Hadamard's three circles theorem
[14/86%]Prove the theorem: if is regular for , and is the maximum modulus of , then for the quantity is a convex function of (Hadamard's Three-Circles Theorem).
Hint. It is useful to consider the function , choosing so that the quantities and for are equal.
Let the function be regular in the disk . Suppose
Then
This means that in an orthogonal system of coordinates the graph of as a function of appears as a convex curve. (Hadamard's three circle theorem.) [Examine with suitably chosen .]
(continued). The function is a strictly convex function of unless is of the form , constants, real: this is the only type of function for which the inequality in problem 304 becomes an equality.
Suppose that the function is regular for but not of the form , constant, integer; let
denote the arithmetic mean of on the circle , . The function is monotone increasing with and is a strictly convex function of .
Let be regular for ;
denotes the geometric mean of on the circle , . The function is monotone increasing with and a convex function of (in the wide sense).
The function is supposed to be regular for and not a constant. We put
The function is monotone increasing with and is a convex function of . [Problems 299, 304.]
We suppose that is regular and not constant for and that is a positive number. We define
The function is monotone increasing with and is a convex function of . (Cf.problems 306, 308, 307, 267 and 304, for an analogous case see Part IV, problem 19.)
Consider a regular harmonic function in the disk . We denote by its maximum on the circle , . When we have
i.e. is a convex function of .
Deduce Hadamard's three circle theorem 304 from problem 320 and vice versa problem 320 from Hadamard's three circle theorem.
The function is represented in a rectangular coordinate system by a curve which is always increasing and is strictly convex, apart from certain exceptional polynomials for which the curve degenerates into a straight line.
Let be fixed, . The quotient is strictly decreasing with increasing , apart from certain polynomials (see problem 20).
With the aid of Problem 123 of Part II, obtain a new proof for the Hadamard three-circle theorem (Problem 304 of Part III).
E. Landau.
The modular graph (see Volume I, p. 130) of an entire function is everywhere convex from below in just two cases: Either when
or when
where and are arbitrary complex numbers, a non-negative integer.
See the definition preceding Problem 130 of Part III. Cf. G. Polya, problem: Jber. deutsch. Math. Ver., Section 2, 35, p. 48 (1926). Solution by H. Kneser, op. cit. 35, p. 119 (1926), and by N. Tchebotarev, op. cit. 36, pp. 40-41 (1927).
Let the function be regular in the annulus . Denote
Prove that for the inequality holds
(Hadamard's three-circle theorem.)