier integral the function

f(x)={sin⁡x,0<x<nπ;n an integer;0,x<0; x>nπ. f(x) = \begin{cases} \sin x, & 0 < x < n\pi ; \quad n \text{ an integer}; \\ 0, & x < 0; \, x > n\pi . \end{cases}
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Represent the function f(x)f(x) by a Fourier integral.

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(1)

f(x)={1, if ∣x∣<τ0, if ∣x∣>τf(x) = \begin{cases} 1, & \text{ if }\left|x\right| < \tau \\ 0, & \text{ if }\left|x\right| > \tau \end{cases}

(2)

f(x)={1−∣x∣/a, if ∣x∣⩽a,0, if ∣x∣>a;f(x) = \begin{cases} 1-\left|x\right| / a, & \text{ if } & \left|x\right| \leqslant a, \\ 0, & \text{ if } & \left|x\right| > a ; \end{cases}

(3)

f(x)=sign⁡(x−a)−sign⁡(x−b),b>af(x) = \operatorname {sign}(x-a)-\operatorname {sign}(x-b), b > a;

(4)

f(x)=1/(x2+a2),a≠0f(x) = 1 /\left(x^{2}+a^{2}\right), a \neq 0.

Represent the function f(x)f(x) by a Fourier integral.

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(1)

f(x)=xx2+a2,a≠0f(x) = \frac{x}{x^{2}+a^{2}}, \quad a \neq 0;

(2)

f(x)={sin⁡x, if ∣x∣⩽π,0, if ∣x∣>π;f(x) = \begin{cases} \sin x, & \text{ if } & \left|x\right| \leqslant \pi , \\ 0, & \text{ if } & \left|x\right| > \pi ; \end{cases}

(3)

f(x)={cos⁡x, if ∣x∣⩽π/2,0, if ∣x∣>π/2;f(x) = \begin{cases} \cos x, & \text{ if } & \left|x\right| \leqslant \pi / 2, \\ 0, & \text{ if } & \left|x\right| > \pi / 2 ; \end{cases}

(4)

f(x)={sin⁡ωx, if ∣x∣⩽2πn/ω,n∈N,ω>0.0, if ∣x∣>2πn/ω,f(x) = \begin{cases} \sin \omega x, & \text{ if } & \left|x\right| \leqslant 2 \pi n / \omega , \quad n \in N, \quad \omega > 0. \\ 0, & \text{ if } & \left|x\right| > 2 \pi n / \omega , \end{cases}

Represent the function f(x)f(x) by a Fourier integral.

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(1)

f(x)=e−α∣x∣sin⁡βx,α>0f(x) = e^{-\alpha \left|x\right|} \sin \beta x, \alpha > 0

(2)

f(x)=e−α∣x∣cos⁡βx,α>0f(x) = e^{-\alpha \left|x\right|} \cos \beta x, \alpha > 0;

(3)

f(x)=e−x2f(x) = e^{-x^{2}};

(4)

f(x)=xe−x2f(x) = x e^{-x^{2}}.

Represent the function f(x)f(x) by a Fourier integral.

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(1)

f(x)={e−αx, if x>0,α>0;0, if x<0;f(x) = \begin{cases} e^{-\alpha x}, & \text{ if } x > 0, \quad \alpha > 0 ; \\ 0, & \text{ if } x < 0 ; \end{cases}

(2)

f(x)={e−αxsin⁡ωx, if x>0,α>0;0, if x<0;f(x) = \begin{cases} e^{-\alpha x} \sin \omega x, & \text{ if } x > 0, \quad \alpha > 0 ; \\ 0, & \text{ if } x < 0 ; \end{cases}

(3)

f(x)={sin⁡x, if 0<x<πn,0, if x<0 or x>πn,n∈N.f(x) = \begin{cases} \sin x, & \text{ if } 0 < x < \pi n, \\ 0, & \text{ if } x < 0 \text{ or } x > \pi n, n \in N. \end{cases}

Represent the function f(x)f(x) by a Fourier integral, extending it as an odd function to the interval (−∞;0)(-\infty ; 0), if:

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(1)

f(x)={sin⁡x, if 0⩽x⩽π0, if x>π;f(x) = \begin{cases} \sin x, & \text{ if } 0 \leqslant x \leqslant \pi \\ 0, & \text{ if } \quad x > \pi ; \end{cases}

(2)

f(x)={2−3x, if 0⩽x⩽2/3,0, if x>2/3.f(x) = \begin{cases} 2-3 x, & \text{ if } 0 \leqslant x \leqslant 2 / 3, \\ 0, & \text{ if } \quad x > 2 / 3. \end{cases}

Represent the function f(x)f(x) by a Fourier integral, extending it as an even function to the interval (−∞;0)(-\infty ; 0), if:

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(1)

f(x)=e−αx,x⩾0,α>0f(x) = e^{-\alpha x}, x \geqslant 0, \alpha > 0;

(2)

f(x)={1, if 0⩽x⩽10, if x>1.f(x) = \begin{cases} 1, & \text{ if } 0 \leqslant x \leqslant 1 \\ 0, & \text{ if } \quad x > 1. \end{cases}

Find φ(y)\varphi (y), if:

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(1)

∫0+∞φ(y)cos⁡xydy=11+x2\int_{0}^{+\infty } \varphi (y) \cos x y d y = \frac{1}{1+x^{2}};

(2)

∫0+∞φ(y)sin⁡xydy=e−x,x>0\int_{0}^{+\infty } \varphi (y) \sin x y d y = e^{-x}, x > 0.

References

[Dem97] Demidovich B.P. Сборник задач и упражнений по математическому анализу. 13-е изд., Издательство Московского университета / Издательство "ЧеРо", 1997.
[ГюКу03] Гюнтер Н.М., Кузьмин Р.О. Сборник задач по высшей математике. 13-е изд., Издательство «Лань», 2003.
[ККЧ+03] Кудрявцев Л.Д., Кутасов А.Д., Чехлов В.И., Шабунин М.И. Функции многих переменных. 2-е изд., ФИЗМАТЛИТ, 2003.