Location and number of zeros of trigonometric polynomials

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The trigonometric polynomial

f(x)=a0+a1cos⁡x+a2cos⁡2x+⋯+ancos⁡nx f(x) = a_0 + a_1 \cos x + a_2 \cos 2x + \cdots + a_n \cos nx

with real coefficients a0,a1,a2,…,ana_0, a_1, a_2, \ldots , a_n has only real zeros if

∣a0∣+∣a1∣+∣a2∣+⋯+∣an−1∣<an. \left|a_0\right| + \left|a_1\right| + \left|a_2\right| + \cdots + \left|a_{n-1}\right| < a_n.
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Let G(z)G(z) be a polynomial of degree 2n2n and

z2nG‾(z−1)=G(z). z^{2n} \overline{G}(z^{-1}) = G(z).

How are the zeros of G(z)G(z) distributed in the complex plane?

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A trigonometric polynomial of order nn with real coefficients

g(ϑ)=λ0+λ1cos⁡ϑ+μ1sin⁡ϑ+λ2cos⁡2ϑ+μ2sin⁡2ϑ+⋯+λncos⁡nϑ+μnsin⁡nϑ, g(\vartheta ) = \lambda _0 + \lambda _1 \cos \vartheta + \mu _1 \sin \vartheta + \lambda _2 \cos 2\vartheta + \mu _2 \sin 2\vartheta + \cdots + \lambda _n \cos n\vartheta + \mu _n \sin n\vartheta ,

in which λn\lambda_n and μn\mu_n are not both zero, has exactly 2n2n zeros, if both real and complex values are admitted and multiple zeros are counted according to their multiplicity.

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Remark.
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ϑ\vartheta and ϑ+2π\vartheta + 2\pi are regarded as not distinct.

Where do the zeros of the following trigonometric polynomials lie:

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(1)

12+cos⁡ϑ+cos⁡2ϑ+⋯+cos⁡nϑ\dfrac {1}{2} + \cos \vartheta + \cos 2\vartheta + \cdots + \cos n\vartheta;

(2)

cos⁡ϑ+cos⁡2ϑ+⋯+cos⁡nϑ\cos \vartheta + \cos 2\vartheta + \cdots + \cos n\vartheta;

(3)

cos⁡ϑ+cos⁡3ϑ+cos⁡5ϑ+⋯+cos⁡(2n−1)ϑ\cos \vartheta + \cos 3\vartheta + \cos 5\vartheta + \cdots + \cos (2n-1)\vartheta;

(4)

sin⁡ϑ+sin⁡2ϑ+⋯+sin⁡nϑ\sin \vartheta + \sin 2\vartheta + \cdots + \sin n\vartheta;

(5)

sin⁡ϑ+sin⁡3ϑ+⋯+sin⁡(2n−1)ϑ\sin \vartheta + \sin 3\vartheta + \cdots + \sin (2n-1)\vartheta;

(6)

n+12+ncos⁡ϑ+(n−1)cos⁡2ϑ+⋯+cos⁡nϑ\dfrac {n+1}{2} + n \cos \vartheta + (n-1) \cos 2\vartheta + \cdots + \cos n\vartheta?

References

[PóSz98] Pólya G., Szegő G. Problems and Theorems in Analysis. Springer, 1998.