Algebraic functions
[7/86%]Find the singular points of the equation .
Algebraic functions satisfy an equation , where is a polynomial in the complex variables and . If both of these variables remain real, then the equation written represents an algebraic curve. If the equation has degree in , then it defines branches of a multivalued function of . They represent regular functions of in a domain where their values are finite and unequal. If is a point lying in such a domain, then each of the functions expands in integer powers of . If, however, at the point several of the coincide, then in a neighborhood of this point the functions expand in fractional powers of by the formula
where the number may be negative, and does not exceed . The values can be found by substituting these series into the equation. The singular points themselves can be found from the equations:
Find the singular points of the equation .
Find the singular points of the equation .
Find the singular points of the equation .
Let the function be regular (possibly many-valued) in the annular region , , and satisfy there identically an equation of the form
where are regular in a neighbourhood of the point . If there exists a power series such that the function remains bounded in the neighbourhood of for infinitely many values of , then is regular in the neighbourhood of , and we have .
Let be an analytic function, , and let the square of the absolute value of
be an algebraic function of the real variables and . Then the function is itself an algebraic function of .
H. A. Schwarz, oral communication.
Suppose and are function elements, is a polynomial in two variables, and in . Suppose and can be analytically continued along a curve , to and . Prove that . Extend this to more than two functions. Is there such a theorem for some class of functions which is larger than the polynomials?