Toeplitz forms and Szego's limit theorems
[7/100%]Let be real and let the complex numbers
have the following property: If
denotes an arbitrary trigonometric polynomial of degree at most , that does not vanish identically and does not have a negative value for any value of , let
Show that for this to be true, it is necessary and sufficient that the Hermitian form
is positive (or positive definite, respectively).
Let the function be properly integrable in the interval . Let its Fourier series (Section 4 of Part VI) be
The Hermite forms
formed from the constants , , , , are called the Toeplitz forms associated with . (Cf. Problem 43).
Form the Toeplitz forms that belong to the following functions:
If the function is positive in the interval , then all its associated Toeplitz forms are positive definite. More precisely: If lies between the bounds in the interval , then we have
provided that the variables satisfy the condition . The equality sign can hold here only if at every point of continuity of .
Calculate the determinant of the form for the functions in Problem 67 and show that, if is everywhere positive,
Let be a trigonometric polynomial of first order and let be a parameter. The determinant of the Toeplitz form associated with is a polynomial of degree in with only real zeros. Calculate these zeros.
(continued). The zeros of all lie between the minimum and the maximum of , that is , if in the interval . Moreover if denotes an arbitrary properly integrable function in the interval , then we have
Let the Hermitian form
be positive definite. Then all the zeros of the polynomial
lie in the interior of the unit circle.