Coefficient extraction and contour-deformation tricks

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(continued). We find

12πi∫Leeζ dζ=1. \frac{1}{2\pi i}\int _{L} e^{e^{\zeta }}\, d\zeta = 1.
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Let the function f(z)f(z) be continuous in the angle

−α⩽arg⁡z⩽α(0<α<π), -\alpha \leqslant \arg z \leqslant \alpha \quad (0 < \alpha < \pi ),

and let zf(z)→Az f(z) \rightarrow A as z→∞,∣arg⁡z∣⩽αz \rightarrow \infty , \quad \left|\arg z\right| \leqslant \alpha. Denote by CRC_{R} the arc of the circle ∣z∣=R,∣arg⁡z∣⩽α\left|z\right| = R, \quad \left|\arg z\right| \leqslant \alpha, going from the point z=Re−iαz = R e^{-i \alpha } to the point z=Reiαz = R e^{i \alpha }. Prove that

lim⁡R→∞∫CRf(z)dz=2iαA \lim _{R \rightarrow \infty } \int _{C_{R}} f(z) d z = 2 i \alpha A
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References

[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.
[ШПК15] Шабунин М.И., Половинкин Е.С., Карлов М.И. Сборник задач по теории функций комплексного переменного. 4-е изд., БИНОМ. Лаборатория знаний, 2015.