Conformal change of variables in derivatives and the Laplacian

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Assume that f(z)f(z) is analytic, use the notation

w=u+iv=f(z)=f(x+iy) w = u+iv = f(z) = f(x+iy)

as above and use subscripts to denote partial derivatives in the usual way. Verify that

ux2+vx2=uy2+vy2=ux2+uy2=vx2+vy2=uxvy−uyvx=∣dwdz∣2. u_{x}^{2} + v_{x}^{2} = u_{y}^{2} + v_{y}^{2} = u_{x}^{2} + u_{y}^{2} = v_{x}^{2} + v_{y}^{2} = u_{x}v_{y} - u_{y}v_{x} = \left|\frac{dw}{dz}\right|^{2}.
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(continued). Let φ(x,y)\varphi (x,y) and ψ(x,y)\psi (x,y) denote functions of the two real variables xx and yy having continuous derivatives of first order; they can also be considered as functions of uu and vv where f′(z)≠0f'(z) \neq 0. Verify that

φxψx+φyψy=(φuψu+φvψv)∣dwdz∣2. \varphi _{x}\psi _{x} + \varphi _{y}\psi _{y} = (\varphi _{u}\psi _{u} + \varphi _{v}\psi _{v})\left|\frac{dw}{dz}\right|^{2}.
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(continued). If φ(x,y)\varphi (x,y) has continuous derivatives of the second order, also

φxx+φyy=(φuu+φvv)∣dwdz∣2. \varphi _{xx} + \varphi _{yy} = (\varphi _{uu}+\varphi _{vv})\left|\frac{dw}{dz}\right|^{2}.
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(continued). Assume that a,b,ca, b, c and dd are real constants,

ad−bc=1, ad - bc = 1,

and consider

w=az+bcz+d. w = \frac{az+b}{cz+d}.

Then

φu2+φv2φx2+φy2=φuu+φvvφxx+φyy=y2v2. \frac{\varphi _{u}^{2}+\varphi _{v}^{2}}{\varphi _{x}^{2}+\varphi _{y}^{2}} = \frac{\varphi _{uu}+\varphi _{vv}}{\varphi _{xx}+\varphi _{yy}} = \frac{y^{2}}{v^{2}}.
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References

[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.