Dirichlet and Fejer kernels

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Prove that for 0<x<π0 < x < \pi the equality holds:

∑ν=1nsin⁡νxν=−x2+∫0x/2sin⁡(2n+1)tt dt+ \sum _{\nu =1}^{n} \frac{\sin \nu x}{\nu } = -\frac{x}{2}+\int _{0}^{x/2} \frac{\sin (2n+1)t}{t}\, dt+ +∫0x/2(1sin⁡t−1t)sin⁡(2n+1)t dt. +\int _{0}^{x/2} \left(\frac{1}{\sin t}-\frac{1}{t}\right) \sin (2n+1)t\, dt .
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Prove that for any real xx and integer n>0n > 0 the equality holds

∑ν=1nsin⁡νxν=2πθ;∣θ∣<1. \sum _{\nu =1}^{n} \frac{\sin \nu x}{\nu } = 2\pi \theta ; \quad \left|\theta \right| < 1 .
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For 0<x<π0 < x < \pi, prove the equality:

∑ν=1nsin⁡(2ν−1)x2ν−1= \sum _{\nu =1}^{n} \frac{\sin (2\nu -1)x}{2\nu -1} = =12∫0xsin⁡2ntt dt+12∫0x(1sin⁡t−1t)sin⁡2nt dt. = \frac{1}{2}\int _{0}^{x} \frac{\sin 2nt}{t}\, dt+\frac{1}{2}\int _{0}^{x} \left(\frac{1}{\sin t}-\frac{1}{t}\right) \sin 2nt\, dt .
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For any real xx and integer n>0n > 0, prove the equality:

∑ν=1nsin⁡(2ν−1)x2ν−1=32θ;∣θ∣<1. \sum _{\nu =1}^{n} \frac{\sin (2\nu -1)x}{2\nu -1} = \frac{3}{2}\theta ; \quad \left|\theta \right| < 1 .
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Prove Fejér's inequality:

∣cos⁡xn+cos⁡2xn−1+…+cos⁡nx1−cos⁡(n+1)x1−cos⁡(n+2)x2−…−cos⁡2nxn∣<10. \left|\frac{\cos x}{n}+\frac{\cos 2x}{n-1}+\ldots +\frac{\cos nx}{1}-\frac{\cos (n+1)x}{1}-\frac{\cos (n+2)x}{2}-\ldots -\frac{\cos 2nx}{n}\right| < 10 .
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The Fejér sum σn\sigma_{n} is the arithmetic mean of the first nn Fourier sums of the function f(x)f(x):

nσn=s0+s1+…+sn−1, n\sigma _{n} = s_{0}+s_{1}+\ldots +s_{n-1},

where for m⩾1m \geqslant 1

sm=a02+∑ν=1m(aνcos⁡νx+bνsin⁡νx);s0=a02, s_{m} = \frac{a_{0}}{2}+\sum _{\nu =1}^{m} (a_{\nu }\cos \nu x+b_{\nu }\sin \nu x); \quad s_{0} = \frac{a_{0}}{2},

aνa_{\nu }, bνb_{\nu } being the Fourier coefficients of the function f(x)f(x). Prove that ∣σn(x)∣<M\left|\sigma_{n}(x)\right| < M, if ∣f(x)∣<M\left|f(x)\right| < M throughout the period.

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Prove that if f(x)f(x) is a continuous function on the interval [−π,π]\left[-\pi ,\pi \right], l⩽f(x)⩽Ll \leqslant f(x) \leqslant L, and for every mm, ∣mam∣<A\left|ma_{m}\right| < A, ∣mbm∣<B\left|mb_{m}\right| < B, then

l−(A+B)⩽sn(x)⩽L+(A+B); l-(A+B) \leqslant s_{n}(x) \leqslant L+(A+B);

where ama_{m}, bmb_{m} are the Fourier coefficients, sn(x)s_{n}(x) is the nn-th partial sum of the Fourier series of f(x)f(x).

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Prove Lemma 13.17.

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Remark.
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Lemma 13.17: Let χN\chi_{N} denote the discrete characteristic function of the set {−N,…,N}\left\{ -N, \ldots , N\right\}, i.e., χN(n)=∑m=−NNδm(n)\chi_{N}(n) = \sum_{m = -N}^{N}\delta_{m}(n) (so χN(n)=1\chi_{N}(n) = 1 for −N≤n≤N-N \leq n \leq N and χN(n)=0\chi_{N}(n) = 0 for ∣n∣>N\left|n\right| > N). Then for each N∈NN \in \mathbb {N} we have dN(x)=∑n=−NNe2πinx=sin⁡((2N+1)πx)sin⁡πx=χ^N(x)=(χN)∨(x)d_{N}(x) = \sum_{n = -N}^{N} e^{2 \pi i n x} = \frac{\sin \left((2 N+1)\pi x\right)}{\sin \pi x} = \widehat{\chi }_{N}(x) = \left(\chi_{N}\right)^{\vee }(x).

Prove Theorem 13.18.

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Remark.
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Theorem 13.18: dN∈L1(T)d_{N} \in L^{1}(\mathbf{T}) and ∫01dN=1\int_{0}^{1} d_{N} = 1 for each N∈NN \in \mathbb {N}, and for N>1N > 1 we have 4π2∑k=1N1k≤∥dN∥L1≤3+4π2∑k=1N1k\frac{4}{\pi^{2}} \sum_{k = 1}^{N} \frac{1}{k} \leq \left\| d_{N}\right\|_{L^{1}} \leq 3+\frac{4}{\pi^{2}} \sum_{k = 1}^{N} \frac{1}{k}.

Prove the equality appearing in equation (13.18).

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Prove Lemma 13.20.

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(a)

wN(x)w_{N}(x) has the closed form wN(x)=1N+1(sin⁡π(N+1)xsin⁡πx)2w_{N}(x) = \frac{1}{N+1}\left(\frac{\sin \pi (N+1) x}{\sin \pi x}\right)^{2}.

(b)

{wN}\left\{ w_{N}\right\} forms an approximate identity on T\mathbf{T}.

Let AA be a nuclear integral operator on L2([0,1])L^{2}\left({[0,1]}\right) with continuous kernel K(x,y)K(x,y). Prove the identity

tr⁡A=∫01K(x,x) dx. \operatorname {tr}A=\int _0^1K(x,x)\, dx.
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Construct a δ\delta-shaped sequence consisting of trigonometric polynomials on the torus Tn\mathrm{T}^n.

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Prove that ∫0π/2(sin⁡nxsin⁡x)2dx=nπ2,  n∈N\int_{0}^{\pi / 2}\left(\frac{\sin n x}{\sin x}\right)^{2} d x = \frac{n \pi }{2}, \; n \in N (Fejér).

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Find the integrals:

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(1)

∫0πsin⁡nxsin⁡xdx\int_{0}^{\pi } \frac{\sin n x}{\sin x} d x;

(2)

∫0πcos⁡(2n+1)xcos⁡xdx\int_{0}^{\pi } \frac{\cos (2 n+1) x}{\cos x} d x.

Prove the equality

∫0π/2sin⁡nxsin⁡xdx=π2−2cos⁡πn2∫01xndx1+x2,n=0,1,2,… \int _{0}^{\pi / 2} \frac{\sin n x}{\sin x} d x = \frac{\pi }{2}-2 \cos \frac{\pi n}{2} \int _{0}^{1} \frac{x^{n} d x}{1+x^{2}}, \quad n = 0,1,2, \ldots
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Let f(x)f(x) be a continuous periodic function with period 2π2\pi. Then

lim⁡n→∞12nπ∫02πf(t)(sin⁡nx−t2sin⁡x−t2)2 dt=f(x), \lim _{n \to \infty } \frac{1}{2n\pi } \int _{0}^{2\pi } f(t) \left(\frac{\sin n \dfrac {x-t}{2}}{\sin \dfrac {x-t}{2}}\right)^{2} \, dt = f(x),

the convergence is uniform for all xx.

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References

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[KiGv88] Kirillov A.A., Gvishiani A.D. Теоремы и задачи функционального анализа. 2-е изд., Наука, 1988.
[ККЧ+03] Кудрявцев Л.Д., Кутасов А.Д., Чехлов В.И., Шабунин М.И. Интегралы. Ряды. 2-е изд., ФИЗМАТЛИТ, 2003.
[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.