Sharkovskii theorem (period three implies all periods)
[3/100%]The set is called the trajectory of the point . If the trajectory is finite, then there exists such that the points are pairwise distinct, while ; in this case is called a periodic point, the number its period, and the tuple an -cycle.
Prove that if a continuous map of a segment into itself has a 4-cycle, then it also has a 2-cycle.
The set is called the trajectory of the point . If the trajectory is finite, then there exists such that the points are pairwise distinct, while ; in this case is called a periodic point, the number its period, and the tuple an -cycle.
Let be a continuous map of a segment into itself. Prove that the following statements are equivalent:
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there exists a point such that the points , satisfy the inequalities or ;
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in there exists a point having period three;
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for any , in there exists a point having period .
The implication b) ⇒ c) and problem 1.30 are special cases of A.N. Sharkovsky's theorem [Sh]. Let be a continuous map . Consider the natural numbers ordered as follows:
If stands to the left of in this sequence and has a -cycle, then also has a -cycle.
The set is called the trajectory of the point . If the trajectory is finite, then there exists such that the points are pairwise distinct, while ; in this case is called a periodic point, the number its period, and the tuple an -cycle.
Let be a continuous map of the circle into itself having a fixed point and a 3-cycle.
Prove that also has -cycles for all .
Must have a 2-cycle?